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Twisted Boundary Conditions Jonathan Flynn Tsukuba LQCD&PP 15 Dec 2004 1/17
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Page 1: Twisted Boundary Conditions

Twisted Boundary ConditionsJonathan Flynn

Tsukuba LQCD&PP 15 Dec 2004 1/17

Page 2: Twisted Boundary Conditions

Contents

θ-BC: twisted boundary conditions

TChPT: twisted chiral perturbation theory

Partial twisting

Applications?

Tsukuba LQCD&PP 15 Dec 2004 2/17

Page 3: Twisted Boundary Conditions

Some recent work

N-N phase shifts PF Bedaque nucl-th/0402051

Pseudoscalar mesondispersion relation(quenched)

GM de Divitiis,R Petronzio andN Tantalo

hep-lat/0405002

θ-BC and two-particlestates

GM de Divitiisand N Tantalo

hep-lat/0409154

ChPT analysis CT Sachrajdaand G Villadoro

hep-lat/0411033

Tsukuba LQCD&PP 15 Dec 2004 3/17

Page 4: Twisted Boundary Conditions

Boundary Conditions

PBC: lattice momenta quantised

pi =2π

Lni

lowest non-zero momentum is quite large, big gaps

non-periodic or twisted spatial boundary conditions:allow continuously variable offset in the comb of allowedthree-momenta

Tsukuba LQCD&PP 15 Dec 2004 4/17

Page 5: Twisted Boundary Conditions

Twisted BC in QCD

Lq = q̄(x)( /D +M)q(x)

observables should besingle-valued: OK ifaction is single-valued ona torus

⇒ field satisfies

ψ(x + eiL) = Uiψ(x)

for i = 1, 2, 3, where Ui

is a symmetry of theaction

for general diagonal M,Ui should be diagonal(CSA of U(3))

Ui = exp(iΘi)

allowed momenta:

pi =2πni

L+θi

L

Tsukuba LQCD&PP 15 Dec 2004 5/17

Page 6: Twisted Boundary Conditions

Twisted BC: 2

change variable:

q̃(x) = e−iΘ·xq(x) (Θ0 = 0)

q̃ satisfies PBC

Lagrangian:

Lq = ¯̃q(x)( /̃D +M)q̃(x)

with

D̃µ = Dµ + iBµ, Bi = Θi/L, B0 = 0

Tsukuba LQCD&PP 15 Dec 2004 6/17

Page 7: Twisted Boundary Conditions

Twisted BC: 3

propagator encodes shift: S(x, y)→ S̃(x, y)

S̃(x) = 〈q̃(x)¯̃q(0)〉 =∫

dk0

1

L3

k

eik·x

i(/k + /B) +M

sum over k = 2πn/L

momentum in denominator is shifted by θ/L

Tsukuba LQCD&PP 15 Dec 2004 7/17

Page 8: Twisted Boundary Conditions

Twisted BC on the Lattice

change of variable modifies the lattice covariantderivatives:

∇Θµψ(x) = eiΘµ/LUµ(x)ψ(x + µ̂) − ψ(x)

∇Θ ∗µ ψ(x) = ψ(x) − e−iΘµ/LU†µ(x − µ̂)ψ(x − µ̂)

Tsukuba LQCD&PP 15 Dec 2004 8/17

Page 9: Twisted Boundary Conditions

Twisted BC on the Lattice

change of variable modifies the lattice covariantderivatives:

∇Θµψ(x) = eiΘµ/LUµ(x)ψ(x + µ̂) − ψ(x)

∇Θ ∗µ ψ(x) = ψ(x) − e−iΘµ/LU†µ(x − µ̂)ψ(x − µ̂)

inverting the modified operator encodes the momentumshift Θ/L in the calculated propagator

Tsukuba LQCD&PP 15 Dec 2004 8/17

Page 10: Twisted Boundary Conditions

Twisted BC on the Lattice

change of variable modifies the lattice covariantderivatives:

∇Θµψ(x) = eiΘµ/LUµ(x)ψ(x + µ̂) − ψ(x)

∇Θ ∗µ ψ(x) = ψ(x) − e−iΘµ/LU†µ(x − µ̂)ψ(x − µ̂)

inverting the modified operator encodes the momentumshift Θ/L in the calculated propagator

hadron momentum shifted by sum of quark shifts

dDPT: quenched study of pseudoscalar mesondispersion relation

SV: ChPT analysis

Tsukuba LQCD&PP 15 Dec 2004 8/17

Page 11: Twisted Boundary Conditions

SV Chiral PT Analysis

Exponential suppression of finite-volume correctionsfrom θ-BC for quantities without FSI (masses, decayconstants, semileptonic FF’s)

Tsukuba LQCD&PP 15 Dec 2004 9/17

Page 12: Twisted Boundary Conditions

SV Chiral PT Analysis

Exponential suppression of finite-volume correctionsfrom θ-BC for quantities without FSI (masses, decayconstants, semileptonic FF’s)

Not possible in general to extract matrix elements usingθ-BC for amplitudes involving FSI (eg K→ ππ)

Tsukuba LQCD&PP 15 Dec 2004 9/17

Page 13: Twisted Boundary Conditions

SV Chiral PT Analysis

Exponential suppression of finite-volume correctionsfrom θ-BC for quantities without FSI (masses, decayconstants, semileptonic FF’s)

Not possible in general to extract matrix elements usingθ-BC for amplitudes involving FSI (eg K→ ππ)

The above remain true for ‘partial twisting’: θ-BC forvalence, PBC for sea

Tsukuba LQCD&PP 15 Dec 2004 9/17

Page 14: Twisted Boundary Conditions

SV Chiral PT Analysis

Exponential suppression of finite-volume correctionsfrom θ-BC for quantities without FSI (masses, decayconstants, semileptonic FF’s)

Not possible in general to extract matrix elements usingθ-BC for amplitudes involving FSI (eg K→ ππ)

The above remain true for ‘partial twisting’: θ-BC forvalence, PBC for sea

They construct effective Lagrangian in presence of θ-BC.

Tsukuba LQCD&PP 15 Dec 2004 9/17

Page 15: Twisted Boundary Conditions

Twisted ChPT

Twisted BC:

Σ(x + eiL) = UiΣ(x)U†i

Redefine fields:

Σ̃(x) = e−iΘ·x/LΣ(x)eiΘ·x/L

Tsukuba LQCD&PP 15 Dec 2004 10/17

Page 16: Twisted Boundary Conditions

Twisted ChPT

Twisted BC:

Σ(x + eiL) = UiΣ(x)U†i

Redefine fields:

Σ̃(x) = e−iΘ·x/LΣ(x)eiΘ·x/L

to get

LChPT =f 2

8〈D̃µΣ̃†D̃µΣ̃〉 −

f 2

8〈Σ̃χ† + χΣ̃†〉

whereD̃µΣ̃ = ∂µ + i[Bµ, Σ̃]

Tsukuba LQCD&PP 15 Dec 2004 10/17

Page 17: Twisted Boundary Conditions

Twisted ChPT: 2

Standard ChPT Lagrangian coupled to vector field Bµ.

Effect of twist on mesons found from [Bi, Σ̃]:

Tsukuba LQCD&PP 15 Dec 2004 11/17

Page 18: Twisted Boundary Conditions

Twisted ChPT: 2

Standard ChPT Lagrangian coupled to vector field Bµ.

Effect of twist on mesons found from [Bi, Σ̃]:

neutral mesons:

[Bi, π0] = 0 −→ no shift

Tsukuba LQCD&PP 15 Dec 2004 11/17

Page 19: Twisted Boundary Conditions

Twisted ChPT: 2

Standard ChPT Lagrangian coupled to vector field Bµ.

Effect of twist on mesons found from [Bi, Σ̃]:

neutral mesons:

[Bi, π0] = 0 −→ no shift

charged mesons shifted by difference of the twists of thetwo valence quarks

[Bi, π±] = ±(θui − θdi)

Lπ±

Tsukuba LQCD&PP 15 Dec 2004 11/17

Page 20: Twisted Boundary Conditions

Twisted ChPT: 2

Standard ChPT Lagrangian coupled to vector field Bµ.

Effect of twist on mesons found from [Bi, Σ̃]:

neutral mesons:

[Bi, π0] = 0 −→ no shift

charged mesons shifted by difference of the twists of thetwo valence quarks

[Bi, π±] = ±(θui − θdi)

Lπ±

allowed values of meson momenta shifted in externalstates and in propagators

Tsukuba LQCD&PP 15 Dec 2004 11/17

Page 21: Twisted Boundary Conditions

dDPT Quenched Study

fixed volume L3T withL = 3.2r0 ≈ 1.6 fm

163 × 32

243 × 48

323 × 64

O(a) improved

4 quark masses

invert for each of

|θ| = 0,√

3, 2√

3, 3√

3

calculate pseudoscalarmeson correlator withone quark twisted

Expected mesonmomentum

|p| = |θ|L=

0.000 GeV0.217 GeV0.433 GeV0.650 GeV

cf. 2π/L ≈ 0.785 GeV

Tsukuba LQCD&PP 15 Dec 2004 12/17

Page 22: Twisted Boundary Conditions

dDPT: 2

extract effective energies

interpolate to fixedphysical quark masses

extrapolate a→ 0 atfixed quark mass, fixed L

Tsukuba LQCD&PP 15 Dec 2004 13/17

Page 23: Twisted Boundary Conditions

dDPT: 2

extract effective energies

interpolate to fixedphysical quark masses

extrapolate a→ 0 atfixed quark mass, fixed L

relativistic dispersionrelation

E2i j =M2

i j + |θ|2/L2

is well satisfied

Tsukuba LQCD&PP 15 Dec 2004 13/17

Page 24: Twisted Boundary Conditions

dDPT: 3

Dispersion relation test

2

3

4

5

6

7

8

9

0 0.5 1 1.5 2 2.5 3

(r0

E)2

(r0 |θ|/L)2

Tsukuba LQCD&PP 15 Dec 2004 14/17

Page 25: Twisted Boundary Conditions

Partial Twisting

ChPT analysis above was in full QCD

Do you have to twist the sea quarks by the sameamount as the valence quarks?

Tsukuba LQCD&PP 15 Dec 2004 15/17

Page 26: Twisted Boundary Conditions

Partial Twisting

ChPT analysis above was in full QCD

Do you have to twist the sea quarks by the sameamount as the valence quarks?

SV say ‘Not always’

extend analysis to a partially twisted chiral Lagrangiancorresponding to Nv +Ns quarks with Nv ghostquarks

for processes with at most one hadron in externalstates and where shift does not introduce cuts in thecorrelator

Tsukuba LQCD&PP 15 Dec 2004 15/17

Page 27: Twisted Boundary Conditions

Partial Twisting: 2

Example from SV: fK± for untwisted d and s quarks:

fK(L) − fK(∞)

fK(∞)

= −m2π

f 2π

e−mπL

(2πmπL)3/2

94 u untwisted(1

2

i cosθi +34

)

u fully twisted(∑

i cosθi − 34

)

u partially twisted

Tsukuba LQCD&PP 15 Dec 2004 16/17

Page 28: Twisted Boundary Conditions

Applications?

Numerical tests with twisted valence quarks onuntwisted sea quarks: meson dispersion relations,meson decay constants with different meson momenta

Tsukuba LQCD&PP 15 Dec 2004 17/17

Page 29: Twisted Boundary Conditions

Applications?

Numerical tests with twisted valence quarks onuntwisted sea quarks: meson dispersion relations,meson decay constants with different meson momenta

Heavy-to-light semileptonic decays (eg: D→ πlν)

at fixed quark masses: map out full q2 range

chiral extrapolation: generate points at fixedE = v · pπ for different light quarks and avoid fittingto a model FF

Tsukuba LQCD&PP 15 Dec 2004 17/17


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