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Warm Up Solve each equation. 1. –5 a = 30 2.

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Warm Up Solve each equation. 1. –5 a = 30 2. –10. –6. 3. 4. Graph each inequality. 5. x ≥ –10. 6. x < –3. Lesson 3.3 Solving Inequalities by Multiplying or Dividing. Less than or equal to. Less than. ≤. . ≥. - PowerPoint PPT Presentation
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Warm Up Solve each equation. 1. –5a = 30 2. Graph each inequality. 5. x ≥ –10 6. x < –3 –6 –10 3 . 4.
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Page 1: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Warm UpSolve each equation. 1. –5a = 30 2.

Graph each inequality.

5. x ≥ –10

6. x < –3

–6 –10

3. 4.

Page 2: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Lesson 3.3Solving Inequalities by Multiplying or Dividing

<

>

≤Less than or equal to

greater than greater than or equal to

Less than

Page 3: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Preparation for 5.0 Students solve multistep problems, including word problems, involving linear equations and linear inequalities in one variable and provide justification for each step.

California Standards

Page 4: Warm Up Solve each equation.          1.  –5 a  = 30   2.
Page 5: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Inequalities and their Graphs

Terms you see and need to know to graph inequalities correctly

Notice colored in circles

≤ is less than or equal to

≥ is greater than or equal to

Page 6: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Inequalities and their Graphs

Terms you see and need to know to graph inequalities correctly

Notice

open circles

< is less than

> is greater than

Page 7: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Solving Inequalities Using MultiplicationSolving Inequalities Using Multiplication x -2

3

x -2 3 x -6

Translation: x divided by 3 is greater than or equal

to negative 2.

The opposite of divided by 3 is Multiplying by 3.

What you do on one side you do on the other!

3 • • 3

Graph

-2 0 4-4-6

Page 8: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Solving Inequalities Using DivisionSolving Inequalities Using Division

3x ≤ 12

3x ≤ 12 3

Translation: 3times x is less than or equal to 12.

The opposite of multiplying by 3 is divided by 3.

What you do on one side you do on the other!31

Graph

0 2 4-2-4

x ≤ 4

Page 9: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Solve the inequality. Then Solve the inequality. Then graph the solution.graph the solution.

k210)2 3

6)1r

Page 10: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Multiplying and Dividing Inequalities by aMultiplying and Dividing Inequalities by a

Negative NumberNegative Number Solve the

inequality. 12 > -3m

4 < m

Step1: solve for m -divide by -3

Step 2: reverse the inequality symbol-3 -3

<12 > -3m

When multiplying or dividing by a negative number reverse the inequality symbol.

Page 11: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Multiplying and Dividing Inequalities by a Negative Number

Solve the inequality. k < -3

Step1: solve for k -Multiply by -2

Step 2: reverse the inequality symbol>

-2.

When multiplying or dividing by a negative number reverse the inequality symbol.

-2

.-2

k > 6

Page 12: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Tell whether the operation reverses Tell whether the operation reverses

the sign of the inequality.the sign of the inequality.

1) Multiply each side by -1

2) Multiply each side b

3) Divide each side by 4.

4) Divide each side by -5.

1

4

Page 13: Warm Up Solve each equation.          1.  –5 a  = 30   2.

You try: Solve the InequalitiesYou try: Solve the Inequalities

1) 2x 16

4)7 m4

2)x

510

3) 4k 12

Page 14: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Additional Example: Application

$4.30 times number of tubes is at most $20.00.

4.30 • p ≤ 20.00

Jill has a $20 gift card to an art supply store where 4 oz tubes of paint are $4.30 each after tax. What are the possible numbers of tubes that Jill can buy?

Let p represent the number of tubes of paint that Jill can buy.

Page 15: Warm Up Solve each equation.          1.  –5 a  = 30   2.

4.30p ≤ 20.00

p ≤ 4.65…

Since p is multiplied by 4.30, divide both sides by 4.30. The symbol does not change.

Since Jill can buy only whole numbers of tubes, she can buy 0, 1, 2, 3, or 4 tubes of paint.

Additional Example ContinuedJill has a $20 gift card to an art supply store where 4 oz tubes of paint are $4.30 each after tax. What are the possible numbers of tubes that Jill can buy?

Page 16: Warm Up Solve each equation.          1.  –5 a  = 30   2.

Lesson QuizSolve each inequality and graph the solutions.

1. 8x < –24 x < –3 2. –5x ≥ 30 x ≤ –6

3. x > 20 4. x ≥ 6

5. A soccer coach plans to order more shirts for her team. Each shirt costs $9.85. She has $77 left in her uniform budget. What are the possible numbers of shirts she can buy?0, 1, 2, 3, 4, 5, 6, or 7 shirts


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