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STRUCTURAL DESIGN AND ANALYSIS REPORT
MODEL C-91 PROJECT A TWO-STOREY RESIDENTIAL BUILDING
PHILIPPINES
PREPARED FOR:
CAMELLA COMMUNITIES
A VISTA LAND COMPANY
PREPARED BY:
ROY MARTIN D. CASUMPANG, MSCE STRUCTURAL ENGINEER
LICENSE NO. 0104459
PTR NO. 0825106
PLACE ISSUED: DAVAO CITY
DATE ISSUED: 01-04-2012
JUNE 14, 2012
MATERIAL PROPERTIES
The following material properties were used as a design parameter for the main structural system.
Concrete:
Structural Element 28-day Compressive Strength, fc’
Footing 21 MPa (3,000 psi)
Column 21 MPa (3,000 psi)
Slab 21 MPa (3,000 psi)
Beam 21 MPa (3,000 psi)
Reinforcing Bars (longitudinal and ties): ASTM 615
Minimum yield strength, fy = 230 MPa (Grade 33)
Minimum tensile strength, ft = 400 MPa
DESIGN CRITERIA
Floor Dead Load:
� Self-weight of the material:
Reinforced concrete unit weight: 23.5 kN/cu.m
� Floor Finish – 1.20 kPa
� 100mm thk. Chb wall – 10 kPa
Floor Live load:
� Floor – 2.40 kPa (Residential)
Roof Dead load:
� Roof finish and Purlins – 0.30 kPa
Roof Live load:
� Floor – 0.60 kPa
Wind Load:
� Exposure Category – C
� Importance Factor, Iw – 1.0
� Basic Wind Speed, V – 200 kph
� Gust Effect factor, G – 0.85 (3-sec)
� Topographic factor, Kzt – 1.0
� Directionality factor, Kd – 0.85
Earthquake Load:
� Seismic Use Group – I
� Importance Factor, Ie – 1.0
� Site Class type - D
� Seismic Zone, Z – 0.4
� Response Modification factor, R – 8.5
� Near Source factor, Na – 1.0
� Near Source factor, Nv – 1.0
� Seismic Coefficient, Ca – 0.44
� Seismic Coefficient, Cv – 0.64
� Damping – 0.05
Framing Model:
Second Floor Framing Plan
Roof Framing Plan
ANALYSIS
Beam Forces:
STORY BEAM ITEM P V2 V3 T M2 M3
(kN) (kN) (kN) (kN-m) (kN-m) (kN-m)
STORY2 B1 Min Value -1.29 -5.87 -0.17 -0.537 -0.519 -4.846
Min Case UDCON2 UDCON4 UDCON13 UDCON5 UDCON6 UDCON3
Max Value -0.5 8.14 0.51 0.564 0.698 2.045
Max Case UDCON11 UDCON2 UDCON6 UDCON10 UDCON6 UDCON3
STORY2 B2 Min Value -5.23 -12.88 -0.07 -0.174 -0.216 -8.525
Min Case UDCON2 UDCON2 UDCON6 UDCON14 UDCON9 UDCON2
Max Value -1.95 11.92 0.11 0.433 0.277 6.046
Max Case UDCON11 UDCON2 UDCON9 UDCON5 UDCON9 UDCON2
STORY2 B3 Min Value -3.51 -5.31 -0.08 -0.945 -0.644 -5.758
Min Case UDCON6 UDCON5 UDCON11 UDCON2 UDCON4 UDCON6
Max Value -0.79 6.84 0.26 -0.092 0.26 2.105
Max Case UDCON13 UDCON2 UDCON4 UDCON12 UDCON4 UDCON6
STORY2 B4 Min Value -0.89 -5.5 -1.2 -0.699 -0.995 -3.827
Min Case UDCON4 UDCON5 UDCON4 UDCON4 UDCON4 UDCON5
Max Value -0.24 2.26 -0.11 0.559 1.384 1.469
Max Case UDCON11 UDCON6 UDCON11 UDCON11 UDCON4 UDCON9
STORY2 B5 Min Value -2.56 -6.36 -0.44 -0.503 -0.497 -4.33
Min Case UDCON2 UDCON5 UDCON3 UDCON3 UDCON6 UDCON5
Max Value -1.08 3.39 -0.05 0.566 0.451 2.745
Max Case UDCON13 UDCON6 UDCON12 UDCON8 UDCON3 UDCON9
STORY2 B6 Min Value -7.32 -6.33 0.09 -0.984 -0.955 -4.579
Min Case UDCON5 UDCON2 UDCON12 UDCON4 UDCON2 UDCON5
Max Value -2.55 5.46 0.39 0.067 0.431 1.869
Max Case UDCON14 UDCON2 UDCON2 UDCON11 UDCON3 UDCON2
STORY2 B7 Min Value -5.03 -11.78 -2.3 -0.164 -1.957 -10.002
Min Case UDCON3 UDCON2 UDCON2 UDCON10 UDCON2 UDCON2
Max Value -1.34 13.54 1.32 0.04 2.477 6.382
Max Case UDCON12 UDCON2 UDCON2 UDCON5 UDCON2 UDCON2
STORY2 B8 Min Value -3.62 -1.41 0.04 -0.238 -0.159 -4.382
Min Case UDCON2 UDCON9 UDCON13 UDCON11 UDCON10 UDCON6
Max Value -1.48 5.3 0.12 0.767 0 0.623
Max Case UDCON14 UDCON2 UDCON10 UDCON4 UDCON14 UDCON13
STORY2 B9 Min Value -1.68 -4.53 0.16 0.239 -0.701 -2.587
Min Case UDCON2 UDCON4 UDCON14 UDCON14 UDCON2 UDCON3
Max Value -0.73 4.78 0.51 1.072 0.646 1.722
Max Case UDCON11 UDCON3 UDCON2 UDCON2 UDCON2 UDCON2
STORY2 B10 Min Value -0.64 -5.96 -0.41 0.061 -0.539 -1.955
Min Case UDCON6 UDCON5 UDCON2 UDCON12 UDCON2 UDCON5
Max Value 0 3.58 -0.05 0.508 0.007 3.309
Max Case UDCON13 UDCON6 UDCON14 UDCON3 UDCON5 UDCON5
STORY2 B18 Min Value -1.45 -8.47 0.24 0.421 -1.368 -5.857
Min Case UDCON4 UDCON2 UDCON11 UDCON14 UDCON4 UDCON4
Max Value -0.26 4.5 0.81 0.714 0.45 1.705
Max Case UDCON11 UDCON3 UDCON4 UDCON1 UDCON6 UDCON4
STORY1 B1 Min Value -0.49 -20.58 -0.46 -0.825 -0.057 -25.514
Min Case UDCON6 UDCON4 UDCON6 UDCON5 UDCON10 UDCON3
Max Value 1.13 35.87 0.36 2.492 0.062 8.084
Max Case UDCON5 UDCON3 UDCON5 UDCON5 UDCON5 UDCON3
STORY1 B2 Min Value -0.14 -42.41 -0.55 -0.71 -0.018 -34.174
Min Case UDCON12 UDCON1 UDCON4 UDCON5 UDCON6 UDCON4
Max Value 3.61 39.33 0.03 3.186 0.093 24.237
Max Case UDCON3 UDCON3 UDCON6 UDCON6 UDCON4 UDCON2
STORY1 B3 Min Value -2.34 -35.99 -0.49 -5.679 -0.071 -26.92
Min Case UDCON9 UDCON5 UDCON5 UDCON3 UDCON4 UDCON6
Max Value 1.52 42.85 0.9 0.14 0.013 15.496
Max Case UDCON14 UDCON6 UDCON4 UDCON2 UDCON4 UDCON6
STORY1 B4 Min Value -1.4 -32.96 -0.05 -4.006 -0.015 -21.623
Min Case UDCON5 UDCON5 UDCON4 UDCON4 UDCON4 UDCON5
Max Value 0.66 17.9 1 1.738 0.067 4.504
Max Case UDCON7 UDCON5 UDCON4 UDCON11 UDCON4 UDCON6
STORY1 B5 Min Value -1.87 -23.68 -0.58 -1.274 -0.028 -15.79
Min Case UDCON13 UDCON5 UDCON10 UDCON4 UDCON10 UDCON6
Max Value 2.38 27.07 0.49 0.23 0.03 5.998
Max Case UDCON6 UDCON6 UDCON5 UDCON8 UDCON5 UDCON14
STORY1 B6 Min Value -0.34 -37.69 -0.05 -4.955 -0.17 -25.875
Min Case UDCON13 UDCON5 UDCON6 UDCON2 UDCON2 UDCON5
Max Value 5.75 38.12 2.56 0.969 0.037 19.294
Max Case UDCON5 UDCON6 UDCON2 UDCON4 UDCON2 UDCON2
STORY1 B7 Min Value -1.74 -34.76 -0.81 -3.677 -0.026 -43.08
Min Case UDCON11 UDCON4 UDCON2 UDCON6 UDCON2 UDCON2
Max Value 2.48 58.9 2.09 4.755 0.335 25.002
Max Case UDCON4 UDCON2 UDCON2 UDCON2 UDCON2 UDCON5
STORY1 B8 Min Value -3.7 -19.85 -1.55 -2.817 -0.02 -24.452
Min Case UDCON6 UDCON9 UDCON2 UDCON3 UDCON2 UDCON6
Max Value 0.22 34.22 0.04 0.243 0.125 3.94
Max Case UDCON13 UDCON6 UDCON5 UDCON12 UDCON2 UDCON9
STORY1 B9 Min Value -1.1 -29.57 -1.65 0.099 -0.244 -7.941
Min Case UDCON5 UDCON4 UDCON2 UDCON14 UDCON2 UDCON4
Max Value 2.53 19.4 0.03 3.944 0.216 12.147
Max Case UDCON2 UDCON3 UDCON5 UDCON2 UDCON2 UDCON2
STORY1 B10 Min Value -1.19 -24.49 -1.43 0.883 -0.123 -8.367
Min Case UDCON6 UDCON5 UDCON2 UDCON13 UDCON3 UDCON14
Max Value 2.6 19.71 0.04 4.324 0.112 12.889
Max Case UDCON5 UDCON10 UDCON6 UDCON6 UDCON2 UDCON5
STORY1 B11 Min Value -1.9 -20.43 -0.11 -7.072 -0.01 -24.287
Min Case UDCON11 UDCON4 UDCON5 UDCON2 UDCON13 UDCON3
Max Value 3.19 45 0.24 3.487 0.028 12.281
Max Case UDCON4 UDCON3 UDCON6 UDCON5 UDCON10 UDCON2
STORY1 B12 Min Value -2.1 -33.47 -0.18 -9.022 -0.011 -24.443
Min Case UDCON12 UDCON4 UDCON11 UDCON2 UDCON12 UDCON4
Max Value 3.56 5.74 0.32 -1.206 0.023 2.502
Max Case UDCON3 UDCON5 UDCON4 UDCON12 UDCON3 UDCON3
STORY1 B13 Min Value -1.75 -22.91 -0.13 -1.365 -0.024 -25.394
Min Case UDCON6 UDCON6 UDCON3 UDCON3 UDCON3 UDCON6
Max Value 1.14 38.05 0.14 7.144 0.023 10.151
Max Case UDCON13 UDCON2 UDCON3 UDCON4 UDCON3 UDCON2
STORY1 B14 Min Value -1.2 -42.91 -1.94 -2.785 -0.032 -25.285
Min Case UDCON13 UDCON5 UDCON2 UDCON3 UDCON4 UDCON5
Max Value 1.27 12.01 0.09 4.548 0.286 5.336
Max Case UDCON6 UDCON6 UDCON8 UDCON3 UDCON2 UDCON2
STORY1 B15 Min Value -1.33 -8.59 -1.08 -0.173 -0.163 -6.14
Min Case UDCON6 UDCON5 UDCON6 UDCON3 UDCON6 UDCON6
Max Value 0.79 10.89 0.22 4.709 0.049 4.667
Max Case UDCON4 UDCON6 UDCON11 UDCON3 UDCON4 UDCON6
STORY1 B16 Min Value -0.1 -12.41 -0.02 -0.148 -0.002 -2.449
Min Case UDCON14 UDCON6 UDCON6 UDCON10 UDCON6 UDCON6
Max Value 0.18 6.3 0.01 0.087 0.002 3.291
Max Case UDCON5 UDCON2 UDCON13 UDCON6 UDCON4 UDCON6
STORY1 B17 Min Value -6.43 -61.75 -0.99 -2.338 -0.214 -56.628
Min Case UDCON3 UDCON4 UDCON2 UDCON13 UDCON6 UDCON4
Max Value 3.32 38.21 0.59 3.149 0.178 35.088
Max Case UDCON12 UDCON3 UDCON6 UDCON6 UDCON13 UDCON6
Column Forces:
STORY COLUMN LOAD LOC P V2 V3 T M2 M3
(kN) (kN) (kN) (kN-m) (kN-m) (kN-m)
STORY2 C12 UDCON1
0 -4.96 0 -0.21 -0.04 -0.464 -0.11
1.35 -3.96 0 -0.21 -0.04 -0.18 -0.108
2.7 -2.96 0 -0.21 -0.04 0.104 -0.105
STORY2 C12 UDCON2
0 -8.1 -0.12 -0.3 -0.023 -0.556 -0.309
1.35 -7.24 -0.12 -0.3 -0.023 -0.146 -0.142
2.7 -6.38 -0.12 -0.3 -0.023 0.264 0.024
STORY2 C12 UDCON3
0 -8.21 -0.08 -0.93 -0.1 -1.569 -0.212
1.35 -7.35 -0.08 -0.93 -0.1 -0.319 -0.109
2.7 -6.5 -0.08 -0.93 -0.1 0.931 -0.007
STORY2 C12 UDCON4
0 -5.1 -0.08 0.41 0.045 0.576 -0.245
1.35 -4.24 -0.08 0.41 0.045 0.02 -0.138
2.7 -3.38 -0.08 0.41 0.045 -0.535 -0.03
STORY2 C12 UDCON5
0 -5.76 0.38 -0.29 -0.003 -0.511 0.372
1.35 -4.9 0.38 -0.29 -0.003 -0.125 -0.138
2.7 -4.05 0.38 -0.29 -0.003 0.261 -0.649
STORY2 C12 UDCON6
0 -7.55 -0.53 -0.23 -0.051 -0.482 -0.829
1.35 -6.69 -0.53 -0.23 -0.051 -0.173 -0.109
2.7 -5.84 -0.53 -0.23 -0.051 0.135 0.611
STORY2 C12 UDCON7
0 -5.8 0 -0.85 -0.106 -1.471 -0.077
1.35 -4.95 0 -0.85 -0.106 -0.324 -0.078
2.7 -4.09 0 -0.85 -0.106 0.822 -0.078
STORY2 C12 UDCON8
0 -2.69 0 0.49 0.039 0.674 -0.111
1.35 -1.84 0 0.49 0.039 0.015 -0.106
2.7 -0.98 0 0.49 0.039 -0.644 -0.102
STORY2 C12 UDCON9
0 -3.35 0.45 -0.21 -0.01 -0.412 0.507
1.35 -2.5 0.45 -0.21 -0.01 -0.13 -0.107
2.7 -1.64 0.45 -0.21 -0.01 0.152 -0.72
STORY2 C12 UDCON10
0 -5.14 -0.46 -0.15 -0.058 -0.384 -0.695
1.35 -4.29 -0.46 -0.15 -0.058 -0.179 -0.078
2.7 -3.43 -0.46 -0.15 -0.058 0.026 0.54
STORY2 C12 UDCON11
0 -4.74 0 -0.8 -0.098 -1.371 -0.054
1.35 -4.1 0 -0.8 -0.098 -0.286 -0.055
2.7 -3.46 0 -0.8 -0.098 0.8 -0.056
STORY2 C12 UDCON12
0 -1.63 0 0.53 0.047 0.774 -0.087
1.35 -0.99 0 0.53 0.047 0.054 -0.083
2.7 -0.35 0 0.53 0.047 -0.666 -0.08
STORY2 C12 UDCON13
0 -2.29 0.45 -0.16 -0.001 -0.313 0.53
1.35 -1.65 0.45 -0.16 -0.001 -0.092 -0.084
2.7 -1.01 0.45 -0.16 -0.001 0.129 -0.698
STORY2 C12 UDCON14
0 -4.08 -0.46 -0.11 -0.05 -0.284 -0.671
1.35 -3.44 -0.46 -0.11 -0.05 -0.14 -0.055
2.7 -2.8 -0.46 -0.11 -0.05 0.004 0.562
STORY1 C6 UDCON1
0 -91.83 -1.83 1.84 0 0 0
1.3 -89.9 -1.83 1.84 0 -2.397 2.381
2.6 -87.98 -1.83 1.84 0 -4.793 4.762
STORY1 C6 UDCON2
0 -100.25 -2.12 2.07 0 0 0
1.3 -98.6 -2.12 2.07 0 -2.689 2.757
2.6 -96.95 -2.12 2.07 0 -5.379 5.513
STORY1 C6 UDCON3
0 -89.1 -1.81 0.56 0 0 0
1.3 -87.45 -1.81 0.56 0 -0.734 2.358
2.6 -85.8 -1.81 0.56 0 -1.469 4.715
STORY1 C6 UDCON4
0 -95.25 -2.01 3.21 0 0 0
1.3 -93.6 -2.01 3.21 0 -4.168 2.619
2.6 -91.95 -2.01 3.21 0 -8.335 5.238
STORY1 C6 UDCON5
0 -90.86 1.3 1.98 0 0 0
1.3 -89.21 1.3 1.98 0 -2.573 -1.695
2.6 -87.56 1.3 1.98 0 -5.146 -3.39
STORY1 C6 UDCON6
0 -93.48 -5.13 1.79 0 0 0
1.3 -91.83 -5.13 1.79 0 -2.329 6.672
2.6 -90.18 -5.13 1.79 0 -4.658 13.343
STORY1 C6 UDCON7
0 -75.63 -1.47 0.26 0 0 0
1.3 -73.98 -1.47 0.26 0 -0.338 1.91
2.6 -72.33 -1.47 0.26 0 -0.675 3.821
STORY1 C6 UDCON8
0 -81.78 -1.67 2.9 0 0 0
1.3 -80.13 -1.67 2.9 0 -3.771 2.172
2.6 -78.48 -1.67 2.9 0 -7.542 4.343
STORY1 C6 UDCON9
0 -77.4 1.65 1.67 0 0 0
1.3 -75.75 1.65 1.67 0 -2.176 -2.142
2.6 -74.1 1.65 1.67 0 -4.353 -4.285
STORY1 C6 UDCON10
0 -80.02 -4.79 1.49 0 0 0
1.3 -78.37 -4.79 1.49 0 -1.932 6.224
2.6 -76.72 -4.79 1.49 0 -3.864 12.449
STORY1 C6 UDCON11
0 -55.96 -1.08 -0.14 0 0 0
1.3 -54.72 -1.08 -0.14 0 0.176 1.4
2.6 -53.48 -1.08 -0.14 0 0.352 2.8
STORY1 C6 UDCON12
0 -62.11 -1.28 2.51 0 0 0
1.3 -60.87 -1.28 2.51 0 -3.257 1.661
2.6 -59.63 -1.28 2.51 0 -6.514 3.323
STORY1 C6 UDCON13
0 -57.72 2.04 1.28 0 0 0
1.3 -56.49 2.04 1.28 0 -1.663 -2.653
2.6 -55.25 2.04 1.28 0 -3.325 -5.305
STORY1 C6 UDCON14
0 -60.34 -4.4 1.09 0 0 0
1.3 -59.1 -4.4 1.09 0 -1.419 5.714
2.6 -57.87 -4.4 1.09 0 -2.837 11.428
STORY1 C16 UDCON1
0 -73.87 -0.17 0.1 0 0 0
1.3 -72.16 -0.17 0.1 0 -0.134 0.222
2.6 -70.45 -0.17 0.1 0 -0.269 0.444
STORY1 C16 UDCON2
0 -96.79 -0.1 0.14 0 0 0
1.3 -95.32 -0.1 0.14 0 -0.186 0.133
2.6 -93.85 -0.1 0.14 0 -0.373 0.267
STORY1 C16 UDCON3
0 -86.6 7.18 0.12 0 0 0
1.3 -85.14 7.18 0.12 0 -0.154 -9.335
2.6 -83.67 7.18 0.12 0 -0.308 -18.669
STORY1 C16 UDCON4
0 -81.87 -7.42 0.13 0 0 0
1.3 -80.4 -7.42 0.13 0 -0.166 9.644
2.6 -78.93 -7.42 0.13 0 -0.331 19.288
STORY1 C16 UDCON5
0 -82.87 -0.34 0.62 0 0 0
1.3 -81.4 -0.34 0.62 0 -0.809 0.44
2.6 -79.93 -0.34 0.62 0 -1.618 0.88
STORY1 C16 UDCON6
0 -85.61 0.1 -0.38 0 0 0
1.3 -84.14 0.1 -0.38 0 0.49 -0.13
2.6 -82.67 0.1 -0.38 0 0.979 -0.26
STORY1 C16 UDCON7
0 -65.68 7.15 0.08 0 0 0
1.3 -64.22 7.15 0.08 0 -0.109 -9.299
2.6 -62.75 7.15 0.08 0 -0.219 -18.598
STORY1 C16 UDCON8
0 -60.95 -7.45 0.09 0 0 0
1.3 -59.48 -7.45 0.09 0 -0.121 9.68
2.6 -58.02 -7.45 0.09 0 -0.242 19.359
STORY1 C16 UDCON9
0 -61.95 -0.37 0.59 0 0 0
1.3 -60.48 -0.37 0.59 0 -0.765 0.475
2.6 -59.01 -0.37 0.59 0 -1.529 0.951
STORY1 C16 UDCON10
0 -64.69 0.07 -0.41 0 0 0
1.3 -63.22 0.07 -0.41 0 0.534 -0.095
2.6 -61.75 0.07 -0.41 0 1.068 -0.189
STORY1 C16 UDCON11
0 -49.86 7.19 0.06 0 0 0
1.3 -48.76 7.19 0.06 0 -0.081 -9.347
2.6 -47.66 7.19 0.06 0 -0.161 -18.693
STORY1 C16 UDCON12
0 -45.12 -7.41 0.07 0 0 0
1.3 -44.02 -7.41 0.07 0 -0.092 9.632
2.6 -42.92 -7.41 0.07 0 -0.185 19.264
STORY1 C16 UDCON13
0 -46.12 -0.33 0.57 0 0 0
1.3 -45.02 -0.33 0.57 0 -0.736 0.428
2.6 -43.92 -0.33 0.57 0 -1.472 0.855
STORY1 C16 UDCON14
0 -48.86 0.11 -0.43 0 0 0
1.3 -47.76 0.11 -0.43 0 0.563 -0.142
2.6 -46.66 0.11 -0.43 0 1.126 -0.285
Support Reactions:
STORY POINT LOAD FX FY FZ MX MY MZ
(kN) (kN) (kN) (kN-m) (kN-m) (kN-m)
BASE 16 DEAD 0.06 -0.02 33.86 0 0 0
BASE 16 EQX -7.3 0 2.37 0 0 0
BASE 16 EQY 0.22 -0.5 -1.37 0 0 0
BASE 16 SDL 0.07 -0.05 18.91 0 0 0
BASE 16 LIVE -0.03 -0.03 20.92 0 0 0
BASE 15 DEAD -0.35 0.01 8.81 0 0 0
BASE 15 EQX -5.32 0 8.44 0 0 0
BASE 15 EQY 0.07 -0.78 -2.24 0 0 0
BASE 15 SDL -1.11 -0.01 20.35 0 0 0
BASE 15 LIVE -0.04 0.02 0.81 0 0 0
BASE 3 DEAD 0.07 -0.02 41.11 0 0 0
BASE 3 EQX -5.3 -0.01 -6.45 0 0 0
BASE 3 EQY -0.48 -1.32 9.83 0 0 0
BASE 3 SDL 0.37 -0.09 77.21 0 0 0
BASE 3 LIVE -0.07 0 26.77 0 0 0
BASE 1 DEAD 0.16 -0.12 27.33 0 0 0
BASE 1 EQX -4.64 -0.02 4.98 0 0 0
BASE 1 EQY 0.22 -1.11 3.92 0 0 0
BASE 1 SDL 0.51 -0.12 47.68 0 0 0
BASE 1 LIVE 0 -0.07 14.24 0 0 0
BASE 7 DEAD -0.44 -0.58 23.72 0 0 0
BASE 7 EQX -1.38 -0.02 3.68 0 0 0
BASE 7 EQY 0.01 -3.62 6.22 0 0 0
BASE 7 SDL -0.96 -1.27 44.25 0 0 0
BASE 7 LIVE -0.22 -0.41 13.08 0 0 0
BASE 9 DEAD -0.22 0.02 24.47 0 0 0
BASE 9 EQX -1.13 0.07 1.64 0 0 0
BASE 9 EQY -0.03 -4.1 -1.29 0 0 0
BASE 9 SDL -0.19 0.17 43.87 0 0 0
BASE 9 LIVE -0.18 0.01 12.47 0 0 0
BASE 14 DEAD 0.03 0.27 33.82 0 0 0
BASE 14 EQX -1.33 0.23 3.33 0 0 0
BASE 14 EQY -0.03 -4.33 2.99 0 0 0
BASE 14 SDL 0.05 0.14 19.47 0 0 0
BASE 14 LIVE 0.01 0.06 22.32 0 0 0
BASE 11 DEAD -0.05 0.05 11.36 0 0 0
BASE 11 EQX -1.32 0 3.94 0 0 0
BASE 11 EQY -0.08 -3.73 -14.61 0 0 0
BASE 11 SDL -0.2 0.28 20.85 0 0 0
BASE 11 LIVE -0.03 0.03 1.63 0 0 0
BASE 13 DEAD 0.13 0.88 19.27 0 0 0
BASE 13 EQX -1.39 -0.01 -4.04 0 0 0
BASE 13 EQY -0.08 -3.06 -6.43 0 0 0
BASE 13 SDL 0.44 2.09 36.21 0 0 0
BASE 13 LIVE 0.09 0.68 9.3 0 0 0
BASE 6 DEAD 0.41 0.41 22.79 0 0 0
BASE 6 EQX -1.32 -0.1 -3.08 0 0 0
BASE 6 EQY 0.09 -3.22 -1.31 0 0 0
BASE 6 SDL 0.91 0.9 42.8 0 0 0
BASE 6 LIVE 0.31 0.34 13.46 0 0 0
BASE 5 DEAD 0.15 -0.56 24.37 0 0 0
BASE 5 EQX -1.5 -0.08 -7.41 0 0 0
BASE 5 EQY 0.02 -4.11 -6.09 0 0 0
BASE 5 SDL 0.06 -1.25 36.59 0 0 0
BASE 5 LIVE 0.13 -0.44 11.46 0 0 0
BASE 4 DEAD 0.05 -0.33 14.15 0 0 0
BASE 4 EQX -1.48 -0.07 -7.39 0 0 0
BASE 4 EQY 0.06 -3.52 10.39 0 0 0
BASE 4 SDL 0.04 -0.8 22.97 0 0 0
BASE 4 LIVE 0.04 -0.19 5.49 0 0 0
( )Design of Reinforced Concrete beam:mark:B1mark:B1mark:B1mark:B1
Input Parameters:
fc' 21 MPa= dbar 16 mm= nt 2= Mun 24.5 kN m=
fy 275 MPa= dties 10 mm= nb 2= Mup 12.3 kN m=
β1 0.85= b 200 mm= Vu 45 kN=
Es 200 GPa= h 400 mm=
Esεcu 600 MPa=Ab
π
4dbar
2201.062 mm
2==
Analysis:
DEFINING CONDITIONS: ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
= Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
FCc kd( ) 0.85 fc' b β1 kd=
Design for Negative flexure: Design for Positive flexure:
dt h 65 mm−= db h 65 mm−=
Ast nt Ab 402.124 mm2
== Asb nb Ab 402.124 mm2
==
at
Ast fy
0.85 fc' b30.976 mm== ab
Asb fy
0.85 fc' b30.976 mm==
ct
at
β1
36.442 mm== cb
ab
β1
36.442 mm==
εst 0.003ct dt−
ct
0.025−== εsb 0.003cb db−
cb
0.025−==
thus, use: ϕbt ϕ εst( ) 0.9== thus, use: ϕbb ϕ εsb( ) 0.9==
Mnn 0.85 fc' at b dt
at
2−
35.333 kN m== Mnp 0.85 fc' ab b db
ab
2−
35.333 kN m==
ϕbt Mnn 31.8 kN m= > Mun 24.5 kN m= ϕbb Mnp 31.8 kN m= > Mup 12.3 kN m=
Design for Shear: ϕv 0.75=Av 2
π
4dties
2157.08 mm
2==
Vc1
6fc' MPa b dt 51.172 kN==
VsVu
ϕv
Vc− 8.828 kN==.5 ϕv Vc 19.19 kN= < Vu 45 kN=
Vsmax2
3fc' MPa b dt 204.688 kN== sa min 0.5 dt 600 mm, ( ) Vs
1
3fc' MPa b dt<if
min 0.25 dt 300 mm, ( ) otherwise
=
Vnmax Vc Vsmax+ 255.86 kN==
sa 167.5 mm=svu
Av fy dt
Vs1.639 10
3× mm==
sb16 Av fy
fc' MPa b754.107 mm==
s2 100 mm= Vn2Av fy dt
s2
Vc+ 195.882 kN==
sc3 Av fy MPa
1−
b647.953 mm==
s3 150 mm= Vn3Av fy dt
s3
Vc+ 147.645 kN==smax min sa sb, sc, ( ) 167.5 mm==
therefore, use 200x400mm with 2-16mmϕ top bars and 2-16mmϕ bot. bars (Grade 40)
10mmϕ stirrups: 3@50mm, 10@100mm and rest at 150mm o.c.
Design of Reinforced Concrete beam:mark:B2mark:B2mark:B2mark:B2
Input Parameters:
fc' 21 MPa= dbar 16 mm= nt 3= Mun 43.1 kN m=
fy 275 MPa= dties 10 mm= nb 2= Mup 25 kN m=
β1 0.85= b 200 mm= Vu 58.9 kN=
Es 200 GPa= h 400 mm=
Esεcu 600 MPa=Ab
π
4dbar
2201.062 mm
2==
Analysis:
DEFINING CONDITIONS: ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
= Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
FCc kd( ) 0.85 fc' b β1 kd=
Check for Negative flexure: Check for Positive flexure:
dt h 65 mm−= db h 65 mm−=
Ast nt Ab 603.186 mm2
== Asb nb Ab 402.124 mm2
==
at
Ast fy
0.85 fc' b46.464 mm== ab
Asb fy
0.85 fc' b30.976 mm==
ct
at
β1
54.663 mm== cb
ab
β1
36.442 mm==
εst 0.003ct dt−
ct
0.015−== εsb 0.003cb db−
cb
0.025−==
thus, use: ϕbt ϕ εst( ) 0.9== thus, use: ϕbb ϕ εsb( ) 0.9==
Mnn 0.85 fc' at b dt
at
2−
51.715 kN m== Mnp 0.85 fc' ab b db
ab
2−
35.333 kN m==
ϕbt Mnn 46.543 kN m= < Mun 43.1 kN m= ϕbb Mnp 31.8 kN m= < Mup 25 kN m=
o.k.! o.k.! Check for Shear: ϕv 0.75=
Av 2π
4dties
2157.08 mm
2==
Vc1
6fc' MPa b dt 51.172 kN==
VsVu
ϕv
Vc− 27.361 kN==.5 ϕv Vc 19.19 kN= < Vu 58.9 kN=
Vsmax2
3fc' MPa b dt 204.688 kN== sa min 0.5 dt 600 mm, ( ) Vs
1
3fc' MPa b dt<if
min 0.25 dt 300 mm, ( ) otherwise
=
Vnmax Vc Vsmax+ 255.86 kN==
sa 167.5 mm=svu
Av fy dt
Vs528.885 mm==
sb16 Av fy
fc' MPa b754.107 mm==
s2 100 mm= Vn2Av fy dt
s2
Vc+ 195.882 kN==
sc3 Av fy MPa
1−
b647.953 mm==
s3 150 mm= Vn3Av fy dt
s3
Vc+ 147.645 kN==smax min sa sb, sc, ( ) 167.5 mm==
therefore, use 200x400mm with 3-16mmϕ top bars and 2-16mmϕ bot. bars (Grade 40)
10mmϕ stirrups: 3@50mm, 10@100mm and rest at 150mm o.c.
Design of Reinforced Concrete beam:mark:B3mark:B3mark:B3mark:B3
Input Parameters:
fc' 21 MPa= dbar 16 mm= nt 3= Mun 56.7 kN m=
fy 275 MPa= dties 10 mm= nb 2= Mup 35.1 kN m=
β1 0.85= b 200 mm= Vu 61.8 kN=
Es 200 GPa= h 500 mm=
Esεcu 600 MPa=Ab
π
4dbar
2201.062 mm
2==
Analysis:
DEFINING CONDITIONS: ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
= Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
FCc kd( ) 0.85 fc' b β1 kd=
Check for Negative flexure: Check for Positive flexure:
dt h 65 mm−= db h 65 mm−=
Ast nt Ab 603.186 mm2
== Asb nb Ab 402.124 mm2
==
at
Ast fy
0.85 fc' b46.464 mm== ab
Asb fy
0.85 fc' b30.976 mm==
ct
at
β1
54.663 mm== cb
ab
β1
36.442 mm==
εst 0.003ct dt−
ct
0.021−== εsb 0.003cb db−
cb
0.033−==
thus, use: ϕbt ϕ εst( ) 0.9== thus, use: ϕbb ϕ εsb( ) 0.9==
Mnn 0.85 fc' at b dt
at
2−
68.302 kN m== Mnp 0.85 fc' ab b db
ab
2−
46.391 kN m==
ϕbt Mnn 61.472 kN m= > Mun 56.7 kN m= ϕbb Mnp 41.752 kN m= > Mup 35.1 kN m=
Check for Shear: ϕv 0.75=Av 2
π
4dties
2157.08 mm
2==
Vc1
6fc' MPa b dt 66.447 kN==
VsVu
ϕv
Vc− 15.953 kN==.5 ϕv Vc 24.918 kN= < Vu 61.8 kN=
Vsmax2
3fc' MPa b dt 265.789 kN== sa min 0.5 dt 600 mm, ( ) Vs
1
3fc' MPa b dt<if
min 0.25 dt 300 mm, ( ) otherwise
=
Vnmax Vc Vsmax+ 332.237 kN==
sa 217.5 mm=svu
Av fy dt
Vs1.178 10
3× mm==
sb16 Av fy
fc' MPa b754.107 mm==
s2 100 mm= Vn2Av fy dt
s2
Vc+ 254.354 kN==
sc3 Av fy MPa
1−
b647.953 mm==
s3 150 mm= Vn3Av fy dt
s3
Vc+ 191.718 kN==smax min sa sb, sc, ( ) 217.5 mm==
therefore, use 200x500mm with 3-16mmϕ top bars and 2-16mmϕ bot. bars (Grade 40)
10mmϕ stirrups: 3@50mm, 10@100mm and rest at 150mm o.c.
Design of Reinforced Concrete beam:mark:RBmark:RBmark:RBmark:RB
Input Parameters:
fc' 21 MPa= dbar 12 mm= nt 2= Mun 10 kN m=
fy 275 MPa= dties 10 mm= nb 2= Mup 6.40 kN m=
β1 0.85= b 150 mm= Vu 13.6 kN=
Es 200 GPa= h 300 mm=
Esεcu 600 MPa=Ab
π
4dbar
2113.097 mm
2==
Analysis:
DEFINING CONDITIONS: ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
= Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
FCc kd( ) 0.85 fc' b β1 kd=
Check for Negative flexure: Check for Positive flexure:
dt h 65 mm−= db h 65 mm−=
Ast nt Ab 226.195 mm2
== Asb nb Ab 226.195 mm2
==
at
Ast fy
0.85 fc' b23.232 mm== ab
Asb fy
0.85 fc' b23.232 mm==
ct
at
β1
27.332 mm== cb
ab
β1
27.332 mm==
εst 0.003ct dt−
ct
0.023−== εsb 0.003cb db−
cb
0.023−==
thus, use: ϕbt ϕ εst( ) 0.9== thus, use: ϕbb ϕ εsb( ) 0.9==
Mnn 0.85 fc' at b dt
at
2−
13.895 kN m== Mnp 0.85 fc' ab b db
ab
2−
13.895 kN m==
ϕbt Mnn 12.506 kN m= < Mun 10 kN m= ϕbb Mnp 12.506 kN m= > Mup 6.4 kN m=o.k.!
o.k.! Check for Shear: ϕv 0.75=
Av 2π
4dties
2157.08 mm
2==
Vc1
6fc' MPa b dt 26.923 kN==
VsVu
ϕv
Vc− 8.789− kN==.5 ϕv Vc 10.096 kN= < Vu 13.6 kN=
Vsmax2
3fc' MPa b dt 107.691 kN== sa min 0.5 dt 600 mm, ( ) Vs
1
3fc' MPa b dt<if
min 0.25 dt 300 mm, ( ) otherwise
=
Vnmax Vc Vsmax+ 134.613 kN==
sa 117.5 mm=svu
Av fy dt
Vs1.155− 10
3× mm==
sb16 Av fy
fc' MPa b1.005 10
3× mm==
s2 100 mm= Vn2Av fy dt
s2
Vc+ 128.435 kN==
sc3 Av fy MPa
1−
b863.938 mm==
s3 150 mm= Vn3Av fy dt
s3
Vc+ 94.598 kN==smax min sa sb, sc, ( ) 117.5 mm==
therefore, use 150x300mm with 2-12mmϕ top bars and 2-12mmϕ bot. bars (Grade 40)
10mmϕ stirrups: 3@50mm, 10@100mm and rest at 150mm o.c.
DESIGN OF COLUMN mark:c1mark:c1mark:c1mark:c1b 300 mm= d' 65 mm=
nl 2=h 150 mm= db 12 mm=
i 0 nl..=fc' 21 MPa= dties 10 mm=
Mu 8.4 kN m=fy 275 MPa=
Pu 92 kN=Ab
π
4db2
113.097 mm2
==β1 0.85= Vu 5.2 kN=
Esεcu 600 MPa=
Es 200000 MPa= d
d'
0.5 h
h d'−
= As
3 Ab
0 Ab
3 Ab
=
fy 0.85 fc'− 257.1 MPa=
Maximum Axial capacity and location of plastic centroid:
Cc 0.85 fc' b h 803.25 kN== DEFINING CONDITIONS: Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
fsi fy 0.85 fc'−= FCc kd( ) 0.85 fc' b β1 kd=
Fsi Asi fsi=ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
=
Pn0 Cc
0
nl
i
Fsi∑=
+ 977.748 kN==
xp Cch
20
nl
i
Fsi di( )∑=
+
1
Pn0
75 mm==εy
fy
Es0.00137==
ϕc 0.65=
MaxϕPn0 ϕc 0.8 Pn0 508.429 kN== ρ
As∑b h
1.508 %==
Capacity at balanced condition: Tension-controlled capacity :
εb εy−= εt 0.005−=
cb
Esεcu
Esεcu fy+dnl 58.286 mm== ct
Esεcu
Esεcu Es εt−dnl 31.875 mm==
ab β1 cb 49.543 mm== at β1 ct 27.094 mm==
Ccb FCc cb( )= fsi Ffs cb di, ( )= Fsi Asi fsi= Cct FCc ct( )= fsi Ffs ct di, ( )= Fsi Asi fsi=
Pnb Ccb
0
nl
i
Fsi∑=
+ 78.691 kN== Pnt Cct
0
nl
i
Fsi∑=
+ 41.524− kN==
Mnb Cc 0.5 h 0.5 ab−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+= Mnt Cc 0.5 h 0.5 at−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+=
eb
Mnb
Pnb
512.713 mm== et
Mnt
Pnt
1.189− 103
× mm==
ϕb 0.65= ϕt 0.9=
ϕb Pnb 51.1 kN= ϕt Pnt 37.4− kN=
ϕb Mnb 26.2 kN m= ϕt Mnt 44.4 kN m=
Section Capacity at applied eccentriciy due to loads:
euMu
Pu91.304 mm==
p cn( ) FCc cn( ) eu .5 h− .5 β1 cn+( )0
nl
i
Asi Ffs cn di, ( ) eu 0.5 h− di+( ) ∑=
+=
cn
et eu−
et eb−cb ct−( ) ct+ 12.005 mm==
c root p cn( ) cn, ( ) 58.695 mm==
εs 0.003c d2−
c
0.00134−==
ϕn ϕ εs( ) 0.65==
Pn FCc c( )
0
nl
i
Asi Ffs c di, ( )( )∑=
+ 154.062 kN==
Mn FCc c( ) 0.5 h .5 β1 c−( )0
nl
i
Asi Ffs c di, ( )( ) 0.5 h di−( ) ∑=
+ 14.067 kN m==
ϕn Pn 100.14 kN= < Pu 92 kN=o.k.!
ϕn Mn 9.143 kN m= < Mu 8.4 kN m=
Check for Shear:
ϕv 0.75=
Vc 1Pu kN
1−
14 b h m2−
+
fc' MPa b d2
62.864 10
3× kN==
Vu
ϕv
6.933 kN=>
smax min 16 db 48 dties, min b h, ( ), ( )=
smax 150 mm=
therefore, use 150x300mm with 6-12mmϕ longitudinal bars
10mmϕ stirrups: 10@75mm, and rest at 160mm o.c.
DESIGN OF COLUMN mark:c2mark:c2mark:c2mark:c2b 150 mm= d' 65 mm=
nl 2=h 400 mm= db 12 mm=
i 0 nl..=fc' 21 MPa= dties 10 mm=
Mu 19.3 kN m=fy 275 MPa=
Pu 81.9 kN=Ab
π
4db2
113.097 mm2
==β1 0.85= Vu 7.4 kN=
Esεcu 600 MPa=
Es 200000 MPa= d
d'
0.5 h
h d'−
= As
2 Ab
2 Ab
2 Ab
=
fy 0.85 fc'− 257.1 MPa=
Maximum Axial capacity and location of plastic centroid:
Cc 0.85 fc' b h 1.071 103
× kN== DEFINING CONDITIONS: Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
fsi fy 0.85 fc'−= FCc kd( ) 0.85 fc' b β1 kd=
Fsi Asi fsi=ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
=
Pn0 Cc
0
nl
i
Fsi∑=
+ 1.245 103
× kN==
xp Cch
20
nl
i
Fsi di( )∑=
+
1
Pn0
200 mm==εy
fy
Es0.00137==
ϕc 0.65=
MaxϕPn0 ϕc 0.8 Pn0 647.659 kN== ρ
As∑b h
1.131 %==
Capacity at balanced condition: Tension-controlled capacity :
εb εy−= εt 0.005−=
cb
Esεcu
Esεcu fy+dnl 229.714 mm== ct
Esεcu
Esεcu Es εt−dnl 125.625 mm==
ab β1 cb 195.257 mm== at β1 ct 106.781 mm==
Ccb FCc cb( )= fsi Ffs cb di, ( )= Fsi Asi fsi= Cct FCc ct( )= fsi Ffs ct di, ( )= Fsi Asi fsi=
Pnb Ccb
0
nl
i
Fsi∑=
+ 456.56 kN== Pnt Cct
0
nl
i
Fsi∑=
+ 219.666 kN==
Mnb Cc 0.5 h 0.5 ab−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+= Mnt Cc 0.5 h 0.5 at−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+=
eb
Mnb
Pnb
275.735 mm== et
Mnt
Pnt
788.783 mm==
ϕb 0.65= ϕt 0.9=
ϕb Pnb 296.8 kN= ϕt Pnt 197.7 kN=
ϕb Mnb 81.8 kN m= ϕt Mnt 155.9 kN m=
Section Capacity at applied eccentriciy due to loads:
euMu
Pu235.653 mm==
p cn( ) FCc cn( ) eu .5 h− .5 β1 cn+( )0
nl
i
Asi Ffs cn di, ( ) eu 0.5 h− di+( ) ∑=
+=
cn
et eu−
et eb−cb ct−( ) ct+ 237.846 mm==
c root p cn( ) cn, ( ) 140.871 mm==
εs 0.003c d2−
c
0.00413−==
ϕn ϕ εs( ) 0.65==
Pn FCc c( )
0
nl
i
Asi Ffs c di, ( )( )∑=
+ 259.603 kN==
Mn FCc c( ) 0.5 h .5 β1 c−( )0
nl
i
Asi Ffs c di, ( )( ) 0.5 h di−( ) ∑=
+ 61.176 kN m==
ϕn Pn 168.742 kN= < Pu 81.9 kN=o.k.!
ϕn Mn 39.765 kN m= < Mu 19.3 kN m=
Check for Shear:
ϕv 0.75=
Vc 1Pu kN
1−
14 b h m2−
+
fc' MPa b d2
63.78 10
3× kN==
Vu
ϕv
9.867 kN=>
smax min 16 db 48 dties, min b h, ( ), ( )=
smax 150 mm=
therefore, use 150x400mm with 6-12mmϕ longitudinal bars
10mmϕ stirrups: 10@75mm, and rest at 160mm o.c.
DESIGN OF COLUMN mark:c3mark:c3mark:c3mark:c3b 150 mm= d' 65 mm=
nl 2=h 150 mm= db 12 mm=
i 0 nl..=fc' 21 MPa= dties 10 mm=
Mu 1.6 kN m=fy 275 MPa=
Pu 8.2 kN=Ab
π
4db
2113.097 mm
2==
β1 0.85= Vu 1 kN=
Esεcu 600 MPa=
Es 200000 MPa= d
d'
0.5 h
h d'−
= As
2 Ab
0 Ab
2 Ab
=
fy 0.85 fc'− 257.1 MPa=
Maximum Axial capacity and location of plastic centroid:
Cc 0.85 fc' b h 401.625 kN== DEFINING CONDITIONS: Ffs kd di, ( ) fs Esεcukd di−
kd
←
fs fy← fs fy>if
fs fy−← fs fy−<if
fs fs 0.85 fc'−← β1 kd di>if
fs
=
fsi fy 0.85 fc'−= FCc kd( ) 0.85 fc' b β1 kd=
Fsi Asi fsi=ϕ εt( ) ϕ 0.48 83 εt+←
ϕ 0.65← εt 0.002−>if
ϕ 0.65← εt 0.003<if
ϕ 0.9← εt 0.005−<if
ϕ
=
Pn0 Cc
0
nl
i
Fsi∑=
+ 517.957 kN==
xp Cch
20
nl
i
Fsi di( )∑=
+
1
Pn0
75 mm==εy
fy
Es0.00137==
ϕc 0.65=
MaxϕPn0 ϕc 0.8 Pn0 269.338 kN== ρ
As∑b h
2.011 %==
Capacity at balanced condition: Tension-controlled capacity :
εb εy−= εt 0.005−=
cb
Esεcu
Esεcu fy+dnl 58.286 mm== ct
Esεcu
Esεcu Es εt−dnl 31.875 mm==
ab β1 cb 49.543 mm== at β1 ct 27.094 mm==
Ccb FCc cb( )= fsi Ffs cb di, ( )= Fsi Asi fsi= Cct FCc ct( )= fsi Ffs ct di, ( )= Fsi Asi fsi=
Pnb Ccb
0
nl
i
Fsi∑=
+ 8.244 kN== Pnt Cct
0
nl
i
Fsi∑=
+ 51.864− kN==
Mnb Cc 0.5 h 0.5 ab−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+= Mnt Cc 0.5 h 0.5 at−( )0
nl
i
Fsi 0.5 h di−( ) ∑=
+=
eb
Mnb
Pnb
2.447 103
× mm== et
Mnt
Pnt
475.885− mm==
ϕb 0.65= ϕt 0.9=
ϕb Pnb 5.4 kN= ϕt Pnt 46.7− kN=
ϕb Mnb 13.1 kN m= ϕt Mnt 22.2 kN m=
Section Capacity at applied eccentriciy due to loads:
euMu
Pu195.122 mm==
p cn( ) FCc cn( ) eu .5 h− .5 β1 cn+( )0
nl
i
Asi Ffs cn di, ( ) eu 0.5 h− di+( ) ∑=
+=
cn
et eu−
et eb−cb ct−( ) ct+ 25.812 mm==
c root p cn( ) cn, ( ) 54.315 mm==
εs 0.003c d2−
c
0.00169−==
ϕn ϕ εs( ) 0.65==
Pn FCc c( )
0
nl
i
Asi Ffs c di, ( )( )∑=
+ 34.709 kN==
Mn FCc c( ) 0.5 h .5 β1 c−( )0
nl
i
Asi Ffs c di, ( )( ) 0.5 h di−( ) ∑=
+ 6.773 kN m==
ϕn Pn 22.561 kN= < Pu 8.2 kN=o.k.!
ϕn Mn 4.402 kN m= < Mu 1.6 kN m=
Check for Shear:
ϕv 0.75=
Vc 1Pu kN
1−
14 b h m2−
+
fc' MPa b d2
6263.234 kN==
Vu
ϕv
1.333 kN=>
smax min 16 db 48 dties, min b h, ( ), ( )=
smax 150 mm=
therefore, use 150x150mm with 4-12mmϕ longitudinal bars
10mmϕ stirrups: 10@75mm, and rest at 160mm o.c.
Design of Reinforced Concrete Slab:mark:S-1mark:S-1mark:S-1mark:S-1
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 300 mm=
β1 0.85= t 100 mm=
Es 200 GPa= Ln 1.2 m=
Analysis: For Negative Reinforcement
For 1-meter strip: b 1 m=
ωsw γc t 2.35 kPa==
ωf 1.20 kPa=
ωL 2.40 kPa=
wD ωsw ωf+( ) b 3.55kN
m==
wL ωL b 2.4kN
m==
wU 1.2wD 1.6 wL+ 8.1kN
m==
MuwU Ln
2
81.458 kN m==
Abπ
4db
278.54 mm
2==
AsAb b
sp
261.799 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b4.033 mm==
ca
β1
4.745 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.041== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
4.894 kN m==
ϕ Mn 4.405 kN m= Mu 1.458 kN m=
Since; ϕMn Mu> andLn
3633.333 mm= < t o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 300mm o.c. top reinforcement
Design of Reinforced Concrete Slab:mark:S-1mark:S-1mark:S-1mark:S-1
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 300 mm=
β1 0.85= t 100 mm=
Es 200 GPa= Ln 1.2 m=
Analysis: For Positive Reinforcement
For 1-meter strip: b 1 m=
ωsw γc t 2.35 kPa==
ωf 1.20 kPa=
ωL 2.40 kPa=
wD ωsw ωf+( ) b 3.55kN
m==
wL ωL b 2.4kN
m==
wU 1.2wD 1.6 wL+ 8.1kN
m==
Mu9wU Ln
2
1280.82 kN m==
Abπ
4db
278.54 mm
2==
AsAb b
sp
261.799 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b4.033 mm==
ca
β1
4.745 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.041== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
4.894 kN m==
ϕ Mn 4.405 kN m= Mu 0.82 kN m=
Since; ϕMn Mu> andLn
3633.333 mm= < t o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 300mm o.c. top reinforcement
Design of Reinforced Concrete Slab:mark:S-2mark:S-2mark:S-2mark:S-2
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 280 mm=
β1 0.85= t 100 mm=
Es 200 GPa= Ln 1.5 m=
Analysis: For Negative Reinforcement
For 1-meter strip: b 1 m=
ωsw γc t 2.35 kPa==
ωf 1.20 kPa=
ωL 2.40 kPa=
wD ωsw ωf+( ) b 3.55kN
m==
wL ωL b 2.4kN
m==
wU 1.2wD 1.6 wL+ 8.1kN
m==
MuwU Ln
2
82.278 kN m==
Abπ
4db
278.54 mm
2==
AsAb b
sp
280.499 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b4.321 mm==
ca
β1
5.084 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.038== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
5.233 kN m==
ϕ Mn 4.71 kN m= Mu 2.278 kN m=
Since; ϕMn Mu> andLn
3641.667 mm= < t o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 280mm o.c. top reinforcement
Design of Reinforced Concrete Slab:mark:S-2mark:S-2mark:S-2mark:S-2
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 280 mm=
β1 0.85= t 100 mm=
Es 200 GPa= Ln 1.5 m=
Analysis: For Positive Reinforcement
For 1-meter strip: b 1 m=
ωsw γc t 2.35 kPa==
ωf 1.20 kPa=
ωL 2.40 kPa=
wD ωsw ωf+( ) b 3.55kN
m==
wL ωL b 2.4kN
m==
wU 1.2wD 1.6 wL+ 8.1kN
m==
Mu9wU Ln
2
1281.281 kN m==
Abπ
4db
278.54 mm
2==
AsAb b
sp
280.499 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b4.321 mm==
ca
β1
5.084 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.038== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
5.233 kN m==
ϕ Mn 4.71 kN m= Mu 1.281 kN m=
Since; ϕMn Mu> andLn
3641.667 mm= < t o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 280mm o.c. top reinforcement
Design of Reinforced Concrete Slab:mark:SD-1mark:SD-1mark:SD-1mark:SD-1
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 200 mm=
β1 0.85= t 100 mm=
Es 200 GPa=
Analysis: For Positive Reinforcement
For 1-meter strip: b 1 m=
Mu 5.4 kN m=
Abπ
4db
278.54 mm
2==
AsAb b
sp
392.699 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b6.05 mm==
ca
β1
7.118 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.027== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
7.233 kN m==
ϕ Mn 6.51 kN m= Mu 5.4 kN m=
Since; ϕMn Mu> and o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 200mm o.c. top reinforcement
Design of Reinforced Concrete Slab:mark:SD-1mark:SD-1mark:SD-1mark:SD-1
Input Parameters:
fc' 21 MPa= db 10 mm=γc 23.5
kN
m3
=fy 275 MPa= sp 125 mm=
β1 0.85= t 100 mm=
Es 200 GPa= Ln 3 m=
Analysis: For Negative Reinforcement
For 1-meter strip: b 1 m=
Mu 10.1 kN m=
Abπ
4db
278.54 mm
2==
AsAb b
sp
628.319 mm2
==
Depth of rectangular compressive stress block:
aAs fy
0.85 fc' b9.68 mm==
ca
β1
11.388 mm==
d t 30 mm−=
εyfy
Es
1.375 103−
×==
εy (fs = fy)
εs 0.003d c−
c
0.015== exceeds0.005 (tension-controlled)
thus, use: ϕ 0.90=
Mn 0.85 fc' a b da
2−
11.259 kN m==
ϕ Mn 10.133 kN m= Mu 10.1 kN m=
Since; ϕMn Mu> o.k.!
therefore; use 100mm thk. slab with 10mmϕ rebar
spaced at 125mm o.c. top reinforcement
DESIGN OF A ISOLATED FOOTING Mark :
INPUT DATA :
Concrete Strength, fc' =
Rebar Yield strength, fy =
Net Allowable Soil pressure, qa =
Footing Embedment Depth, Df =
Surcharge, qs =
Soil Weight, ws =
Column Width, cx =
Column Depth, cy =
Column Location in X-dir., dx = Use 1.3 x 1.3 x 0.3m thk. footing
Column Location in Y-dir., dy = w/ 6-16mm along X-direction
Footing Length, L = 6-16mm along Y-direction rebar
Footing Width, B =
Footing Thickness, t =
Longitudinal Rebar, Ax = 6 - Gravity Service Loads :
Transverse Rebar, Ay = 6 - PD =
Rebar center to Conc. edge, c = PL =
Check Soil Bearing Capacity :
Load on Footings :
PD + PL = 145.1 kN (Applied load) αs = 40
qs(BL) = 5.9 kN (Surcharge load) φVc2 =
(23.5-ws) tBL = 3.8 kN (Increased Footing)
Pa = 154.8 kN
φVc3 =
φVc = Min(φVc1 ,φVc2 ,φVc3 )
x-z plane: eX = 0.000 m < L/6 = 0.2167 φVc = > Vu <ok!>
qmaxX = 92 kPa < qa <ok!> Check for One-way Shear :
y-z plane: eY = 0.000 m < B/6 = 0.2167
qmaxY = 92 kPa < qa <ok!>
Vux = 56.7 kN Vuy =
Check thickness for Two-way Shear :
1.2PD + 1.6PL =
1.2qs(BL) = 7.1 kN φVcx = 148.9 kN φVcy =
1.2(23.5-ws) tBL = 4.6 kN > Vu <ok!> > Vu <ok!>
PU = 196.5 kN Check Flexural Reinforcement :
Governing Moments:
MUx = 25.0 kN-m MUy =
x-z plane: eUX = 0.000 m < L/6 = 0.2167 Asx = Asy = (provided)
qUmaxX = 116.3 kPa Asmin(x) = 702 mm² Asmin(y) = (= 0.0018Bt)
y-z plane: eUY = 0.000 m < B/6 = 0.2167 sx = 201 mm sy = (Smax = 500mm)
qUmaxY = 116.3 kPa
d = 0.20 m ax = ay =
Vu = qu [BL-(cx+d)(cy+d)] Check Tension-controlled limit :
Vu = ab/d = 0.616
bo = 2(cy+d)+2(cx+d) ax/d = 0.059 ay/d = 0.059
bo = 1.70 m < ab/d <ok!> < ab/d <ok!>
φMnx = φMny =
> MU <ok!> > MU <ok!>
βc = 2.00
φVc1 =
11.9 mm
48.0 kN-m
148.9 kN
18.9 kN-m
F1
184.8 kN
389.5 kN
45.3 kN
1,206 mm² 1,206 mm²
702 mm²
201 mm
16.0 kN/m³
0.15 m
0.30 m
1.3 m
21.0 MPa
228.0 MPa
100.0 kPa
1.0 m
3.5 kPa
389.5 kN
653.0 kN
16 mm φ
16 mm φ
48.0 kN-m
118.3 kN
26.8 kN0.10 m
0.30 m
1.3 m
0.65 m
0.65 m
φVc2 =
φVcy =
φMnx =
ax =
φVc3 =
ay =
φMny =
βc =
φVc1 =
φVcx =
176.2 kN
11.9 mm
389.5 kN
from CL of footing.
from CL of footing.
f ikjj2 + 4
bc
y{zz è!!!!!!
fc bo d
12
long side of col .
short s ide of col .
f ikjj2 + as d
bo
y{zz è!!!!!!
fc bo d
12
f 1
3 è!!!!!!
fc bo d
eu =Mu
Pu
e =M
P
VuX = qu B@max Hd x , L-d x L -0.5 c x -dD VuY = qu L@max Hdy , B-dyL -0.5 cy -dD
f 1
6 è!!!!!!
fc Bd f 1
6 è!!!!!!
fc Ld
Asx fy
0.85 fc B
Asy fy
0.85 fc L
fAsx fy Jd -a x
2N fAsy fy Jd -
ay
2N
y
x
z
x
z
L
x
y
f
f
xy
yx
y
surcharge
surcharge surcharge
dx
y
DESIGN OF A ISOLATED FOOTING Mark :
INPUT DATA :
Concrete Strength, fc' =
Rebar Yield strength, fy =
Net Allowable Soil pressure, qa =
Footing Embedment Depth, Df =
Surcharge, qs =
Soil Weight, ws =
Column Width, cx =
Column Depth, cy =
Column Location in X-dir., dx = Use 1 x 1 x 0.275m thk. footing
Column Location in Y-dir., dy = w/ 5-16mm along X-direction
Footing Length, L = 5-16mm along Y-direction rebar
Footing Width, B =
Footing Thickness, t =
Longitudinal Rebar, Ax = 5 - Gravity Service Loads :
Transverse Rebar, Ay = 5 - PD =
Rebar center to Conc. edge, c = PL =
Check Soil Bearing Capacity :
Load on Footings :
PD + PL = 80.9 kN (Applied load) αs = 40
qs(BL) = 3.5 kN (Surcharge load) φVc2 =
(23.5-ws) tBL = 2.1 kN (Increased Footing)
Pa = 86.5 kN
φVc3 =
φVc = Min(φVc1 ,φVc2 ,φVc3 )
x-z plane: eX = 0.000 m < L/6 = 0.1667 φVc = > Vu <ok!>
qmaxX = 86 kPa < qa <ok!> Check for One-way Shear :
y-z plane: eY = 0.000 m < B/6 = 0.1667
qmaxY = 86 kPa < qa <ok!>
Vux = 27.2 kN Vuy =
Check thickness for Two-way Shear :
1.2PD + 1.6PL =
1.2qs(BL) = 4.2 kN φVcx = 100.2 kN φVcy =
1.2(23.5-ws) tBL = 2.5 kN > Vu <ok!> > Vu <ok!>
PU = 108.8 kN Check Flexural Reinforcement :
Governing Moments:
MUx = 9.8 kN-m MUy =
x-z plane: eUX = 0.000 m < L/6 = 0.1667 Asx = Asy = (provided)
qUmaxX = 108.8 kPa Asmin(x) = 495 mm² Asmin(y) = (= 0.0018Bt)
y-z plane: eUY = 0.000 m < B/6 = 0.1667 sx = 180 mm sy = (Smax = 500mm)
qUmaxY = 108.8 kPa
d = 0.18 m ax = ay =
Vu = qu [BL-(cx+d)(cy+d)] Check Tension-controlled limit :
Vu = ab/d = 0.616
bo = 2(cy+d)+2(cx+d) ax/d = 0.073 ay/d = 0.073
bo = 1.60 m < ab/d <ok!> < ab/d <ok!>
φMnx = φMny =
> MU <ok!> > MU <ok!>
βc = 2.00
φVc1 =
F2
102.1 kN
320.8 kN
19.0 kN
1,005 mm² 1,005 mm²
495 mm²
180 mm
16.0 kN/m³
0.15 m
0.28 m
1.0 m
21.0 MPa
228.0 MPa
100.0 kPa
1.0 m
3.5 kPa
320.8 kN
511.2 kN
320.8 kN
from CL of footing.
from CL of footing.
16 mm φ
16 mm φ
34.8 kN-m
68.4 kN
12.5 kN0.10 m
0.30 m
1.0 m
0.50 m
0.50 m
φVc2 =
φVcy =
φMnx =
ax =
φVc3 =
ay =
φMny =
12.8 mm
34.8 kN-mβc =
φVc1 =
φVcx =
92.0 kN
12.8 mm
100.2 kN
6.7 kN-m
f ikjj2 + 4
bc
y{zz è!!!!!!
fc bo d
12
long side of col .
short s ide of col .
f ikjj2 + as d
bo
y{zz è!!!!!!
fc bo d
12
f 1
3 è!!!!!!
fc bo d
eu =Mu
Pu
e =M
P
VuX = qu B@max Hd x , L-d x L -0.5 c x -dD VuY = qu L@max Hdy , B-dyL -0.5 cy -dD
f 1
6 è!!!!!!
fc Bd f 1
6 è!!!!!!
fc Ld
Asx fy
0.85 fc B
Asy fy
0.85 fc L
fAsx fy Jd -a x
2N fAsy fy Jd -
ay
2N
y
x
z
x
z
L
x
y
f
f
xy
yx
y
surcharge
surcharge surcharge
dx
y
DESIGN OF A ISOLATED FOOTING Mark :
INPUT DATA :
Concrete Strength, fc' =
Rebar Yield strength, fy =
Net Allowable Soil pressure, qa =
Footing Embedment Depth, Df =
Surcharge, qs =
Soil Weight, ws =
Column Width, cx =
Column Depth, cy =
Column Location in X-dir., dx = Use 1.1 x 1.1 x 0.25m thk. footing
Column Location in Y-dir., dy = w/ 5-16mm along X-direction
Footing Length, L = 5-16mm along Y-direction rebar
Footing Width, B =
Footing Thickness, t =
Longitudinal Rebar, Ax = 5 - Gravity Service Loads :
Transverse Rebar, Ay = 5 - PD =
Rebar center to Conc. edge, c = PL =
Check Soil Bearing Capacity :
Load on Footings :
PD + PL = 89.4 kN (Applied load) αs = 40
qs(BL) = 4.2 kN (Surcharge load) φVc2 =
(23.5-ws) tBL = 2.3 kN (Increased Footing)
Pa = 95.9 kN
φVc3 =
φVc = Min(φVc1 ,φVc2 ,φVc3 )
x-z plane: eX = 0.000 m < L/6 = 0.1833 φVc = > Vu <ok!>
qmaxX = 79 kPa < qa <ok!> Check for One-way Shear :
y-z plane: eY = 0.000 m < B/6 = 0.1833
qmaxY = 79 kPa < qa <ok!>
Vux = 35.7 kN Vuy =
Check thickness for Two-way Shear :
1.2PD + 1.6PL =
1.2qs(BL) = 5.1 kN φVcx = 94.5 kN φVcy =
1.2(23.5-ws) tBL = 2.7 kN > Vu <ok!> > Vu <ok!>
PU = 120.8 kN Check Flexural Reinforcement :
Governing Moments:
MUx = 12.4 kN-m MUy =
x-z plane: eUX = 0.000 m < L/6 = 0.1833 Asx = Asy = (provided)
qUmaxX = 99.8 kPa Asmin(x) = 495 mm² Asmin(y) = (= 0.0018Bt)
y-z plane: eUY = 0.000 m < B/6 = 0.1833 sx = 205 mm sy = (Smax = 500mm)
qUmaxY = 99.8 kPa
d = 0.15 m ax = ay =
Vu = qu [BL-(cx+d)(cy+d)] Check Tension-controlled limit :
Vu = ab/d = 0.616
bo = 2(cy+d)+2(cx+d) ax/d = 0.078 ay/d = 0.078
bo = 1.50 m < ab/d <ok!> < ab/d <ok!>
φMnx = φMny =
> MU <ok!> > MU <ok!>
βc = 2.00
φVc1 =
βc =
φVc1 =
φVcx =
107.3 kN
11.7 mm
94.5 kN
8.8 kN-m
257.8 kN
from CL of footing.
from CL of footing.
16 mm φ
16 mm φ
29.7 kN-m
75.1 kN
14.3 kN0.10 m
0.30 m
1.1 m
0.55 m
0.55 m
φVc2 =
φVcy =
φMnx =
ax =
φVc3 =
ay =
φMny =
11.7 mm
29.7 kN-m
F3
113.0 kN
257.8 kN
27.5 kN
1,005 mm² 1,005 mm²
495 mm²
205 mm
16.0 kN/m³
0.15 m
0.25 m
1.1 m
21.0 MPa
228.0 MPa
100.0 kPa
1.0 m
3.5 kPa
257.8 kN
386.7 kN
f ikjj2 + 4
bc
y{zz è!!!!!!
fc bo d
12
long side of col .
short s ide of col .
f ikjj2 + as d
bo
y{zz è!!!!!!
fc bo d
12
f 1
3 è!!!!!!
fc bo d
eu =Mu
Pu
e =M
P
VuX = qu B@max Hd x , L-d x L -0.5 c x -dD VuY = qu L@max Hdy , B-dyL -0.5 cy -dD
f 1
6 è!!!!!!
fc Bd f 1
6 è!!!!!!
fc Ld
Asx fy
0.85 fc B
Asy fy
0.85 fc L
fAsx fy Jd -a x
2N fAsy fy Jd -
ay
2N
y
x
z
x
z
L
x
y
f
f
xy
yx
y
surcharge
surcharge surcharge
dx
y
DESIGN OF A ISOLATED FOOTING Mark :
INPUT DATA :
Concrete Strength, fc' =
Rebar Yield strength, fy =
Net Allowable Soil pressure, qa =
Footing Embedment Depth, Df =
Surcharge, qs =
Soil Weight, ws =
Column Width, cx =
Column Depth, cy =
Column Location in X-dir., dx = Use 0.9 x 0.9 x 0.25m thk. footing
Column Location in Y-dir., dy = w/ 4-16mm along X-direction
Footing Length, L = 4-16mm along Y-direction rebar
Footing Width, B =
Footing Thickness, t =
Longitudinal Rebar, Ax = 4 - Gravity Service Loads :
Transverse Rebar, Ay = 4 - PD =
Rebar center to Conc. edge, c = PL =
Check Soil Bearing Capacity :
Load on Footings :
PD + PL = 64.8 kN (Applied load) αs = 40
qs(BL) = 2.8 kN (Surcharge load) φVc2 =
(23.5-ws) tBL = 1.5 kN (Increased Footing)
Pa = 69.2 kN
φVc3 =
φVc = Min(φVc1 ,φVc2 ,φVc3 )
x-z plane: eX = 0.000 m < L/6 = 0.15 φVc = > Vu <ok!>
qmaxX = 85 kPa < qa <ok!> Check for One-way Shear :
y-z plane: eY = 0.000 m < B/6 = 0.15
qmaxY = 85 kPa < qa <ok!>
Vux = 21.7 kN Vuy =
Check thickness for Two-way Shear :
1.2PD + 1.6PL =
1.2qs(BL) = 3.4 kN φVcx = 77.3 kN φVcy =
1.2(23.5-ws) tBL = 1.8 kN > Vu <ok!> > Vu <ok!>
PU = 86.7 kN Check Flexural Reinforcement :
Governing Moments:
MUx = 6.8 kN-m MUy =
x-z plane: eUX = 0.000 m < L/6 = 0.15 Asx = Asy = (provided)
qUmaxX = 107.0 kPa Asmin(x) = 405 mm² Asmin(y) = (= 0.0018Bt)
y-z plane: eUY = 0.000 m < B/6 = 0.15 sx = 212 mm sy = (Smax = 500mm)
qUmaxY = 107.0 kPa
d = 0.15 m ax = ay =
Vu = qu [BL-(cx+d)(cy+d)] Check Tension-controlled limit :
Vu = ab/d = 0.616
bo = 2(cy+d)+2(cx+d) ax/d = 0.076 ay/d = 0.076
bo = 1.50 m < ab/d <ok!> < ab/d <ok!>
φMnx = φMny =
> MU <ok!> > MU <ok!>
βc = 2.00
φVc1 =
F4
81.5 kN
257.8 kN
14.5 kN
804 mm² 804 mm²
405 mm²
212 mm
16.0 kN/m³
0.15 m
0.25 m
0.9 m
21.0 MPa
228.0 MPa
100.0 kPa
1.0 m
3.5 kPa
257.8 kN
386.7 kN
257.8 kN
from CL of footing.
from CL of footing.
16 mm φ
16 mm φ
23.8 kN-m
55.5 kN
9.3 kN0.10 m
0.30 m
0.9 m
0.45 m
0.45 m
φVc2 =
φVcy =
φMnx =
ax =
φVc3 =
ay =
φMny =
11.4 mm
23.8 kN-mβc =
φVc1 =
φVcx =
72.3 kN
11.4 mm
77.3 kN
4.3 kN-m
f ikjj2 + 4
bc
y{zz è!!!!!!
fc bo d
12
long side of col .
short s ide of col .
f ikjj2 + as d
bo
y{zz è!!!!!!
fc bo d
12
f 1
3 è!!!!!!
fc bo d
eu =Mu
Pu
e =M
P
VuX = qu B@max Hd x , L-d x L -0.5 c x -dD VuY = qu L@max Hdy , B-dyL -0.5 cy -dD
f 1
6 è!!!!!!
fc Bd f 1
6 è!!!!!!
fc Ld
Asx fy
0.85 fc B
Asy fy
0.85 fc L
fAsx fy Jd -a x
2N fAsy fy Jd -
ay
2N
y
x
z
x
z
L
x
y
f
f
xy
yx
y
surcharge
surcharge surcharge
dx
y
DESIGN OF A ISOLATED FOOTING Mark :
INPUT DATA :
Concrete Strength, fc' =
Rebar Yield strength, fy =
Net Allowable Soil pressure, qa =
Footing Embedment Depth, Df =
Surcharge, qs =
Soil Weight, ws =
Column Width, cx =
Column Depth, cy =
Column Location in X-dir., dx = Use 0.6 x 0.6 x 0.175m thk. footing
Column Location in Y-dir., dy = w/ 3-16mm along X-direction
Footing Length, L = 3-16mm along Y-direction rebar
Footing Width, B =
Footing Thickness, t =
Longitudinal Rebar, Ax = 3 - Gravity Service Loads :
Transverse Rebar, Ay = 3 - PD =
Rebar center to Conc. edge, c = PL =
Check Soil Bearing Capacity :
Load on Footings :
PD + PL = 30.0 kN (Applied load) αs = 40
qs(BL) = 1.3 kN (Surcharge load) φVc2 =
(23.5-ws) tBL = 0.5 kN (Increased Footing)
Pa = 31.7 kN
φVc3 =
φVc = Min(φVc1 ,φVc2 ,φVc3 )
x-z plane: eX = 0.000 m < L/6 = 0.1 φVc = > Vu <ok!>
qmaxX = 88 kPa < qa <ok!> Check for One-way Shear :
y-z plane: eY = 0.000 m < B/6 = 0.1
qmaxY = 88 kPa < qa <ok!>
Vux = 9.6 kN Vuy =
Check thickness for Two-way Shear :
1.2PD + 1.6PL =
1.2qs(BL) = 1.5 kN φVcx = 25.8 kN φVcy =
1.2(23.5-ws) tBL = 0.6 kN > Vu <ok!> > Vu <ok!>
PU = 38.4 kN Check Flexural Reinforcement :
Governing Moments:
MUx = 1.6 kN-m MUy =
x-z plane: eUX = 0.000 m < L/6 = 0.1 Asx = Asy = (provided)
qUmaxX = 106.7 kPa Asmin(x) = 189 mm² Asmin(y) = (= 0.0018Bt)
y-z plane: eUY = 0.000 m < B/6 = 0.1 sx = 176 mm sy = (Smax = 500mm)
qUmaxY = 106.7 kPa
d = 0.08 m ax = ay =
Vu = qu [BL-(cx+d)(cy+d)] Check Tension-controlled limit :
Vu = ab/d = 0.616
bo = 2(cy+d)+2(cx+d) ax/d = 0.171 ay/d = 0.171
bo = 1.20 m < ab/d <ok!> < ab/d <ok!>
φMnx = φMny =
> MU <ok!> > MU <ok!>
βc = 2.00
φVc1 =
F5
36.3 kN
103.1 kN
4.8 kN
603 mm² 603 mm²
189 mm²
176 mm
16.0 kN/m³
0.15 m
0.18 m
0.6 m
21.0 MPa
228.0 MPa
100.0 kPa
1.0 m
3.5 kPa
103.1 kN
116.0 kN
103.1 kN
from CL of footing.
from CL of footing.
16 mm φ
16 mm φ
8.5 kN-m
29.2 kN
0.8 kN0.10 m
0.30 m
0.6 m
0.30 m
0.30 m
φVc2 =
φVcy =
φMnx =
ax =
φVc3 =
ay =
φMny =
12.8 mm
8.5 kN-mβc =
φVc1 =
φVcx =
29.4 kN
12.8 mm
25.8 kN
0.7 kN-m
f ikjj2 + 4
bc
y{zz è!!!!!!
fc bo d
12
long side of col .
short s ide of col .
f ikjj2 + as d
bo
y{zz è!!!!!!
fc bo d
12
f 1
3 è!!!!!!
fc bo d
eu =Mu
Pu
e =M
P
VuX = qu B@max Hd x , L-d x L -0.5 c x -dD VuY = qu L@max Hdy , B-dyL -0.5 cy -dD
f 1
6 è!!!!!!
fc Bd f 1
6 è!!!!!!
fc Ld
Asx fy
0.85 fc B
Asy fy
0.85 fc L
fAsx fy Jd -a x
2N fAsy fy Jd -
ay
2N
y
x
z
x
z
L
x
y
f
f
xy
yx
y
surcharge
surcharge surcharge
dx
y