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Work, Power, and Machines
Physical Science – Unit 7
Chapter 9
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Work
• What is work?– Work is the quantity of energy transferred
by a force when it is applied to a body and causes that body to move in the direction of the force.
• Examples:– Weightlifter raises a barbell over his/her
head
– Using a hammer
– Running up a ramp
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Work
Work in simple terms:
• Transfer of energy that occurs when a force makes an object move
• The object must move for work to be done
• The motion of the object must be in the same direction as the applied force
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Work
• The formula for work:– Work = force x distance
– W = F x d
• Measured in Joules (J)– Because work is calculated as force times
distance, it is measured in units of newtons times meters (N●m)
– 1 N●m = 1 J = 1 kg●m2/s2
• They are all equal and interchangeable!
James Joule - English scientist and inventor 1818-1889
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Work
• 1 J of work is done when 1N of force is applied over a distance of 1 m.
• kJ = kilojoules = thousands of joules
• MJ = Megajoules = millions of joules
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Practice problem
A father lifts his daughter repeatedly in the air. How much work does he do with each lift, assuming he lifts her 2.0 m and exerts an average force of 190 N?
W = F x d
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Practice problem
A father lifts his daughter repeatedly in the air. How much work does he do with each lift, assuming he lifts her 2.0 m and exerts an average force of 190 N?
W = F x d
W = 190 N x 2.0 m
= 380 N●m = 380 J
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Practice problems
A mover is moving about 200 boxes a day. How much work is he doing with each box, assuming he lifts each 10 m with a force of 250 N.
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Practice problems
A mover is moves about 200 boxes a day. How much work is he doing with each box, assuming he lifts each 10 m with a force of 250 N.
W = F x d
= 250 N x 10 m
= 2,500 N●m = 2,500 J
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Practice problems
A box with a mass of 3.2 kg is pushed 0.667 m across a floor with an acceleration of 3.2 m/s2. How much work is done on the box?
What do you need to calculate first?????
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Practice problems
A box with a mass of 3.2 kg is pushed 0.667 m across a floor with an acceleration of 3.2 m/s2. How much work is done on the box?
F = ma
= 3.2 kg x 3.2 m/s2
= 10.2 kg● m/s2 = 10.2 N
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Practice problems
A box with a mass of 3.2 kg is pushed 0.667 m across a floor with an acceleration of 3.2 m/s2. How much work is done on the box?
F = ma
= 3.2 kg x 3.2 m/s2
= 10.2 kg● m/s2 = 10.2 N
W = F x d
= 10.2 N x 0.667 m
= 6.80 N●m = 6.80 J
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• Practice problems
Get a calculator
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• Page 54 asks for distance……
W= F x D
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• #1
.6 m
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• #2
.6m
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• #3
2.6m
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• #4
2.398m
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• P55 asks for force
W= F x D
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• #5
2 800 000N
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• #6
27N
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• #7
900 000N
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• #8
95 454N
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• P56 asks for W………thank goodness
W= F x D
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• #9
237 825J
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• #10
3.2 x 106 J
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• #11
5 625 000 J
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• #12
2 127 840J
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How about a harder one….
#18
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• #18
• Calculate force first, then work
276 115J
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Power
• Power is a quantity that measures the rate at which work is done– It is the relationship between work and
time
– If two objects do the same amount of work, but one does it in less time. The faster one has more power.
• Rate at which work is done or how much work is done in a certain amount of time
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Power
• Formula for power:
Power = work
time
P = W/t
• SI units for power – watts (W)
• 1 kW – Kilowatt = 1000 watts
• 1 MW – Megawatt= 1 million watts
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Power
• A watt is the amount of power required to do 1 J of work in 1 s. (Reference – the power you need to lift an apple over your head in 1 s)
• Named for James Watt who developed the steam engine in the 18th century.
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Practice problems
A weight lifter does 686 J of work on a weight that he lifts in 3.1 seconds. What is the power with which he lifts the weight?
P = W/t
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Practice problems
A weight lifter does 686 J of work on a weight that he lifts in 3.1 seconds. What is the power with which he lifts the weight?
P = W = 686 J
t 3.1 s
221 J/s = 221 W
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Practice problems
• How much energy is wasted by a 60 W bulb if the bulb is left on over an 8 hours night?
P = W
t
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Practice problems
• How much energy is wasted by a 60 W bulb if the bulb is left on over an 8 hours night?
P = W
t
1st convert 8 hr to seconds
8 hr (60 min/1hr)(60 sec/1min) = 28800 sec
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Practice problems
• How much energy is wasted by a 60 W bulb if the bulb is left on over an 8 hours night?
P = W
t
1st convert 8 hr to seconds
8 hr (60 min/1hr)(60 sec/1min) = 28800 sec
2nd calculate for energy
W = P x t
= 60 W x 28800 sec
= 1.7 x 107 J
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• Practice problems
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• P58 asks for work
P= W/t
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• #1
412.5J
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• #2
1 710 000J
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• #3
7 500 000 J
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• #4
1.17 x 1010J
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• P59 asks for time
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• #5
955.36 sec
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• #6
456.14sec
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• #7
1 500sec
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• #8
4.5sec
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• P60 asks for power
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• #9
5 x 108 watts
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• #10
2.75 x 1010
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• Do 11 & 12
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• #11
300sec
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• #12
6 162 000J
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Machines and Mechanical Advantage
• Which is easier… lifting a car yourself or using a jack?
• Which requires more work?
• Using a jack may be easier but does not require less work. – It does allow you to apply less force at any
given moment.
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What is a machine?
• A device that makes doing work easier… is a machine
• Machines increase the applied force and/or change the distance/direction of the applied force to make the work easier
• They can only use what you provide!
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Why use machines?
• If machines cannot make work, why use them?
– Same amount of work can be done by applying a small force over a long distance as opposed to a large force over a small distance.
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Effort and Resistance
• Machines help move things that resist being moved
• Force applied to the machine is effort force (aka: Input force)
• Force applied by the machine is resistance force (aka: Load, output force)
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Mechanical Advantage
• Mechanical advantage is a quantity that measures how much a machine multiplies force or distance
• Defined as the ratio between output force and input force
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Mechanical Advantage
• Mechanical advantage = output force
input force
• Mechanical advantage= input distance
output distance
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MachinesMachines MachinesMachines
Simple Machines
Lever Pulley Wheel & Axle
Inclined Plane Screw Wedge
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The Lever family
• Lever– a rigid bar that is free to pivot about a
fixed point, or fulcrum– Force is transferred from one part of the
arm to another.
“Give me a place to stand and I will move the Earth.”
– Archimedes
Engraving from Mechanics Magazine, London, 1824
Effort arm
Resistancearm
Fulcrum
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Lever
• First Class Lever– Most common type– Fulcrum in middle– can increase force, distance, or neither– changes direction of force
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Lever
• Second Class Lever– always increases force
– Resistance/load in middle
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Lever
• Third Class Levers– always increases distance
– Effort in middle
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Pulley
• Pulley– grooved wheel with a rope or chain
running along the groove
– a “flexible first-class lever” or modified lever
LeLr
F
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Pulley
• Ideal Mechanical Advantage (IMA)– equal to the number of supporting ropes
IMA = 0 IMA = 1 IMA = 2
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Pulley
• Fixed Pulley
IMA = 1
does not increase force
changes direction of force
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Pulley
• Movable Pulley
IMA = 2 increases forcedoesn’t change direction
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Pulley
• Block & Tackle
combination of fixed & movable pulleys increases force (IMA = 4) may or may not change direction
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Wheel and Axle
• Wheel and Axle
– two wheels of different sizes that rotate together
– a pair of “rotatinglevers”
– When the wheel is turned so so is the axle
Wheel
Axle
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Wheel and Axle
• Wheel and Axle
– Bigger the difference in size between the two wheels= greater MA
Wheel
Axle
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What is an inclined plane?
• A sloping surface, such as a ramp.
• An inclined plane can be used to alter the effort and distance involved in doing work, such as lifting loads.
• The trade-off is that an object must be moved a longer distance than if it was lifted straight up, but less force is needed.
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What is an inclined plane?
• MA=Length/Height
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Incline Plane Family
• A wedge is a modified incline plane– Example ax blade for splitting wood
– It turns a downward force into two forces directed out to the sides
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Incline Plane Family
• A screw looks like a spiral incline plane.– It is actually an incline plane wrapped
around a cylinder
– Examples include a spiral staircase and jar lids
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Practice problems
• A roofer needs to get a stack of shingles onto a roof. Pulling the shingles up manually used 1549 N of force. Using a system of pulleys requires 446 N. What is the mechanical advantage?
Mechanical advantage = output force
input force
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Practice problems
• A roofer needs to get a stack of shingles onto a roof. Pulling the shingles up manually used 1549 N of force. Using a system of pulleys requires 446 N. What is the mechanical advantage?
Mechanical advantage = output force
input force
= 1549 N = 3.47
446 N
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• Practice problems
1) Asks for output force (N)
2) Asks for input distance (cm)
3) Asks for output force (N)
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• #1
444.4N
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• #2
11cm
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• #3
3 675N
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4) Asks for output distance (cm)
5) Asks for input force (N)
6) Asks for output distance (m)
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• #4
3/0.85= 3.52
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• #5
2220/.0893= 24 860N
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• #6
1.57/12.5=0.1256m
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Help Solve for MA in #7 & #8
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• #7
3.28
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• #8
23.99
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Compound Machines
• Compound machines are machines made of more than one simple machine– Example include a pair of scissors has 2
first class levers joined with a common fulcrum; each lever arm has a wedge that cuts into the paper
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Energy
• Energy is the ability to cause changes.
– It is measured in Joules or kg●m/s2
– When work is done on an object, energy is given off
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Energy
5 main forms of energy:
1. Mechanical – associated with motion
2. Heat – internal motion of atoms
3. Chemical – the energy required to bond atoms together
4. Electromagnetic – movement of electric charges
5. Nuclear – released when nuclei of atoms fuse or split
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Mechanical Energy
• Mechanical Energy is the sum of the kinetic and potential energy of a large-scale objects in a system– Nonmechanical energy is the energy that
lies at the level of atoms and does not affect motion on a large scale
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Energy
• Those 5 forms of energy can be classified into one of two states:
– Potential energy – stored energy
– Kinetic energy – energy in motion
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Kinetic Energy
• The energy of motion
• An object must have mass and be moving to possess kinetic energy– The greater the mass or velocity--- the
greater the kinetic energy
– Formula:
KE = ½ mv2
m = mass
v = velocity
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Kinetic Energy
• Atoms and molecules are in constant motion and therefore have kinetic energy– As they collide then the kinetic energy is
transferred from one to another
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Practice problem
A sprinter runs at a forward velocity of 10.9 m/s. If the sprinter has a mass of 72.5 kg. What is their kinetic energy?
KE = ½ mv2
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Practice problem
A sprinter runs at a forward velocity of 10.9 m/s. If the sprinter has a mass of 72.5 kg. What is their kinetic energy?
KE = ½ mv2
= ½ (72.5 kg) (10.9 m/s)2
= .5 x 72.5 x 118.81
= 4306.86 kg●m/s = 4306.86 J
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Potential Energy
• The stored energy that a body possesses because of its position. – Examples: chemical energy in fuel or food
or an elevated book because it has the potential to fall.
• Potential energy due to elevated potential is called gravitational potential energy (GPE).
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Potential energy
• Formula:
• PE = mghm = mass
g = gravity (9.8 m/s2)
h = height
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Practice problems
A pear is hanging from a pear tree. The pear is 3.5 m above the ground and has a mass of 0.14 kg. What is the pear’s gravitational potential energy?
PE = mgh
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Practice problems
A pear is hanging from a pear tree. The pear is 3.5 m above the ground and has a mass of 0.14 kg. What is the pear’s gravitational potential energy?
PE = mgh
= .14 kg x 9.8 m/s2 x 3.5 m
= 4.8 kg●m2/s2 = 4.8 J
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Conservation of Energy
• Energy is almost always converted into another form of energy
• One most common conversion is changing from potential energy to kinetic energy or the reverse.
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Conservation of Energy
• The transfer of energy from one object to the next is a conversion of energy.
The law of conservation of energy states that all energy
can neither be created or destroyed; it is just converted
into another form.
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Conservation of Energy
• Energy conversions occur without a loss or gain in energy
• Therefore…. KE = PE
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Energy Transformations
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Conservation of Energy
• Amount of energy the machines transfers to the object cannot be greater than energy you put in
• Some energy is change to heat by friction
• An ideal machine would have no friction so energy in = energy out
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Efficiency
• Efficiency is a measure of how much work put into a machine is changed to useful work output by the machine
• Not all work done by a machine is useful therefore we look at the efficiency of the machine
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Efficiency
• Formula for Efficiency
• (Work output / Work input) X 100– Efficiency = useful work output x 100
work input
• Efficiency is always less than 100% because no machine has zero friction or 100% efficiency
• Lubricants can make a machine more efficient by reducing friction– Oil
– Grease
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Practice Problem
What is the efficiency of a machine if 55.3 J of work are done on the machine, but only 14.3 J of work are done by the machine?
Efficiency = useful work output
work input
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Practice Problem
What is the efficiency of a machine if 55.3 J of work are done on the machine, but only 14.3 J of work are done by the machine?
Efficiency = useful work output
work input
= 14.3 J x 100 = 25.9 %
55.3 J
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Perpetual Motion Machines
• Perpetual motions machines are machines designed to keep going forever without any input of energy
• It is not possible because we have not been able to have a machine with a complete absence of friction!
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• Newman’s machine
Joseph Newman, claimed it would produce mechanical power exceeding the electrical power being supplied to it
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• Take out your homework
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Power, Work and Force I
1. 6.48W
2. 6 692J
3. 5.76S
4. 112.93 kg
5. 7.11W
6. 16.4S
7. 9.45W
8. 1.8kg
9. 61.25W
10. 11 340J
11. 4344.6W
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Work and Power I
1. 20J
2. 5 900J
3. 14 000J
4. 50m
5. 5.10m
6. 50W
7. 13W
8. 18 000J
9. 100J
10. 60W
11. 588W
12. 5000W
13. 115N in 15m(1725J
14. 20kg lift=1960J
15. 80%
16. 500J
17. over 490J
18. What do you think?
19. 25%