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What are the 3 steps of you use in STOICHIOMETRY???

Date post: 30-Dec-2015
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What are the 3 steps of you use in STOICHIOMETRY???. HINT: you did this yesterday…. Step 1: Convert given information to moles…. Step 2: Figure out the coefficient ratio. Step 3: Convert to what you are looking for. - PowerPoint PPT Presentation
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What are the 3 steps of you use in STOICHIOMETRY ??? HINT: you did this yesterday…
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Page 1: What are the 3 steps of you use in STOICHIOMETRY???

What are the 3 steps of you use in

STOICHIOMETRY???

HINT: you did this yesterday…

Page 2: What are the 3 steps of you use in STOICHIOMETRY???

Step 1: Convert given information

to moles…

Page 3: What are the 3 steps of you use in STOICHIOMETRY???

Step 2: Figure out the coefficient

ratio

Page 4: What are the 3 steps of you use in STOICHIOMETRY???

Step 3: Convert to what you are

looking for

Page 5: What are the 3 steps of you use in STOICHIOMETRY???

Don’t forget to balance the

chemical equation and identify the

knowns and unknowns.

Page 6: What are the 3 steps of you use in STOICHIOMETRY???

http://www.youtube.com/watch?v=ZWSRIIg8KXQ

AND NOW A DISASTER OF CHEMICAL PROPORTIONS!!!

Page 7: What are the 3 steps of you use in STOICHIOMETRY???

GET READY TO BE A COOKIE CHEMIST

Just don’t do experiments on this guy’s cookie…

Page 8: What are the 3 steps of you use in STOICHIOMETRY???

Limiting ReactantThe reactant that determines, or LIMITS, the quantity of product that can be formed over the course of a reaction.

The reaction will stop when all of the limiting reactant is consumed.

Page 9: What are the 3 steps of you use in STOICHIOMETRY???

Limiting Reactant – an extension on stoich

How do we find it?Think about how you completed the cookie investigation

We have to do stoichiometry MORE THAN ONCE and determine which reactant will produce LESS product. That will be the limiting reactant.

Please give me $10 if you are ready to practice!!!

Page 10: What are the 3 steps of you use in STOICHIOMETRY???

Practice Problems1) Hg + S HgS

48.6g 3.6g ? G

2) C4H10 + O2 CO2 + H2O 215g 75.0g ? g


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