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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary.Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz.
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The element sulfur, S(s), contains 6.022 x 1023 S atoms/mole.
The compound carbon dioxide, CO2(g), contains 6.022 x 1023 CO2 molecules/mole .
The compound bromine, Br2(l), contains 6.022 x 1023 Br2 molecules/mole.
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S(s) = 32.066 g/mol
Br2(l) = 159.808 g/mol
CO2(g) = 44.010 g/mol
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S(s) 16 cm3/mol
Br2(l) 51 cm3/mol
CO2(g) 2 x 104 cm3/mol
At room temperature and pressure:
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sulfur atoms, S atomic weight = 32.066 32.066 g S/mol S
bromine molecules, Br2
atomic weight = 79.904 molecular weight159.808 159.808 g Br2/mol Br2
carbon dioxide molecules, CO2
atomic weights
carbon 12.011, oxygen 15.9994molecular weight 44.010
44.010 g CO2/mol CO2
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1.Convert 30 g carbon to moles.
C: atomic weight 12.011
12.011 g C/mol C
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mass (g) carbon moles carbon
(Convert 30 g C to mol.)
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(Convert 30 g C to mol.)
30 g C
1 12.011
x _________mole C g C
30 mole C12.011
= 2.5 mol C
2. Convert 3.5 liters of ammonia at S.T.P. to moles.
volume (L) ammonia
moles ammonia
22.414 L/mole NH3(g)
(at S.T.P.)
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(Convert 3.5 L NH3 at S.T.P. to mol.)
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___________
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(Convert 3.5 L NH3 at S.T.P. to mol.)
3.5 L NH3
x
3.5 mol NH3 22.414
= 0.16 mol NH3
mol NH3
L NH3
1 22.414
M (molar) = mol solute/L solution
0.5 M glucose = 0.5 mol glucose/1 L soln
3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution?
volume (mL) solution volume (L) solution moles solvent
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(# mol glucose in 10 mL 0.5 M soln?)
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10 mL solution
x 1 1000or10 mL solution x 1 L 103 mL
or
10 mL solution x 10-3 L 1 mL
______ LmL
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(# mol glucose in 10 mL 0.5 M soln?)
10 mL solution x 1 L 1000 mL
or 10 mL solution x 1 L 103 mL
or 10 mL solution x 10-3 L 1 mL
x mol glucose L solution
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x mol glucose L solution
x mol glucose L solution
0.5 1
0.5 1
0.5 1
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(# mol glucose in 10 mL 0.5 M soln?)
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10 mL solution x 1 L x 0.5 mol glucose 1000 mL 1 L solution
or
10 mL solution x 1 L x 0.5 mol glucose 103 mL 1 L solution
or
10 mL solution x 10-3 L x 0.5 mol glucose 1 mL 1 L solution
(# mol glucose in 10 mL 0.5 M soln?)
10 x 0.5 mol glucose 1000or10 x 0.5 mol glucose 103
or10 x 10-3 x 0.5 mol glucose
= 0.005 or 5 x 10-3 mol glucose
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(# mol glucose in 10 mL 0.5 M soln?)
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4. How many atoms are
present in 4.0 moles of phosphine, PH3?
4.0 atoms/molecule PH3
moles phosphine molecules phosphine atoms
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(# atoms in 4.0 mol PH3?)
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4.0 mol PH3x 6.02 x 1023
1
x atoms molecule PH3
4 1
molecules PH3 mol PH3
_____________________
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(# atoms in 4.0 mol PH3?)
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4.0 mol PH3 x 6.02 x 1023 molecules PH3
1 mol PH3
x 4 atoms 1 molecules PH34.0 x 6.02 x 1023 x 4 atoms
= 9.6 x 1024 atoms
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(# atoms in 4.0 mol PH3?)
5. How many electrons are lost by ionization of 0.65 moles of calcium?
Ca Ca 2+ + 2e
moles calcium atoms calcium electrons
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(# electrons lost by 0.65 mol Ca?)
x electrons atom Ca
0.65 mol Ca x __________________atoms Ca mol Ca
6.02 x 1023
1
21
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(# electrons lost by 0.65 mol Ca?)
0.65 x 6.02 x 1023 x 2 electrons= 7.8 x 1023 electrons
END OF TUTORIAL
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0.65 mol Ca x 6.02 x 1023 atoms Ca 1
mol Ca x 2 electrons
1 atom Ca
(# electrons lost by 0.65 mol Ca?)
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