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Dislocations and their dynamics
How are strength and dislocation motion related?
How do we increase strength?
How can heating change strength and other properties?
TOPIC 7:DISLOCATIONS AND
STRENGTHENING
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EDGE DISLOCATION
Extra half plane of atoms
Edge dislocation line: Directed into the page
Atoms above dislocation line are in compression, and
those below are in tension
Symbol
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SCREW DISLOCATION
Symbol
AB is screwdislocation line
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Incrementally breaking bonds
If dislocations don't move, deformation doesn't happen!
(But fracture will, like in a ceramic)
DISLOCATION MOTION
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Metals: Disl. motion easier.
-non-directional bonding
-close-packed directions
for slip. electron cloud ion cores
Covalent Ceramics(Si, diamond): Motion hard.
-directional (angular) bonding
Ionic Ceramics (NaCl):
Motion hard.-need to avoid ++ and --
neighbors.
DISLOCATIONS & MATERIALS
CLASSES
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DISLOCATION DENSITY
Dislocation density: total dislocation length per unitvolume of material
or, the number of dislocations that intersect a unitarea of a random section
The dislocation density typically determines thestrength of a material
Metals (carefully solidified): 103 mm-2
Metals (heavily deformed): 109-1010 mm-2
Metals (heat treated): 105-106 mm-2 Ceramics: 102-104 mm-2
Single crystal silicon for ICs: 0.1-1 mm-2
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LOCAL STRAIN FIELDS
Edge dislocation: compression (above dislocation
line) & tension (below dislocation line)
Screw dislocation: shear
Stress & strain fields decrease with radial
distance from dislocation line
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DISLOCATION INTERACTION
Strain field from one dislocation can affect aneighboring dislocation
Two like dislocations can repel each other
Unlike dislocations attract and annihilate each other
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SLIP SYSTEMS
Dislocations do not move with the same degree ofease on all crystallographic planes and directions
There are preferred planes (slip planes) and
preferred directions (slip directions)
Slip planes are planes with high planar density ofatoms, and slip directions are lines with high lineardensity
Slip system: the combination of slip plane and slipdirection
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SLIP SYSTEM: EXAMPLES
FCC (Al, Cu, Ni, Ag, Au) Close packed planes: {111}, e.g., ADF
Close packed directions: , e.g., AD, DF, AF
Slip system: {111} (12 independent slip systems)
BCC (Fe, W, Mo): {110} (12 independent slipsystems)
HCP (Zn, Cd, Mg, Ti, Be): 3 independent slip systems
FCC & BCC metals: ductile, HCP metals: brittle
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SLIP IN SINGLE CRYSTALS Single crystals easy to treat; can generalize to polycrystals later
Regardless of what type of external stress is applied to amaterial, plastic deformation or dislocation motion occurs due toa shear stress
Some component of the applied stress has to be a shear stresson a slip plane and along a slip direction
This component is called the resolved shear stress
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coscos
cos/
cos
A
F
R
ns
A
As
RESOLVED SHEAR STRESS
slip plane
normal, ns
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Condition for dislocation motion: R CRSS Crystal orientation can make it easy or hard to move disl.
R cos cos
CRITICAL RESOLVED SHEAR
STRESS (CRSS)
Maximum possible R = /2; thus y = 2CRSS
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BCC EXAMPLE
Slip system: {110}
= 45 degrees = tan-1(a2/a) = 54.7 degrees
From which or can be calculated if one ofthem is specified
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Slip planes & directions (, )
change from one crystal toanother.
Rwill vary from one crystal toanother.
The crystal with the largest Ryields first.
Other (less favorably
oriented) crystals yield later.
Polycrystalline materialsgenerally stronger than single
crystals, due to geometric
constraints & the requirement of
larger stresses for yielding
Adapted from Fig.
7.10, Callister 6e.
(Fig. 7.10 is
courtesy of C.
Brady, NationalBureau of
Standards [now the
National Institute of
Standards and
Technology,
Gaithersburg, MD].)
300 mm
DISL. MOTION IN POLYCRYSTALS
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STRENGTHENING MECHANISMS
Macroscopic plastic deformation corresponds to themotion of large numbers of dislocations The ability of a metal to plastically deform depends on the
ability of dislocations to move
Virtually all strengthening techniques rely onrestricting or hindering dislocation motion
We will look at 4 such mechanisms Reduce grain size
Solid-solution strengthening
Precipitation strengthening
Strain hardening (or cold working)
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Grain boundaries arebarriers to slip.
- dislocation has to change
directions
- grain boundary regiondisordered, so discontinuity inslip planes
Barrier "strength
increases with
misorientation.
Smaller grain size: morebarriers to slip.
Hall-Petch Equation:
grain
bounda
ry
slip plane
grain AgrainB
yield o kyd1/ 2
Adapted from Fig. 7.12, Callister 6e.
(Fig. 7.12 is fromA Textbook of Materials
Technology, by Van Vlack, Pearson Education,
Inc., Upper Saddle River, NJ.)
STRENGTHENING STRATEGY 1:
REDUCE GRAIN SIZE
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70wt%Cu-30wt%Zn brass alloy
yield
o
kyd1/ 2
Adapted from Fig. 7.13,
Callister 6e.
(Fig. 7.13 is adapted from
H. Suzuki, "The Relation
Between the Structure
and Mechanical Properties
of Metals", Vol. II, National
Physical Laboratory
Symposium No. 15, 1963,
p. 524.)
GRAIN SIZE STRENGTHENING:
AN EXAMPLE
Grain size controlled by heat treatment (e.g., cooling rateduring solidification, annealing)
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Can be induced by rolling a polycrystalline metal
-before rolling -after rolling
235 mm
-isotropicsince grains areapprox. spherical
& randomly
oriented.
-anisotropicsince rolling affects grainorientation and shape.
rolling direction
Adapted from Fig. 7.11,
Callister 6e. (Fig. 7.11 is from
W.G. Moffatt, G.W. Pearsall,
and J. Wulff, The Structure
and Properties of Materials,
Vol. I, Structure, p. 140, John
Wiley and Sons, New York,1964.)
ANISOTROPY IN yield
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Impurity atoms distort the lattice & generate stress.
Stress can produce a barrier to dislocation motion.
Smaller substitutional
impurity
Larger substitutional
impurity
Impurity generates local shear atA
and B that opposes disl motion to the
right.
Impurity generates local shear at C
and D that opposes disl motion to the
right.
STRENGTHENING STRATEGY 2:SOLID SOLUTION STRENGTHENING
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SOLID SOLUTION STRENGTHENING
Impurity atoms attracted to dislocations so as to
reduce the overall strain energy, i.e., to partiallycancel the strain in the lattice surrounding thedislocation
If a dislocation wants to move, it has to tear itselffrom the impurity atoms which will cost energy
Smaller impurity atom
above dislocation line
Larger impurity atom
below dislocation line
EXAMPLE SOLID SOLUTION
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EXAMPLE: SOLID SOLUTION
STRENGTHENING IN COPPER
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Hard precipitates are difficult to shear.Ex: Ceramics in metals (SiC in Iron or Aluminum).
Result: y ~1
S
STRENGTHENING STRATEGY 3:PRECIPITATION STRENGTHENING
SIMULATION
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View onto slip plane of Nimonic PE16 Precipitate volume fraction: 10%
Simulation courtesy of Volker
Mohles, Institut fr Materialphysik
der Universitt, Mnster, Germany
(http://www.uni-munster.de/physik
/MP/mohles/). Used with
permission.
SIMULATION:
PRECIPITATION STRENGTHENING
APPLICATION
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Internal wing structure on Boeing 767
Aluminum is strengthened with precipitates formed
by alloying.
Adapted from Fig.
11.24, Callister 6e.
(Fig. 11.24 is courtesyof G.H. Narayanan
and A.G. Miller,
Boeing Commercial
Airplane Company.)
Adapted from Fig.
11.0, Callister 5e.
(Fig. 11.0 is courtesy
of G.H. Narayanan
and A.G. Miller,
Boeing Commercial
Airplane Company.)
1.5mm
APPLICATION:
PRECIPITATION STRENGTHENING
STRENGTHENING STRATEGY 4
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Room temperature deformation. Common forming operations change the cross sectional
area:
%CW Ao Ad
Ao
x100
Ao Ad
force
dieblank
force
-Forging -Rolling
-Extrusion-Drawing
Adapted from Fig.
11.7, Callister 6e.
tensile
forceAo
Addie
die
STRENGTHENING STRATEGY 4:
COLD WORK (%CW)
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Ti alloy after cold working:
Dislocations entangle
with one anotherduring cold work.
Dislocation motion
becomes more difficult.
Adapted from Fig.
4.6, Callister 6e.(Fig. 4.6 is courtesy
of M.R. Plichta,
Michigan
Technological
University.)
DISLOCATIONS DURING COLD WORK
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Dislocation density (rd) goes up:
Carefully prepared sample: rd ~ 103 mm/mm3Heavily deformed sample: rd ~ 1010 mm/mm3
Ways of measuring dislocation density:
OR
dN
A
Area , A
N dislocation
pits (revealed
by etching)
dislocation
pit
r
Yield stress increasesas rd increases:
Micrograph
adapted from Fig.
7.0, Callister 6e.
(Fig. 7.0 is
courtesy of W.G.
Johnson, General
Electric Co.)
40mm
RESULT OF COLD WORK
SIMULATION DISLOCATION
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Tensile loading (horizontal dir.) of a FCC metal with
notches in the top and bottom surface.
Over 1 billion atoms modeled in 3D block.
Note the large increase in disl. density.
SIMULATION: DISLOCATION
MOTION/GENERATION
Simulation courtesy
of Farid Abraham. Used withpermission from International
Business Machines Corporation.
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Dislocations generate stress.
This traps other dislocations.
DISLOCATION-DISLOCATION TRAPPING
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Yield strength increases.
Tensile strength (TS) increases. Ductility (%EL or %AR) decreases (dramatically).
Adapted from Fig. 7.18,
Callister 6e. (Fig. 7.18 is
from Metals Handbook:
Properties and Selection:
Iron and Steels, Vol. 1, 9th
ed., B. Bardes (Ed.),
American Society for Metals,
1978, p. 221.)
IMPACT OF COLD WORK
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What is the tensile strength &
ductility after cold working?
Adapted from Fig. 7.17, Callister 6e. (Fig. 7.17 is adapted from Metals Handbook: Properties and Selection:
Iron and Steels, Vol. 1, 9th ed., B. Bardes (Ed.), American Society for Metals, 1978, p. 226; and Metals
Handbook: Properties and Selection: Nonferrous Alloys and Pure Metals, Vol. 2, 9th ed., H. Baker
(Managing Ed.), American Society for Metals, 1979, p. 276 and 327.)
%CW ro2 rd2
ro2x100 35.6%
COLD WORK ANALYSIS
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Results for
polycrystalline iron:
y and TS decrease with increasing test temperature. %EL increases with increasing test temperature.
Why?
Adapted from Fig. 6.14,
Callister 6e.
-e BEHAVIOR VS TEMPERTURE
Vacancies helpdislocations past
obstacles.
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1 hour treatment at Tanneal...
decreases TS and increases %EL. Effects of cold work are reversed!
3 Annealingstages to
discuss...
Adapted from Fig. 7.20, Callister 6e. (Fig.
7.20 is adapted from G. Sachs and K.R. van
Horn, Practical Metallurgy, Applied Metallurgy,
and the Industrial Processing of Ferrous and
Nonferrous Metals and Alloys, American
Society for Metals, 1940, p. 139.)
EFFECT OF HEATING AFTER %CW
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Annihilation reduces dislocation density.
Scenario 1
Scenario 2
RECOVERY
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New crystals are formed that:
--have a small disl. density--are small
--consume cold-worked crystals.
33% cold
worked
brass
New crystals
nucleate after
3 sec. at 580C.
Adapted from
Fig. 7.19 (a),(b),
Callister 6e.
(Fig. 7.19 (a),(b)
are courtesy of
J.E. Burke,
General Electric
Company.)
0.6 mm 0.6 mm
RECRYSTALLIZATION
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All cold-worked crystals are consumed.
After 4
seconds
After 8
seconds
Adapted fromFig. 7.19 (c),(d),
Callister 6e.
(Fig. 7.19 (c),(d)
are courtesy of
J.E. Burke,
General Electric
Company.)
0.6 mm0.6 mm
FURTHER RECRYSTALLIZATION
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At longer times, larger grains consume smaller ones. Why? Grain boundary area (and therefore energy) is reduced.
Empirical Relation:
After 8 s,
580C
After 15 min,
580C
dn don
Ktelapsed time
coefficient dependent
on material and T.
grain diam.
at time t.
exponent typ. ~ 2
0.6 mm 0.6 mm
Adapted from
Fig. 7.19 (d),(e),
Callister 6e.
(Fig. 7.19 (d),(e)are courtesy of
J.E. Burke,
General Electric
Company.)
GRAIN GROWTH
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Dislocations motion correlates to plastic deformation.
Strength is increased by making dislocation motion difficult.
Particular ways to increase strength are to:--decrease grain size
--solid solution strengthening
--precipitate strengthening
--cold work
Heating (annealing) can reduce dislocation densityand increase grain size.
SUMMARY