The atomorbiting electrons
Nucleus (protons and neutrons)
Nuclide notation
Li3
7
Proton number (Z) = number of protons
Nucleon number (A) = number of protons and neutrons
Neutron number (N) = A - Z
Isotopes
Li3
7
It is possible for the nuclei of the same element to have different numbers of neutrons in the nucleus (but it must have the same number of protons)
Li3
6
Isotopes
Li3
7
For example, Lithium atoms occur in two forms, Lithium-6 and Lithium-7
Li3
6
4 neutrons3 neutrons
Isotopes of Hydrogen
H1
1
The three isotopes of Hydrogen even have their own names!
H1
2
H1
3
Hi! I’m hydrogen
They call me
deuterium
Hola! Mi nombre es tritium y yo
soy de Madrid!
How do we know the structure of the atom?
The famous Geiger-Marsden Alpha scattering experiment
In 1909, Geiger and Marsden were studying how alpha particles are scattered by a thin gold foil.
Alpha source
Thin gold foil
Geiger-Marsden
As expected, most alpha particles were detected at very small scattering angles
Alpha particles
Thin gold foil Small-angle scattering
Geiger-Marsden
To their great surprise, they found that some alpha particles (1 in 20 000) had very large scattering angles
Alpha particles
Thin gold foil Small-angle scattering
Large-angle scattering
Explaining Geiger and Marsdens’ results
The results suggested that the positive (repulsive) charge must be concentrated at the centre of the atom. Most alpha particles do not pass close to this so pass undisturbed, only alpha particles passing very close to this small nucleus get repelled backwards (the nucleus must also be very massive for this to happen).
nucleus
Rutherford did the calculations!Atomic nucleus had a diameter of about 10-15 m
That’s 100,000 times smaller than the size of an atom (about 10-10 meters).
Stadium as atom
If the nucleus of an atom was a ping-pong ball, the atom would be the size of a football stadium (and mostly full of nothing)!
Nucleus (ping-pong ball
Forces in the Nucleus
Coulomb Force in Nucleus
• Repulsive force between protons
+
+
The Strong Force
The nucleons (protons and neutrons) in the nucleus are bound together by the strong nuclear force
Strong Force
• Acts over short distances (10-15 m)• Acts only between adjacent particles in the
nucleus• Carried by “gluons”
Why is a nucleus unstable?
Because of the relative numbers of p and nEx. Uranium 235
Hi! I’m uranium-235 and I’m unstable. I really need to
lose some particles from my nucleus to become more
stable.
The unstable nucleus emits a particle to become stable
Thus, the atom (nucleus) has decayed.
Weeeeeeeeeeeeee!
Decay of an Unstable Nucleus1. Random –
It’s going to happen, but when?!
2. Spontaneous – Not affected by temperature, pressure etc.
Weeeeeeeeeeeeee!
Becquerels (Bq)
• The amount of radioactivity given out by a substance is measured in Becquerels.
• One Becquerel is one particle emitted per second.
How to detect particles?
• Photographic film
• Fluorescence
• Geiger-Müller tube (GM tube) connected to a counter (counts the # of particles)– Use filters to distinguish alpha, beta, and
gamma particles
Three main types of particles can be ejected from an unstable nucleus.
Alpha particles
αHi!
Alpha particles• 2 protons and 2 neutrons joined together
– Helium nucleus• Stopped by paper or a few cm of air• Highly ionising• Deflected by electric and strong magnetic
fields
He2
4 2+
α2
4
Alpha Decay
U92
235
Th90
231
+Atomic number goes down by 2
Atomic mass goes down by 4
He2
4 2+
Alpha Decay
U92
235
Th90
231
+Atomic number goes down by 2
Atomic mass goes down by 4
α2
4
Beta particles
βYo!
Beta particles
• Fast moving electrons or positrons• Stopped by about 3 mm of aluminium• Weakly ionising• Deflected by electric and magnetic fields
e-1
0 β-1
0 e+1
0 β+1
0
Beta Negative electron Beta Positive Positron
• In the nucleus a neutron [or proton] changes into an electron [positron] (the beta particle which is ejected) and a proton [neutron] (which stays in the nucleus) and an antineutrino [neutrino]– During beta decay the mass number stays the same but
the proton number goes up [or down] by 1.
e + עe
Beta decay
e + עe-1
0Ca20
46
Sc +21
46 0
0
antineutrino
+1
0K19
40
Ar +18
40 0
0
neutrino
• In the nucleus a neutron [or proton] changes into an electron [positron] (the beta particle which is ejected) and a proton [neutron] (which stays in the nucleus) and an antineutrino [neutrino]– During beta decay the mass number stays the same but
the proton number goes up [or down] by 1.
β + עe
Beta decay
β + עe-1
0Ca20
46
Sc +21
46 0
0
antineutrino
+1
0K19
40
Ar +18
40 0
0
neutrino
Gamma rays
Hola!
Gamma rays
• High frequency electromagnetic radiation• Stopped by several cm of lead• Very weakly ionising• NOT affected by electric or magnetic fields
Gamma raysUsually associated with alpha decayExcited nucleus relaxes by releasing a
gamma ray.
U92
235
Th*90
231
+ α
Th 90
231
+
Biological Effects of Localized Radiation Exposure
• Short Term – Low dosage – skin reddening– High dosage – skin or tissue necrosis
• Long Term – through direct or indirect actions– Damages or mutates DNA and other cells
(specific concern: somatic cells)– Potential cancer causing
Best Practice: Prevention!• Limit Radiation Concentration (in labs)
• Limit Exposure Time
• Increase Distance
• Use Appropriate Shielding Materials
½ - life
• The decay of a single nuclei is totally random
• However, with large numbers of atoms a pattern does occur
½ - life
• This is the time it takes half the nuclei to decay
half-life (t½)
Number of nuclei undecayed
time
½ - life
• This is the time it takes half the nuclei to decay
half-life (t½)
Number of nuclei undecayed
time
½ - life
• This is the time it takes half the nuclei to decay
half-life (t½)
Number of nuclei undecayed
timeA graph of the count rate against time will be the same shape
Different ½ - lives
• Different isotopes have different half-lives• The ½-life could be a few milliseconds or
5000 million years!
half-life (t½)
Number of nuclei undecayed
time
Decay Constant (λ)
• The probability that an atom will decay
– Remember that the decay of a single nuclei is totally random
• Activity = the decay constant times the number of atoms– Equation A = λ N
Determining ½ - lives• For short half-lives
– Use a GM-tube to measure initial activity, and then measure the time it takes for that activity to decrease by a half.
– That time is the half-life!• For long half-lives
– Use a GM-tube to measure the initial Activity– Measure the mass of the sample
• Calculate the # of atoms using molar mass and Avogadro’s number
– Calculate λ [decay constant] from A0 = λ N0
– Calculate half-life t1/2 = ln(2) / λ
Nuclear Reactions
Unified mass unit (u)
• Defined as 1/12 of the mass of an atom of Carbon-12
u = 1.6605402 x 10-27 kg
Energy mass equivalence
• E = mc2
• E = 1.6605402 x 10-27 x (2.9979 x 108)2
• E = 1.4923946316 x 10-10 J
• Remembering 1 eV = 1.602177 x 10-19 J• 1 u = 931.5 MeV• The electron-Volt is a convenient unit of
energy for nuclear physics
Mass defect
For helium, the mass of the nucleus = 4.00156 u
But, the mass of two protons and two nuetrons = 4.0320 u!!!!
Where is the missing mass?
Mass defect
The missing mass (mass defect) has been stored as energy in the nucleus. It is called the binding energy of the nucleus.
It can be found from E = mc2
Mass defect calculation
• Find the mass defect of the nucleus of gold, 196.97 - Au
Mass defect calculation
• The mass of this isotope is 196.97u• Since it has 79 electrons its nuclear mass
is 196.97u – 79x0.000549u = 196.924u
Mass defect calculation
• The mass of this isotope is 196.97u• Since it has 79 electrons its nuclear mass
is 196.97u – 79x0.000549u = 196.924u• This nucleus has 79 protons and 118
neutrons, individually these have a mass of 79x1.0007276u + 118x1.008665u = 198.080u
Mass defect calculation
• The mass of this isotope is 196.97u• Since it has 79 electrons its nuclear mass is
196.97u – 79x0.000549u = 196.924u• This nucleus has 79 protons and 118
neutrons, individually these have a mass of 79x1.0007276u + 118x1.008665u = 198.080u
• The difference in mass (mass defect) is therefore 1.156u
Mass defect calculation
• The difference in mass (mass defect) is therefore 1.156u
• This “missing mass” is stored as energy in the nucleus (binding energy).
• 1u is equivalent to 931.5 MeV
Nuclear ReactionsSimilar calculation as mass defect – the products
have less mass that the reactants, and the lost mass is converted into KE of the products
Transmutation - the conversion of the nucleus of one isotope or element into another
Artificial (induced) transmutation – the energy required for transmutation is provided by “artificial” means
EX. Artificial Transmutation – bombard a nitrogen atom with a high E alpha particle
N7
14
+ O8
17
+ p1
1
He2
4 2+
N7
14
+ O8
17
+ p1
1α2
4
Binding energy
The work (energy) required to completely separate the nucleons of the nucleus.
Binding energy per nucleonThe BE / nucleon number
- the work (energy) required to completely remove 1 nucleon from a nucleus
It is a measure of how stable the nucleus is.
The binding energy curve
Let’s do some reading!
Nuclear Fission
Uranium
Uranium 235 has a large unstable nucleus.
Capture
A lone neutron hitting the nucleus can be captured by the nucleus, forming Uranium 236.
Fission and free neutrons
Uranium 236 is very unstable and splits (nuclear fission) into two smaller nuclei (called daughter nuclei) and three neutrons (with lots of kinetic energy)
Fission
These free neutrons can strike more uranium nuclei, causing them to split.
Chain ReactionIf there is enough uranium (critical mass) a chain reaction occurs. Huge amounts of energy are released very quickly.
Chain ReactionIf there is enough uranium (critical mass) a chain reaction occurs. Huge amounts of energy are released very quickly.
Bang!This can result in a nuclear explosion! (movie is of a 23 ktonne nuke detonated underwater.)
http://www.youtube.com/watch?v=b2WQvtGnBQw
Nuclear fusion – Star power!
Nuclear fusion – Star power!
• http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/fusion.html#c1
• http://hyperphysics.phy-astr.gsu.edu/hbase/astro/astfus.html#c1
• Check out the 2 links above to better understand all the types of nuclear reactions that occur in stars.
The binding energy curve