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Seismic R = 1, 1.5, 3 with Low Seismic Design Example Thomas F. Heausler, PE, SE Structural Engineer This presentation will summarize and scrutinize the use of Seismic Response Modification Coefficient, R, equal to 1, 1.5 and 3 for Industrial/Nonbuilding Structures Similar to Buildings, and for Buildings located in Low Seismic Design Categories (SDC B, C). The benefits and disadvantages will be discussed, and Design Examples will compare Low and High R systems, and assess economics, complexity, reliability, and the potential for undesirable modes of failure.
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Seismic R = 1, 1.5, 3 with Low Seismic Design Example

Thomas F. Heausler, PE, SE Structural Engineer

This presentation will summarize and scrutinize the use of Seismic Response Modification Coefficient, R, equal to 1, 1.5 and 3 for Industrial/Nonbuilding Structures Similar to Buildings, and for Buildings located in Low Seismic Design Categories (SDC B, C). The benefits and disadvantages will be discussed, and Design Examples will compare Low and High R systems, and assess economics, complexity, reliability, and the potential for undesirable modes of failure.

2019 Structural Engineering Summit – Anaheim

Indiana Structural Engineers Association2020 Spring Conference

Seismic R = 1, 1.5 and 3With Low Seismic Design Example

By:Thomas F. Heausler, PE, SEStructural EngineerKansas City

2019 Structural Engineering Summit – Anaheim

Thomas F. Heausler, PE, SEStructural Engineer

• ASCE 7 Seismic Voting Member since 2006

• NCSEA Seismic Code Advisory Committee, Chair

• Provide Senior Review and Code Consulting to Engineering Firms

• 38 years experience

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Seismic R = 1, 1.5 and 3 – When and Where &Low Seismic Example

• What is R• Restrictions• Low Seismic, Industrial • Pros, Cons, Prudent

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R - Response Modification Coefficient

Base Shear - V

Sds = 1.0 San Francisco, SDC = D, PGA = 0.4Sds = 0.18 Stillwater, SDC B, PGA = 0.08

Table 12.2-1SCBF R = 6, Omega Ωo = 2, Cd = 5SMF R = 8, Omega Ωo = 3, Cd = 5.5Steel Systems Not Specifically Detailed for Seismic, R = 3, Omega Ωo = 3, Cd = 3

Each R value has strings attached.

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DetailingLimitations(height, permitted)

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R, Omega Ωo, Cd

• Not like Wind

• “R” is measure of effective ductility of system

• Ductility is range between yield and fracture

• R is composed of two components: • Omega Ωo : Overstrength

• Rd: inelastic behavior/energy dissipation

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R - Response Modification Coefficient

•Overstrength

•Ductility

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R - Response Modification CoefficientOverstrength - within the SFRS

• Material Strengths, φ, Utilization• Drift governed• First yield versus fully yield

The maximum strength developed along the curve is substantially higher than that at first significant yield,

and this margin is referred to as the system overstrengthcapacity.

The ratio of these strengths is denoted as Ω.

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Rd

ΩFirst Yield

Design

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R - Response Modification Coefficient

Ductility - within the SFRS

• Region after yield but before fracture

• Reliable, controlled fuse

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Ductility

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R - Response Modification CoefficientDuctility - within the SFRS

•Region after yield but before fracture

•Reliable, controlled fuse

•Moment Frame => Hinge in beam

•Braced Frame => Inelastic buckling of brace

Northridge, CA

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Ductile

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Reduced Beam Section – Moment Frame

R = 8

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Special Concentric Braced Frame - SCBF

R = 6

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Special Concentric Braced Frame - SCBF

R = 6

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Buckling Restrained Braced Frames - BRBF

R = 8

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R = 8

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BRBF Buckling Restrained Braced Frames

R = 8

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BRBF

R = 8

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Strings Attached to High R Factor

•Collectors (ASCE 7 – SDC C, D, E, F) Ωo

•AISC 341 versus AISC 360

•ACI 318-14 Chapter 17, 18

•Masonry

•Wood

Ω is within fuse, Ωo is outside of fuse

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Collector Ωo

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High R factors• AISC 341 Special Moment Frame, R = 8

• AISC 358 “prequalified” moment connections

• Develop expected strength of beam

• Demand Critical Weld, CJP welds

• Protected Zones

• AISC 341 Special Concentric Braced Frame, R = 6•Develop expected strength of brace

• Columns• Width/Thickness Ratios

• Develop expected strength of braces

• Anchor rods, Column splices

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Lower R factors

•AISC 341 Ordinary Moment Frame, R = 3.5

•AISC 341 Ordinary Concentric Braced Frame, R = 3.25

•Not very ordinary - Ωo is triggered for connections, braces, anchor rods etc.

•Ωo = 2, 3

Table 12.2-10BF R = 3.25, Omega Ωo = 2, Cd = 3.25OMF R = 3.5, Omega Ωo = 3, Cd =3Steel Systems Not Specifically Detailed for Seismic, R = 3, Omega Ωo = 3, Cd = 3

Each R value has strings attached.

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OMF R = 3.5 • Develop expected strength of beam• Demand Critical Weld, CJP welds

0BF R = 3.25• Ωo overstrength required• K-Brace prohibited• Beam Support DL+LL for inverted V bracing

Columns – (for both OMF and OBF)• Width/Thickness Ratios• Ωo overstrength required• Anchor rods, Column splices

“Ordinary” = not very ordinary!

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R = 3 for Steel Structures

• Not specifically detailed for seismic – AISC 360 only

• Not permitted in SDC D, E, F

• Ωo only required by ASCE 7 (e.g. collectors) and ACI Concrete anchorage.

• Rationale: Low ductility demand, mostly overstrength, accelerations are low.

• Frequently and economical to use where allowed.

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R = 3 Braced Frame, Moment Frame

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R = 3 Braced Frame, Moment Frame

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R = 3 Braced Frame

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Industrial Structures

•Difficult or impossible to meet prescriptive requirements of high R factor.

R = 1.0 for Steel Moment Frames

R = 1.5 for Steel Braced Frames

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ASCE 7 Chapter 15Nonbuilding Structures Similar to Buildings

BUILDING: Any structure whose intended use includes shelter of human occupants.

NONBUILDING STRUCTURE: A structure, other than a building, constructed of a type included in Chapter 15 and within the limits of Section 15.1.1. (applicability).

11.1.3 Applicability. Structures and their nonstructural components shall be designed and constructed in accordance with the requirement of the following chapters based on the type of structure or component:

a. Buildings: Chapter 12;

b. Nonbuilding Structures: Chapter 15;

Buildings whose purpose is to enclose equipment or machinery and whose occupants are engaged in maintenance or monitoring of that equipment, machinery, or their associated processes shall be permitted to be classified as nonbuilding structures designed and detailed in accordance with Section 15.5 of this standard.

Same as Ch 12, Buildings

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Pipe Rack – Power Plant

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Prescriptive requirements for High R Systems

• Brace Slenderness

• Develop full strength of brace

• Strong Column – Weak Beam

• AISC 358 Prequalified

• Weak axis bending, tube columns, discontinuous systems

• Protected Zones BF, MF

• Field Welding, CJP welds

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Pipe Rack – Power Plant

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Chimney and Stacks – R = 2…ASCE 7 15.6.2, ACI 307

• Low ductility• Industry Standard

Nonbuilding not similar to buildings

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Bin on braced legs R=3

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Bin on Unbraced Legs R = 2

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R – Tanks, SCR, HRSG, Soundwalls

Tanks on Grade, R = 3HRSG R = 8, 3.5, 3, 1.0Cantilevered fence, Wall >6’ R = 1.25

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Industrial Structures

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ASCE 7 Nonbuilding

R = 1.5 BF, 1.0 MF

AISC 360

No proportioning

? R=1: Other than

Steel

UFC Essential

Facilities R = 1

Nuclear Plants

R = 1

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ASCE 7-16 Proposal – Essentially Elastic R = 1

• SIMPLIFY

• Limit Scope of Use

• Reduce Ductility Demand: R = 1

• Diaphragms, Non-Structural, Walls: Rp = 1

• Limit Irregularities, Simplify Drift

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Lightweight Buildings

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Weak column – strong beamK – brace

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High Lateral Resistant Buildings

Foundation Sliding – frost depth

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Brute force

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Low Force

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ASCE 7-16 Proposal – Essentially Elastic R = 1

Negative concerns:

•Magnitude of Earthquake not refined enough

•No ductility required is unsafe, backward direction, • 40 yrs, URM ?

• A second method, different than current

•Uneconomical, impractical

•Not correlated to Collapse Probability

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Negatives:• Need to substantiate R values for all types of structures• Ignores the most basic tenets of seismic performance: ductility,

continuity and capacity based design (acknowledging overstrength).

• Our codes and standards have never allowed unrestricted trade-off between strength and inelastic deformabilty or ductility in seismic design, which starts with what is now SDC B. There has always been a minimum set of detailing requirements specified, dependent solely on the SDC.

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SIMPLIFICATION OF SEISMIC CODE

PROVISIONS

A WHITE PAPER Prepared under the BSSC Simplified Seismic Design Procedures

Development Program

William T. Holmes

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Reduce Material Detailing Requirements (to Achieve Ductility) with Use of Lower R Factors

The detailing requirements for systems with high R factors generally involve design checks to avoid

brittle limit states (e.g., tensile fracture of structural steel or compressive crushing of concrete) and to

avoid focusing the inelastic demand in a small portion of the system (e.g., the “strong-column, weak-

beam” rule for special moment frames). Many of these detailing rules are rooted in the concept of

“capacity design,” in which the structure is constrained by design to perform in certain desirable

manners. These detailing requirements can be very time consuming in engineering practice.

The NEHRP Provisions and ASCE/SEI 7-10 are written to exclude the most brittle systems, generally

those with the lower R factors, from use on the higher seismic design categories, generally in locations

with the potential for very large seismic ground motions. In some cases, the restrictions apply primarily

to tall structures whereas in others, the restrictions apply to all heights. Suggestions to relax these

restrictions by requiring higher loading (smaller R factors) have been made in the past. Since the design

procedures include a reduction in the MCE ground motion as a part of the basic equation for an

equivalent design force, even an R of 1.0 implies acceptable structural performance beyond the design

loading assumptions. Some individuals cognizant of this fact suggest a value of R equal to 2/3 as a safe

alternative. Given that the ground motions to be considered exhibit a significant variability in key

parameters and that the capacity of a structure is not known with certainty, a probabilistic approach is

probably needed when considering these marginal cases. The methodology of FEMA P-695 would

provide guidance in this regard, but the amount of work required to perform these analyses

systematically for a wide category of structural systems would be overwhelming. Therefore, this option

was not selected for consideration in this study.

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R = 1 Status:

• Limited Scope Proposal nearly passed ASCE 7-16• SDC B, C; Regular, 3 story max

• The proposal is currently shelved• Could be used as a design guide – meets Code• Grass roots demand could bring it forward

• Needs justification of R values

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Conclusions:

• R = 3, 1.5 and 1 are allowed in certain areas and with heavy restrictions.

• SDC B, C => R = 3 for steel is the norm.

• Nonbuilding Industrial structures benefit from R = 1 MF, 1.5 BF.

• Use judgement for each configuration and proportioning; and consider vulnerability to an overload.• Collapse, redundancy, robustness/utilization

Introduction to Seismic Design Low Seismic

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byThomas F. Heausler, PE, SEStructural Engineer

Agenda

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• Complete seismic load analysis of a simple building – Small Building

• Low Seismic Risk - Not optimized for Seismic

• Calculations as Flowchart

• Present the Underlying Theory

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Given: ASCE 7-10, AISC 340, ACI 318 [Note: ASCE 7-10 maps and Provisions are used, Accidental Torsion of ASCE 7-16 is described.]Location: Hardeeville, South CarolinaUse: Storage and office without partitions. See Section 4.3.2 and 12.7.2(2) for partition load requirements), Risk Category IIRoof dead load = 70 psfRoof Live Load = 20 psf, Ground and minimum Roof Snow Load = 20 psfSeismic Force Resisting System: Steel Braced FrameSoil Allowable Net Bearing Pressure = 2,000 psfMaterials: Concrete f’c = 4,000psi; Steel Shapes and Plates Grade 50; Welding E70 electrode, Bolts A325N, Snug tight.

Figure 1 Simple Building Perspective

Calculations:

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• W10 cols with double clip angles

– prying action

Seismic Design :Determine SS and S1:Site Class D default as per 11.4.2From ASCE Hazards Tool or USGS Website SS = 0.31, S1 = 0.130, SDS = 0.356, SD1 = 0.198 Verify that exemptions do not apply (11.1.2) and (11.4.1).

Exceptions: Low seismic , one and two family dwellingsSeismic Design Category A

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Calculations:

Seismic Design Category A

• [11.4.1] [11.7] [1.4]• Don’t Use Chapter 12• [1.4] General Structural Integrity • 1% W, 5% beam connections, 20% wall

connections• Non-Structural Components Exempt

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F = ma

Base Shear - V

F = maSDS, SD1 ?

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Ground Motion

SMS = FaSS (11.4-1)SM1 = FvS1 (11.4-2)

SDS = 2/3 SMS (11.4-3)

SD1= 2/3 SM1 (11.4-4)

SDS = 2/3 FaSS

SD1 = 2/3 FvS1

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F = ma• Rock accelerates during an earthquake

• Soft soil above rock amplifies the acceleration

• Building amplifies that acceleration from its base to roof

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Ground Acceleration

Ground Acceleration measured during an earthquake

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Site Class, Fa, Fv

• Rock displaces during earthquake

• A peak acceleration may be measured

• Soft soil above rock amplifies acceleration – Fa, Fv

• Resulting in the ground motion at your site

- at base of building

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Amplification Due to Soil

SMS = FaSS (11.4-1)

SM1 = FvS1 (11.4-2)

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Amplified Forces - Clay and soft soil

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Amplified Forces - Clay and soft soil

Like runny whip cream on jelloon ceramic plate

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Liquefaction

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Building’s Response

to

Acceleration at base.

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Period of Vibration T

Ruler with Erasers

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Period T

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Period of Vibration T

Swing setPartitions dampen

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Building Response to Ground Motion

• Ground motion is amplified through the structure

• This is called “Response”

• Up to 2.5 times acceleration at ground

• Response is a function of mass and stiffness => Period, T

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Period T

How to calculate T

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Rayleigh Equation

Or Software Analysis – T…with limits

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e.g. Braced Frame, Wood Shearwall, etc.

Period T

Moment Frames

1 story T = 0.1 second5 story T = 0.5 seconds20 story T = 2 seconds

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22 Story Building – T=2 seconds

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Response of Building – ASCE 7 Maps

• 0.2 second Map

• 1.0 second Map

• Calibrate a Response Spectrum for your site

• Apply Period T to determine Response acceleration

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Map: ASCE 7-10 Chapter 22

Response Accelerations

San Francisco, CA

Ss = 1.50S1 = 0.67

PGA = 0.6

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Black line in margin indicates change from previous edition.

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SDS = 0.355SD1 = 0.198

PGA = 0.19

San Francisco, CASDS = 1.00SD1 = 0.67

PGA = 0.4

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Site CoefficientsFa

Fv

Seismic Design Category “C”

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New ASCE 7 Hazard ToolASCE 7-10, ASCE 7-16

Spectral Response Acceleration

SDS = 2/3 SMS (11.4-3)

SD1 = 2/3 SM1 (11.4-4)

2/3?

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2/3

• “2/3”

converts from

• Maximum Considered Earthquake (Collapse Prevention)

To

• Design Earthquake (Life Safety)

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Gro

un

d M

oti

on

The Big One

Minor EQ

Expected Performance

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Ground Motion

SMS = FaSS (11.4-1)SM1 = FvS1 (11.4-2)

SDS = 2/3 SMS (11.4-3)

SD1= 2/3 SM1 (11.4-4)

SDS = 2/3 FaSS

SD1 = 2/3 FvS1

SDS and SM1 are now calibrated for site Now use Period T, to determine Base Shear for our Building

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Base Shear - V

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Figure 11.4-1 Design Response Spectrum

SDS = 1.0

PGA = 0.4

San Francisco

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What is a Response Spectrum?

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Figure 11.4-1 Design Response Spectrum

1-Story 5-Story 10-Story 20-StorySolidBlock of Concrete

80-Story

PGA = 0.4

SDS = 1.0

San Francisco

• Spectrum• Response• Design Level

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Figure 11.4-1 Design Response Spectrum

SDS = 1.0

PGA = 0.4

San Francisco

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Create a Response Spectrum

Ground Acceleration measured during an earthquake

Sometime during the duration, a building will have a maximum response

could be here

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Creating a Response Spectrum

• One SDOF system is subjected to time history of earthquake ground acceleration record.

• The SDOF model responds to ground acceleration.

• Sometime during the earthquake a peak acceleration response is measured for that SDOF

• Not necessarily at same time as peak ground acceleration

• Analysis is repeated for various different SDOF models completing a spectrum of results

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Response Spectrum

Period

(seconds)1 Story CMU

1 Story Moment Frame

2 Story Building20 story Building

10 Story Building

Res

po

nse

Acc

eler

atio

n

Resonance to Rhythmic Forcing Function

SDS

SD1/T

Earthquake 1

Earthquake 2

Earthquake 3

Ruler with Erasers:• Short Period• Resonance• Long Period

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Response Spectrum

Calibrate this graph to your specific site

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F = ma

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Base Shear - V

We now know SDS and SD1

and T.

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Exception!

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Base Shear - V

What is R and Ie ?

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R – Response Modification Factor

Now we know the building’s response due to:

• Acceleration of Rock at our site

• Soil amplification

• Building Period, T (i.e. m,k) – Amplification/Response

• Now we modify it further – Ductility - R

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Table 12.2-1SCBF R = 6, Omega Ωo = 2, Cd = 5SMF R = 8, Omega Ωo = 3, Cd = 5.5Steel Systems Not Specifically Detailed for Seismic, R = 3, Omega Ωo = 3, Cd = 3

Each R value has strings attached.

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R, Omega Ωo, Cd

• Not like Wind

• “R” is measure of effective ductility of system

• Ductility is range between yield and fracture

• R is composed of two components: • Omega Ωo : Overstrength

• Rd: inelastic behavior/energy dissipation

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Wind

Seismic

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R, Omega Ωo, Cd

• Overstrength Omega Ωo : • Material overstrength

• Phi

• Conservative overdesign, min ratios, drift driven

•Rd, Inelastic Behavior: • Level of inelastic response capability

• Bend not break

• Period lengthens, energy dissipation/damping

• Observed System Performance

• Possibility of vertical load system failure

• Redundancy (rho) and Backup frames

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R, Omega Ωo, Cd

• See NEHRP FEMA 450-2/2003 pages 36 – 41

• Special detailing required to insure inelastic performance

• Omega is overstrength factor (e.g. collectors, connections, columns)

• Cd converts elastic analysis deflection to inelastic/actual

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Overstrength

Ductility

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Further Modifiers

Ieoffice

SDCC

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Further Modifiers

Ie

SDCC

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Importance Factor

• [11.5.1] [Table 1.5-2] [Table 1.5-1] and

• [IBC Table 1604.5] • Risk Category • Hazard, Essential, • e.g. 300 people, storage Ie= 1.0, 1.25, 1.5 Ip = 1.0, 1.5 [13.1.3] Life Safety,

Essential, Hazardous

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Importance factor, Seismic Design Category

• “Ie” Importance Factor

• A method to increase safety by reducing ductility demand

• (R/Ie)

• “SDC” Seismic Design Category triggers provisions, restrictions and detailing

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Base Shear - V

Now we have our base shear quantified

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Calculations:Determine Analysis Procedure Allowed:

See (12.6) and (Table 12.6-1).

Check 12.14 Simplified method (OK, but not used in this example).

Period (12.8.2.1): Ta = CT hnx ; CT = 0.02, x = 0.75; hn = 14’; Ta = 0.14

seconds

T = Ta (12.8.2 last sentence); T = 0.14 seconds; TS = SDS/SD 1 =

0.198/0.356 = 0.55 seconds

TL = 8 seconds (Figure 22-14)

Check for Irregularities (12.3):

Horizontal (Tables 12.3-1) = None (See accidental Torsion check below).

Vertical (Table 12.3-2) = None

Check T < 3.5TS; 0.14 seconds < (3.5) 0.55 seconds; OK (Table 12.6-1).

Therefore the Equivalent Lateral Force Procedure may be used and it is

not necessary to use Modal Response Spectrum method nor Seismic

Response History procedure.

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NP = includes Horz Irregularity 1a, 1b, Vert Irregularity 1a, 1b, 2, 3

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Calculations:

Determine Response Modification Factor, R:

As per Tables 11.6-1 and 11.6-2 Seismic Design Category (SDC) = C

Seismic Force Resisting System: Braced Frame as per Table 12.2-1 H.

Steel Systems Not Specifically Detailed for Seismic Resistance: R = 3,

ΩO = 3, Cd = 3,

Detailing required as per (14.1), and (14.1.2.2.1 Exception): Use AISC

360 (need not detail as per AISC 341 Seismic).

Determine Seismic Importance factor, Ie:

See (11.5.1) and Table 1.5-2. Risk Category II, Ie = 1.0

Effective Seismic Weight -W

• [12.7.2] Dead Load• No Live Load except:o 25% of Storageo Partitions 10 psf [4.3.2]o Industrial Operating Weight – Unbalancedo 20% of snow > 30psfo Roof Gardens

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Calculations:Determine Base Shear:

Effective Seismic Weight (12.7.2)

Roof = 70psf dead load (20’x20’) = 28.0k

Walls = Height tributary to roof = 14’/2 = 7’; Perimeter of building = 80’;

Wall weight = 10psf (7’x80’) = 5.6k

W= Effective Seismic Weight = 28.0k + 5.6k = 33.6k

Seismic Base Shear: V = CsW (Eq. 12.8.1)

CS = SDS/(R/Ie) = 0.356/(3/1.0) = 0.1187 (Eq. 12.8-2)

CS = SD1/(T(R/Ie)) = 0.198/(0.14 (3/1.0)) = 0.471 need not exceed (Eq. 12.8.3)

CS = 0.044 SDS Ie = 0.044(0.356)(1.0) = 0.0157 minimum (Eq. 12.8-5)

CS = 0.01 (Eq. 12.8-5) minimum

CS = 0.1187 governs

V = CSW = 0.1187(33.6k) = 4.0k

V = 4.0 kips

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Calculations:

Vertical Distribution of force (12.8.3) and Diaphragm forces

(12.10.1.1) yield same results for a one story structure: 100% of

base shear V is distributed to roof; and this applies to

diaphragm calculations as well as vertical bracing calculations.

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Accidental Torsion:

• Required for non-flexible diaphragms only

• ASCE 7-16 has a significant change from ASCE 7-10 for

accidental torsion requirements.

• For many buildings, accidental torsion forces are now only

applied to verify if a horizontal torsional irregularity exists.

If it does not exist, then the earthquake forces may be

calculated without accidental torsion.

• See Section 12.8.4.2 for specifics.

For this building, earthquake and accidental torsion forces are

applied and the displacements at each corner are calculated.

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Calculations:

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As per Table 12.3-1, torsional irregularity check, the following formula may

be created.

Torsional irregularity exists if drift at ends of building are as follows:

Δ1 max > 1.2 (Δ1 max + Δ1 min)/2

0.015” < 1.2 (0.015+0.013)/2 = 0.0168” OK – No torsional irregularity

exists.

Note that since this is a relative displacement check, it does not matter if

drift is calculated at the elastic or inelastic level.

Since no torsional irregularity exists, then as per Section 12.8.4.2, third

paragraph, accidental torsion moments need not be included when

determining the seismic forces E in the design of the structure and in

determination of the design story drifts. The applied loads, drift and

reactions may be calculated as shown in Figure 4b.

Calculations:

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Calculations:

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Calculations:

Load Combinations:

See (12.4), (2.3.6); and (12.4.3) when ΩO overstrength factor is

specifically required.

Redundancy (12.3.4.1) ρ = 1.0 in SDC C.

Horizontal Seismic Load Effect (12.4.2.1) Eh = ρQE = 1.0QE = QE

Vertical Seismic Load Effect (12.4.2.2) Ev = 0.2SDS = 0.2(0.356) =

0.0712

Orthogonal Effects (12.5.3) 100% - 30% corner columns: SDC C

not required.

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Calculations:

Check Drift:

From elastic computer analysis, maximum roof displacement measured at the

center of rigidity (excluding accidental torsion) is 0.014 inches. As per (12.8.6):

δxe = 0.014”

δx = Cd(δxe)/Ie = 3.0(0.014”)/1.0 = 0.042”

Drift = Δ1 = δx = 0.042”

P-delta Effects as per (12.8.7) are inconsequential by inspection.

Allowable Drift (12.12) Table 12.12-1 Δa = 0.020hsx = 0.020(14’)(12”/’) = 3.36”

0.042” < 3.36” therefore OK.

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Member and Connection

Checks:

• Figure 5a and 5b display

roof framing plan forces with

and without accidental

torsion respectively.

• Figure 6 displays elevation

view forces without

accidental torsion.

The following checks will use

the forces without accidental

torsion for the reasons

mentioned above.

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Calculations:

Diaphragm Forces

Not simultaneous with Base Shear Forces, not additive

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Calculations:Diaphragm:

Diaphragm forces are outlined in Section 12.10.1.1.

wpx = 33.6 k

Fpx = [4.0k/(33.6k)] 33.6k = 4.0 k

(Eq. 12.10-1)

Fpx min = 0.2SDSIewpx = 0.2(0.356)(1.0)33.6k = 2.4 k min

(Eq. 12.10-2)

Fpx max = 0.4SDSIewpx = 0.4(0.356)(1.0)33.6k = 4.8 k max

(Eq. 12.10-3)

The diagram forces from equation Eq. 12.10-1 need not exceed Eq. 12.10-3, however,

Section 12.10.1.1 states that “Floor and roof diaphragms shall be designed to resist

design forces from structural analysis, but shall not be less than Eq. 12.10-1.” This

infers that the diaphragm forces shall not be less than those caused by the Base Shear,

V, Fx forces of Section 12.8, including accidental torsion Mta when applicable.

Thus: v = diaphragm shear = 2.0k/(20’) = 0.10 k/’ See Figure 5b.

Check concrete slab thickness and connection of diaphragm to collector beams for

this ultimate strength level force.

Omega Ωo Triggers

• [12.4 Load Combinations with Omega zero] • [12.2.5.2 Cantilever Columns] SDC B,C,D,E,F

• [12.10.2.1 Collectors – Light Frame, Wood excepted] SDC C,D,E,F

• [12.3.3.3 Columns, Beams Supporting Discontinuous Walls] SDC B,C,D,E,F

• [12.13.6.5 Pile Anchorage] SDC D,E,F

• [AISC where R>3, ACI 318-11Chapter 21, Appendix D, Etc.] SDC B,C,D,E,F

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Calculations:Collector:

Collector force requirements are outlined in Section 12.10.2.1. In

essence this section requires that collectors be designed for the

maximum of the following (paraphrasing):

1. Forces Fx in diaphragm due to Base Shear V, including accidental

torsion Mta, and including ΩO, but excluding redundancy ρ (12.3.4.1(5))

i.e. ρ = 1.0.

2. Forces Fpx in diaphragm due to Eq. 12.10-1 excluding accidental

torsion Mta, including ΩO, and excluding redundancy ρ.

3. Forces Fpx max from Eq. 12.10-2 excluding accidental torsion Mta,

excluding ΩO, but including redundancy ρ.

For this example however, accidental torsion Mta need not be included

in the above determination for collectors (Section 12.8.4.2 third

paragraph).

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Calculations:W12x26: Item 1 above governs thus:

v = diaphragm shear (including accidental torsion) = 0.10 k/’

T = tension (or compression force) = 0.10k/’(10’) = 1.0 kips axial load in beam.

Dead load = 1.75 k down

Live load = 0.50 k down

Check beam end connection for the following ultimate strength level loads as per

Section 2.3.6 (6)):

1.2D + Ev+ Eh + 1.0L + 0.2S (eqn. 2.3.6 (6))

Which as per eqn. 12.4-4a and eqn. 12.4-3 evolves to:

(1.2 + 0.2SDS)D + ρQE + 1.0L + 0.2S

and as per 12.10.2.1 SDC C use load combinations with overstrength as per 2.3.6(6):

1.2D + Ev+ Emh + 1.0L + 0.2S (eqn. 2.3.6 (6) with

overstrength)

Which as per eqn. 12.4-4a and eqn. 12.4-7 evolves to:

(1.2 + 0.2SDS)D + ΩOQE + 1.0L + 0.2S (note that r is not included)

(1.2+0.2(0.356))1.75k + 1.0(0.5k) = 2.72k vertical shear on connection

ΩOQE = 3.0(1.0k) = 3.0 kips axial/horizontal load on connection

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Collector, Continued:

Compare 2.72k vertical and 3.0 k axial to capacity of (3) 3/4”

diameter A325 N Bolts as per AISC ϕrn = 17.9 kips per bolt and

verify that all other limit states within connection do not govern.

Note that although this is a Seismic Design Category (SDC) = C,

and R = 3 was used, ASCE 7 Section 12.10.2.1 requires use of ΩO

for collectors, independent of AISC requirements.

Calculations:

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Brace:

E = 3.4 kips

Capacity of brace L = 17’ (approx./conservative)

From AISC Tables L= 17’, ϕcPn = 56.1 kips

3.4 kips < 56.1 kips therefore OK

See Figure 7.

Brace Connection:

E = 3.4 kips

Capacity of 1/4” fillet weld as per AISC ϕRn = 0.8(0.6)70ksi (0.707)(0.25”) = 5.56

kips/”.

Compare E = 3.4k to weld capacity and check other limit states within the connection

(e.g. gusset plate).

Note that this is a Braced Frame as per Table 12.2-1 H. Steel Systems Not Specifically

Detailed for Seismic Resistance, SDC C, and R = 3. AISC 360 is used and we need not

detail as per AISC 341 Seismic. Therefore, brace connections need not be designed for

ΩO, nor full strength of the brace, as would be required in AISC 341 and SDC D, E, and

F for higher R factor systems.

Calculations:

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Calculations:Column:

Axial Loads Dead Load = 7.0k; Live Load = 2.0 kips; E = 2.8 k

Orthogonal Effects (12.5.3) does not apply (SDC C – parallel system)

Section 2.3.6 (6)):

1.2D + Ev+ Eh + 1.0L + 0.2S

Which as per eqn. 12.4-4a and eqn. 12.4-3 evolves to:

(1.2 + 0.2SDS)D + ρQE + 1.0L + 0.2S

Pu = (1.2 + 0.2(0.356))D + 1.0E + 1.0L + 0.2S

Pu = 1.27(7.0k) + 1.0(2.8) + 1.0(2.0) + 0.2(0.0)

Pu = 13.7 k

As per AISC Tables L = 14’; W10x33 col; ϕcPn = 248 kips

13.7k < 248k therefore OK.

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Calculations:Column Base Connection:

Uplift case governs by inspection

Horizontal Shear = 2.0 k

Dead Load = 2.4 kips

Seismic = 2.8 kips

Section 2.3.6 (7)):

0.9D – Ev + Eh (eqn. 2.3.6 (7))

Which as per eqn. 12.4-4a and eqn. 12.4-3 evolves to:

(0.9 – 0.2SDS)D + ρQE

Tu = (0.9-0.2(0.356))D - 1.0E

Tu = (0.829)2.4k - 1.0(2.8k)

Tu = 0.82 kip net uplift

Vu = 2.0 kip horizontal shear

Compare to anchor bolt ultimate capacities for combined tension and shear

(See AISC Design Guide Number 1). See Figure 8.

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Calculations:

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Calculations:

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Calculations:Footing Loads:

Uplift: Verify weight of footing multiplied by 0.9 exceeds Tu = 0.89 kips.

Tprovided = Footing weight x (0.9) = 0.9(0.150kcf)(3’x3’x2’) = 2.4kips

0.89k < 2.4k therefore no net uplift, OK

Bearing Pressure:

New to ASCE 7-16, there is no need to include Ev in bearing pressure calculations. See

Section 12.4.2.2 for specifics.

Allowable Net Bearing Pressure = 2000 psf.

Dead Load = 7.0 kips

Live Load = 2.0 kips

Seismic = 2.8 kips

Convert Seismic load to Allowable strength level by multiplying by 0.7 as permitted by

Allowable Stress Design Load Combinations Section 2.4.5(8) and (9).

1.0D + 0.7Ev+0.7Eh (eqn. 2.4.5(8))

Which as per 12.4.2.2 Exception 2, eqn. 12.4-4a and eqn. 12.4-3 evolves to:

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Calculations:1.0D + 0.7ρQE

P = (1.0D + 0.7(1.0)E

P = (1.0(7.0k)) + 0.7(1.0)2.8k

P = 9.0 kips

And

1.0D + 0.525Ev + 0.525Eh + 0.75L + 0.75S (eqn. 2.4.5(9))

Which as per 12.4.2.2 Exception 2, eqn. 12.4-4a and eqn. 12.4-3 evolves to:

1.0D + 0.525ρQe + 0.75L + 0.75S

P = 1.0D + 0.525(1.0)E + 0.75L + 0.75S

P = (1.0(7.0k)) + 0.525(1.0)2.8k + 0.75(2.0) + 0.75(0.0)

P = 9.97 kips

P = 9.97 kips governs maximum downward ASD Force on footing.

fbrg = applied bearing pressure = 9.97k/(3’x3’) = 1.108 psf

1,108 psf < 2,000psf therefore 3’ x 3’ Footing is OK

Note that a reduction of applied bearing pressure could be implemented as per (12.13.4),

but was not used in this example.

2019 Structural Engineering Summit – Anaheim

Questions?

Thomas F. Heausler, PE, SE

(913) 963-1180

[email protected]

2019 Structural Engineering Summit – Anaheim

Questions? DiscussionElaboration

Thomas F. Heausler, PE, SE

(913) 963-1180

[email protected]

2019 Structural Engineering Summit – Anaheim

Questions? DiscussionElaboration

I have a friend who...

Thomas F. Heausler, PE, SE

(913) 963-1180

[email protected]


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