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ASSIGNMENT 5 - NPTEL

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ASSIGNMENT 5 (Based on Dual Simplex method, IP) Q.1. The following optimization problem is : Maximize z =2x - 9y subject to 5x +7y 27 4x + y 14 3x - 2y 9 x, y 0,x is integer . (a) Mixed-Integer programming problem (b) Non-linear programming problem (c) Quadratic programming problem (d) None of the above Q.2. Use dual simplex method to solve the L.P.P. : Maximize z = -2x 1 - 3x 2 - x 3 subject to 2x 1 + x 2 +2x 3 3 3x 1 +2x 2 + x 3 4 x 1 ,x 2 ,x 3 0. (a) z max = - 11 4 (b) z max = 11 4 (c) Unbounded solution (d) No feasible solution Q.3. Solve the following L.P.P. by dual simplex method : Minimize z = 10x 1 +6x 2 +2x 3 subject to - x 1 + x 2 + x 3 1 3x 1 + x 2 - x 3 2 x 1 ,x 2 ,x 3 0. (a) z min = -10 (b) z min = 10 (c) Unbounded solution (d) No feasible solution 1
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ASSIGNMENT 5(Based on Dual Simplex method, IP)

Q.1. The following optimization problem is :

Maximize z = 2x− 9y

subject to 5x+ 7y ≤ 27

4x+ y ≤ 14

3x− 2y ≤ 9

x, y ≥ 0, x is integer .

(a) Mixed-Integer programming problem (b) Non-linear programming problem

(c) Quadratic programming problem (d) None of the above

Q.2. Use dual simplex method to solve the L.P.P. :

Maximize z = −2x1 − 3x2 − x3

subject to 2x1 + x2 + 2x3 ≥ 3

3x1 + 2x2 + x3 ≥ 4

x1, x2, x3 ≥ 0.

(a) zmax = −11

4(b) zmax =

11

4(c) Unbounded solution

(d) No feasible solution

Q.3. Solve the following L.P.P. by dual simplex method :

Minimize z = 10x1 + 6x2 + 2x3

subject to − x1 + x2 + x3 ≥ 1

3x1 + x2 − x3 ≥ 2

x1, x2, x3 ≥ 0.

(a) zmin = −10 (b) zmin = 10 (c) Unbounded solution

(d) No feasible solution

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Q.4. Solve, if possible, the linear programming problem by using dual simplex method.

Minimize z = x1 + 5x2

subject to 3x1 + 4x2 ≤ 6

x1 + 3x2 ≥ 3

x1, x2 ≥ 0.

(a) No feasible solution (b) Unbounded solution (c) zmin = −21

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(d) zmin =21

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Q.5. Using dual simplex method, solve the following problem.

Minimize z = 7x1 + 3x2

subject to x1 − 3x2 ≥ 1

x1 + x2 ≥ 2

−2x1 + 2x2 ≥ 1

x1, x2 ≥ 0.

(a) zmin = −13 (b) zmin = 32 (c) Unbounded solution

(d) No feasible solution

Q.6. Solve, if possible, by dual simplex method the following problem.

Minimize z = 6x1 + 11x2

subject to x1 + x2 ≥ 11

2x1 + 5x2 ≥ 48

x1, x2 ≥ 0.

(a) zmin = 96 (b) zmin = 10 (c) Unbounded solution

(d) No feasible solution

Q.7 Solve the following L.P.P. using dual simplex algorithm :

Minimize z = 6x1 + 7x2 + 3x3 + 5x4

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subject to 5x1 + 6x2 − 3x3 + 4x4 ≥ 12

x2 + 5x3 − 6x4 ≥ 10

2x1 + 5x2 + x3 + x4 ≥ 8

x1, x2, x3, x4 ≥ 0.

(a) No feasible solution (b) Unbounded solution (c) zmin =258

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(d) zmin =127

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Q.8. Solve the L.P.P. :Maximize z = 2x1 + 2x2

subject to 5x1 + 3x2 ≤ 8

x1 + 2x2 ≤ 4

x1, x2 ≥ 0 and are integers .

(a) zmax = −4 (b) zmax = 4 (c) Unbounded solution

(d) No feasible solution

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ANSWERS

Q.1. (a)

Q.2. (a)

Q.3. (b)

Q.4. (d)

Q.5. (d)

Q.6. (a)

Q.7. (c)

Q.8. (b)

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48/5
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-7/5
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