UW- Arch 365- Joris Voorn Chair

Musical Thrown Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058

- Joris Voorn

Joris Voorn,

Thank you. The inspiration you have provided as a distant figure is unparalleled. Meeting you aboard the En-terprise 2000, Vibrations boat cruise in Toronto even surpassed my expectations. To be able to exchange ideas with some, one who has similar passions, if not the exact same, is something so rare, as we both come from a background with an education in architecture, and a love for electronic dance music. The relation between architecture and electronic (house) music is un-canny, not only in principle, but also in feeling. The constructions of either a set, or a track, are easily related to a concept and a component respectively, as are the provocative repetition and rhythm. None the less the progression of a concept in both go through multiple iterations and con-tinuous change, as projects never finish, only go on hold for new ideas.

Balance 014 (Album) both CD1 MIZUIRO and CD2 MIDORI are a great example of this, a contrast of space and feeling. Mizuiro being this time elapsed big night out with great music, a transformable space, allowing the many smaller components to build through out the CD into a feeling of a larger scale. The connection of scale reflects that of space and sound. It is here that you get darker more melodic place, as if the night was to end and the sunrise was near. The transition between Mizuiro and Midori almost comes too soon, leaving you wanting more, which allows for the surprise of about what’s to come next. The tempo changes drastically in a few tracks allowing for a change in pace and scale. From Large and Dark to Intimate and Uplifting. It remains melodic and repetitive, however it allows the adrenaline previously built to dissipate. However not to quickly, with a level of care and consideration that contrasts to many of your peers who so suddenly stop. Leaving you wanting much more.

The same descriptions, based upon my interpretation, I believe in many ways can be used to depict an image of architecture. Dark, melodic, repetitive, scale, all drawing the same level of impact on an individual. Even con-sidering the transition between the two CDs, it is in many ways the shift between work and play that blurs the boundary so well.

This album being so inspirational, has lead me to choose you, as my client to design a chair for my Structural Design Build class this term. Based upon the Balance album that makes me truly feel architecture and emotion through sound, yet blurs the line between work and play. In both fields (Architecture or Music) there is a neces-sity to do the very same thing, and love what we do. The chair in essence will be just that, a transition between play and work, and a functional place to release ideas of music or design.

So thank you one last time.

“Music and architecture each require complete devotion.” –Joris VoornI couldn’t agree more.

I hope this letter finds you well. Geoff Bagga – Jeans

University of Waterloo : School of Architecture [3B]

MANIFESTOGeoff Bagga - Jeans - 20245053

Snehjot Bumrah - 20271058- a letter to Joris Voorn

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Chair 1






Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058

WEIGHT OF THE CHAIR

Volume of the Chair:

Panels: 0.457m x 0.4064m x 0.05m = 0.00928624 m3 x 4 panels = 0.03714496 m3

Base: 0.465m x 0.6096m x 0.05m x 2 panels = 0.0283464 m3

Total volume of the chair: 0.03714496 m3 + 0.0283464 m3 = 0.0654913 m3

Density of Birch plywood: 680‐700 Kg/m3

Total mass of Chair: 680Kg/m3 x 0.0654913m3 = 44.534 Kg

Total Weight of Chair: 44.534 Kg x 9.98 N/Kg = 444.45 N

REACTIONS OF THE CHAIR

Storage Form:

Weight of Half Chair: 222.2 N

W1= 111.1 N

W2= 111.1 N

Analysis

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Analysis

M@R1= 0

R2x0.457m = (W1 x 0.114m) (W2 x 0.342m)

R2 = 110.8 N

R1=222.2N – 110.8 N

R1=111.34 N

Chair position:

W= 444.44 N

M@R1 = 0

R2 (18”) = W (9”)

R2= 444.44 (9)/18

R2 = 222.22 N

Therefore:

R1= 222.22 N


With Body (Worst Case Loading)

W1= 444.44 N

P1= 800N

P2= 100 N

R1= 222.22 N

R2= 1022.22 N

R3 = 100 N

With Body (Position 2)

W1= 444.44 N

P1= 800N

P2= 100 N

R1= 222.22 N

R2= 222.22 N

R3= 900 N

Analysis


Table Position:

Analysis


W1= 0.00928624 m3 x 680 Kg/m3 x 9.98 N/Kg = 63.13 N (1 panel)

W2= 126.26 N (2 panels)

W3= 255.04 N

R1= W1 + (W2/2) = 189.39 N

R2= (W2/2)+(W3/2) = 190.75 NR3= W3/2 = 127.52 N

With Equipment:

E1 (CDJ)= 3.9 Kg x 2 x9.98 N/Kg = 77.84 N

E2 (Machine) = 1.6 Kg x 9.98 N/Kg = 15.96 N

E3 (Mixer) = 5 Kg x 9.98 N/Kg = 49.98 N

Analysis

W1= 0.00928624 m3 x 680 Kg/m3 x 9.98 N/Kg = 63.13 N (1 panel)

W2= 126.26 N (2 panels)

W3= 255.04 N

R1= W1 + (W2/2) = 189.39 N

R2= (W2/2)+(W3/2) = 190.75 NR3= W3/2 = 127.52 N

With Equipment:

E1 (CDJ)= 3.9 Kg x 2 x9.98 N/Kg = 77.84 N

E2 (Machine) = 1.6 Kg x 9.98 N/Kg = 15.96 N

E3 (Mixer) = 5 Kg x 9.98 N/Kg = 49.98 N


R1= 189.39 N + E2 = 205.35 N

R2= 190.7 N + E1 = 268.59 N

R3= 127.53 N + (E3/2) = 151.97 N

CENTRE OF GRAVITY

*Note: All components of the chair are Plywood.

Storage Position

I Bi Hi Ti Vi Xi ViXi Yi YiXi 1 9” 22” 4”* 792 in3 4” 3168

in4 16” 12672

in 4 2 8” 22” 4”* 704 in3 23” 16192

in4 8” 5632

in 4 3 10” 22” 4”* 880 in3 14” 12320

in4 11” 9680

in 4 4 20” 8” 16” 2560

in3 10” 25600

in4 26” 66560

in4 4936

in3 57280

in4 94544

in4 *The reduced thinkness doe the base elements is to accommodate for the voids present within the base for storage. X= ViXi Y = ViYi Vi Vi

X = 57280 in4 Y = 94544 in4 4936 in3 4936 in3 X = 11.6 in Y = 19.15 in

Analysis


P = Mx/H F= ℳN P= (444.44 N)(11.6 in) F= (0.5) (444.44 N) 30” F= 222.22 N P= 171.85 N Since the force applied is smaller than Friction (222.22 N), the chair’s force in its storage position, the chair will tip with 171.85 N of force. P = My/H F= ℳN P= (444.44 N)(19.5 in) F= (0.5) (444.44 N) 19” F= 222.22 N P= 456.13 N Since the force applied is larger than Friction, the chair will require 456.13 N of force to move in its storage position. *Note: This does not account for the metal stabilizing rods attached to the base.

Chair Position


in4 16” 12672

in 4 2 8” 22” 4”* 704 in3 23” 16192

in4 8” 5632 in

4 3 10” 22” 4”* 880 in3 14” 12320

in4 11” 9680 in

4 4 4” 39” 16” 2496

in3 19” 47424

in4 41.5” 103584

in 4 4872

in3 79104

in4 131568

in4

Analysis


X= ViXi Y = ViYi Vi Vi

X = 79104 in4 Y = 131568 in4 4872 in3 4872 in3 X = 16.23 in Y = 27.00 in P = Mx/H F= ℳN P= (444.44 N)(16.23 in) F= (0.5) (444.44 N) 61” F= 222.22 N P= 118.25 N Since the force applied is smaller than Friction, the chair will tip forwards with 118.25 N of force. *This is not accounting for the role of the metal stabilizing bars that are attached to the base.

P = My/H F= ℳN P= (444.44 N)(27.00 in) F= (0.5) (444.44 N) 19” F= 222.22 N P= 631.5 N Since the force applied is larger than the force of friction, the chair requires 631.5 N of force to move in the direction perpendicular to the pannels.

Table Position:


in4 16” 12672

in 4 2 8” 22” 4”* 704 in3 23” 16192

in4 8” 5632 in

4 3 10” 22” 4”* 880 in3 14” 12320

in4 11” 9680 in

4 4 54” 2” 16” 1728

in3 46” 79488

in4 23” 39744

in4 5 2” 24” 16” 768 in3 64” 49152

in4 12” 9216

in4 4872

in3 160321

in4 76944

in4

Analysis


X= ViXi Y = ViYi Vi Vi

X = 160321 in4 Y = 76944 in4 4872 in3 4872 in3 X = 32.90 in Y = 15.79 in P = Mx/H F= ℳN P= (444.44 N)(32.90 in) F= (0.5) (444.44 N) 24” F= 222.22 N P= 609.25 N Since the force applied is larger than Friction, the table will slide on a wodden surface. P = My/H F= ℳN P= (444.44 N)(15.79 in) F= (0.5) (444.44 N) 54” F= 222.22 N P= 129.95 N Since the force applied is smaller than Friction, the table will tip is pushed close to the leg. FBD -‐See next page-‐

Analysis


RACKING (Qualitative Analysis) Due to the large mass, and the method of rigid construction, we are confident that there is very little movement in terms of racking in the chair. Out base is very solid in construction, and acts a singular piece, transferring all the moment within it, therefore resisting any possible racking. There is however some movement that occurs in the Hinges when the chair is in its Storage Formation. The joints tend to skew a little bit due to the allowance given between each join to allow for the transformations. The locking pieces around the hinges prevent this movement when the panels are locked into one another in a used formation. -‐See next page for diagrams-‐

BEAMS AND COLUMNS ANALYSIS W1= weight of body=800N W2=dead weight of chair panels= 63.13 N x 4 = 252.52 N W3= chair base= 191.92 N Beam 1: -‐See next page for diagrams-‐

M@R1=0 R2= (W1 x 0.2285m) + (W2 x 0.457m) / 0.457m R2= 652.52 N R1= 400 N R2= 652.52 N Vmax= 650 N Mmax=0.0914 kN/m Fb=M/S S=bh^2/6 Fb= 0.148525 kN/m S= (0.457m)(0.0508m)^2 0.000196558m3 6 Fb= 755.85 kPa S= 0.000196558 m3 Fv= 3V/2A Fv= 3(0.650 kN) 2(0.457 x 0.0508) Fv= 41.997 kPa

Analysis


Beam 2: -‐See next page for diagrams-‐

R1= 400 N + (191.92 N/2) = 495.96N R2= 652.52 N + (191.92 N/2) = 748.48 N Vmax= 95.96 N Mmax= 0.02192 kN/m Fb=M/S S=bh^2/6 Fb= 0.02192 kN/m S= (0.457m)(0.0254m)^2 0.0004991678m3 6 Fb= 43.93 kPa S= 0.0004991678 m3 Fv= 3V/2A Fv= 3(0.09596 kN) 2(0.457 x 0.0508) Fv= 6.2160 kPa Column 2: -‐See next page for diagrams-‐

P1= ? P2= ? R1= 400 N Slope: 11/4 P1=400N x 11/11.7 P1= 376.06 N P2= 400N x 4/11.7 P2= 136.7 N Arect= (0.0311m)(0.4064m) Arect= 0.01263904 m2 Fa= P/A Fa= (0.376 kN)/(0.01263904 m2) Fa= 29.75 kPa M = P2 = 136.7 N

Analysis


Column 1: -‐See next page for diagrams-‐

P1= ? P2= ? R1= 652.52 N Slope: 11/4 P1= 652.52 N x 11/11.7 P1= 613.48 N P2= 625.52 N x 4/11.7 P2= 223.1 N Arect= (0.0311m)(0.4064m) Arect= 0.01263904 m2 Fa= P/A Fa= (0.613 kN)/(0.01263904 m2) Fa= 48.50 kPa M = P2 = 223.1 N Deflection: (Beam 1 a.k.a. Seat) E (for plywood)= 12.4 GPa Δ max= 5 wl/384 EI I=bh^3/12 Δ max= 5(0.8 kN)(0.4064m) I= (0.457m)(0.0508m^3)/12 384 (12.4 x10^6 kPa)(4.99 x 10^-‐6) I= 4.99 x10^-‐6 Δ max= 6.6 x 10 ^-‐5 m JOING ANALYSIS * Worst case loading analyzed for joints in the Table position since all the joints are made the same. -‐See next page for diagrams-‐

L= 0.4064 m W= 800 N A= 0.127 m W1= 21.55 kN/m W2= 7.60 kN/m B= 0.1046

Analysis


V: W= (l-‐2b)(w1+w2)

2 M: W a + bW(l-‐b) = W1(l-‐b) (l-‐b)

2 2 3 2 3 Derived Formulas: W2= 3 W a b (l-‐b)^3 + b^3 + 3b^2l W2= 3(0.8 kN)(0.127m)(.0146m) (0.3017m)^3 + (0.1046m)^3 – 3(0.1046m)^2(0.4064m) W2= 7.60 kN/m B= l (2l-‐3a 6 (l-‐a) B= (0.4064m)(2(0.4064m)-‐3(0.127m)) 6 (0.4064m – 0.127m) B= 0.1046 m L-‐B= 0.3017m W1= W2 (l-‐b) B W1= (7.6kN/m)(0.3017m) 0.1064m W1= 21.552 kN/m Per Joint: P= (21.55 kN/m)(0.01905m) P= 0.4105275kN Vmax= 410 N Allowable stress for Dowel: Vmax= 4 (Vmax) 3A Vmax= 4 (410 N) 3 (71.25 mm2) Vmax= 7.67 MPa Cross sectional area of Dowel: A= π r^2

Analysis

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Analysis

A= 71.25 mm2 Allowable: 420 psi (pg. 35, NDS, Design values for wood construction, yellow poplar) Therefore: the shear stress of the dowel will be able to resist the worst-‐case (410 N < allowable 420 psi) loading (in table position).

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Photos- Storage

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Photos- Chair

Geoff Bagga - Jeans - 20245053Snehjot Bumrah - 20271058Photos- Desk

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UW- Arch 365- Joris Voorn Chair

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