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The General Solution (HW #3)

Date post: 19-Feb-2022
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The General Solution (HW #3) The general (or ”complete” or ”total”) solution for the system A~ x = ~ b is the set of all solutions for the system. Theorem: If ~ x p is any solution to the system A~ x = ~ b, then the general solution for the system is the set ~ x p + N (A). Proof: We must show that if A~ x = ~ b, then there exists ~ n 2 N (A) so that ~ x = ~ x p + ~ n. But A(~ x - ~ x p )= ~ 0 so . . . finish the proof. The tactics for solving A~ x = ~ b are then: 1) Use Gaussian Elimination on the augmented system. 2) Find a particular solution by setting the free variables to zero. 3) Find N (A) by replacing the reduced ~ b with the zero vector. 4) Writing the final answer using the particular solution and a span of the ”special solutions.” 1
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Page 1: The General Solution (HW #3)

The General Solution (HW #3)

The general (or ”complete” or ”total”) solution for the system A~x = ~b is the set of all solutions for thesystem.

Theorem: If ~xp is any solution to the system A~x = ~b, then the general solution for the system is the set~xp +N(A).

Proof: We must show that if A~x = ~b, then there exists ~n 2 N(A) so that ~x = ~xp + ~n.

But A(~x� ~xp) = ~0 so . . . finish the proof.

The tactics for solving A~x = ~b are then:

1) Use Gaussian Elimination on the augmented system.

2) Find a particular solution by setting the free variables to zero.

3) Find N(A) by replacing the reduced ~b with the zero vector.

4) Writing the final answer using the particular solution and a span of the ”special solutions.”

1

Page 2: The General Solution (HW #3)

Find the general solution for A~x = ~b if A =

2

664

1 0 1 0 12 1 4 0 20 1 2 1 �11 0 1 �1 2

3

775 and ~b =

2

664

2961

3

775.

2

Page 3: The General Solution (HW #3)

Find the general solution for B~x = ~b if B =

2

40 1 1 11 2 0 10 1 �1 0

3

5 and ~b =

2

4132

3

5.

3


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