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Thermo Chemical Reaction Equilibria

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41
 CHEMICAL-REACTION EQUILIBRIA CHAPTER 13
Transcript

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CHEMICAL-REACTION

EQUILIBRIA 

CHAPTER 

13

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13.1 THE REACTION COORDINATE 

 The general chemical reaction :

...... 44332211   ++→++   Av Av Av Av

where | vi | is a stoichiometric coefficient and A

istands for a

chemical formula.

 For vi :

Positive ( + for !roduct "egative ( # for reactants

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Example :

$%4 + %

2& ' $& + 3%

2

The stoichiometric numers are :

14

−=CH v   12

−=O H v   1=COv   32= H v

 The stoichiometric numer for an inert s!ecies is )ero.

 *ince

ε d 

v

dn

v

dn

v

dn

v

dn=====   ...

4

4

3

3

2

2

1

1

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 The general relation etween a differential change dni in the

  numer of moles of a reacting s!ecies and dε is :

dni = vi dε ( i  1 , 2 ,-. N 

 This variale ε called the reaction coordinate, characteri)es the

etent or degree to which a reaction has ta/en !lace.

∫ ∫    =  ε 

ε 0

0

d vdn i

n

n  i

i

or

ε iii

  vnn

  +=0

( i  1 , 2 ,-. N 

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 *ummation over all s!ecies ields :

∑∑∑   +==i

i

i

i

i

i vnnn   ε 0

or n = n0 + vε

 

where ∑≡i

inn   ∑≡i

inn00   ∑≡

i

ivv

 Thus the mole fractions yi of the s!ecies !resent are related to ε  :

ε 

ε 

vn

vn

n

n y

iii

i

+

+==

0

0

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Example 13.2

$onsider a vessel which initiall contains onl no mol of water

va!or. f decom!osition occurs according to the reaction,

22221 O H O H    +→

find e!ressions which relate the numer of moles and the mole

fraction of each chemical s!ecies to the reaction coordinate ε.

Solution 13.2

For the given reaction2

1

2

111   =++−=v

 

!!lication of 5s. (13.4 and(13.6 ields:

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ε −=   02nn O H 

ε 

ε 

2

10

0

2

+

−=n

n y O H 

ε =2 H n

ε 

ε 

2

10

2

+=

n y H 

ε 2

12=On

ε 

ε 

2

12

1

0

2

+=

n

 yO

The fractional decom!osition of water va!or is:

( )00

00

0

0 2

nn

nn

n

nn O H    ε ε  =−−=−

Thus when no  1, ε is identified with the fractional decom!osition of 

the water va!or.

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∑= j

 j jii   d vdn   ε ,

 fter integration :

 j j

 jiii   vnn   ε ∑+=   ,0

 *umming over all s!ecies ields :

 j

 j i

 ji

i

 j

 j

 ji

i

i vnvnn   ε ε  ∑ ∑∑∑∑    

 

 

 

 +=+=

  ,0,0

 For the mole fraction:

+

+=

 j j j

 j

 j jii

ivn

vn

 yε 

ε 

0

,0

( i  1 , 2 ,-. N 

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13.2 APPLICATION OF

EQUILIBRIUM CRITERIA TO

CHEMICAL REACTIONS  t the e5uilirium state :

( dGt  )T , P

The total 7is energ Gt  is a minimum

ts differential is )ero.

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13.3 THE STANDARD GIBBS-ENERGY

CHANGE

AND THE EQUILIBRIUM CONSTANT The fundamental !ro!ert relation for single#!hase sstems,

 !rovides an e!ression for the total differential of the 7is

energ: ( ) ( ) ( )   ∑+−=i

iidndT S dP nV nGd    µ 

 f changes in mole numers ni occur as the result of a single

chemical reaction in a closed sstem , then each dni ma e

re!laced the !roduct vi dε .

( ) ( ) ( )

  ∑+−=

i

ii d vdT S dP nV nGd    ε  µ 

 *ince nG is a state function , the right side of this an eact

differential e!ression :

( )   ( )

 P T 

 P T i

ii

GnGv

,,

∂=

∂=∑

ε ε 

 µ 

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 For chemical#reaction e5uilirium :

0=∑i

iiv µ 

 8ecall the definition of the fugacit of a s!ecies in solution :

( )   iii   f   RT T    9ln+Γ= µ 

 For a !ure s!ecies i in its standard start at the same tem!erature :

( ) 

iii   f   RT T G   ln+Γ =

 The difference etween these two e5uations is :

i

iii

 f  

 f   RT G

9ln=− µ 

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 For the e5uilirium state of a chemical reaction :

( )[ ]   09ln   =+∑i

iiii   f   f   RT Gv  

( )   09ln   =+   ∑∑ i

vii

i

iii f   f   RT Gv  

( ) RT 

Gv f   f     i   ii

i

v

ii

i   ∑∏  −

=

9ln

( )∏   =i

v

ii   K  f   f    i9ln

where

 

 

 

 

 

    ∆−≡

 RT 

G K 

e!

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 lternative e!ression for :

 RT 

G K 

∆−≡ln

 lso definition : ∑∆≡∆i

iGG  

 K  is a function of tem!erature onl .

 In spite of its dependence on temperature , K is called the

equilibrium constant for the reaction ;

∑i   iiGv 

, represented by ΔG˚ , is called the

standard Gibbs-energy change of reaction ,

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13.4 EFFECT OF TEMPERATURE

ON THE EQUILIBRIUM CONSTANT 

 The de!endence of ;G< on T  :

( )2 RT 

 H 

dT 

 RT Gd    ∆−=

 Then ecome:

2

ln

 RT 

 H 

dT 

 K d    ∆=

 5uation aove gives the effect of tem!erature on e5uilirium

  constant and hence on the e5uilirium conversion.

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 =hen ; H <

negative eothermic reaction

 !ositive endothermic reaction

 f ; H < is assumed inde!endent of T, then:

  

 

 

 

′−

−=′   T T  R

 H 

 K 

 K    11ln

 This a!!roimate e5uation im!lies that a !lot of ln K  vs the

reci!rocal of asolute tem!erature is a straight line. Figure

13.2 in tetoo/, shows a !lot of ln K  vs 1>T  for a numer of 

  common reactions, illustrates this near linearit.

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 The rigorous develo!ment of the effect of tem!erature on

the e5uilirium constant is ased on the definition of the

7is energ , written for a chemical s!ecies in its standard

state:

G˚ i = H˚ 

i TS˚ 

 ?ulti!lication vi and summation over all s!ecies gives:

∑∑∑   −=i

ii

i

ii

i

ii   S vT  H vGv  

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 s a result of the definition of standard !ro!ert change of

reaction, this reduces to:

;G˚=; H˚ T ;S˚ 

 =here the standard heat of reaction and standard entro!

  change is related to tem!erature:

dT  RC  R H  H 

T  P 

∫   ∆+∆=∆0

0

∫   ∆+∆=∆

 P 

dT 

 R

C  RS S 

00

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 %owever

0

000

G H S 

  ∆−∆=∆

whence

∫ ∫   ∆

−∆

+∆

+∆−∆

=∆   T 

 P T 

 P 

o

dT 

 R

C dT 

 R

T  RT 

 H 

 RT 

 H G

 RT 

G

00

10

0

00

and 

 RT 

G K 

∆−=ln

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 The !receding e5uation ma e reorgani)ed so as to factor

into three terms , each re!resenting a asic contriution

to its value :

 K = K 0 K 

! K 

"

 K 0 re!resents the e5uilirium constant at reference

tem!erature T 0:

    

     ∆−≡

0

00

 RT G K 

 

 

 

 

  −∆

=T 

 RT 

 H  K    0

0

01   1e!

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    ∆−

∆−= ∫ ∫ 

  T 

 P T 

 P 

dT 

 R

C dT 

 R

T  K 

00

1e!2

with heat ca!acities given :

( )   ( )( ) ( )

  −∆

+

+−

∆+

∆+

  

 

 

   −

−∆= 2

2

20

22

0

2

02

1

2

121

@

11

2

11

lne! τ  

τ  

τ  

τ  τ  

τ  

τ  

τ  

τ  τ  

 #

CT  $T  A K 

 

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13.5 EVALUATION OF EQUILIBRIUM

CONSTANTS 

Example 13.4

$alculate the e5uilirium constant for the va!or#!hase

hdration of ethlene at 146 and at 320A$ from data given in!!. $.

Solution 13.4

First determine values for ;, ;B, ;$, and ;C for the

reaction:

C " H 

%(&) + H 

"O (&) ' C 

" H 

OH (&)

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The meaning of ; is indicated : (C " H 

 OH  # (C 

" H 

% #

( H "O. Thus, from the heat#ca!acit data of Tale $. 1:

; 3.61D # 1.424 # 3.4E0 # 1.3E@

;B (20.001 # 14.34 # 1.460 10#3  4.16E l0#3

;$ (#@.002 + 4.32 # 0.000 10#@  #1.@10 10#@

;C (#0.000 # 0.000 # 0.121 106  #0.121 106

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Galues of ; H"*

 and ;G"*

 at 2D.16 for the hdration reaction are

found from the heat#of#formation and 7is#energ#of#formation data

from Tale $.4:

; H"*

  #236,100 # 62,610 # (#241,D1D #46,E2 H mol#1

;G"*

  #1@D,40 # @D,4@0 # (#22D,6E2 #D,3ED H mol#1 

For T 146 + 2E3.16 41D.16 , values of the integrals in 5. (13.1D

are:

C$P%(2D.16,41D.16I#1.3E@,4.16E#3,#1.@10#@,#0.121 +6 #23.121

C$P*(2D.16,41D.16I#1.3E@,4.16E#3,#1.@10#@,#0.121 +6 #0.0@24

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*ustitution of values into 5. (13.1D for a reference tem!erature of

2D.16 gives:

( )( ) ( )( )   [email protected]@F24.016.41D

121.23

16.41D314.D

EF2,46

16.2FD314.D

EF2,463ED,D41D

=+

+

+

+−

=

∆ RT 

G

For T   320 + 2E3.16 63.16 ,

C$P%(2D.16,63.16I#1.3E@,4.16E#3,#1.@10#@,#0.121 +6

22.@32

C$P*(2D.16,63.16I#1.3E@,4.16E#3,#1.@10#@,#0.121 +6 0.01E31

=hence,

( ) ( ) ( ) ( )

  [email protected]

16.6F3

@32.22

16.6F3314.D

EF2,46

16.2FD314.D

EF2,463ED,D6F3 =−+−+

+−=

 RT 

G

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Finall,

J41D.16: ln K   #1.36@ and K   1.443 10#1 

J63.16: ln K   #6.D2D@ and K 2.42 10#3

!!lication of 5s. (13.21, (13.22, and (13.24 !rovides an

alternative solution to this eam!le. B 5. (13.21,

( ) ( )3@@.2

16.2D314.D

3ED,De!0   == K 

( ) ( )  4E3.1D

16.2FD314.D

EF2,46

0

0 −=−

=∆ RT 

 H 

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?oreover,

=ith these values, the following results are readil otained:

T K  K  K 0

 K !

 K "

 K 

2D.16 1 2.3@@ 1 1 2.3@@

41D.16 1.4026 2.3@@ 4.D610#3 0.D@0 1.44310#1

63.16 1.D4 2.3@@ 1.02310#4 0.E4 2.4210#3

$learl, the influence of K !, is far greater than that of K 

". This

is a t!ical result, and accounts for the fact that the lines on

Fig. 13.2 are nearl linear.

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13.6 REELATION OF EQUILIBRIUM

CONSTANTS TO COMPOSITION

The standard state for gas is the ideal gas#state of the !ure

gas at the standard#state !ressure P < of 1 ar.

*ince for ideal gas : f˚ i = P˚  

Thus :

 P 

 f  

 f  

 f   i

i

i99

=and  K 

 P 

 f  

i

v

i

i

=

 

 

 

 

 

 

∏ 

9

where the constant K  is a function of tem!erature onl .

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For a fied tem!erature the com!osition at e5uilirium must

change with !ressure in such a wa that

( )   K  P  f  

i

v

i

i =∏   9

The fugacit is related to the fugacit coefficient :

 P  y f   iii   φ 99 =*ustitution of this e5uation :

( )   K  P 

 P  y

v

i

v

ii

i

   

  

=∏   φ 9

where

∑≡i ivv and P < is the standard Lstate !ressure if 1 ar ,

e!ressed in the same

remains constant .

units used for P  .

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  for a !ure s!ecies can e evaluated from a generali)ed

correlation once the e5uilirium T  and P  are s!ecified .

 For !ressure sufficientl low or tem!erature sufficientl high,

the e5uilirium ehaves essentiall as an ideal gas

 For ideal solution :

( )   K  P 

 P 

 y

v

i

v

ii

i

   

  

=∏  φ 

iφ 

( )   K 

 P 

 P  y

v

i

v

ii

 

 

 

 

 =∏  

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For reaction occurring in li5uid !hase :

 K 

 f  

 f  

i

v

i

i

i

=

 

 

 

 

 

 

∏ 

9

*ince iiii   f   - f     γ  =9

The fugacit ratio e!resses :

   

  

 ==

i

iii

i

iii

i

i

 f  

 f   -

 f  

 f   -

 f  

 f  γ  

γ  9

the fugacities of li5uids are wea/ function of !ressure .

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For reaction that ta/e !lace in high !ressure

( )  ( )

( )

  −=   ∑∏

i

ii

i

v

ii   V v

 RT 

 P  P  K  -   i

e!γ  

For low !ressure :

( )   K  -i

v

iii =∏   γ  

f the e5uilirium miture is an ideal solution , then .i

 is unit :

( )   K  -i

v

ii =∏

This sim!le relation is /nown as the law of mass action. *ince

li5uids often form nonideal solutions, e5uation aove can e

e!ected in man instances to ield !oor result .

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For s!ecies at low concentration in a5ueous solution,

%enrMs law can e use :

iii   /0  f    =9where  

i is a constant which de!endent on tem!erature and

/i is molalit .

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13.7 EQUILIBRIUM

CONVERSIONS FOR SINGLE

REACTIONS Example 13.5

The water#gas#shift reaction, $&(g + %2&(g ' $&

2(g + %

2(g

is carried out under the different sets of conditions descried elow.

$alculate the fraction of steam reacted in each case. ssume the

miture ehaves as an ideal gas.

(aThe reactants consist of 1 mol of %2& va!or and 1 mol of $&. The

tem!erature is 1,100 and the !ressure is 1 ar.

(*ame as (a ece!t that the !ressure is 10 ar.

(*ame as (a ece!t that 2 mol of "2 is included in the reactants.

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(dThe reactants are 2 mol of %2& and 1 mol of $&. &ther

conditions are the same as in (a.

(eThe reactants are 1 mol of %2& and 2 mol of $&. &ther

conditions are the same as in (a.

(fThe initial miture consists of 1 mol of %2&, 1 mol of $&,and 1 mol of $&

2. &ther conditions are the same as in (a.

(g *ame as (a ece!t that the tem!erature is 1,@60 K .

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Solution 13.5

(a For the given reaction at 1,100 , 104>T   .06, and

Fig. 13.2 !rovides the value. ln K 0 or K   1. For this reaction

01111   =−−+== ∑i

ivv . *ince the reaction miture is an ideal

1

2

22 ==  K  y y

 y y

O H CO

CO H 

B 5. (13.6:

2

1 1CO y

  ε −=

2

12

1

O H  y  ε −=

22

1CO y

  ε =

22

1 H  y

  ε =

gas, 5. (13.2D a!!lies, and here ecomes:

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*ustitution of these values into 5. ( gives:

( )

  11

2

2

=

− 1

1

ε 

ε 

Therefore the fraction of the steam that reacts is 0.6.

( *ince v 0 , the increase in !ressure has no effect on the

ideal#gas reaction, and ε1 is still 0.6.

or ε1  0.6

 (c The "2 does not ta/e !art in the reaction, and serves onl as a

diluent. t does increase the initial numer of moles no from 2 to 4,

and the mole fractions are all reduced a factor of 2. %owever,

5. ( is unchanged and reduces to the same e!ression as

 efore. Therefore, ε1  is again 0.6.

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(d n this case the mole fractions at e5uilirium are:

3

1 1

CO y

  ε −

= 3

22

1

O H  y

  ε −

= 32

1

CO y

  ε 

= 32

1

 H  y

  ε 

=

and 5. ( ecomes:

( ) ( )   121

2

=−−   11

1

ε ε 

ε 

The fraction of steam that reacts is then 0.@@E>2 0.333

or  ε1  0.@@E

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(e%ere the e!ressions for y$& and y%2& are interchanged , ut this

leaves the e5uilirium e5uation the same as in (d. Therefore ε1 

0.@@E, and the fraction of steam that reacts is 0.@@E.

(f n this case 5. ( ecomes:

( )

( )  1

1

12  =

+

1

11

ε 

ε ε 

The fraction of steam reacted is 0.333.

or  ε1  0.333

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(g t 1,@60 K , 104>T   @.0@, and from Fig. 13.2, in #1.16

  or 0.31@.

Therefore 5. ( ecomes:

( )[email protected]

1

2

=− 1

1

ε 

ε 

The reaction is eothermic, and conversion decreases with increasing

tem!erature.

or  ε1  0.3@

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13. PHASE RULE AND DUHEM!S

 THEOREM FOR REACTING

SYSTEM 

 This is !hase rule for reacting sstems.

 2 = " 3 4 + " 35 

  where 4  is numer of !hases , " numer of chemical s!ecies

  and r is numer of inde!endent chemical reactions at

e5uilirium within the sstem .

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13." MULTIREACTION EQUILIBRIA 

 j

i

v

i

i  K  f  

 f    ji

=   

  

 ∏

,9

  where j is the reaction inde.

For gas !hase reaction :

 j

i

v

i  K  P 

 f   ji

=   

 

 

 

,9

For the e5uilirium miture is an ideal#gas,

( )   j

v

v

i   K  P 

 y j

 ji

 

 

 =∏  

,


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