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Week 1 Introduction to Computers and
Programming Languages
UniMAP Sem II – 12/13
EKT120: Computer Programming 1
General Information• Contributes 4 units:
• 2 hours – lectures• 4 hours – labs
• Main Objective:• Students can independently write, compile, debug and execute
computer programs to solve problems, especially engineering related problems.
UniMAP Sem II – 12/13
EKT120: Computer Programming 2
Course Outcomes• Ability to define and describe programming concepts and principles.
• Ability to apply programming techniques and tools such as flowchart and pseudo code to design computer programs.
• Ability to apply GNU/Linux for coding, compiling, executing and debugging computer programs.
• Ability to solve engineering related problems using computer programming techniques.
UniMAP Sem II – 12/13
EKT120: Computer Programming 3
Overall Evaluation• 4 main components:
• Theoretical Tests (2) => 20% (Test1 = 10%, Test2 = 10%)
• Lab Assignments (4) => 30% (Asg1 = 6%, Asg2 = 6%, Asg3 = 8%, Asg4 = 10%)
• Lab Test => 10%• Final Exam => 40%
• Assignments are assessed individually • The two tests are written tests
UniMAP Sem II – 12/13
EKT120: Computer Programming 4
References
• Deitel & Deitel, Sudin, S., Ahmad, R. Badlishah, and Yacob, Y., “C How to Program”, Pearson-Prentice Hall, 2006.
• Cheng, H., “C for Engineers and Scientists”, McGraw Hill, 2010.
• Hanly, J.R. and Koffman, E.B., “C Program Design for Engineers”, 2nd Ed., Addison-Wesley, 2001.
ISBN : 0321204174UniMAP Sem II – 12/13
EKT120: Computer Programming 5
Notes
• This course is NOT about the language per se, it is about problem solving, analytical skills and to apply C to solve problems.
• Write C program in Linux environment.• Do early reading.• Do not hesitate to ask during lecture sessions.
UniMAP Sem II – 12/13
EKT120: Computer Programming 6
Outline• Computer Fundamentals
• Computer organization and hardware• Computer software
• Programming Languages• Machine language• Assembly language• High-level language
• Algorithm : pseudo code and flowchart
• Control Structures
• Simple C ProgramUniMAP Sem II – 12/13
EKT120: Computer Programming 7
Computer Fundamentals
• Computer system is divided into hardware and software.
• Hardware refers to physical components of computer which are:• Main Memory• Central Processing Unit (CPU)• Input Device• Output Device• Secondary Memory Device
UniMAP Sem II – 12/13
EKT120: Computer Programming 8
UniMAP Sem II – 12/13
EKT120: Computer Programming 9
Figure 1.1 The Intel Atom processor chip contains the full circuitry of a central processing unit in an integrated circuit whose small size and low power requirements make it suitable for use in mobile internet devices. (Intel Corporation Pressroom Photo Archives)
Figure 1.2
(a) Notebook Computer (HP Pavilion dv5©, Courtesy of Hewlett-Packard).
(b) Palmtop Computer (iPhone 3G©, Courtesy of Apple, Inc.)
(c) Desktop Computer (iMac©, Courtesy of Apple, Inc.)
UniMAP Sem II – 12/13
EKT120: Computer Programming 10
Figure 1.3 Components of a Computer
UniMAP Sem II – 12/13
EKT120: Computer Programming 11
Computer Hardware
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Input Device Output Device
Secondary Memory
Control UnitArithmetic and
Logic UnitRegister
CPU
Main Memory
Central Processing Unit (CPU)
• CPU is the computer’s administrator and is responsible for supervising the operation of the other sections
• Consists of two functional units; control unit and arithmetic-logic unit (ALU)
• Control unit supervises all activities of the computer system
• ALU performs basic arithmetic operations and comparison operations
UniMAP Sem II – 12/13
EKT120: Computer Programming 13
Main Memory
• keeps information from the input unit • also keeps processed information until it can be placed on output devices
• all programs must be loaded into main memory before they can be executed and all data must be brought into main memory before it can be manipulated.
UniMAP Sem II – 12/13
EKT120: Computer Programming 14
Main Memory
• Main memory can be further classified into two types:• Random Access Memory (RAM)
• information in RAM will be lost when the computer is turned-off.
• Read Only Memory (ROM)• It has been set during manufacturing process. ROM usually
contains instructions and information considered to be fundamental to the computer.
UniMAP Sem II – 12/13
EKT120: Computer Programming 15
Figure 1.4 1000 Memory Cells in Main Memory
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EKT120: Computer Programming 16
Secondary Memory
• Main memory is only used during processing following certain instructions
• Permanent information is NOT stored in main memory but is stored in secondary memory• E.g. program file, data file, etc• E.g. hard disk, diskette, CD
UniMAP Sem II – 12/13
EKT120: Computer Programming 17
Figure 1.5 Secondary Storage Media
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EKT120: Computer Programming 18
Input/Output Devices
• Input devices - feed data and programs into computers • E.g. keyboard, mouse, touch screen, scanners
• Output devices - display results produced by computer• E.g. monitor, printer, speaker
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EKT120: Computer Programming 19
Software
• As a complement to hardware, computer system needs software to solve problems.
• Software are classified into :• System software• Application software
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Software• System software : manages the computer and its peripheral devices (hardware) • E.g. Operating system (OS)• Text editor• Pre-processor• Language translator• Linker• Loader
UniMAP Sem II – 12/13
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Software
• Application software : performs specific tasks• There are two types:
• Program to solve specific problems• Program written by user to solve specified problem
• E.g. word processor, desktop publishing software, spreadsheets, database, graphics, communication, programs perform specific tasks such as accounting, scientific, engineering, education, etc
UniMAP Sem II – 12/13
EKT120: Computer Programming 22
Programming Languages
• Programming language is divided into three categories:• Machine Language• Assembly Language• High-Level Language
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EKT120: Computer Programming 23
Machine Language• Language understood by the computer• Bunch of 0’s and 1’s• Program written in machine language can be executed without being translated
• Nevertheless, hard to learn because it is written in 0’s and 1’s
• Program is too long to solve simple problem• Machine-dependant and not portable• E.g.
• 0101 0001 1100 0100 1011 1000• 0101 1000 0101 1001 1100 0111
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Figure 1.6 Relationship Between a Byte and a Bit
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EKT120: Computer Programming 25
Assembly Language
• Strings of 0’s and 1’s are replaced into instructions which resemble English language to represent computer operation element
• Easier to understand and write• E.g.
UniMAP Sem II – 12/13
EKT120: Computer Programming 26
LOAD rateMULT hourSTOR wages
Assembly Language
• Nevertheless, needs language translator called Assembler to change Assembly Language to Machine Code for execution purpose
• still too long and not portable
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EKT120: Computer Programming 27
High-Level Language
• Improves weaknesses in Machine Language and Assembly Language
• Portable• Written in one instruction to carry out several instructions in machine level • E.g. discount_price = price – discount;
• Must be changed to machine code before executed, needs compiler : a system software that translates source program to object program
UniMAP Sem II – 12/13
EKT120: Computer Programming 28
Algorithms
• The solution to any computing problem involves executing series of actions in a specific order
• Pseudo code : artificial and informal language that helps programmers develop algorithms
• E.g. if student’s grade is greater than or equal to 50
Print “Pass” else
Print “Fail”
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EKT120: Computer Programming 29
Algorithms
• Flowchart: visual-form of an algorithm• E.g.
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Process 2Decision
Data
Process 1
Begin
End
Algorithm-Basic symbols in a flowchart
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Start/End
Process
Input/Output
Decision
Flow direction
Connector
Flowchart-(example)
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Start
read num1, num2
sum=num1+num2
print sum
End
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TRY THIS!!!
Write a pseudo code, flowchart and program that calculates and prints the SUM of two integers A and B.
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EKT120: Computer Programming 34
Pseudo code
• Begin• Input A and B• Calculate A + B• Print result of SUM• End
Flowchart
Begin
Input A,B
CalculateA + B
Print SUM
End
Control Structure
• All programs could be written in terms of three control structures:• Sequence structure• Selection structure• Repetition structure
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EKT120: Computer Programming 35
Sequence Structure
• Is a series of steps executed sequentially by default
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EKT120: Computer Programming 36
Read num1, num2Calculate total=num1+num2Print total
Pseudo code Flowchart
Read num1, num2
total = num1+num2
print total
Selection Structure
• Used to choose among alternative courses of action• C has three types: if, if..else, and switch
UniMAP Sem II – 12/13
EKT120: Computer Programming 37
The if Selection Structure
• “if” structure is a single-entry/single-exit structure
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EKT120: Computer Programming 38
true
false
grade >= 60
print “Pass”
If student’s grade is greater than or equal to 60
Print “Pass”
The if..else Selection Structure
• Specifies an action to be performed both when the condition is true and when it is false
UniMAP Sem II – 12/13
EKT120: Computer Programming 39
truefalse
print “Fail” print “Pass”
grade >= 60
If student’s grade is greater than or equal to 60
Print “Pass”else
Print “Fail”
Repetition Structure
• Specifies a block of one or more statements that are repeatedly executed until a condition is satisfied
• Three types : while, for, do-while
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EKT120: Computer Programming 40
The while Repetition Structure
• Programmer specifies an action is to be repeated while some conditions remain true
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EKT120: Computer Programming 41
product <= 1000 product = 2 * producttrue
falseWhile product is less than or equal 1000
calculate product=2 * product
Basics of a Typical C Program Development Environment
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Figure 1.7 Entering, Translating, and Running a High-Level Language Program
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Figure 1.8 Flow of Information During Program Execution
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Simple C Program: Program to add two numbers #include <stdio.h>int main(void){ int dA, dB, dSum; printf (“input first integer \n”); scanf (“%d”, &dA) printf (“input second integer \n”); scanf (“%d”, &dB) dSum = dA + dB;
printf (“Sum is %d\n”, dSum); return 0;}
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OUTPUTInput first integer39Input second integer27Sum is 66
End Week 1
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Q & A!