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Chapter 1
Basics of Screw Theory
1.1 Introduction
Screw theory is a powerful mathematical tool for the analysis of spatial mechanisms.
A screw consists of two three-dimensional vectors. A screw can be used to denote
the position and orientation of a spatial vector, the linear velocity and angular
velocity of a rigid body, or a force and a couple, respectively. Therefore, the concept
of a screw is convenient in kinematics and dynamics, while the transformation
between the screw-based method and vector and matrix methods is straightforward.
When applied in mechanism analysis, screw theory has the advantages of clear
geometrical concepts, explicit physical meaning, simple expression and convenient
algebraic calculation. It is worth noting that the preliminary requirements for screw
theory are only linear algebra and basic dynamics in undergraduate level. Thus,
screw theory has been widely applied and researchers have used screw theory to
make great contribution to many frontier problems in mechanism theory.
Screw theory was established in the nineteenth century. First, Chasles (1830)
proposed the concept of twist motion of a rigid body, which was further developed
by Poinsot (1848). Then Pl€ucker gave his research and proposed his screw expres-
sion [1]. Then, in his classic book Screw theory (1875), Ball discussed the kinematics
and dynamics of a rigid body under complex constraints using screw theory [2]. In the
last 60 years, many researchers, such as Dimentberg [3], Yang and Freudenstein [4],
Waldron [5], Roth [6], Hunt [7], Phillips [8], Duffy [9] and Angeles [10] etc, have
made important contributions to screw theory.
This chapter first addresses the expression of a straight line and its Pl€ucker linecoordinates in three-dimensional space. The line vector and screw as well as their
characteristics and the screw algebra are introduced. In the last part, this chapter
Z. Huang et al., Theory of Parallel Mechanisms, Mechanisms and Machine Science 6,
DOI 10.1007/978-94-007-4201-7_1, # Springer Science+Business Media Dordrecht 2013
1
also introduces the expression for the instantaneous motion of a rigid body and the
statics of the body using screw theory.1
1.2 Equation of a Line
Two distinct points Aðx1; y1; z1Þ and Bðx2; y2; z2Þ determine a line, as shown in
Fig. 1.1. The vector S denoting the direction of the line can be expressed as
S ¼ ðx2 � x1Þiþ ðy2 � y1Þj þ ðz2 � z1Þk; (1.1)
where i, j, and k are unit vectors corresponding to each coordinate axis.
If we let
x2 � x1 ¼ L
y2 � y1 ¼ M
z2 � z1 ¼ N; ð1:2Þ
then substituting Eq. (1.2) into Eq. (1.1), we have
S ¼ LiþMj þ Nk; (1.3)
where L, M, and N are direction ratios.
The distance between the two points is given by
jSj ¼ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiL2 þM2 þ N2
p: (1.4)
Let
l ¼ L=jSjm ¼ M=jSjn ¼ N=jSj; ð1:5Þ
where l, m and n are direction cosines of the line. Then Eq. (1.4) reduces to
l2 þ m2 þ n2 ¼ 1: (1.6)
1 The content of screw theory in this book is based on the teaching material presented by Dr. Duffy
at Florida University in 1982. At that time, the first author of this book listened attentively to the
lectures and was deeply inspired by the course content. The author wishes to express here once
again his acknowledgments to Dr. Duffy.
2 1 Basics of Screw Theory
Note that a line can be determined by its direction and a point on it. We can
write the vector equation of the line as
ðr � r1Þ � S ¼ 0: (1.7)
Equation (1.7) can also be expressed as
r � S ¼ S0; (1.8)
where
S0 ¼ r1 � S (1.9)
is the moment of the line about the origin O.
The vectors ðS; S0Þ are called the Pl€ucker coordinates of the line and satisfy the
orthogonality condition
S � S0 ¼ 0: (1.10)
Note that ðS; S0Þ is homogeneous, since multiplying both sides of Eq. (1.8) by a
scalar l yields the same line.
Expanding Eq. (1.9) leads to
S0 ¼i j kx1 y1 z1L M N
������
������: (1.11)
Equation (1.11) can be expressed in the form
S0 ¼ Piþ Qj þ Rk; (1.12)
where
P ¼ y1N � z1M
R ¼ x1M � y1L: (1.13)
Z
X
r1
Y
B
r 2
r
O
A
S
Fig. 1.1 Pl€ucker Coordinatesof a line
1.2 Equation of a Line 3
Expanding Eq. (1.8) and considering Eq. (1.12), we have
yN � zM � P ¼ 0
zL� xN � Q ¼ 0
xM � yL� R ¼ 0: ð1:14Þ
From Eqs. (1.3), (1.12) and (1.10), the orthogonality condition can be written as
LPþMQþ NR ¼ 0: (1.15)
The six Pl€ucker coordinates of the line ðL;M;N;P;Q;RÞ are illustrated in
Fig. 1.2.
ðL;M;NÞ consists of the direction ratios of the line and ðP;Q;RÞ are the x, y and zcomponents of the moment of the line about the origin. The coordinates ðS; S0Þ arerelated by Eqs. (1.6) and (1.11). Therefore only four of the six scalars ðL;M;N;P;
Q;RÞ are independent, and there are 14 lines in space.
The distance of the line from the origin is determined by the length of a vector Pfrom O and perpendicular to the line. From Eq. (1.8), we have P� S ¼ S0 , andtherefore
S� ðP� SÞ ¼ S� S0:
Expanding the left side of the above equation, we have
S� ðP� SÞ ¼ ðS � SÞP� ðS � PÞS ¼ ðS � SÞP;
and so solving equation for P gives
P ¼ S� S0S � S : (1.16)
Z
LM
S
N
R
P
Q
O
P YX
Fig. 1.2 Distance between
the line and origin
4 1 Basics of Screw Theory
This can be expressed in the form
P ¼ jSjjS0jjSjjSj e ¼
jS0jjSj e; (1.17)
where e is a unit vector perpendicular to S� S0. Therefore
jPj ¼ jS0jjSj : (1.18)
When S0 ¼ 0, the line passes through the origin and the Pl€ucker line coordinatesare ðS; 0Þ or ðl m n; 0 0 0Þ. When S ¼ 0, the line lies in a plane at infinity
and the Pl€ucker coordinates are ð0; S0Þ or ð0 0 0; l m nÞ.
1.3 Mutual Moment of Two Lines
The vector equations of two skew lines separated by a perpendicular distance of a12and a twist angle of a12 (see Fig. 1.3) are given by
r1 � S1 ¼ S01 (1.19)
r2 � S2 ¼ S02: (1.20)
The projection of the moment vector a12a12 � S2 on the line S1 is given by a12a12 � S2 � S1 and is called the moment of S2 about the line S1. This scalar quantity isusually called the mutual moment of the two lines and can also be obtained by
projecting the moment vector � a12a12 � S1 on the line S2, namely,
Mm ¼ a12a12 � S2 � S1 ¼ a12a21 � S1 � S2: (1.21)
a12
r1
r2
S2
S1
Z
A
YX
O
B
a12
a12
Fig. 1.3 Mutual moment
of two lines
1.3 Mutual Moment of Two Lines 5
Expanding the scalar triple product and considering r2 � r1 ¼ a12a12, we have
ðr2 � r1Þ � S2 � S1 ¼ r2 � S2 � S1 þ r1 � S1 � S2: (1.22)
Substituting Eqs. (1.19) and (1.20) into Eq. (1.22) yields
Mm ¼ S1 � S02 þ S2 � S01: (1.23)
Since both S1 and S2 are unit vectors, S1 � S1 ¼ S2 � S2 ¼ 1, and so
S2 � S1 ¼ �a12 sin a12: (1.24)
The mutual moment of the two lines is then given by
Mm ¼ ðr2 � r1Þ � S2 � S1 ¼ �a12 sin a12: (1.25)
From this expression, it is clear that the mutual moment of two lines is
independent of the coordinate-frame.
Alternatively, Eq. (1.23) can be written as
Mm ¼ l1p2 þ m1q2 þ n1r2 þ p1l2 þ q1m2 þ r1n2: (1.26)
If the lines are parallel or intersect at infinity, we have a12 ¼ 0 and their mutual
moment is zero. If the two lines intersect, which means the perpendicular distance
between the two lines is zero, we have a12 ¼ 0. Therefore, when two lines are
coplanar, the mutual moment of the two lines is always zero:
S1 � S02 þ S2 � S01 ¼ 0: (1.27)
1.4 Line Vectors and Screws
1.4.1 The Line Vector
This section will introduce two important concepts. One is the line vector and the
other is the screw. Recall that in Sect. 1.2 we established the equation of a line:
r � S ¼ S0: (1.28)
The dual vector ðS; S0Þ, which denotes a straight line in space, is also called a
line vector. When jSj ¼ 1 , S is a unit vector and ðS; S0Þ is a unit line vector.
However,S0 is in general not a unit vector. The two vectorsS andS0 are orthogonal,
6 1 Basics of Screw Theory
so that S � S0 ¼ 0. The unit line vectors ðS; S0Þ stand in one-to-one correspondence
with the 14 lines in space.
The vector S is not origin-dependent. The vector S0, which remains constant as Sis being moved along the line, is the moment of S about the origin O. Clearly, S0 isorigin-dependent, and if the origin is shifted from point O to point A, then the
moment of S about A can be written as (Fig. 1.4)
SA ¼ rA � S ¼ ðABþ rBÞ � S: (1.29)
Substituting SB ¼ rB � S into Eq. (1.29), we have
SA ¼ SB þ AB� S: (1.30)
When the line vectors are in different positions in space, the Pl€ucker coordinatesare different. In particular, when the line vector is located in certain special positions
with respect to the coordinate system, many of the components are zero, as shown in
Fig. 1.5. This is convenient for screw analysis.
S
A
AB
rB
rA
B
Fig. 1.4 Line moment is not origin-dependent
(abc;def )
(abc;de0 )
SkewParallel to coordinate axisParallel to coordinate plane
(ab0 ;def)(ab0 ;de0 )
(abc;000 )(100;0ab )(100;010 )
(100;000 )(ab0;00c )
Z
Y
X
Fig. 1.5 Various forms of line vector
1.4 Line Vectors and Screws 7
1.4.2 The Screw
When the two vectors of a dual vector do not satisfy the orthogonality condition
S � S0 6¼ 0,2 which is the more general case, the dual vector is called a screw and is
denoted by
$ ¼ ðS; S0Þ; S � S0 6¼ 0: (1.31)
When jSj ¼ 1, $ is a unit screw.
The vector S of a screw is also not origin-dependent. The vector S0 is
origin-dependent and if the origin is shifted from point O to point A, the moment
of S about A can be obtained as
SA ¼ S0 þ AO� S: (1.32)
Multiplying both sides of this equation by S, we have
S � SA ¼ S � S0: (1.33)
Equation (1.33) shows thatS � S0 is not origin-dependent. IfS 6¼ 0, we can obtain
the origin-independent variable
h ¼ S � S0S � S ¼ lpþ mqþ nr
l2 þ m2 þ n2; (1.34)
which is called the pitch of a screw. The line vector is a special screw with a zero
pitch. A screw with an infinite pitch is called a couple and is denoted by (0; S).The number of the unit screws in 3D space is 15, and the number of screws
in 3D space is 16.
A line vector corresponds to a straight line in space, and a screw also has its axis
line. To determine the axis line that the screw lies on, S0 is decomposed into two
parts, which are parallel and perpendicular to S, respectively, as shown in Fig. 1.6:
ðS; S0Þ ¼ ðS; S0 � hSþ hSÞ: (1.35)
Obviously, S0 � hS is normal to S, and S0 � hS ¼ S0. The equation of the axis ofthe screw is given by
r � S ¼ S0 � hS: (1.36)
2 For the convenience of readers, to distinguish between line vector and screw, the dual component
of screw is expressed as S0.
8 1 Basics of Screw Theory
The Pl€ucker coordinates of the line are ðS; S0 � hSÞ. From Eq. (1.25), a screw
can be expressed as
$ ¼ ðS; S0Þ ¼ ðS;S0 � hSÞ þ ð0; hSÞ; (1.37)
or
$ ¼ ðS; S0Þ ¼ ðS; r � Sþ hSÞ ¼ ðS; S0 þ hSÞ ¼ ðS; S0Þ þ ð0; hSÞ: (1.38)
This indicates that a line vector and a couple can combine to form a screw,
or that any screw with non-zero finite pitch can be considered the summation of a
line vector and a couple. There are four factors that determine a screw: position and
direction of the axis, and the magnitude and pitch of the screw.
Screw: ðS; S0Þ : S 6¼ 0; S � S0 6¼ 0; 1 6¼ h 6¼ 0
Line vector: ðS; S0Þ : S 6¼ 0; S � S0 ¼ 0; h ¼ 0
Couple: ð0; SÞ : S 6¼ 0; h ¼ 1
Example 1.1. l m n; hl hm hnð Þ is a screw with pitch h and passing through
the origin.
Example 1.2. 1 0 0; 1 0 0ð Þ is a screw with pitch h ¼ 1 and passing through the
origin, since
h ¼ ðS � S0Þ=ðS � SÞ ¼ 1;
r � S ¼ S0 � hS ¼ 0:
Example 1.3. 1 1 1; 1 1 1ð Þ= ffiffiffi3
pis also a unit screw with pitch h ¼ 1 that passes
through the origin and points in the direction 1 1 1ð Þ.Example 1.4. Identify $ ¼ ðS; S0Þ ¼ 1 1 0; 1 0 0ð Þ and determine its axis.
Solution. The pitch of the screw is h ¼ ðS � S0Þ=ðS � SÞ ¼ 1=2. Considering that
S0 ¼ S0 þ hS ¼ r � Sþ hS, the equation of the axis is r � S ¼ S0 � hS.
S0
S
hS
S0−hS
Fig. 1.6 Axis of a screw
1.4 Line Vectors and Screws 9
Thus we have
r � S ¼ 1=2� 1=2 0ð ÞT:
1.5 Screw Algebra
Screws obey the following algebraic operations [11], and these operations have
special meanings.
1.5.1 Screw Sum
The sum of two screws $1 ¼ S1; S01
� �, and $2 ¼ S2; S
02
� �is defined as follows
$1 þ $2 ¼ S1 þ S2; S01 þ S02
� �(1.39)
Equation (1.39) shows that the sum of two screws is still a screw.
Theorem 1.1. The sum of two line vectors is a line vector only if their axes arecoplanar and the sum of their first vectors is non-zero, namely S1 þ S2 6¼ 0.
Proof. If $1 and $2 are two line vectors, then S1 � S01 ¼ 0 and S2 � S02 ¼ 0. If the
two line vectors are coplanar, then their mutual moment is equal to zero. That is,
S01 � S2 þ S02 � S1 ¼ 0. Therefore, we obtain
ðS1 þ S2Þ � ðS01 þ S02Þ ¼ 0: (1.40)
Equation (1.40) shows that the sum of two line vectors is still a line vector and its
pitch is zero.
Theorem 1.2. If two line vectors intersect, their sum is a line vector passing theintersection point.
Proof. Since the sum of two line vectors is still a line vector, it can be expressed as
r � ðS1 þ S2Þ ¼ S01 þ S02: (1.41)
If r1 denotes the position vector of the intersection point, r1 lies on both of the
lines and satisfies the equations of both lines:
r1 � S1 ¼ S01; r1 � S2 ¼ S02: (1.42)
Thus we have
r1 � ðS1 þ S2Þ ¼ S01 þ S02: (1.43)
10 1 Basics of Screw Theory
Equation (1.43) shows that the point r1 lies on the line determined by the sum of
the two line vectors.
Note that when two lines are not coplanar, the sum of the two line vectors is a
screw with non-zero pitch instead of a line vector. Further, the sum of a line vector
and a couple is not a line vector.
Theorem 1.3. The sum of two couples, if not zero, is another couple.
1.5.2 Product of a Scalar and a Screw
The product of a scalar l and a screw $ is defined by
l$ ¼ ðlS; lS0Þ: (1.44)
1.5.3 Reciprocal Product
The reciprocal product of two screws, say $1 ¼ S1; S01
� �, $2 ¼ S2; S
02
� �, is defined by
$1 � $2 ¼ S1 � S02 þ S2 � S01 (1.45)
where the symbol ○ denotes the reciprocal product of two screws.
When the origin of the coordinate system shifts from point O to point A, the twoscrews $1 and $2 become
$A1 ¼ S1; SA1
� � ¼ S1; S01 þ AO� S1
� �;
$A2 ¼ S2; SA2
� � ¼ S2; S02 þ AO� S2
� �: (1.46)
The reciprocal product of the two new screws is
$A1 � $A2 ¼ S1 � S02 þ AO� S2� �þ S2 � S01 þ AO� S1
� � ¼ $1 � $2: (1.47)
This result indicates that the reciprocal product of two screws is not origin-
dependent.
The reciprocal product of two screws represents the work produced by a wrench
acting on a rigid body undergoing an infinitesimal twist.
1.6 Instantaneous Kinematics of a Rigid Body
The most general motion in three-dimensional space is screw motion, which means
simultaneous translational and rotational motion. Pure translation and pure rotation
are special cases of screw motion. In this section, we will discuss pure rotation,
1.6 Instantaneous Kinematics of a Rigid Body 11
translation, and screw motion, including how to determine the Pl€ucker coordinates,pitch, and the equation of axis.
1.6.1 Instantaneous Rotation
In Fig. 1.7, the rigid body labeled by 2 is rotating about another rigid body labeled
by 1. The axis of rotation is S. Such a rotation can be described by the angular
velocity line vector
o$ ¼ oðS; S0Þ ¼ ðoS;oS0Þ; (1.48)
whereo is the amplitude of the rotation andS is the unit vector in the direction of theline.
The equation of the axis of rotation is given by
r � S ¼ S0: (1.49)
The second component of Eq. (1.48) is
oS0 ¼ or � S ¼ r �v ¼ v0; (1.50)
which is the velocity of a point coincident with the origin, or the tangent velocity of
the point coincident with the origin. Equation (1.48) can also be rewritten as
follows:
o$ ¼ ðv; v0Þ: (1.51)
Therefore, the dual vectors denoting the rotation of a rigid body include the
angular velocity, v, and the linear velocity, v0 , of the point coincident with the
origin. The Pl€ucker coordinates of a rotating rigid body are oðS; S0Þ or ðv; v0Þ.When the rotational axis passes through the origin, the Pl€ucker coordinates of therotational axis are o$ ¼ ðv; 0Þ or ðv; 0Þ.
Z
X
Y
2
1
r
v0 Sw
O
$
Fig. 1.7 Instantaneous
rotation of a body
12 1 Basics of Screw Theory
1.6.2 Instantaneous Translation
An instantaneous translation of one rigid body relative to another one can be
conveniently modeled by connecting the two bodies by a prismatic or sliding pair
(as illustrated in Fig. 1.7). The translational velocity n can be expressed as a scalar
multiple of the instantaneous linear displacement n and a unit vectorS parallel to thedirection of motion. The vector S is for convenience drawn through the center line
of the joint. However, all points in the moving body have the same linear velocity
v ¼ vS, and a self-parallel displacement of the vector S does not affect the motion.
The same motion is obtained when the joint is reconnected parallel to its original
attachment and the body is given the same instantaneous translational displacement
v. For this reason,S is called a free vector and the motion can be quantified by taking
a scalar multiple of the free vector vð0; SÞ or ð0; nÞ. Some readers may prefer to
consider instantaneous translation to be an instantaneous rotation about an axis that
is orthogonal to S and that lies in the plane at infinity. The Pl€ucker coordinates ofthis axis are ð0; SÞ, and the instantaneous rotation about this axis can be expressed asthe scalar multiple vð0; SÞ.
1.6.3 Instantaneous Screw Motion
When the motion of one body 2 relative to another includes rotation about the axis
S1 and translation in the direction S1, the situation is more complex, as shown in
Fig. 1.8. The body rotates about the axis S1, with the instantaneous wrench o1ðS1; S01Þ, where ðS1; S01Þ is unit screw. The body also translates with screw v2ð0;S1Þalong the axisS1 at the same time. The absolute motion of the body is the sum of the
two parts.
Si
r i× w i
O
w i
vi = hiw iSi
w iSi0 = vi
0
vi
Fig. 1.8 Twist motion
of a body
1.6 Instantaneous Kinematics of a Rigid Body 13
That is,
oi $i ¼ ðo1S1;o1S01Þ þ ð0; v1S1Þ ¼ ðo1S1;o1S01 þ ho1S1Þ¼ o1 S1; S
01
� �; (1.52)
or
oi $i ¼ o1 S1; S01
� � ¼ ðv1; v0Þ; (1.53)
where v1 is the angular velocity of the body and v0 is the velocity of a point in the
body coincident with the origin. Note that the directions of v0 andv1 are different in
general, unless the axis of the screw passes the origin. The pitch is
h ¼ S1 � S01S1 � S1 ¼
v1 � v0v1 �v1
: (1.54)
1.7 Statics of a Rigid Body
1.7.1 A Force Acting on a Body
Analogous to instantaneous rotation, unit line vectors can be used to express the
action of a force on a body, as shown in Fig. 1.9. A force f can be expressed as a
scalar multiple fS of the unit vector S bound to the line. The moment of the force C0
about a reference point O can be expressed as a scalar multiple fS0 of the moment
vector S0 ¼ r � S . The action of the force upon the body can thus be elegantly
expressed as a scalar multiple f$ of the unit line vector
Z
YX
Or
f
Fig. 1.9 Force acting
on a body
14 1 Basics of Screw Theory
f$ ¼ ðf ; fS0Þ ¼ ðf ;C0Þ; (1.55)
where $ is unit line vector, S � S ¼ 1 and S � S0 ¼ 0. The line vector can be used to
express the magnitude, direction and the acting line in space.
The Pl€ucker coordinates of the force line vector are f ðS; S0Þ, ðfS; fS0Þ or ðf ;C0Þ,where C0 is the moment of force f about the origin, that is, C0 ¼ fS0 ¼ f r � S0.When the force f passes through the origin, the moment vanishes (C0 ¼ 0), and the
Pl€ucker coordinates of the force are ðf ; 0Þ.
1.7.2 A Couple Acting on a Body
Figure 1.10 illustrates a rigid body subjected to two equal and opposite forces f 1and f 2. These two forces constitute a couple, the moment of which is given by
C ¼ ðr2 � r1Þ � f 2 ¼ ðr1 � r2Þ � f 1 (1.56)
The vector C is clearly normal to the plane containing the forces, and C can
thus be expressed as a scalar multiple CS of any unit vector normal to the plane.
The vector S is therefore a free vector and the couple vector C can be given a self-
parallel displacement without altering the statics of the body.
The couple C can thus be expressed as a scalar multiple C(0; SÞ of the free vectorð0; SÞ . Alternatively, the couple can be considered a force acting upon the body
along a line that is orthogonal to S and that lies in the plane at infinity. The Pl€uckercoordinates of this line are ð0; SÞ, and the force acting upon the body can be
expressed as the scalar multiple C(0;SÞ.
1.7.3 A Twist Acting on a Body
A general system of forces and couples acting upon a rigid body can be reduced to a
single force f1 Si; S0i
� �and a single couple C(0;SÞ. This force couple combination
Z
O
X
Y
S
f1
f2
r 1
r2
Fig. 1.10 A couple acting
on a body
1.7 Statics of a Rigid Body 15
was called a dyname by Pl€ucker and Hunt. The above mentioned force screw f1Si;S
0i
� �can be expressed as the sum of a force f1 Si; S
0i
� �and a couple C(0; SÞ with
the same direction as the force. When the origin is located on the axis S1, this forcescrew can be expressed as
f1 S1; S01
� � ¼ ðf 1;C0Þ: (1.57)
When the origin does not lie on the axis S1, the force screw is
f1 S1; S01
� � ¼ ðf 1;C0Þ; (1.58)
where C0 is the moment about the origin.
References
1. Pl€ucker J (1865) On a new geometry of space. Philos Trans 155:725–791
2. Ball RA (1900) Treatise on the theory of screws. Cambridge University Press, Cambridge,
pp 1–30
3. Dimentberg FM (1950) Determination of the motion of spatial mechanisms. Akad Nauk,
Moscow (Russian)
4. Yang AT, Freudenstein F (1964) Application of dual-number quaternion algebra to the
analysis of spatial mechanisms. Trans ASME 86E:300–308 (J Appl Mech 31)
5. Waldron KJ (1966) The constraint analysis of mechanisms. J Mech 1:101–114
6. Roth B (1967) On the screw axes and other special lines associated of a rigid body. J Eng Ind
89:102–109
7. Hunt KH (1978) Kinematic geometry of mechanisms. Oxford University Press, Oxford
8. Phillips J (1990) Freedom in machinery. Cambridge University Press, Sydney, pp 147–168
9. Duffy J (1982). The screw theory and its application. Class note of University of Florida,
Gainesville
10. Angeles J (1994) On twist and wrench generators and annihilators. In: Seabra Pereira MFO,
Ambrosio JAC (eds) Computer-aided analysis of rigid and flexible mechanical system. Kluwer
Academic, Dordrecht
11. Brand L (1947) Vector and tensor analysis. Wiley, New York, pp 51–83
16 1 Basics of Screw Theory