Topic Slides Minutes1 Displacement 9 27

2 13 393 Kinematics 13 39

4 Graphs 10 30

5 Energy 10 30

6 Power 5 15

7 Springs 4 12

8 Shadows 3 9

9 Field of Vision 7 21

10 Colors 3 9

11 Concave mirrors 7 21

12 Convex mirrors 4 12

13 Refraction 5 15

14 Lenses 10 30

15 Optical Power 6 18

Vectors

The word “component” means a “part” of a system.

When dealing with vectors, the word “components” refersto the vector parts that “add up” or constitute a vector.

Note well that while any vector may have many componentvectors, there are two “special” vectors that that when addedtogether result in the given vector.

Horizontal Component The horizontal component of a givenvector is that part which acts along the horizontal axis (x-axis).

Vertical Component The vertical component of a given vectoris that part which acts along the vertical axis (y-axis).

Click

FH FH

FV FV

Click

Together, the horizontal and vertical components make up a vector.

Vector

Vert

ical axis

Horizontal axis

Vertical component

Horizontal component

Vector = Horizontal component + Vertical component

REMEMBERREMEMBER

All vectors can beAll vectors can berepresented by theirrepresented by their

Horizontal and VerticalHorizontal and Verticalcomponents.components.

Remember

Next

“North” is “Up”

“South” is “Down”

“East” is “Right”

“West” is “Left”

N (Up)

S (Down)

E (Right)(Left) W

Calculate and sketch the horizontal and vertical componentsfor each of the given forces:

200 N [West]

FH = ____________________ FV = ____________________200 N [West] 0

N (or Up)

S (or Down)

E (or Right)W (or Left)

Vectors Slide: 2. 1

N

S

EW

Calculate and sketch the horizontal and vertical componentsfor each of the given forces:

500 N [North]

FH = ____________________ FV = ____________________0 500 N [North]

Vectors Slide: 2. 2

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

500 N [Southeast]

FH = ____________________ FV = ____________________354 N [East] 354 N [South]

FH = 500 N Cos 45o = 354 N

FV = 500 N Sin 45o = 354 N

REMINDER

Southeast means at 45o

between South and East.

NOTENOTE

Round off your answers toRound off your answers to the nearest whole number. the nearest whole number.

45o

Vectors Slide: 2. 3

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

400 N [25o from the horizontal]

FH = ____________________ FV = ____________________363 N [East] 169 N [North]

FH = 400 N Cos 25o = 363 N

FV = 400 N Sin 25o =169 N25o

400 N

Vectors Slide: 2. 4

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

290 N [S 60o E]

FH = ____________________ FV = ____________________251 N [East] 145 N [South]

This means “from the South , 60o East”

60o

FH = 290 N Sin 60o = 251 N

FV = 290 N Cos 60o = 145 N290 N

Vectors Slide: 2. 5

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

600 N [W 60o S]

FH = ____________________ FV = ____________________300 N [West] 520 N [South]

This means “from the West , 60o South”

FV = 600 N Sin 60o = 520 N

60o

FH = 600 N Cos 60o = 300 N

600

N

Vectors Slide: 2. 6

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

400 N [E 35o N]

FH = ____________________ FV = ____________________328 N [East] 229 N [North]

This means “from the East , 35o North”

35o

FH = 400 N Cos 35o = 328 N

FV = 400 N Sin 35o = 229 N 400 N

Vectors Slide: 2. 7

Click

Calculate and sketch the horizontal and vertical componentsfor the following force:

500 N [S 20o W]

FH = ____________________ FV = ____________________171 N [West] 470 N [South]

This means “from the South , 20o West”

20o

FH = 500 N Sin 20o = 171 N

FV = 500 N Cos 20o = 470 N

500 N

Vectors Slide: 2. 8

The diagram on the right illustrates fourforces acting on a cart that is free tomove in any direction.

Which of the following forces willplace the system in equilibrium?

A) 3.00 N at 0o from horizontal

B) 12.2 N at 180o from horizontal

C) 12.2 N at 0o from horizontal

D) 3.00 N at 180o from horizontal

E) 22.4 N at 0o from horizontal

FR180o

FE

Vectors Slide: 2. 9

Vectors Slide: 2. 10

An electron is subjected to a magnetic force of 2.6 x 10‑24 N actinghorizontally and an electric force of 3.0 x 10‑24 N acting vertically.

Determine the equilibrant force.

Vectors Slide: 2. 11

Click

An object is suspended by a cord which is 5.2 m long. As shownin the diagram, the horizontal force, F, is 75 N East. Calculatethe mass of the object.

A) 18 kg

B) 1.8 kg

C) 39 kg

D) 28 kg

E) 46.5 kg

FH = 75 N

A

First we find the angle

Click

11o

Click

11o

386 N

Next we find the weight

Click

Finally we find the mass

w

Click

Vectors Slide: 2. 12

When a weight is hung in the middle of a 20 m long wire,the wire sags 3 m. If the tension in the wire is 270 N,determine the weight.

A) 155 N

B) 102 N

C) 78 N

D) 48 N

E) 26 N

Click

Step-1 Draw all the forces acting on the system.

T = 270 N

w

T = 270 Nw/2w/2

Click

Step-2 Find the angle.

3 m10 m

Click

73.3o

73.3o

Step-3 Find the weight.

With reference to the shaded triangle:

Click

Vectors Slide: 2. 13

… and good luck!