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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any...

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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You CLICK TO CONTINUE
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Page 1: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary.Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz.

CLICK TO CONTINUE

Page 2: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

The element sulfur, S(s), contains 6.022 x 1023 S atoms/mole.

The compound carbon dioxide, CO2(g), contains 6.022 x 1023 CO2 molecules/mole .

The compound bromine, Br2(l), contains 6.022 x 1023 Br2 molecules/mole.

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

CLICK TO CONTINUE

Page 3: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

S(s) = 32.066 g/mol

Br2(l) = 159.808 g/mol

CO2(g) = 44.010 g/mol

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CLICK TO CONTINUE

Page 4: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

S(s) 16 cm3/mol

Br2(l) 51 cm3/mol

CO2(g) 2 x 104 cm3/mol

At room temperature and pressure:

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CLICK TO CONTINUE

Page 5: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

sulfur atoms, S atomic weight = 32.066 32.066 g S/mol S

bromine molecules, Br2

atomic weight = 79.904 molecular weight159.808 159.808 g Br2/mol Br2

carbon dioxide molecules, CO2

atomic weights

carbon 12.011, oxygen 15.9994molecular weight 44.010

44.010 g CO2/mol CO2

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CLICK TO CONTINUE

Page 6: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

1.Convert 30 g carbon to moles.

C: atomic weight 12.011

12.011 g C/mol C

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CLICK TO CONTINUE

Page 7: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

CLICK TO CONTINUE

mass (g) carbon moles carbon

(Convert 30 g C to mol.)

Page 8: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

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CLICK TO CONTINUE

(Convert 30 g C to mol.)

30 g C

1 12.011

x _________mole C g C

30 mole C12.011

= 2.5 mol C

Page 9: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

2. Convert 3.5 liters of ammonia at S.T.P. to moles.  

Page 10: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

volume (L) ammonia

moles ammonia

22.414 L/mole NH3(g)

(at S.T.P.)

CLICK TO CONTINUE

(Convert 3.5 L NH3 at S.T.P. to mol.)

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Page 11: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

___________

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CLICK TO CONTINUE

(Convert 3.5 L NH3 at S.T.P. to mol.)

3.5 L NH3

x

3.5 mol NH3 22.414

= 0.16 mol NH3

mol NH3

L NH3

1 22.414

Page 12: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

M (molar) = mol solute/L solution

0.5 M glucose = 0.5 mol glucose/1 L soln

3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution?

Page 13: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

volume (mL) solution volume (L) solution moles solvent

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CLICK TO CONTINUE

(# mol glucose in 10 mL 0.5 M soln?)

Page 14: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

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10 mL solution

x 1 1000or10 mL solution x 1 L 103 mL

or

10 mL solution x 10-3 L 1 mL

______ LmL

CLICK TO CONTINUE

(# mol glucose in 10 mL 0.5 M soln?)

Page 15: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

10 mL solution x 1 L 1000 mL

or 10 mL solution x 1 L 103 mL

or 10 mL solution x 10-3 L 1 mL

x mol glucose L solution

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x mol glucose L solution

x mol glucose L solution

0.5 1

0.5 1

0.5 1

CLICK TO CONTINUE

(# mol glucose in 10 mL 0.5 M soln?)

Page 16: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

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CLICK TO CONTINUE

10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution

or

10 mL solution x 1 L x 0.5 mol glucose 103 mL 1 L solution

or

10 mL solution x 10-3 L x 0.5 mol glucose 1 mL 1 L solution

(# mol glucose in 10 mL 0.5 M soln?)

Page 17: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

10 x 0.5 mol glucose 1000or10 x 0.5 mol glucose 103

or10 x 10-3 x 0.5 mol glucose

= 0.005 or 5 x 10-3 mol glucose

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(# mol glucose in 10 mL 0.5 M soln?)

CLICK TO CONTINUE

Page 18: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

4. How many atoms are

present in 4.0 moles of phosphine, PH3? 

Page 19: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

4.0 atoms/molecule PH3

moles phosphine molecules phosphine atoms

CLICK TO CONTINUE

(# atoms in 4.0 mol PH3?)

Page 20: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY

4.0 mol PH3x 6.02 x 1023

1

x atoms molecule PH3

4 1

molecules PH3 mol PH3

_____________________

CLICK TO CONTINUE

(# atoms in 4.0 mol PH3?)

Page 21: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

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4.0 mol PH3 x 6.02 x 1023 molecules PH3

1 mol PH3

x 4 atoms 1 molecules PH34.0 x 6.02 x 1023 x 4 atoms

= 9.6 x 1024 atoms

___________________

CLICK TO CONTINUE

(# atoms in 4.0 mol PH3?)

Page 22: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

5. How many electrons are lost by ionization of 0.65 moles of calcium?

Page 23: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

Ca Ca 2+ + 2e

moles calcium atoms calcium electrons

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(# electrons lost by 0.65 mol Ca?)

Page 24: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

x electrons atom Ca

0.65 mol Ca x __________________atoms Ca mol Ca

6.02 x 1023

1

21

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(# electrons lost by 0.65 mol Ca?)

Page 25: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

0.65 x 6.02 x 1023 x 2 electrons= 7.8 x 1023 electrons

END OF TUTORIAL

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0.65 mol Ca x 6.02 x 1023 atoms Ca 1

mol Ca x 2 electrons

1 atom Ca

(# electrons lost by 0.65 mol Ca?)

CLICK TO CONTINUE

Page 26: TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand.

RETURN TO TUTORIAL

GO TO POST-QUIZ

OR


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