Unit 4 – Unit 4 – Conservation of Conservation of
Mass and Mass and StoichiometryStoichiometry
Cartoon courtesy of NearingZero.net
IonsIonsIonsIons CationCation: A positive ion: A positive ion
MgMg2+2+, NH, NH44++
AnionAnion: A negative ion: A negative ion ClCl, SO, SO44
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Ionic BondingIonic Bonding: Force of attraction : Force of attraction between oppositely charged ions.between oppositely charged ions.
Predicting Ionic ChargesPredicting Ionic Charges
Group 1Group 1::Lose 1 electron to form Lose 1 electron to form 1+1+ ions ions
HH++ LiLi++ NaNa++ KK++
Predicting Ionic ChargesPredicting Ionic Charges
Group 2Group 2::Loses 2 electrons to form Loses 2 electrons to form 2+2+ ions ions
BeBe2+2+ MgMg2+2+ CaCa2+2+ SrSr2+2+ BaBa2+2+
Predicting Ionic ChargesPredicting Ionic ChargesGroup 13Group 13:: Loses 3 Loses 3 electrons to form electrons to form 3+3+ ions ions
BB3+3+ AlAl3+3+ GaGa3+3+
Predicting Ionic ChargesPredicting Ionic ChargesGroup 14Group 14:: Lose 4 Lose 4 electrons or gain electrons or gain 4 electrons?4 electrons?
Neither! Neither! Group 13 Group 13 elements rarely elements rarely form ions.form ions.
Predicting Ionic ChargesPredicting Ionic ChargesGroup 15Group 15:: Gains 3 Gains 3 electrons to form electrons to form 3-3- ions ions
NN3-3-
PP3-3-
AsAs3-3-
Nitride
Phosphide
Arsenide
Predicting Ionic ChargesPredicting Ionic ChargesGroup 16Group 16:: Gains 2 Gains 2 electrons to form electrons to form 2-2- ions ions
OO2-2-
SS2-2-
SeSe2-2-
Oxide
Sulfide
Selenide
Predicting Ionic ChargesPredicting Ionic ChargesGroup 17Group 17:: Gains 1 Gains 1 electron to form electron to form 1-1- ions ions
FF1-1-
ClCl1-1-
BrBr1-1-Fluoride
Chloride
Bromide
II1-1- Iodide
Predicting Ionic ChargesPredicting Ionic ChargesGroup 18Group 18:: Stable Stable Noble gases Noble gases do do notnot form ions! form ions!
Predicting Ionic ChargesPredicting Ionic ChargesGroups 3 - Groups 3 - 1212::
Many Many transitiontransition elements elements have more than one possible oxidation have more than one possible oxidation state.state.Iron(II) = Fe2+ Iron(III) = Fe3+
Predicting Ionic ChargesPredicting Ionic ChargesGroups 3 - Groups 3 - 1212::
Some Some transitiontransition elements elements have only one possible oxidation state.have only one possible oxidation state.
Zinc = Zn2+ Silver = Ag+
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Barium nitrate
1. Write the formulas for the cation and anion, including CHARGES!
BaBa2+2+ NONO33--2. Check to see if charges are
balanced.
3. Balance charges , if necessary, using subscripts. Use parentheses if you need more than one of a polyatomic ion.
Not balanced!
( )( ) 22
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Ammonium sulfate
1. Write the formulas for the cation and anion, including CHARGES!
NHNH44++ SOSO44
2-2-2. Check to see if charges are balanced.
3. Balance charges , if necessary, using subscripts. Use parentheses if you need more than one of a polyatomic ion.
Not balanced!
( )( )22
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Iron(III) chloride
1. Write the formulas for the cation and anion, including CHARGES!
FeFe3+3+ClCl--2. Check to see if charges are balanced.
3. Balance charges , if necessary, using subscripts. Use parentheses if you need more than one of a polyatomic ion.
Not balanced!
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Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Aluminum sulfide
1. Write the formulas for the cation and anion, including CHARGES!
AlAl3+3+ SS2-2-2. Check to see if charges are balanced.
3. Balance charges , if necessary, using subscripts. Use parentheses if you need more than one of a polyatomic ion.
Not balanced!
22 33
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Magnesium carbonate
1. Write the formulas for the cation and anion, including CHARGES!
MgMg2+2+ COCO332-2-2. Check to see if
charges are balanced.
They are balanced!
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Zinc hydroxide
1. Write the formulas for the cation and anion, including CHARGES!
ZnZn2+2+ OHOH--2. Check to see if charges are balanced.
3. Balance charges , if necessary, using subscripts. Use parentheses if you need more than one of a polyatomic ion.
Not balanced!
( )( )22
Writing Ionic Compound Writing Ionic Compound FormulasFormulas
Example: Aluminum phosphate
1. Write the formulas for the cation and anion, including CHARGES!
AlAl3+3+ POPO443-3-2. Check to see if charges are
balanced.
They ARE balanced!
Naming Ionic CompoundsNaming Ionic CompoundsNaming Ionic CompoundsNaming Ionic Compounds• 1. 1. Cation first, then anionCation first, then anion
• 2. Monatomic cation = name of the 2. Monatomic cation = name of the elementelement
• CaCa2+2+ = calcium = calcium ionion
• 3. Monatomic anion = 3. Monatomic anion = rootroot + + --ideide
• ClCl = chlor = chlorideide
• CaClCaCl22 = calcium chlor= calcium chlorideide
Naming Ionic CompoundsNaming Ionic Compounds(continued)(continued)
Naming Ionic CompoundsNaming Ionic Compounds(continued)(continued)
• -- some some metal forms more than one metal forms more than one cationcation
• -- use use Roman numeralRoman numeral in namein name
• PbClPbCl22
• PbPb2+2+ is cationis cation
• PbClPbCl22 = lead( = lead(IIII) chloride) chloride
Metals with multiple oxidation Metals with multiple oxidation statesstates
Naming Binary CompoundsNaming Binary CompoundsNaming Binary CompoundsNaming Binary Compounds• -- Compounds between two Compounds between two nonmetalsnonmetals• -- First element First element in the formula is in the formula is named firstnamed first..• -- Second element Second element is named as if it were an is named as if it were an
anionanion..• -- Use prefixesUse prefixes• -- Only use Only use monomono on second element - on second element -
PP22OO55 ==COCO22 = =
CO =CO =
NN22O =O =
didiphosphorus phosphorus pentpentoxideoxide
carbon carbon didioxideoxide
carbon carbon monmonoxideoxide
didinitrogen nitrogen monmonoxideoxide
Calculating Formula MassCalculating Formula MassCalculate the formula mass of magnesium Calculate the formula mass of magnesium carbonate, MgCOcarbonate, MgCO33..
24.31 g + 12.01 g + 3(16.00 g) 24.31 g + 12.01 g + 3(16.00 g) ==
84.32 g84.32 g
Calculating Percentage Calculating Percentage CompositionComposition
Calculate the percentage composition of Calculate the percentage composition of magnesium carbonate, MgCOmagnesium carbonate, MgCO33..
From previous slide:From previous slide:24.31 g + 12.01 g + 3(16.00 g) = 24.31 g + 12.01 g + 3(16.00 g) = 84.32 g84.32 g 24.31
100 28.83%84.32
Mg 12.01
100 14.24%84.32
C 48.00
100 56.93%84.32
O
100.00
FormulasFormulas
molecular formula = (empirical molecular formula = (empirical formula)formula)nn [ [nn = integer] = integer]
molecular formula = Cmolecular formula = C66HH66 = (CH) = (CH)66
empirical formula = CHempirical formula = CH
Empirical formula: the lowest whole number ratio of atoms in a compound.
Molecular formula: the true number of atoms of each element in the formula of a compound.
FormulasFormulas (continued)(continued)
Formulas for Formulas for ionic compoundsionic compounds are are ALWAYSALWAYS empirical (lowest whole empirical (lowest whole number ratio).number ratio).Examples:Examples:
NaCl MgCl2 Al2(SO4)3 K2CO3
FormulasFormulas (continued)(continued)
Formulas for Formulas for molecular compoundsmolecular compounds MIGHTMIGHT be empirical (lowest whole be empirical (lowest whole number ratio).number ratio).
Molecular:Molecular:
H2O
C6H12O6 C12H22O11
Empirical:
H2O
CH2O C12H22O11
Empirical Formula Empirical Formula DeterminationDetermination
1.1. Base calculation on 100 grams of Base calculation on 100 grams of compound. compound.
2.2. Determine moles of each element in 100 Determine moles of each element in 100 grams of compound.grams of compound.
3.3. Divide each value of moles by the Divide each value of moles by the smallest of the values.smallest of the values.
4.4. Multiply each number by an integer to Multiply each number by an integer to obtain all whole numbers.obtain all whole numbers.
Empirical Formula Empirical Formula DeterminationDetermination
Adipic acid contains 49.32% C, 43.84% O, and 6.85% H by mass. What is the empirical formula of adipic acid?
49.32 14.107
12.01
g C mol Cmol C
g C
6.85 16.78
1.01
g H mol Hmol H
g H
43.84 12.74
16.00
g O mol Omol O
g O
Empirical Formula Empirical Formula DeterminationDetermination
(part 2)(part 2)
4.1071.50
2.74
mol C
mol O
6.782.47
2.74
mol H
mol O
2.741.00
2.74
mol O
mol O
Divide each value of moles by the Divide each value of moles by the
“smolest” “smolest” of the values.of the values.
Carbon:Carbon:
Hydrogen:Hydrogen:
Oxygen:Oxygen:
Empirical Formula Empirical Formula DeterminationDetermination
(part 3)(part 3)Multiply each number by an integer to Multiply each number by an integer to obtain all whole numbers.obtain all whole numbers.
Carbon: 1.50Carbon: 1.50 Hydrogen: 2.50Hydrogen: 2.50 Oxygen: 1.00Oxygen: 1.00x 2 x 2 x 2
33 55 22
Empirical formula:C3H5O
2
Finding the Molecular Finding the Molecular FormulaFormula
The empirical formula for adipic acid The empirical formula for adipic acid is Cis C33HH55OO22. The molecular mass of . The molecular mass of adipic acid is 146 g/mol. What is the adipic acid is 146 g/mol. What is the molecular formula of adipic acid?molecular formula of adipic acid?
1. Find the formula mass of 1. Find the formula mass of CC33HH55OO22
3(12.01 g) + 5(1.01) + 2(16.00) = 3(12.01 g) + 5(1.01) + 2(16.00) = 73.08 g73.08 g
Finding the Molecular Finding the Molecular FormulaFormula
The empirical formula for adipic acid The empirical formula for adipic acid is Cis C33HH55OO22. The molecular mass of . The molecular mass of adipic acid is 146 g/mol. What is the adipic acid is 146 g/mol. What is the molecular formula of adipic acid?molecular formula of adipic acid?
3(12.01 g) + 5(1.01) + 2(16.00) = 3(12.01 g) + 5(1.01) + 2(16.00) = 73.08 g73.08 g
2. Divide the molecular mass by 2. Divide the molecular mass by the mass given by the emipirical the mass given by the emipirical formula.formula.
1462
73