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Trigonometry Review

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Trigonometry Review. 9/4 tutoring until 3:10 today You need a calculator everyday. Quiz first thing. Get out ½ piece of paper long ways. Record first and last name and period at top. Title it Unit I Qz. Number 1-15 down the side. - PowerPoint PPT Presentation
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Trigonometry Review
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Page 1: Trigonometry Review

Trigonometry ReviewTrigonometry Review

Page 2: Trigonometry Review

9/4 tutoring until 3:10 todayYou need a calculator everyday.

9/4 tutoring until 3:10 todayYou need a calculator everyday.

Quiz first thing. Get out ½ piece of paper long ways. Record first and last name and period at top. Title it Unit I Qz. Number 1-15 down the side.

Pick up Trig notes and Yesterday we worked on metrics and dimensional analysis.

For tomorrow complete any 5 of the first 6 DA problems s 02 Meas WS1. I would strongly suggest you include #4

Today is trig review. Remember to put your calculators away at the end of the

period in the correct pocket. I am not your maid.

Page 3: Trigonometry Review

9/19/1

Yesterday we worked on solving right triangles Today’s goal: Practice solving right triangles using trig Periods 5-7: pick up Math Ref 04 (4th got this handout

yesterday) Solve Now: One dime has the mass of 2.59 grams and

a diameter of 17.9 mm. If these dimes are aligned edge to edge, how many kilometers would 1.0 mole of dimes cover? Assume that 1 mole of dimes = 6.02 x 1023 dimes.

Tomorrow: Quiz over right triangles & dimensional analysis.

Page 4: Trigonometry Review

9/69/6

Turn in triangle WS to blue sorter. I will answer questions about DA and triangles,

and then we will take quiz

Page 5: Trigonometry Review

Cylinder Lab #3Cylinder Lab #3

The expected relationship between circumference /diameter is pi.

IF c = 2лr and d=2rTHEN c/d is 2лr/2r = л

Page 6: Trigonometry Review

One dime has the mass of 2.59 grams and a diameter of 17.9 mm. If these dimes are aligned edge to edge, how many kilometers would 1.0 mole of dimes cover? Assume that 1 mole of dimes = 6.02 x 1023 dimes.

Page 7: Trigonometry Review

Convert moles to km.Convert moles to km.

1 mole 6.02 x 1023 dimes 17.9 mm 1 m1 1 mole 1 dime 1000 mm

1.08 x 1019 km

1km1000 m

Page 8: Trigonometry Review

Convert moles to km.Convert moles to km.

1 mole 6.02 x 1023 pennies

1.5 cm 1 in

1 1 mole 1 penny 2.54cm

5.61 x 1018 miles

1ft

12 in

1 mile

5280 ft

Page 9: Trigonometry Review

What is the difference between the following?What is the difference between the following?

PerimeterAreaCircumference

Page 10: Trigonometry Review

What is the difference between the following?What is the difference between the following?

Perimeter

Total length of outer boundary of a figure

L+W+L+W Area

Measure of bounded region on a plane

L x W (rectangle) Circumference

The line bounding a circle

2лr

Page 11: Trigonometry Review

RadiusDistance from center to periphery of

a circleHypotenuseSide of right triangle opposite the 90

angle

Page 12: Trigonometry Review

We will be focusing on trianglesWe will be focusing on triangles

Page 13: Trigonometry Review

Ex A: What is the area of triangle A?Ex A: What is the area of triangle A?

A= ½ bhA=

½(3.00u)(6.00u)A= 9.00

u2

3

6

Page 14: Trigonometry Review

Ex B: What is the measure triangle A’s hypotenuse?Ex B: What is the measure triangle A’s hypotenuse?

a2 + b2 = c2

3.002 + 6.002 = c2

c = 6.71 u

3

6

Page 15: Trigonometry Review

Ex C: Given the following triangle CEx C: Given the following triangle C

a = 4.21u

b = 7.43 u

Angle C = 90.0°

What is c?

c = 8.54 u

b

a

c

Page 16: Trigonometry Review

Same triangle CSame triangle C

What is measure of smallest angle, A?

b

a

c

a = 4.21u

b = 7.43 u

c = 8.54 u

A

Page 17: Trigonometry Review

SOH CAH TOASOH CAH TOAThis is a good time to review SOH

CAH TOASine = opposite / hypotenuseCosine = adjacent / hypotenuseTangent = opposite / adjacentThese only work for right triangles!

Page 18: Trigonometry Review

What’s this SOHCAHTOA?What’s this SOHCAHTOA?

What does sine, cosine, and tangent represent?

Page 19: Trigonometry Review

.5934 34 .5592 .8290 .6745 1.7883 1.2062 1.4826 56 .9774

.6109 35 .5736 .8192 .7002 1.7434 1.2208 1.4281 55 .9599

.6283 36 .5878 .8090 .7265 1.7013 1.2361 1.3764 54 .9425

.6458 37 .6018 .7986 .7536 1.6616 1.2521 1.3270 53 .9250

.6632 38 .6157 .7880 .7813 1.6243 1.2690 1.2799 52 .9076

.6807 39 .6293 .7771 .8098 1.5890 1.2868 1.2349 51 .8901

.6981 40 .6428 .7660 .8391 1.5557 1.3054 1.1918 50 .8727

.7156 41 .6561 .7547 .8693 1.5243 1.3250 1.1504 49 .8552

.7330 42 .6691 .7431 .9004 1.4945 1.3456 1.1106 48 .8378

.7505 43 .6820 .7314 .9325 1.4663 1.3673 1.0724 47 .8203

.7679 44 .6947 .7193 .9657 1.4396 1.3902 1.0355 46 .8029

.7854 45 .7071 .7071 1.0000 1.4142 1.4142 1.0000 45 .7854

Cos Sin Cot Sec Csc Tan Deg Rad

Page 20: Trigonometry Review

What’s this SOHCAHTOA?What’s this SOHCAHTOA?

What does sine, cosine, and tangent represent?

TableThe proportionality constant

between given sides of a right triangle in reference to a specific angle.

Page 21: Trigonometry Review

Naming the sidesNaming the sides

A right angledtriangle

The angle weare interested in.

H

This is the longest side— the hypotenuse.

O

This side is oppositeour angle.

AThis side is adjacentto our angle.

Page 22: Trigonometry Review

Naming the sidesNaming the sides

H = Hypotenuse

O = Opposite

A = Adjacent

H

O

A

O

H

AH

OA

HO

A H

O

A

Page 23: Trigonometry Review

Sine Let’s check if the angle is really 30°Sine Let’s check if the angle is really 30°

30°

4cm

8cmH =

O =

Here we know the Hypotenuse and the Opposite side.

So we use the Sine function.

This tells us that sin 30° = 4/8 = 0.5.

You can check with a calculator that sin 30° is 0.5.

Page 24: Trigonometry Review

If O/H is .5 How do I get the angle? Sin-1(4/8)

Page 25: Trigonometry Review

Same triangleSame triangle

a = 4.21u

b = 7.43 u

c = 8.54 uWhat is measure of smallest angle, A?

Sin θ = opp/hyp

Sin θ = 4.21/8.54

θ = 29.5°a

bc

A

Page 26: Trigonometry Review

Same triangleSame triangle

a = 4.21u

b = 7.43 u

c = 8.54 uCan I find measure of smallest angle, A with another function?

Cos θ = adj/hyp

Cos θ = 7.43/8.54

θ = 29.5°

a

cb

A

Page 27: Trigonometry Review

How would you determine the last angle?How would you determine the last angle?

We will use trig, not geometry. ☺

Page 28: Trigonometry Review

Complete triangles D and E on bottom of pg 2 of unit 02 trig review.

Page 29: Trigonometry Review

Ex D: A right triangle D has sides with measurements of 7.48, 15.0, and 13.0 units. What is the measure of the hypotenuse? What is the measure of the largest UNKNOWN angle of such triangle? What is the measure of the smallest angle?

Ex D: A right triangle D has sides with measurements of 7.48, 15.0, and 13.0 units. What is the measure of the hypotenuse? What is the measure of the largest UNKNOWN angle of such triangle? What is the measure of the smallest angle?

Hypotenuse = 15 u Largest angle = 60.1° Smallest angle = 29.9°

Page 30: Trigonometry Review
Page 31: Trigonometry Review

Ex E: A right triangle E has a hypotenuse measuring 28.0 u. One angle has a measure of 22.0°. What is the measure of the smallest side? What is the measure of the remaining side? What is the measure of the remaining angle?

Ex E: A right triangle E has a hypotenuse measuring 28.0 u. One angle has a measure of 22.0°. What is the measure of the smallest side? What is the measure of the remaining side? What is the measure of the remaining angle?

Side a = 10.5u Side b = 26.0 u Angle θ = 68.0°

Page 32: Trigonometry Review

Refer to table on notes page:Refer to table on notes page: What can be said of the sine value of an angle

as that angle’s size increases? increases What can be said of the cosine value of an angle

as that angle’s size increases? decreases As the cosine value of an angle decreases, the

sine value of that same angle increases.

Page 33: Trigonometry Review

9/9 Thursday9/9 Thursday

Goal: Assess understanding of dimensional analysis and solving right triangles

Introduce Law of Sines and Cosines

Have your homework out so we can check it!

Page 34: Trigonometry Review

9/10 Friday9/10 FridayGoal: Introduce Law of Sines and

CosinesIf you were absent yesterday you will be

taking the Trig/DA Quiz during class. You will be responsible for getting any missed notes and will be required to complete the homework assignment.

HW: Oblique Triangles

Page 35: Trigonometry Review

Tests are available to be viewed on Test Correction Days. Test corrections will earn you a daily grade Retakes (For Quizzes and Tests with less than a 70 average) :

You must have completed your review sheet before the test.You must perform test correctionsYou must have all class notes and assignments completed. This must be shown to me for approval.Failure to comply negates retake eligibility.You must fill out a retake appointment sheet 24 hours in advance. Failure to show at scheduled time voids your option for retake.Corrections and retakes must be performed within 5 days of receiving the graded assignment and are available only during after school tutoring days unless otherwise noted. (Mon-Wed 2:35 -3:15)I am available this Friday and next Monday and Tuesday.

Page 36: Trigonometry Review

Quizzes are graded but not in gradebook yet. Please return them to lue sorter or get a zero.

Quizzes are graded but not in gradebook yet. Please return them to lue sorter or get a zero.

Page 37: Trigonometry Review

Given the following triangle GGiven the following triangle Ga = 7.20u

b = 4.35u

One angle is 95°

How do you solve this triangle?

Page 38: Trigonometry Review

Law of CosinesLaw of Cosines

Useful when know side-angle-side or side-side-side

Law of Cosinesa2 = b2 + c2 – [2bc cosA]b2 = a2 + c2 – [2ac cosB]c2 = a2 + b2 – [2ab cosC]

Page 39: Trigonometry Review

Law of Cosinesa2 = b2 + c2 – [2bc cosA]b2 = a2 + c2 – [2ac cosB]c2 = a2 + b2 – [2ab cosC]

If you know the adjacent sides on any angle you can determine the third side

Page 40: Trigonometry Review

a2 = b2 + c2 – [2bc cosA]Solve for cosA

a2 = b2 + c2 – [2bc cosA]Solve for cosA

a2 = b2 + c2 – [2bc cosA]cosA = [a2 - b2 - c2 ]/[-2bc]

If you know all the sides you can determine any angle. You just have to rearrange the appropriate law and solve for the angle.

Page 41: Trigonometry Review

Triangle F. First Draw and labelTriangle F. First Draw and label

Sides in lower cases

Angles in upper case and across for corresponding side.

Can use law of cosines to determine c

c2 = a2 + b2 – [2ab cosC]

b

a

c

95°

A

C

B

Page 42: Trigonometry Review

Triangle F a = 7.20u b = 4.35 u

c2 = a2 + b2 – [2ab cosC]

Triangle F a = 7.20u b = 4.35 u

c2 = a2 + b2 – [2ab cosC]c2 = (7.20u)2 + (4.35u)2 – [2(7.20u)(4.35u)(cos95°)]

c2 = 76.2

c = 8.73u

Page 43: Trigonometry Review

Triangle F. Know sides and one angle. How to determine the other angles?

Triangle F. Know sides and one angle. How to determine the other angles?

a = 7.20u b = 4.35 u c = 8.73u C = 95°

Use Law of Sinesa/sinA = b/sinB = c/sinC

b

a

c

95°

A

C

B

Page 44: Trigonometry Review

a/sinA = b/sinB = c/sinCWhat is angle A?

a/sinA = b/sinB = c/sinCWhat is angle A?

a/sinA = c/sinC solve for sin Asin A = [a(sinC)] ÷ csin A = [(7.20u) (sin 95°)] ÷ 8.73uSin A = 0.822A = 55.2°

a = 7.20u b = 4.35 u c = 8.73u C = 95°

Page 45: Trigonometry Review

Triangle F. Know sides and two angles. How to determine the last angle?

Triangle F. Know sides and two angles. How to determine the last angle? a = 7.20u A = 55.2°

b = 4.35u

c = 8.73u C = 95°

Remember a triangle equals 180°

180°- (55.2° + 95°)B = 29.8°

b

a

c

95°

A

C

B

Page 46: Trigonometry Review

Some things to rememberSome things to remember Angles in a parallelogram total 360o

SOH CAH TOA for right triangles only Pythagorean Theorem (for right triangles):

a2 + b2 = c2

Law of Cosinesa2 = b2 + c2 – [2bc cosA]b2 = a2 + c2 – [2ac cosB]

c2 = a2 + b2 – [2ab cosC]

Law of Sines

a/sinA = b/sinB = c/sinC

B

A

C

a

b

c

Page 47: Trigonometry Review

Beware:Beware:

Law of Sines has problem when solving for angles above 100. It is okay to use if you know the side corresponding to an angle above 100. But if the angle you are solving for could be over 100, use the law of cosines. Add your total angles up to check!

Page 48: Trigonometry Review

Consider a triangle G with the following measures: B = 85.0° a = 4.00 b = 6.00

Determine A, C, and Side c.

Consider a triangle G with the following measures: B = 85.0° a = 4.00 b = 6.00

Determine A, C, and Side c. What would you solve for first?

A =

C =

c =

Page 49: Trigonometry Review

Consider a triangle G with the following measures: B = 85.0° a = 4.00 b = 6.00

Determine A, C, and Side c.

Consider a triangle G with the following measures: B = 85.0° a = 4.00 b = 6.00

Determine A, C, and Side c. What would you solve for first?

A = 41.6°

C = 53.4°

c = 4.84

Page 50: Trigonometry Review

Consider a triangle H with the following measures: C = 103° B = 16° c = 12

Determine A, Side a, and Side b.

Consider a triangle H with the following measures: C = 103° B = 16° c = 12

Determine A, Side a, and Side b. What would you solve for first?A =

a =

b =

Page 51: Trigonometry Review

Consider a triangle H with the following measures: C = 103° B = 16° c = 12

Determine A, Side a, and Side b.

Consider a triangle H with the following measures: C = 103° B = 16° c = 12

Determine A, Side a, and Side b. What would you solve for first?A = 61°

a = 10.8 (with law of sines)

b = 3.39

Page 52: Trigonometry Review

Disregard following slidesDisregard following slides

Page 53: Trigonometry Review

The SwimmerThe SwimmerA swimmer attempts to swim due north to the pier 2.00 miles away but the current takes him at a bearing of 40°. After a while he notices he is due east of the pier. How far has he travelled?

Step 1. Draw a diagram.

pier

2.00

mile

s

40°?

Page 54: Trigonometry Review

The SwimmerThe Swimmer

?2 40°

Step 2. Identify the sides.

Here we have the Adjacent side and want to find the Hypotenuse. So we use the CAH triangle.

C H

A

Putting our finger on H shows that H = A/C

= 2.00 ÷ (cos 40°)= 2.00 ÷ 0.766= 2.61 miles

Page 55: Trigonometry Review

The Church SteepleThe Church SteepleEric decides to find the height of the steeple of his local church. He measures a distance of 50. m along the ground. The angle of elevation of the top of the steeple is 35°. How high is the steeple?

Step 1. Draw a diagram.

50.m 35°

?

Page 56: Trigonometry Review

The Church SteepleThe Church Steeple

?

50

35°

Step 2. Identify the sides.

Here we have the Adjacent side and want to find the Opposite. So, we use the TOA triangle.

Putting our finger on O shows that O = T × A

= (tan 35°) × 50.= 0.70 × 50.= 35 m

T AO

Page 57: Trigonometry Review

Finding An Angle (1)Finding An Angle (1)At Heathwick airport there is a forest just 500. m from the end of the runway. The trees can be as tall as 30. m. What is the minimum angle of climb if aircraft are to avoid the trees?

Step 1. Draw a diagram.

30.m

500.m?

Page 58: Trigonometry Review

Finding An Angle (2)Finding An Angle (2)

30

500

Step 2. Identify the sides

Here we have the Adjacent and Opposite sides and want to find an angle. So, we use the TOA triangle.

Putting our finger on T shows that… tan = O/A

= 30. ÷ 500.= 0.060

T AO

Now we can use the inverse tan to find the angle. = tan-1 0.060 = 3.4°

Page 59: Trigonometry Review

Remember…Remember…

S H

OC H

A

T A

O

SOH-CAH-TOA

Page 60: Trigonometry Review

30°

? cm

8 cmH =

O =

S HO

Sin Finding the Opposite Sin Finding the Opposite SOH-CAH-TOA? ?

Opp = Sin × Hyp

= (Sin 30°) × 8

= 4 cm

Page 61: Trigonometry Review

27°

? km

12.3 km

H =

A =

C HA

Cos Finding the AdjacentCos Finding the Adjacent

SOH-CAH-TOA? ?

Adj = Cos × Hyp

= (Cos 27°) × 12.3

= 0.891 × 12.3

= 11.0 km

Page 62: Trigonometry Review

53°

? cm

T AO

Tan Finding the Opposite Tan Finding the Opposite

O =

A =

16 cm

SOH-CAH-TOA? ?

Opp = Tan × Adj

= (Tan 53°) × 16

= 1.327 × 16

= 21 cm

Page 63: Trigonometry Review

36°

87 m

? mH =

O =

S HO

Sin Finding the Hypotenuse Sin Finding the Hypotenuse SOH-CAH-TOA

??

Hyp = Opp Sin

= 87 (Sin 36°)

= 87 0.5878

= 150 m

Page 64: Trigonometry Review

0.80 cm

? cmH =

A =

C HA

Cos Finding the Hypotenuse Cos Finding the Hypotenuse

60°SOH-CAH-TOA

? ?

Hyp = Adj Cos

= 0.80 (Cos 60.°)

= 0.80 0.50

= 1.6 cm

Page 65: Trigonometry Review

30°

3.1 cm T AO

Tan Finding the Adjacent Tan Finding the Adjacent

O =

A = ? cm

SOH-CAH-TOA? ?

Adj = Opp Tan

= 3.1 (Tan 30.°)

= 3.1 0.5773

= 5.4 cm

Page 66: Trigonometry Review

What happens when you don’t know the angle?What happens when you don’t know the angle?

We can find the usable number mentioned previously using the ratios.

The problem is we know need to convert it back into the original angle.

The Buttons on your calculator are…

Sin Cos Tan

The opposite of these are SHIFT then

Sin-1 Cos-1 Tan-1

Page 67: Trigonometry Review

3.0 km

7.0 kmH =

O =

S HO

Sin Finding the Angle Sin Finding the Angle SOH-CAH-TOA

? ??

Sin = Opp Hyp

Sin = 3.0 7.0

Sin = 0.4285

= Sin-1 (0.4285)

= 25°

Page 68: Trigonometry Review

12.1 cm

14.5cm

H =

A =

C HA

Cos Finding the Angle Cos Finding the Angle SOH-CAH-TOA

? ??

Cos = Adj Hyp

Cos = 12.1 14.5

Cos = 0.834

= Cos-1 (0.834)

= 33.4 °

Page 69: Trigonometry Review

67.0 cm T AO

Tan Finding the Angle Tan Finding the Angle

O =

A = 187 cm

SOH-CAH-TOA? ??

Tan = Opp Adj

Tan = 67.0 187

Tan = 0.358

= Tan-1 (0.358)

= 19.7°

Page 70: Trigonometry Review

If two vectors are not at right angles to each other then we must use the Law of Cosines:

C2 = A2 + B2 – 2AB cos “” or Theta, is any unknown

angle but in this case it is the angle between the two vectors


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