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Unit 4: Discrete Functions

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PAGE 414 #1 - 3 Warm Up
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Page 1: Unit 4: Discrete Functions

PAGE 414 #1 - 3

Warm Up

Page 2: Unit 4: Discrete Functions

Unit 4: Discrete Functions

Page 3: Unit 4: Discrete Functions

Unit 4: Discrete Functions

Discrete Functions covers topics on patterns, arithmetic and geometric sequences and series and then moves into financial math.

Financial Applications: Simple interest, compound interest, present value, amount of an annuity and present value of an annuity are all covered as applications of financial math.

Page 4: Unit 4: Discrete Functions

Lesson 1: Sequences

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Learning Goals & Success Criteria

β€’ Identify and Classify Sequences

β€’ Create functions for describing sequences and use the sequences to make predictions

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What does the term β€œsequence” mean in everyday language?

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What is the most important aspect of a sequence?

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Sequence

β€’ In mathematics, a sequence is a set of numbers, usually separated by commas, arranged in a particular order.

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Sequences in Our Lives

β€’ Many natural phenomena, such as the spiral patterns seen in seashells, sunflowers, and galaxies, can be represent by sequences

Ex. β€œThe Golden Ratio”

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β€œBeauty is in the phi of the beholder”

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Why does it matter to us in MCR3U?

β€’ Some sequences have very specific patterns and can be represented by mathematical rules or functions.

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Definition: Sequence

β€’ A set of numbers arranged in order.

β€’ This set is identified by a pattern or rule that may stop at some number or it may continue indefinitely.

β€’ Ex. 3, 7, 11, 15,

β€’ Ex. 2, 6, 18, 54, …

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Definition: Sequence

β€’ A function is considered to be a sequence if it’s domain is the set, or a subset, of the natural numbers (positive whole integers) and whose range is the terms of a sequence

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Definition: Term

β€’ a single value (number) or object in a sequence is a term.β€’ Ex. 3, 12, 21, 30, …

β€’ Subscripts are usually used to identify the positions of the terms.β€’ In the example above,

β€’ π‘‘π‘’π‘Ÿπ‘š 1 = 𝑑1 = 3

β€’ π‘‘π‘’π‘Ÿπ‘š 2 = 𝑑2 = 12

β€’ π‘‘π‘’π‘Ÿπ‘š 3 = 𝑑3 = 21

β€’ π‘‘π‘’π‘Ÿπ‘š 4 = 𝑑4 = 30

β€’ π‘‘π‘’π‘Ÿπ‘š 5 = 𝑑5 = _______

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Definition: General Term

β€’ A formula, labelled, 𝑑𝑛, that expresses each term of a sequence as a function of its position.

β€’ Example:

If the general term is 𝑑𝑛 = 2𝑛,

then to calculate the 12th term 𝑑12 , we would substitute 𝑛 = 12 into our general term

𝑑𝑛 = 2𝑛⇒ 𝑑12 = 2 12

𝑑12 = 24

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Definition: Explicit Formula

β€’ A formula that represents any term in a sequence relative to the term number, 𝑛, where 𝑛 ∈ β„• (1, 2, 3,…)

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Example 1: Use the Explicit Formula to Write TermsWrite the first three terms of each sequence, given the explicit formula for the π‘›π‘‘β„Ž term of the sequence 𝑛 ∈ β„• .

a)𝑑𝑛 = 3𝑛2 βˆ’ 1

b)𝑑𝑛 =π‘›βˆ’1

𝑛

Page 19: Unit 4: Discrete Functions

Example 2: Determine Explicit Formulae in Function Notation

For each sequence,

i. Make a table of values using the term number and term.

ii. Calculate the finite differences. (first, second, … until its constant)

iii. Graph the sequence using the ordered pairs from PART i.

iv. Determine an explicit formula for the nth term, using function notation.

a) 7, 12, 17, 22, …b) 1, 10, 25, 46

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Sequences

Arithmetic Geometric+/βˆ’ Γ—

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Definition: Arithmetic Sequence

β€’ A sequence that has the same difference, common difference (𝑑), between any pair of consecutive terms.

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Definition: Explicit Formula

β€’ An explicit formula for the nth term of a sequence can sometimes be determined by finding a pattern among the terms.

Term Number Term

1 π‘Ž

2 π‘Ž + 𝑑

3 π‘Ž + 𝑑 + 𝑑 = ________________

4

5

6

… …

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Definition: Explicit Formula

An arithmetic sequence can be written as π‘Ž, π‘Ž + 𝑑, π‘Ž + 2𝑑, π‘Ž + 3𝑑,…

where 𝒂 is the first term and 𝒅 is the common difference. Then the formula for the general term, or the π‘›π‘‘β„Ž term, of an arithmetic sequence is

𝑑𝑛 = π‘Ž + 𝑛 βˆ’ 1 𝑑,π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

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Definition: Explicit FormulaExpanding & simplifying the right side of the equation allows to rewrite

our General Term Explicit Formula as a FUNCTION!

𝑑𝑛 = π‘Ž + 𝑛 βˆ’ 1 𝑑,π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

𝑑𝑛 = π‘Ž + 𝑑 βˆ™ 𝑛 βˆ’ 𝑑,π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

𝑑𝑛 = 𝑑 βˆ™ 𝑛 + (βˆ’π‘‘ + π‘Ž), π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

Comparable to 𝒇 𝒙 = π’Žπ’™ + 𝒃, with the restriction π‘₯ ∈ β„•

π‘‘π‘’π‘π‘’π‘›π‘‘π‘’π‘›π‘‘π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’

π‘π‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘(π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘ π‘œπ‘Ÿ #) 𝑖𝑛𝑑𝑒𝑝𝑒𝑛𝑑𝑒𝑛𝑑

π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’

π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘ π‘‘π‘’π‘Ÿπ‘š

Page 25: Unit 4: Discrete Functions

So…

β€’ We can see that arithmetic differences have a LINEAR RELATIONSHIP.

β€’ So we that the arithmetic function must be a linear function

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Example 3:

How many terms are there in the following sequence?

1, 4, 7, …, 121

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Example 4:In the arithmetic sequence, 𝑑5 = 16 π‘Žπ‘›π‘‘ 𝑑8 = 25. Find 𝑑1(π‘Ž) and d, π‘“π‘œπ‘Ÿ 𝑑𝑛.

16, ___, ___, 25𝑑5 𝑑6 𝑑7 𝑑8

𝑑8βˆ’π‘‘5= 25-163 differences = 9

3d = 93d/3 = 9/3

d = 3

𝑑𝑛 = π‘Ž + 𝑛 βˆ’ 1 𝑑,π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

If 𝑑5 = 16 & d = 3

β‡’ 𝑑𝑛 = π‘Ž + 𝑛 βˆ’ 1 3β‡’ 𝑑5 = π‘Ž + 5 βˆ’ 1 3β‡’ 16 = π‘Ž + 4 316 = π‘Ž + 1216 βˆ’ 12 = π‘Ž

π‘Ž = 4

∴ 𝒕𝒏 = πŸ’ + 𝒏 βˆ’ 𝟏 πŸ‘, π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑛 ∈ β„•

Page 28: Unit 4: Discrete Functions

Example 5: Length of Ownership

Anna paid $500 for an antique guitar. The guitar appreciates in value by $160 every year. If she sells the guitar for a little over $7000, how long has she owned it?

Page 29: Unit 4: Discrete Functions

Sequences

Arithmetic Geometric+/βˆ’ Γ—/Γ·

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Definition: Geometric Sequences

β€’ A sequence where the ratio, the common ratio, of consecutive terms is a constant.β€’ What operation does ratio refer to?

β€’ Common Ratio: refers to the ratio of any two consecutive terms in a geometric sequence (GS).

Page 31: Unit 4: Discrete Functions

Geometric Sequence

The terms of a GS are obtained by multiplying the first term, π‘Ž, and each subsequent term by a common ratio, π‘Ÿ.

A GS can be written as π‘Ž, π‘Žπ‘Ÿ, π‘Žπ‘Ÿ2, π‘Žπ‘Ÿ3, π‘Žπ‘Ÿ4,…

Then the formula for the general term or the π‘›π‘‘β„Ž term of a GS is

𝑑𝑛 = π‘Žπ‘Ÿπ‘›βˆ’1 π‘€β„Žπ‘’π‘Ÿπ‘’ π‘Ÿ β‰  0 π‘Žπ‘›π‘‘ 𝑛 ∈ β„•

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Geometric Sequence – The Explicit FormulaRewriting the right side of the equation in terms of π‘₯ & 𝑓 π‘₯ allows to

rewrite our General Term Explicit Formula as

a FUNCTION! (an EXPONENTIAL FUNCTION)

𝑑𝑛 = π‘Žπ‘Ÿπ‘›βˆ’1 π‘€β„Žπ‘’π‘Ÿπ‘’ π‘Ÿ β‰  0 π‘Žπ‘›π‘‘ 𝑛 ∈ β„•

Comparable to 𝒇 𝒙 = π‘Žπ‘π‘₯βˆ’1, with the restriction π‘₯ ∈ β„•

π‘‘π‘’π‘π‘’π‘›π‘‘π‘’π‘›π‘‘π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’

π‘π‘œπ‘’π‘“π‘“π‘–π‘π‘–π‘’π‘›π‘‘(π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘ π‘œπ‘Ÿ #)

π‘–π‘›π‘‘π‘’π‘π‘’π‘›π‘‘π‘’π‘›π‘‘π‘£π‘Žπ‘Ÿπ‘–π‘Žπ‘π‘™π‘’

π‘π‘Žπ‘ π‘’

Page 33: Unit 4: Discrete Functions

Example 1: Determine the Type of Sequence

Determine whether each sequence is arithmetic, geometric, or neither. Justify your answer.

a) 2, 5, 10, 17,…

b) 0.2, 0.02, 0.002, 0.0002,…

c)π‘Ž + 2, π‘Ž + 4, π‘Ž + 6, π‘Ž + 8,…

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Example 1: a) 2, 5, 10, 17,…

1. Check if the sequence is arithmetic (i.e., is there a common first difference?)

∴ as there is no common first difference,

we can conclude that this is not an

arithmetic sequence

Term #, n Term, 𝒕𝒏

1 2

2 5

3 10

4 17

First Difference

5 – 2 = 3

10 – 5 = 5

17 – 10 = 7

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Example 1: a) 2, 5, 10, 17,…

2. Check if the sequence is geometric (i.e., is there a common first ratio?)

∴ as there is no common ratio,we can conclude that this is

not a Geometric Sequence

Term #, n Term, 𝒕𝒏

1 2

2 5

3 10

4 17

First Ratio

5

2= 2.5

10

5= 2

17

10= 1.7

Page 36: Unit 4: Discrete Functions

a) 2, 5, 10, 17

b) 0.2, 0.02, 0.002, 0.0002,…

c)π‘Ž + 2, π‘Ž + 4, π‘Ž + 6, π‘Ž + 8,…

Term #, n Term, 𝒕𝒏

1

2

3

4

First Difference Term #, n Term, 𝒕𝒏

1

2

3

4

First Ratio

Page 37: Unit 4: Discrete Functions

Example 2: Write the terms in a GS

Write the first three terms of each GS.

a) 𝑓 𝑛 = 5(3)π‘›βˆ’1

b) 𝑑𝑛 = 161

4

π‘›βˆ’1

c) π‘Ž = 125 π‘Žπ‘›π‘‘ π‘Ÿ = βˆ’2

𝑑𝑛 = π‘Žπ‘Ÿπ‘›βˆ’1 π‘€β„Žπ‘’π‘Ÿπ‘’ π‘Ÿ β‰  0 π‘Žπ‘›π‘‘ 𝑛 ∈ β„•

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Example 3: Determine the number of terms

Determine the number of terms in the GS

4, 12, 36, …, 2916

𝑑𝑛 = π‘Žπ‘Ÿπ‘›βˆ’1 π‘€β„Žπ‘’π‘Ÿπ‘’ π‘Ÿ β‰  0 π‘Žπ‘›π‘‘ 𝑛 ∈ β„•

Page 39: Unit 4: Discrete Functions

Example 4:

Seatbelt use became law in Canada in 1976. Since that time, the number of deaths due to motor vehicle collisions has decreased. From 1984 to 2003, the number of deaths decreased by about 8% every 5 years. The number of deaths due to motor vehicle collisions in Canada in 1984 was approximately 4100.

a) Determine a formula to predict the number of deaths for any fifth year following 1984.

b) Write the number of deaths as a sequence for five 5-year intervals.

𝑑𝑛 = π‘Žπ‘Ÿπ‘›βˆ’1 π‘€β„Žπ‘’π‘Ÿπ‘’ π‘Ÿ β‰  0 π‘Žπ‘›π‘‘ 𝑛 ∈ β„•

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Page 41: Unit 4: Discrete Functions

Homework

β€’ Pg. 424β€’ #1 - 4, 8 - 10, 12, 14 - 17

β€’ Pg. 430β€’ #2 - 4, 6, 8, 9 - 11, 13, 15, 16, 17, 18, 20 - 22.


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