of 20
8/7/2019 TPE4001A23CSE 101
1/20
8/7/2019 TPE4001A23CSE 101
2/20
ACKNOWLEDGEMENT
I take this opportunity to present my votes of thanksto all those guidepost who really acted as lighteningpillars to enlighten our way throughout this projectthat has led to successful and satisfactory completionof this study.We are really grateful to our teacher Mr. BalijepaliSivakiran for providing
us with an opportunity to undertake this project inthis university and providing us with all the facilities.We are highly thankful to him for his active support,valuable time and advice, whole-hearted guidance,sincere cooperation and pains-taking involvementduring the study and in completing the assignment ofpreparing the said project within the time stipulated.Lastly, We are thankful to all those, particularly the
various friends , who have been instrumental increating proper, healthy and conductive environmentand including new and fresh innovative ideas for usduring the project, their help, it would have beenextremely difficult for us to prepare the project in atime bound framework.
Name- Nikhil
Ladha
Regd. No- 11003993
Roll no. -RE4001A23
8/7/2019 TPE4001A23CSE 101
3/20
TABLE OF CONTENTS
Introduction
Proposed system
Description
System requirements
Requirement Analysis
System Design Source code
Future scope of project
References
8/7/2019 TPE4001A23CSE 101
4/20
INTRODUCTION
In the existing system, most of the records are maintained on paper. It becomes veryinconvenient to modify the data. In the existing system, here is a possibility that the same data
in different registers may have different values which means the entries of the same data do
not match. This inconsistent state does not supply the concrete information which poses a
problem in the case information related to particular search record.
Our project is very useful. User is no longer required to check his register in search of
records, as now it can be searched over the software by choosing some options. The user need
not to type in most of the information. He/she is just required to enter the desired options. On
the whole, it liberates the user from keeping lengthy manual records. In a nutshell, it abates
the work load of an organization.
In todays world, no one likes to perform calculations on calculator or manually when
computer is there. Everyone wants his/her work to be done by computer automatically and
displaying the result for further manipulations.
This term paper project is just an application of the language C in developing softwares.
This is the program for keeping records of the bank ,that is the entire details of the customer,
savings, how much money he/she can deposit and withdraw from the bank, to open the new
account, create a new account, display all account holders, balance enquiry etc.
8/7/2019 TPE4001A23CSE 101
5/20
PROPOSED SYSTEM
The following documentation is a project the BANKING . It is a detailed summary of allthe drawbacks of the old system and how the new proposed system overcomes these
shortcomings. The new system takes into account the various factors while designing a new
system. It keeps into the account the Economical bandwidth available for the new system.
The foremost thing that is taken care of is the Need and Requirements of the User.
DESCRIPTION
Before developing software we keep following things in mind that we can develop powerful
and quality software
PROBLEM STATEMENT
o Problem statement was to design a module:
o Which is user friendly
o Which will restrict the user from accessing other users data.
o Which will help user in viewing his data and privileges.
o Which will help the administrator to handle all the changes.
FUNCTIONS TO BE PROVIDED
The system will be user friendly and completely menu driven so that the users shall have no
problem in using all options.
o The system will be efficient and fast in response.
o The system will be customized according to needs.
o Create new account
o Search, edit and display customer details
o Display account holders
o Deposit money
o Withdraw money
o Balance enquiry
SYSTEM REQUIRMENTS
Operating system: MS Windows XP or Windows Vista
Language: C Language
Processor: Pentium IV Processor
RAM: 512 MB
Hard disk: 5 GB
8/7/2019 TPE4001A23CSE 101
6/20
REQUIREMENT ANALYSIS
This process is adopted when management of the system development, Personnel decide thatthe particular system needs improvement. The system development life cycle is the set of
activities, carried out by the analyst, designers and users to develop and implement a system.
The systems that are present in the nature follow common life cycle pattern. For example
consider the raining system. Initially the rain falls into the river, river flows into sea, the sea
water evaporates to form vapors, the vapors form clouds which again bring rain. Similarly
consider a man made system initially a system is analyzed, designed and made operational by
the efforts of system analysis. After successful operation or a number of users, the system
becomes less and less effective by change in the environment. So these changes have to be
incorporated in to the system by minor modifications. So the general activities from the life
cycle of the system are given below:
Selection and identification of the system to be studied
Preliminary study
Defining the system
Design and development of the system
Implementation of the system
8/7/2019 TPE4001A23CSE 101
7/20
SYSTEM DESIGN
Then we began with the design phase of the system. System design is a solution, a HOWTO approach to the creation of a new system. It translates system requirements into ways by
which they can be made operational. It is a translational from a user oriented document to a
document oriented programmers. For that, it provides the understanding and procedural
details necessary for the implementation. Here we use Flowchart to supplement the working
of the new system. The system thus made should be reliable, durable and above all should
have least possible maintenance costs. It should overcome all the drawbacks of the Old
existing system and most important of all meet the user requirements.
Welcome to the project on banking
Enter
your
choice
11?
Create account Customer details Deposit withdraw
Do you want to
continue?
START
STOP
Balance enquiry
8/7/2019 TPE4001A23CSE 101
8/20
SOURCE CODE
# include # include
# include
# include //library header file
int dmenu(); //main menu
void dadd(); //add to list
void dfind(); //search from the list
void dedit(); //edit the record
void ddel(); //delete from the list
void ddisp(); //display all
void ddisp1();//display1
void ddisp2();//display2void dwith();
void ddepo();
void dcurrent_with();
void dcurrent_depo();
void deposit();
void withdrawal();
struct dnode {
int num,bal,check;
char dlname[20], dfname[20], dtel[15];
struct dnode *dnext;
};typedef struct dnode node;
node *dstart, *dtemp;
int i=5000,chk=1,j=15000;
int dmenu()
{
int dch;
gotoxy(30,5);
printf(" BANKING DATABASE ");
gotoxy(30,6);
printf(" ================ ");
gotoxy(3,24);
gotoxy(27,10);
printf(" 1. Create a new account");
gotoxy(27,11);
printf(" 2. Search customer details");
gotoxy(27,12);
printf(" 3. Edit customer details");
gotoxy(27,13);
printf(" 4. Delete a customer");
gotoxy(27,14);
printf(" 5. Display all account holders ");gotoxy(27,15);
8/7/2019 TPE4001A23CSE 101
9/20
printf(" 6. Deposit money");
gotoxy(27,16);
printf(" 7. Withdrawal money");
gotoxy(27,17);
printf(" 8. Balance Enquiry");
gotoxy(27,18);printf(" 9. Exit ");
gotoxy(27,21);
printf(" Enter your choice(1-9):");
gotoxy(55,21);
scanf("%d", &dch);
return dch;
}
void dadd()
{
int type;
node *dptr,*dprev;dtemp=(node *)malloc(sizeof(node));
printf("\nWhich type of account you want to create?\n1->Savings\n2->Current\nenter
your choice : ");
scanf("%d",&type);
if(type==1)
{
do{
printf("\nYour Account No:");
dtemp->num=i;
printf("%d",dtemp->num);
i++;
}while(i>10000);
printf("\nFirst name: ");
scanf("%s", dtemp->dfname);
printf("Last name:");
scanf("%s", dtemp->dlname);
printf("Telephone No.: ");
scanf("%s", dtemp->dtel);
a:
printf("Deposit Sum:");
scanf("%d",&dtemp->bal);if(dtemp->baldnext=NULL;
if(dstart==NULL) dstart=dtemp;
else {
dprev=dptr=dstart;
while(strcmp(dtemp->dfname,dptr->dfname)>0){
dprev=dptr;dptr= dptr->dnext;
8/7/2019 TPE4001A23CSE 101
10/20
if (dptr == NULL) break;
}
if(dptr==dprev) {
dtemp->dnext=dstart;
dstart=dtemp;
}else if(dptr==NULL)
dprev->dnext=dtemp;
else {
dtemp->dnext=dptr;
dprev->dnext=dtemp;
}
}
ddisp1();
}
else if(type==2)
{do{
printf("\nYour Account No:");
dtemp->num=j;
printf("%d",dtemp->num);
j++;
}while(j>20000);
printf("\nFirst name: ");
scanf("%s", dtemp->dfname);
printf("Last name:");
scanf("%s", dtemp->dlname);
printf("Telephone No.: ");
scanf("%s", dtemp->dtel);
m:
printf("Deposit Sum:");
scanf("%d",&dtemp->bal);
if(dtemp->baldnext=NULL;if(dstart==NULL) dstart=dtemp;
else {
dprev=dptr=dstart;
while(strcmp(dtemp->dfname,dptr->dfname)>0){
dprev=dptr;
dptr= dptr->dnext;
if (dptr == NULL) break;
}
if(dptr==dprev) {
dtemp->dnext=dstart;
dstart=dtemp;}
8/7/2019 TPE4001A23CSE 101
11/20
else if(dptr==NULL)
dprev->dnext=dtemp;
else {
dtemp->dnext=dptr;
dprev->dnext=dtemp;
}}
printf("Your provided Cheque nos.%d to %d",chk,chk+19);
ddisp2();
}
}
void dfind()
{
node *dptr;
int no,num;
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");getch();
return;
}
printf("Enter the account No : ");
scanf("%d",&no);
dptr=dstart;
while(dptr->num!=no)
{
dptr= dptr->dnext;
if (dptr == NULL) break;
}
if(dptr!=NULL)
{
if(dptr->num>=5000 && dptr->numnum==no)
{
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\n\t\tYou are a SAVINGS account holder of our bank");
printf("\n\t\tAccount number: %d",dptr->num);printf("\n\t\tFirst name: %s", dptr->dfname);
printf("\n\t\tLast name:%s", dptr->dlname);
printf("\n\t\tTelephone No.: %s", dptr->dtel);
printf("\n\t\tYour Balance: %d",dptr->bal);
printf("\n\t\t------------------------------\n");
}
}
else{
printf("\n\n");
printf("\t\t------------------------------\n");
if(dptr->num==no){
8/7/2019 TPE4001A23CSE 101
12/20
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\n\t\tYou are a CURRENT account holder of our bank");
printf("\n\t\tAccount number: %d",dptr->num);
printf("\n\t\tFirst name: %s", dptr->dfname);
printf("\n\t\tLast name:%s", dptr->dlname);
printf("\n\t\tTelephone No.: %s", dptr->dtel);printf("\n\t\tYour Balance: %d",dptr->bal);
chk=1;
printf("\n\t\tCheque nos:%d to %d",chk,chk+19);
printf("\n\t\t------------------------------\n");
}
}
}
else
{
printf("No Matching Records Found .......\n");
}getch();
}
void deposit()
{
int no;
node *dptr,*dprev;
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");
getch();
return;
}
printf("Enter your account no : ");
scanf("%d",&no);
dptr=dstart;
while(dptr->num!=no)
{
dptr= dptr->dnext;
if (dptr == NULL) break;
}
if(dptr!=NULL){
if(dptr->num>=5000 && dptr->num
8/7/2019 TPE4001A23CSE 101
13/20
}
void ddepo()
{
node *dptr;
int bal;
printf("\t\t\n-----------------------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\nAccount No:%d \n",dptr->num);
printf("First Name : %s\n",dptr->dfname);
printf("Last Name : %s\n",dptr->dlname);
printf("Phone Number : %s\n",dptr->dtel);
printf("Your Balance : %d\n",dptr->bal);
printf("Deposit Amount:");
scanf("%d",&bal);
dptr->bal+=bal;
printf("Your New balance:%d",dptr->bal);
getch();}
void dcurrent_depo()
{
node *dptr;
int bal,ch;
printf("\t\t\n-----------------------------------------------\n");
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\nAccount No:%d \n",dptr->num);
printf("First Name : %s\n",dptr->dfname);
printf("Last Name : %s\n",dptr->dlname);
printf("Phone Number : %s\n",dptr->dtel);
printf("Your Balance : %d\n",dptr->bal);
printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");
scanf("%d",&ch);
if(ch==1)
{
printf("Deposit Amount:");
scanf("%d",&bal);
dptr->bal+=bal;
printf("Your New balance:%d",dptr->bal);
}else if(ch==2)
{
do{
printf("\nYour Check No:");
dtemp->check=chk;
printf("%d\n",dtemp->check);
chk++;
}while(chk>21);
printf("Deposit Amount:");
scanf("%d",&bal);
dptr->bal+=bal;printf("Your New balance:%d",dptr->bal);
8/7/2019 TPE4001A23CSE 101
14/20
}
getch();
}
void withdrawal()
{
node *dptr;int no;
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");
getch();
return;
}
printf("Enter the account No : ");
scanf("%d",&no);
dptr=dstart;
while(dptr->num!=no){
dptr= dptr->dnext;if (dptr == NULL) break;
}
if(dptr!=NULL)
{
if(dptr->num>=5000 && dptr->numdlname);
printf("\nAccount No:%d \n",dptr->num);
printf("First Name : %s\n",dptr->dfname);
printf("Last Name : %s\n",dptr->dlname);
printf("Phone Number : %s\n",dptr->dtel);
printf("Your Balance : %d\n",dptr->bal);
b:
printf("Withdrawal Amount:");
scanf("%d",&bal);if((dptr->bal-bal)
8/7/2019 TPE4001A23CSE 101
15/20
{
printf("INSUFFICIENT FUND-A minimum of Rs.500/- should be maintained\n");
goto b;
}
dptr->bal-=bal;
printf("Your New balance:%d",dptr->bal);getch();
}
void dcurrent_with()
{
node *dptr;
int no,bal,ch;
printf("\t\t\n-----------------------------------------------\n");
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\nAccount No:%d \n",dptr->num);
printf("First Name : %s\n",dptr->dfname);
printf("Last Name : %s\n",dptr->dlname);printf("Phone Number : %s\n",dptr->dtel);
printf("Your Balance : %d\n",dptr->bal);
printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");
scanf("%d",&ch);
if(ch==1)
{
b:
printf("Withdrawal Amount:");
scanf("%d",&bal);
if((dptr->bal-bal)bal-=bal;
printf("Your New balance:%d",dptr->bal);
}
else if(ch==2)
{
do{
printf("\nYour Check No:");dtemp->check=chk;
printf("%d\n",dtemp->check);
chk++;
}while(chk>21);
c:
printf("Withdrawal Amount:");
scanf("%d",&bal);
if((dptr->bal-bal)
8/7/2019 TPE4001A23CSE 101
16/20
dptr->bal-=bal;
printf("Your New balance:%d",dptr->bal);
}
getch();
}
void dedit(){
node *dptr;
int no,bal;
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");
getch();
return;
}
printf("Enter number to Edit : ");
scanf("%d",&no);
dptr=dstart;while(dptr->num!=no){
dptr= dptr->dnext;
if (dptr == NULL) break;
}
if(dptr!=NULL) {
printf("\t\t\n-----------------------------------------------\n");
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\nOld First Name : %s", dptr->dfname);
printf("\nNew First Name : ");
scanf("%s", dptr->dfname);
printf("\nOld Last Name : %s", dptr->dlname);
printf("\nNew Last Name : ");
scanf("%s", dptr->dlname);
printf("\nPhone Number : %s", dptr->dtel);
printf("\nNew Phone Number : ");
scanf("%s", dptr->dtel);
printf("\nOld Balance : %d", dptr->bal);
m:
printf("\nNew Balance : ");
scanf("%d", &bal);
if(balbal=bal;
}
else {
printf("No Matching Records Found .......\n");
}
getch();
}void ddel()
8/7/2019 TPE4001A23CSE 101
17/20
{
node *dptr,*dprev,*dtemp;
int no;
char dyn='n';
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");getch();
return;
}
printf("Enter your account no to delete : ");
scanf("%d",&no);
dprev=dptr=dstart;
while(dptr->num!=no){
dprev=dptr;
dptr= dptr->dnext;
if (dptr == NULL) break;
}if(dptr!=NULL){
printf("\nDeleting Record.....Confirm [y/n]: ");
dyn=getch();
printf("\n\n---------------------------------------------------------");
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\nAccount No : %d\n",dptr->num);
printf("First Name : %s\n",dptr->dfname);
printf("Last Name : %s\n",dptr->dlname);
printf("Phone Number : %s\n",dptr->dtel);
printf("Balance : %d\n",dptr->bal);
printf("---------------------------------------------------------");
if(dyn=='y') {
if (dptr==dstart) {
dtemp=dstart->dnext;
free(dstart);
dstart=dtemp;
}
else {
dtemp=dptr->dnext;
free(dptr);
dprev->dnext=dtemp;}
printf("\n\n1 Record Deleted....");
}
else
printf("\n\nRecord not Deleted....");
}
else {
printf("\nNo Matching Records Found .......");
}
getch();
}void ddisp()
8/7/2019 TPE4001A23CSE 101
18/20
{
node *dptr;
if(dstart==NULL) {
printf("\n\t\t\tNO ACCOUNT DATABASE....\n");
getch();
return;}
clrscr();
printf("\t\t------------------------------\n");
for(dptr=dstart; dptr!=NULL; dptr=dptr->dnext) {
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);
printf("\n\t\tAccount number: %d",dptr->num);
printf("\n\t\tFirst name: %s", dptr->dfname);
printf("\n\t\tLast name:%s", dptr->dlname);
printf("\n\t\tTelephone No.: %s", dptr->dtel);
printf("\n\t\tYour Balance: %d",dptr->bal);
printf("\n\t\t------------------------------\n");}
getch();
}
void ddisp1()
{
printf("\n\n");
printf("\t\t------------------------------\n");
printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);
printf("\n\t\tYou are a SAVINGS account holder of our bank");
printf("\n\t\tAccount number: %d",dtemp->num);
printf("\n\t\tFirst name: %s", dtemp->dfname);
printf("\n\t\tLast name:%s", dtemp->dlname);
printf("\n\t\tTelephone No.: %s", dtemp->dtel);
printf("\n\t\tYour Balance: %d",dtemp->bal);
printf("\n\t\t------------------------------\n");
getch();
}
void ddisp2()
{
printf("\n\n");
printf("\t\t------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);
printf("\n\t\tYou are a CURRENT account holder of our bank");
printf("\n\t\tAccount number: %d",dtemp->num);
printf("\n\t\tFirst name: %s", dtemp->dfname);
printf("\n\t\tLast name:%s", dtemp->dlname);
printf("\n\t\tTelephone No.: %s", dtemp->dtel);
printf("\n\t\tYour Balance: %d",dtemp->bal);
chk=1;
printf("\n\t\tCheque nos:%d to %d",chk,chk+19);
printf("\n\t\t------------------------------\n");
getch();}
8/7/2019 TPE4001A23CSE 101
19/20
void main()
{
int dch;
dstart=(node *)malloc(sizeof(node));
dstart=NULL;
do{clrscr();
dch=dmenu();
clrscr();
switch(dch) {
case 1: dadd();
break;
case 2: dfind();
break;
case 3: dedit();
break;
case 4: ddel();break;
case 5:
ddisp();
break;
case 6:
deposit();
break;
case 7:
withdrawal();
break;
case 8:
dfind();
break;
}
}while(dch!=9);
}
8/7/2019 TPE4001A23CSE 101
20/20
FUTURE SCOPE OF THE PROJECT
Our project will be able to implement in future after making some changes and modificationsas we make our project at a very low level. So the modifications that can be done in our
project are:-
This project can be implement only at small bank branches. It cannot be used for large scale
bank purposes.
REFERENCES:-
www.google.com Universal search websitewww.wikipedia.com Educational search website
Programming with C Book by Byron S. Gottrified
http://www.google.com/http://www.wikipedia.com/http://www.google.com/http://www.wikipedia.com/
