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Unit 8, Chapter 27 CPO Science Foundations of Physics.

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Unit 8, Chapter 27 CPO Science Foundations of Physics
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Page 1: Unit 8, Chapter 27 CPO Science Foundations of Physics.

Unit 8, Chapter 27

CPO ScienceFoundations of Physics

Page 2: Unit 8, Chapter 27 CPO Science Foundations of Physics.

Unit 8: Matter and Energy

27.1 Properties of Solids

27.2 Properties of Liquids and Fluids

27.3 Properties of Gases

Chapter 27 The Physical Properties of Matter

Page 3: Unit 8, Chapter 27 CPO Science Foundations of Physics.

Chapter 27 Objectives1. Perform calculations involving the density of solids,

gases, and liquids.

2. Apply the concepts of force, stress, strain, and tensile strength to simple structures.

3. Describe the cause and some consequences of thermal expansion in solids, liquids, and gases.

4. Explain the concept of pressure and calculate pressure caused by the weight of fluids.

5. Explain how pressure is created on a molecular level.

6. Understand and apply Bernoulli’s equation to flow along a streamline.

7. Apply the gas laws to simple problems involving pressure, temperature, mass, and volume.

Page 4: Unit 8, Chapter 27 CPO Science Foundations of Physics.

Chapter 27 Vocabulary Terms stress density strain tensile

strength cross section

area pressure volume tension compression elastic,

elasticity

fluid brittle ductile safety factor modulus of

elasticity alloy airfoil buoyancy fluid

mechanics ideal gas law

Boyle’s law streamline laminar flow turbulent flow Bernoulli’s

equation pascal (Pa) Charles’ law gas constant (R) composite

material thermal

expansion

Page 5: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of Solids

Key Question:

How do you measure the strength of a solid material?

*Students read Section 27.1 AFTER Investigation 27.1

Page 6: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of Solids

The density of a material is the ratio of mass to volume.

Density is a physical property of the material and stays the same no matter how much material you have.

Page 7: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Density

= m V

Mass (kg)

Volume (m3 or L)

Density (kg/m3)

Most engineers and scientists use the greek letter rho (ρ) to represent density.

Page 8: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Densities of Common Materials

Which materials are less dense than water?

Page 9: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of Solids The concept of physical

“strength” means the ability of an object to hold its form even when force is applied.

To evaluate the properties of materials, it is sometimes necessary to separate out the effects of design, such as shape and size.

Page 10: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Stress The stress in a material is the ratio of the force

acting through the material divided by the cross section area through which the force is carried.

The metric unit of stress is the pascal (Pa). One pascal is equal to one newton of force per

square meter of area (1 N/m2).

= F A

Force (N)

Area (m2)

Stress (N/m2)

Page 11: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of Solids

Page 12: Unit 8, Chapter 27 CPO Science Foundations of Physics.

26.1 Properties of Solids

A thicker wire can support more force at the same stress as a thinner wire because the cross section area is increased.

Page 13: Unit 8, Chapter 27 CPO Science Foundations of Physics.

26.1 Tensile strength

The tensile strength is the stress at which a material breaks under a tension force.

The tensile strength also describes how materials break in bending.

Page 14: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Tensile strength

Page 15: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of solids

The safety factor is the ratio of how strong something is compared with how strong it has to be.

The safety factor allows for things that might weaken the wire (like rust) or things you did not consider in the design (like heavier loads).

A safety factor of 10 means you choose the wire to have a breaking strength of 10,000 newtons, 10 times stronger than it has to be.

Page 16: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Evaluate 3 Designs

Three designs have been proposed for supporting a section of road. Each design uses three supports spaced at intervals along the road. A total of 4.5 million N of force is required to hold up the road. Evaluate the strength of each design. The factor of safety must be 5 or higher even when the road is

bumper-to-bumper on all 4 lanes with the heaviest possible trucks.

Page 17: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Evaluate Design #1

High strength steel tubes Cross section = 0.015 m2

Tensile strength = 600 Mpa

Page 18: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Evaluate Design #2

Aluminum alloy tubes Cross section = 0.015 m2

Tensile strength = 290 Mpa

Page 19: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Evaluate Design #3

Steel cables Cross section = 0.03 m2

Tensile strength = 400 Mpa

Page 20: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of solids

Elasticity measures the ability of a material to stretch.

The strain is the amount a material has been deformed, divided by its original size.

Page 21: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Strain The Greek letter epsilon (ε) is usually used

to represent strain.

=l l

Change in length (m)

Original length (m)

Strain

Page 22: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of solids The modulus of elasticity

plays the role of the spring constant for solids.

A material is elastic when it can take a large amount of strain before breaking.

A brittle material breaks at a very low value of strain.

Page 23: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Modulus of Elasticity

Page 24: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Stress for solids Calculating stress for solids is similar

to using Hooke's law for springs.

Stress and strain take the place of force and distance in the formula:

= -E

Modulus ofelasticity (pa)

StrainStress (Mpa)

Page 25: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Properties of solids

The coefficient of thermal expansion describes how much a material expands for each change in temperature.

Concrete bridges always have expansion joints.

The amount of contraction or expansion is equal to the temperature change times the coefficient of thermal expansion.

Page 26: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Thermal Expansion

l = (T2-T1)

l

Change in temperature (oC)

Original length (m)

Coefficient of thermal expansionChange in length (m)

Page 27: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Thermal Expansion

Which substances will expand or contract the most with temperature changes?

Page 28: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Plastic

Plastics are solids formed from long chain molecules.

Different plastics can have a wide range of physical properties including strength, elasticity, thermal expansion, and density.

Page 29: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Metal Metals that bend and stretch easily without cracking

are ductile. The properties of metals can be changed by mixing

elements. An alloy is a metal that is a mixture of more than one

element. Steel is an alloy.

Page 30: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Wood Many materials have different properties in

different directions. Wood has a grain that is created by the way

trees grow.

Wood is very difficult to break against the grain, but easy to break along the grain.

A karate chop easily breaks wood along its grain.

Page 31: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.1 Composite materials Composite materials are

made from strong fibers supported by much weaker plastic.

Like wood, composite materials tend to be strongest in a preferred direction.

Fiberglass and carbon fiber are two examples of useful composite materials.

Page 32: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of Liquids and FluidsKey Question:

What are some implications of Bernoulli’s equation?

*Students read Section 27.2 AFTER Investigation 27.2

Page 33: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of Liquids and Fluids

Fluids can change shape and flow when forces are applied to them.

Gas is also a fluid because gases can change shape and flow.

Density, buoyancy and pressure are three properties exhibited by liquids and gases.

Page 34: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Density vs. Buoyancy

The density of a liquid is the ratio of mass to volume, just like the density of a solid.

An object submerged in liquid feels an upward force called buoyancy.

The buoyancy force is exactly equal to the weight of liquid displaced by the object.

Objects sink if the buoyancy force is less than their own weight.

Page 35: Unit 8, Chapter 27 CPO Science Foundations of Physics.
Page 36: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Pressure Forces applied to

fluids create pressure instead of stress.

Pressure is force per unit area, like stress.

A pressure of 1 N/m2 means a force of one newton acts on each square meter.

Page 37: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Pressure Like stress, pressure is a ratio of force per

unit area.

Unlike stress however, pressure acts in all directions, not just the direction of the applied force.

Page 38: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Pressure The concept of pressure is

central to understanding how fluids behave within themselves and also how fluids interact with surfaces, such as containers.

If you put a box with holes underwater, pressure makes water flow in from all sides.

Pressure exerts equal force in all directions in liquids that are not moving.

Page 39: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases Gravity is one cause of

pressure because fluids have weight.

Air is a fluid and the atmosphere of the Earth has a pressure.

The pressure of the atmosphere decreases with altitude.

Page 40: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases

The pressure at any point in a liquid is created by the weight of liquid above that point.

Page 41: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Pressure in liquids The pressure at the same depth is the same

everywhere in any liquid that is not moving.

P = g d

Density (kg/m3)

Depth (m)

Pressure (pa or N/m2)

Strength of gravity (9.8 N/kg)

Page 42: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Calculate pressure Calculate the pressure

1,000 meters below the surface of the ocean.

The density of water is 1,000 kg/m3.

The pressure of the atmosphere is 101,000 Pa.

Compare the pressure 1,000 meters deep with the pressure of the atmosphere.

Page 43: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases Pressure comes from collisions between atoms

or molecules.

The molecules in fluids (gases and liquids) are not bonded tightly to each other as they are in solids.

Molecules move around and collide with each other and with the solid walls of a container.

Page 44: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Pressure and forces Pressure creates force on surfaces.

The force is equal to the pressure times the area that contacts the molecules.

F = P A

Pressure (N/m2)

Area (m2)Force (N)

Page 45: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Calculate pressure

A car tire is at a pressure of 35 psi.

Four tires support a car that weighs 4,000 pounds.

Each tire supports 1,000 pounds.

How much surface area of the tire is holding up the car?

Page 46: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Motion of fluids The study of motion of fluids is called fluid

mechanics. Fluids flow because of differences in pressure. Moving fluids usually do not have a single

speed.

Page 47: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases A flow of syrup down a

plate shows that friction slows the syrup touching the plate.

The top of the syrup moves fastest because the drag from friction decreases away from the plate surface.

Page 48: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases Pressure and

energy are related.

Differences in pressure create potential energy in fluids just like differences in height create potential energy from gravity

Page 49: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases Pressure does work

as fluids expand.

A pressure of one pascal does one joule of work pushing one square meter a distance of one meter.

Page 50: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Energy in fluids The potential energy is equal to volume

times pressure.

E = P V

Pressure (N/m2)

Volume (m3)Potentialenergy

(J)

Page 51: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Energy in fluids The total energy of a small mass of fluid is

equal to its potential energy from gravity (height) plus its potential energy from pressure plus its kinetic energy.

Page 52: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Energy in fluids The law of conservation

of energy is called Bernoulli’s equation when applied to a fluid.

Bernoulli’s equation says the three variables of height, pressure, and speed are related by energy conservation.

Page 53: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Bernoulli's Equation If one variable increases, at least one of the other

two must decrease. If the fluid is not moving (v = 0), then Bernoulli’s

equation gives us the relationship between pressure and depth (negative height).

Page 54: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Properties of liquids and gases Streamlines are imaginary lines drawn to

show the flow of fluid. We draw streamlines so that they are

always parallel to the direction of flow. Fluid does not flow across streamlines.

Page 55: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Applying Bernoulli's equation

The wings of airplanes are made in the shape of an airfoil.

Air flowing along the top of the airfoil (B) moves faster than air flowing along the bottom of the airfoil (C).

Page 56: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Calculating speed of fluids

Water towers create pressure to make water flow.

At what speed will water come out if the water level in the tower is 50 meters higher than the faucet?

Page 57: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.2 Fluids and friction Viscosity is caused by forces

that act between atoms and molecules in a liquid.

Friction in fluids also depends on the type of flow.

Water running from a faucet can be either laminar or turbulent depending on the rate of flow.

Page 58: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Properties of Gases

Key Question:

How much matter is in a gas?

*Students read Section 27.3 AFTER Investigation 27.3

Page 59: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Properties of Gases

Air is the most important gas to living things on the Earth.

The atmosphere of the Earth is a mixture of nitrogen, oxygen, water vapor, argon, and a few trace gases.

Page 60: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Properties of Gases

An object submerged in gas feels an upward buoyant force.

You do not notice buoyant forces from air because the density of ordinary objects is so much greater than the density of air.

The density of a gas depends on pressure and temperature.

Page 61: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Boyle's Law If the mass and temperature are kept constant, the

product of pressure times volume stays the same.

P1V1 = P2V2

Original volume (m3)

Original pressure(N/m2)

Final pressure (N/m2)

Final volume (m3)

Page 62: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Calculate using Boyle's law A bicycle pump creates

high pressure by squeezing air into a smaller volume.

If air at atmospheric pressure (14.7 psi) is compressed from an initial volume of 30 cubic inches to a final volume of three cubic inches, what is the final pressure?

Page 63: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Charles' Law If the mass and volume are kept constant, the

pressure goes up when the temperature goes up.

Original temperture

(k)

Original pressure(N/m2)

Final pressure (N/m2)

Final temperature (K)

P1 = P2

T1 T2

Page 64: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Calculate using Charles' law

A can of hair spray has a pressure of 300 psi at room temperature (21°C or 294 K).

The can is accidentally moved too close to a fire and its temperature increases to 800°C (1,073 K).

What is the final pressure in the can?

Page 65: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Ideal gas law

The ideal gas law combines the pressure, volume, and temperature relations for a gas into one equation which also includes the mass of the gas.

In physics and engineering, mass (m) is used for the quantity of gas.

In chemistry, the ideal gas law is usually written in terms of the number of moles of gas (n) instead of the mass (m).

Page 66: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Gas Constants

The gas constants are different because the size and mass of gas molecules are different.

Page 67: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Ideal gas law If the mass and temperature are kept constant, the

product of pressure times volume stays the same.

P V = m R T

Volume (m3)

Pressure(N/m2)

gas constant (J/kgK)

Temperature (K)Mass

(kg)

Page 68: Unit 8, Chapter 27 CPO Science Foundations of Physics.

27.3 Calculate using Ideal gas law Two soda bottles contain the

same volume of air at different pressures.

Each bottle has a volume of 0.002 m3 (two liters).

The temperature is 21°C (294 K). One bottle is at a gauge pressure

of 500,000 pascals (73 psi). The other bottle is at a gauge

pressure of zero. Calculate the mass difference

between the two bottles.

Page 69: Unit 8, Chapter 27 CPO Science Foundations of Physics.

Application: The Deep Water Submarine Alvin


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