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CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS MOHAMMAD SAL MOSLEHIAN 1 AND MOJTABA BAKHERAD 2 Abstract. We establish several operator extensions of the Chebyshev inequality. The main version deals with the Hadamard product of Hilbert space operators. More precisely, we prove that if A is a C * -algebra, T is a compact Hausdorff space equipped with a Radon measure μ(t), α : T [0, +) is a measurable function and (A t ) tT , (B t ) tT are suitable continuous fields of operators in A having the synchro- nous Hadamard property, then Z T α(s)(s) Z T α(t)(A t B t )(t) Z T α(t)A t (t) Z T α(s)B s (s) . We apply states on C * -algebras to obtain some versions related to synchronous func- tions. We also present some Chebyshev type inequalities involving the singular values of positive n × n matrices. Several applications are given as well. 1. Introduction and preliminaries Let B(H ) denote the C * -algebra of all bounded linear operators on a complex Hilbert space H together with the operator norm k·k. Let I stand for the identity operator. In the case when dimH = n, we identify B(H ) with the matrix algebra M n of all n × n matrices with entries in the complex field C. An operator A B(H ) is called positive (positive semidefinite for a matrix) if hAx, xi≥ 0 for all x H and then we write A 0. By a strictly positive operator (positive definite for a matrix) A, denoted by A> 0, we mean a positive invertible operator. For self-adjoint operators A, B B(H ), we say B A (B>A, resp.) if B - A 0(B - A> 0, resp.). Let B J h (H ) be the set of all self-adjoint operators in B(H ), whose spectra are con- tained in J . The Gelfand map f (t) 7f (A) is an isometrically *-isomorphism between the C * -algebra C (Sp(A)) of continuous functions on the spectrum Sp(A) of a self- adjoint operator A and the C * -algebra generated by I and A. If f,g C (Sp(A)), then f (t) g(t)(t Sp(A)) implies that f (A) g(A). If f be a continuous real valued function on an interval J . The function f is called 2010 Mathematics Subject Classification. Primary 47A63, Secondary 47A60. Key words and phrases. Chebyshev inequality; Hadamard product; Bochner integral; super- multiplicative function; singular value; operator mean. 1
Transcript

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACEOPERATORS

MOHAMMAD SAL MOSLEHIAN1 AND MOJTABA BAKHERAD2

Abstract. We establish several operator extensions of the Chebyshev inequality.

The main version deals with the Hadamard product of Hilbert space operators.

More precisely, we prove that if A is a C∗-algebra, T is a compact Hausdorff space

equipped with a Radon measure µ(t), α : T → [0,+∞) is a measurable function and

(At)t∈T , (Bt)t∈T are suitable continuous fields of operators in A having the synchro-

nous Hadamard property, then∫T

α(s)dµ(s)

∫T

α(t)(At ◦Bt)dµ(t) ≥(∫

T

α(t)Atdµ(t))◦(∫

T

α(s)Bsdµ(s)).

We apply states on C∗-algebras to obtain some versions related to synchronous func-

tions. We also present some Chebyshev type inequalities involving the singular values

of positive n× n matrices. Several applications are given as well.

1. Introduction and preliminaries

Let B(H ) denote the C∗-algebra of all bounded linear operators on a complex Hilbert

space H together with the operator norm ‖ · ‖. Let I stand for the identity operator.

In the case when dimH = n, we identify B(H ) with the matrix algebra Mn of all

n × n matrices with entries in the complex field C. An operator A ∈ B(H ) is called

positive (positive semidefinite for a matrix) if 〈Ax, x〉 ≥ 0 for all x ∈ H and then

we write A ≥ 0. By a strictly positive operator (positive definite for a matrix) A,

denoted by A > 0, we mean a positive invertible operator. For self-adjoint operators

A,B ∈ B(H ), we say B ≥ A (B > A, resp.) if B − A ≥ 0 (B − A > 0, resp.).

Let BJh(H ) be the set of all self-adjoint operators in B(H ), whose spectra are con-

tained in J . The Gelfand map f(t) 7→ f(A) is an isometrically ∗-isomorphism between

the C∗-algebra C(Sp(A)) of continuous functions on the spectrum Sp(A) of a self-

adjoint operator A and the C∗-algebra generated by I and A. If f, g ∈ C(Sp(A)), then

f(t) ≥ g(t) (t ∈ Sp(A)) implies that f(A) ≥ g(A).

If f be a continuous real valued function on an interval J . The function f is called

2010 Mathematics Subject Classification. Primary 47A63, Secondary 47A60.

Key words and phrases. Chebyshev inequality; Hadamard product; Bochner integral; super-

multiplicative function; singular value; operator mean.

1

2 M.S. MOSLEHIAN, M. BAKHERAD

operator monotone (operator decreasing, resp.) if A ≤ B implies f(A) ≤ g(B)

(f(B) ≤ g(A), resp.) for all A,B ∈ BJh(H ). For A ∈ Mn, the singular values

of A, denoted by s1(A), s2(A), · · · , sn(A), are the eigenvalues of the positive matrix

|A| = (A∗A)12 enumerated as s1(A) ≥ · · · ≥ sn(A) with their multiplicities counted.

Given an orthonormal basis {ej} of a Hilbert space H , the Hadamard product A◦Bof two operators A,B ∈ B(H ) is defined by 〈A ◦ Bei, ej〉 = 〈Aei, ej〉〈Bei, ej〉. It is

known that the Hadamard product can be presented by filtering the tensor product

A⊗B through a positive linear map. In fact,

A ◦B = U∗(A⊗B)U,

where U : H → H ⊗ H is the isometry defined by Uej = ej ⊗ ej; see [6]. For

matrices, one easily observe [14] that the Hadamard product of A = (aij) and B = (bij)

is A ◦B = (aijbij), a principal submatrix of the tensor product A⊗B = (aijB)1≤i,j≤n.

From now on when we deal with the Hadamard product of operators, we explicitly

assume that we fix an orthonormal basis.

The axiomatic theory of operator means has been developed by Kubo and Ando

[8]. An operator mean is a binary operation σ defined on the set of strictly positive

operators, if the following conditions hold:

(i) A ≤ C,B ≤ D imply AσB ≤ CσD;

(ii) An ↓ A,Bn ↓ B imply AnσBn ↓ AσB, where An ↓ A means that A1 ≥ A2 ≥ · · ·and An → A as n→∞ in the strong operator topology;

(iii) T ∗(AσB)T ≤ (T ∗AT )σ(T ∗BT ) (T ∈ B(H ));

(iv) IσI = I.

There exists an affine order isomorphism between the class of operator means and

the class of positive operator monotone functions f defined on (0,∞) with f(1) = 1

via f(t)I = Iσ(tI) (t > 0). In addition, AσB = A12f(A

−12 BA

−12 )A

12 for all strictly

positive operators A,B. The operator monotone function f is called the representing

function of σ. Using a limit argument by Aε = A+ εI, one can extend the definition of

AσB to positive operators. The operator means corresponding to the positive operator

monotone functions f]µ(t) = tµ and f!(t) = 2t1+t

on [0,∞) are the operator weighted

geometric mean A]µB = A12

(A

−12 BA

−12

)µA

12 and the operator harmonic mean A!B =

2(A−1 +B−1)−1, respectively.

Let us consider the real sequences a = (a1, · · · , an), b = (b1, · · · , bn) and the non-

negative sequence w = (w1, · · · , wn). Then the weighed Chebyshev function is defined

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 3

by

T (w; a, b) :=n∑j=1

wj

n∑j=1

wjajbj −n∑j=1

wjaj

n∑j=1

wjbj.

In 1882, Cebysev [3] proved that if a and b are monotone in the same sense, then

T (w; a, b) ≥ 0.

Some integral generalizations of this inequality was given by Barza, Persson and Soria

[1]. The Chebyshev inequality is a complement of the Gruss inequality; see [10] and

references therein.

A related notion is synchronicity. Recall that two continuous functions f, g : J → Rare synchronous on an interval J , if(

f(t)− f(s))(g(t)− g(s)

)≥ 0

for all s, t ∈ J . It is obvious that, if f, g are monotonic and have the same monotonicity,

then they are synchronic. Dragomir [4] generalized Chebyshev inequality for convex

functions on a real normed space and applied his results to show that if p1, · · · , pn is

a sequence of nonnegative numbers with∑n

j=1 pj = 1 and two sequences (v1, · · · , vn)

and (u1, · · · , un) in a real inner product space are synchronous, that is, 〈vk − vj, uk −uj〉 ≥ 0 for all j, k = 1, · · · , n, then

∑nk=1 pk〈vk, uk〉 ≥ 〈

∑nk=1 pkvk,

∑nk=1 pkuk〉. He

also presented some Chebyshev inequalities for self-adjoint operators acting on Hilbert

spaces in [5].

In this paper we provide several operator extensions of the Chebyshev inequality. In

the second section, we present our main results dealing with the Hadamard product

of Hilbert space operators and weighted operator geometric means. The key notion

is the so-called synchronous Hadamard property. More Chebyshev type inequalities

regarding operator means are presented in Section 3. In Section 4, we apply states on

C∗-algebras to obtained some versions related to synchronous functions. We present

some Chebyshev type inequalities involving the singular values of positive n×nmatrices

in the last section.

2. Chebyshev inequality dealing with Hadamard product

This section is devoted to presentation of some operator Chebyshev inequalities

dealing with the Hadamard product and weighted operator geometric means. The key

notion is the so-called synchronous Hadamard property.

4 M.S. MOSLEHIAN, M. BAKHERAD

Let A be a C∗-algebra of operators acting on a Hilbert space and let T be a compact

Hausdorff space. A field (At)t∈T of operators in A is called a continuous field of

operators if the function t 7→ At is norm continuous on T . If µ(t) is a Radon measure

on T and for a field (At) the function t 7→ ‖At‖ is integrable, one can form the Bochner

integral∫TAtdµ(t), which is the unique element in A such that

ϕ

(∫T

Atdµ(t)

)=

∫T

ϕ(At)dµ(t)

for every linear functional ϕ in the norm dual A ∗ of A .

By [13, Page 78], since t 7→ At is a continuous function from T to A , for every operator

At ∈ A we can consider an element of the form

Iλ(At) = Σnk=1At(sk)µ(Ek),

where the Ek’s form a partition of T into disjoint Borel subsets, and

sk ∈ Ek ⊆ {t ∈ T : ‖At − At(sk)‖ ≤ ε} (1 ≤ k ≤ n),

with λ = {E1, · · · , En, ε}. Then (Iλ(At))λ∈Λ is a uniformly convergent net to∫TAtdµ(t).

Let C(T,A ) denote the set of bounded continuous functions on T with values in A . It

is easy to see that the set C(T,A ) is a C∗-algebra under the pointwise operations and

the norm ‖(At)‖ = supt∈T ‖At‖; cf. [7]. Now since tensor product of two operators is

norm continuous, for any operator B ∈ A we have∫T

(At ⊗B)dµ(t) =( ∫

T

Atdµ(t))⊗B.

Also, for any operator C ∈ A∫T

(C∗AtC)dµ(t) = C∗( ∫

T

Atdµ(t))C.

Therefore ∫T

(At ◦B)dµ(t) =

∫T

V ∗(At ⊗B)V dµ(t) = V ∗∫T

(At ⊗B)dµ(t)V

= V ∗(

∫T

Atdµ(t)⊗B)V =

∫T

Atdµ(t) ◦B (At, B ∈ A ). (2.1)

Let us give our key definition.

Definition 2.1. Two fields (At)t∈T and (Bt)t∈T are said to have the synchronous

Hadamard property if (At − As

)◦(Bt −Bs

)≥ 0

for all s, t ∈ T .

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 5

The first result reads as follows.

Theorem 2.2. Let A be a C∗-algebra, T be a compact Hausdorff space equipped with

a Radon measure µ, let (At)t∈T and (Bt)t∈T be fields in C(T,A ) with the synchronous

Hadamard property and let α : T → [0,+∞) be a measurable function. Then∫T

α(s)dµ(s)

∫T

α(t)(At ◦Bt)dµ(t) ≥(∫

T

α(t)Atdµ(t))◦(∫

T

α(s)Bsdµ(s)). (2.2)

Proof. We have∫T

α(s)dµ(s)

∫T

α(t)(At ◦Bt)dµ(t)−(∫

T

α(t)Atdµ(t))◦(∫

T

α(s)Bsdµ(s))

=

∫T

∫T

α(s)α(t)(At ◦Bt)dµ(t)dµ(s)−∫T

(∫T

α(t)Atdµ(t))◦ α(s)Bsdµ(s)

(by 2.1)

=

∫T

∫T

α(s)α(t)(At ◦Bt)dµ(t)dµ(s)−∫T

∫T

α(t)α(s)(At ◦Bs)dµ(t)dµ(s)

(by 2.1)

=

∫T

∫T

(α(s)α(t)(At ◦Bt)− α(t)α(s)(At ◦Bs)

)dµ(t)dµ(s)

=1

2

∫T

∫T

[α(s)α(t)(At ◦Bt)− α(t)α(s)(At ◦Bs)

− α(s)α(t)(As ◦Bt) + α(t)α(s)(As ◦Bs)]dµ(t)dµ(s)

=1

2

∫T

∫T

[α(s)α(t)

(At − As

)◦(Bt −Bs

)]dµ(t)dµ(s)

≥ 0. (since the fields (At) and (Bt) have synchronous Hadamard property)

In the discrete case T = {1, · · · , n}, set α(i) = ωi ≥ 0 (1 ≤ i ≤ n). Then Theorem

2.2 forces the following result.

Corollary 2.3. [9, Teorem 2.1] Let A1 ≥ · · · ≥ An, B1 ≥ · · · ≥ Bn be self-adjoint

operators and ω1, · · · , ωn be positive numbers. Then

n∑j=1

ωj

n∑j=1

ωj(Aj ◦Bj) ≥( n∑j=1

ωjAj

)◦( n∑j=1

ωjBj

).

Recall that a continuous function f : J → R is super-multiplicative if f(xy) ≥f(x)f(y), for all x, y ∈ J . In the next result we need the notion of increasing field. Let

T be a compact Hausdorff space as well as a totaly order set under an order �. We

6 M.S. MOSLEHIAN, M. BAKHERAD

say (At) is an increasing (decreasing, resp.) field, whenever t � s implies that At ≤ As

(At ≥ As, resp.).

Theorem 2.4. Let A be a C∗-algebra, T be a compact Hausdorff space equipped with a

Radon measure µ as a totaly order set, let (At)t∈T , (Bt)t∈T , (Ct)t∈T , (Dt)t∈T be positive

increasing fields in C(T,A ), let α : T → [0,+∞) be a measurable function and σ be

an operator mean with the super-multiplicative representing function. Then∫T

α(s)dµ(s)

∫T

α(t)(

(At ◦Bt)σ(Ct ◦Dt))dµ(t)

≥(∫

T

α(t)(AtσCt)dµ(t))◦(∫

T

α(s)(BsσDs)dµ(s)).

Proof. Let s, t ∈ T . Without loss of generality assume that s � t. Then by the property

(i) of the operator mean we have 0 ≤ (AtσBt)− (AsσBs). Then∫T

α(s)dµ(s)

∫T

(α(t)(At ◦Bt)σ(Ct ◦Dt)

)dµ(t)

−(∫

T

α(t)(AtσCt)dµ(t))◦(∫

T

α(s)(BsσDs)dµ(s))

=

∫T

∫T

α(s)α(t)(

(At ◦Bt)σ(Ct ◦Dt))dµ(t)dµ(s)

−∫T

∫T

α(t)α(s)(

(AtσCt) ◦ (BsσDs))dµ(t)dµ(s) (by 2.1)

≥∫T

∫T

α(s)α(t)(

(AtσCt) ◦ (BtσDt))dµ(t)dµ(s)

−∫T

∫T

α(t)α(s)(

(AtσCt) ◦ (BsσDs))dµ(t)dµ(s) (by [12, Theorem 6.7])

=1

2

∫T

∫T

α(s)α(t)[(

(AtσCt) ◦ (BtσDt))−(

(AtσCt) ◦ (BsσDs))

+(

(AsσCs) ◦ (BsσDs))−(

(AsσCs) ◦ (BtσDt))]dµ(t)dµ(s)

=1

2

∫T

∫T

α(s)α(t)[(AtσCt)− (AsσCs)

]◦[(BtσDt)− (BsσDs)

]dµ(t)dµ(s)

≥ 0. (by the property (i) of the operator mean)

A discrete version of the theorem above is the following result obtained by taking

T = {1, · · · , n}.

Corollary 2.5. Let Ai+1 ≥ Ai ≥ 0, Bi+1 ≥ Bi ≥ 0, Ci+1 ≥ Ci ≥ 0, Di+1 ≥ Di ≥0 (1 ≤ i ≤ n− 1), ω1, · · · , ωn be positive numbers and σ be an operator mean with the

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 7

super-multiplicative representing function. Then

n∑j=1

ωj

n∑j=1

ωj

[(Aj ◦Bj)σ(Cj ◦Dj)

]≥( n∑j=1

ωj(AjσCj))◦( n∑j=1

ωj(BjσDj)).

Theorem 2.6. Let A be a C∗-algebra, T be a compact Hausdorff space equipped with a

Radon measure µ as a totaly order set, let (At)t∈T , (Bt)t∈T be positive increasing fields

in C(T,A ) and let α : T → [0,+∞) be a measurable function. Then∫T

α(s)dµ(s)

∫T

α(t)(At ◦Bt)dµ(t) ≥(∫

T

α(t)(At]µBt)dµ(t))◦(∫

T

α(s)(As]1−µBs)dµ(s))

for all µ ∈ [0, 1].

Proof. Let s, t ∈ T . Without loss of generality assume that s � t. Then by the property

(i) of the operator mean, we have 0 ≤ (At]µBt) − (As]µBs) and 0 ≤ (At]1−µBt) −(As]1−µBs). Then∫T

α(s)dµ(s)

∫T

α(t)(At ◦Bt)dµ(t)−(∫

T

α(t)(At]µBt)dµ(t))◦(∫

T

α(s)(As]1−µBs)dµ(s))

=

∫T

∫T

α(s)α(t)(At ◦Bt)dµ(t)dµ(s)−∫T

∫T

α(t)α(s)(

(At]µBt) ◦ (As]1−µBs))dµ(t)dµ(s)

(by 2.1)

≥∫T

∫T

α(s)α(t)(

(At]µBt) ◦ (At]1−µBt))dµ(t)dµ(s)

−∫T

∫T

α(t)α(s)(

(At]µBt) ◦ (As]1−µBs))dµ(t)dµ(s) (by [12, Theorem 6.6])

=1

2

∫T

∫T

[α(s)α(t)

((At]µBt) ◦ (At]1−µBt)

)− α(t)α(s)

((At]µBt) ◦ (As]1−µBs)

)+ α(t)α(s)

((As]µBs) ◦ (As]1−µBs)

)− α(s)α(t)

((As]µBs) ◦ (At]1−µBt)

)]dµ(t)dµ(s)

=1

2

∫T

∫T

α(s)α(t)[(At]µBt)− (As]µBs)

]◦[(At]1−µBt)− (As]1−µBs)

]dµ(t)dµ(s)

≥ 0. (by the property (i) of the operator mean)

In the discrete case T = {1, · · · , n}, set α(i) = ωi ≥ 0 (1 ≤ i ≤ n) in Theorem 2.6.

Then

8 M.S. MOSLEHIAN, M. BAKHERAD

Corollary 2.7. Let An ≥ · · · ≥ A1 ≥ 0, Bn ≥ · · · ≥ B1 ≥ 0 and ω1, · · · , ωn be positive

numbers. Then

n∑j=1

ωj

n∑j=1

ωj(Aj ◦Bj

)≥( n∑j=1

ωj(Aj]µBj))◦( n∑j=1

ωj(Aj]1−µBj))

for all µ ∈ [0, 1].

Proposition 2.8. Let f : [0,∞)→ R be a super-multiplicative and operator monotone

function, A1 ≥ · · · ≥ An ≥ 0, B1 ≥ · · · ≥ Bn ≥ 0 and ω1, · · · , ωn be positive numbers.

Then

n∑j=1

ωj

n∑j=1

ωjf(Aj ◦Bj) ≥( n∑j=1

ωjf(Aj))◦( n∑j=1

ωjf(Bj)).

Proof.

n∑j=1

ωj

n∑j=1

ωjf(Aj ◦Bj)−( n∑j=1

ωjf(Aj))◦( n∑j=1

ωjf(Bj))

≥n∑j=1

ωj

n∑j=1

ωj

(f(Aj) ◦ f(Bj)

)−( n∑j=1

ωjf(Aj))◦( n∑j=1

ωjf(Bj))

(by [12, Theorem 6.3])

=n∑

i,j=1

[ωiωj

(f(Aj) ◦ f(Bj)

)− ωiωj

(f(Ai) ◦ f(Bj)

)]=

1

2

n∑i,j=1

ωiωj

[(f(Aj) ◦ f(Bj)

)−(f(Ai) ◦ f(Bj)

)+(f(Ai) ◦ f(Bi)

)−(f(Aj) ◦ f(Bi)

)]=

1

2

n∑i,j=1

ωiωj

[(f(Aj)− f(Ai)

)◦(f(Bj)− f(Bi)

)]≥ 0. (by the operator monotonicity of f)

Example 2.9. Let A1 ≥ · · · ≥ An ≥ 0, B1 ≥ · · · ≥ Bn ≥ 0 and ω1, · · · , ωn be positive

numbers. Then

n∑j=1

ωj

n∑j=1

ωj(Aj ◦Bj)p ≥

( n∑j=1

ωjApj

)◦( n∑j=1

ωjBpj

)for each p ∈ [0, 1].

In the finite dimensional case we get the following.

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 9

Corollary 2.10. Let A1 ≥ · · · ≥ Ak, B1 ≥ · · · ≥ Bk be positive n × n matrices and

ω1, · · · , ωk be positive numbers. Then

( k∑j=1

ωj)n

det( k∑j=1

ωj(Aj ◦Bj))≥( k∑j=1

ωnj det(Aj))( k∑

j=1

ωnj det(Bj)).

Proof.

( k∑j=1

ωj)n

det( k∑j=1

ωj(Aj ◦Bj))

= det( k∑j=1

ωj

k∑j=1

ωj(Aj ◦Bj))

≥ det(( k∑

j=1

ωjAj)◦( k∑j=1

ωjBj

))(by Corolary 2.3)

≥ det( k∑j=1

ωjAj

)det( k∑j=1

ωjBj

)(by the property of Hadamard product)

≥( k∑j=1

ωnj det(Aj))( k∑

j=1

ωnj det(Bj)). (by the property of det)

Proposition 2.11. Let A1 ≥ · · · ≥ Ak > 0, Bk ≥ · · · ≥ B1 ≥ 0 be n× n matrices and

ω1, · · · , ωk be positive numbers. Then

( k∑j=1

ωj)( k∑

j=1

ωjtr(A−1j Bj)

)≥( k∑j=1

ωjtr(Aj)−1)( k∑

j=1

ωjtr(Bj)).

Proof.

( k∑j=1

ωj)( k∑

j=1

ωjtr(A−1j Bj)

)≥( k∑j=1

ωj)( k∑

j=1

ωjtr(Aj)−1tr(Bj)

)(by [16, page 224])

≥( k∑j=1

ωjtr(Aj)−1)( k∑

j=1

ωjtr(Bj)). (by Chebyshev inequality)

3. More Chebyshev type inequalities regarding operator means

The first author and Najafi [11, Theorem 2.4] showed that for any non-negative

operator monotone function f on [0,+∞), positive operators Aj (j = 1, · · · , n) with

10 M.S. MOSLEHIAN, M. BAKHERAD

spectra in [λ, (1 + 2√

2)λ] for some λ ∈ R+ and operators Cj (j = 1, · · · , n) with∑nj=1C

∗jC = I, it holds that

f( n∑j=1

C∗jAjC)≤ 2

n∑j=1

C∗j f

(Aj2

)Cj. (3.1)

By [12, Theorem 5.7] for positive operators A,B,C,D ∈ B(H ) we have

AσC +BσD ≤ (A+B)σ(C +D). (3.2)

Now we show that the reverse of inequality (3.2) is true under some suitable conditions.

Theorem 3.1. Let A,B,C,D ∈ B(H ) be positive operators such that λA ≤ C ≤(1 + 2

√2)λA, λB ≤ D ≤ (1 + 2

√2)λB for some λ ∈ R+ and σ be an operator mean.

Then

(i) 2 (AσC +BσD) ≥ (A+B)σ(C +D)

(ii) 2α(AσC) + 2(1− α)(BσD) ≥ (αA+ (1− α)B)σ(αC + (1− α)D)

for all α ∈ [0, 1].

Proof. (i) Let A,B,C,D be strictly positive operators. Put X = A12 (A + B)−

12 , Y =

B12 (A+B)−

12 , V = A−

12CA−

12 and W = B−

12DB−

12 . It follows from X∗X + Y ∗Y = I

that S =

(X 0

Y 0

)is a contraction. Note that the spectrum of T =

(V 0

0 W

)is

contained in the interval [λ, (1 + 2√

2)λ]. Put S ′ = (I −S∗S)12 . Since S∗S +S ′∗S ′ = I,

by inequality (3.1) we have

f(S∗TS) ≤ f(S∗TS + S ′∗λS ′) ≤ 2S∗f

(T

2

)S + 2S ′∗f

2

)S ′. (3.3)

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 11

Hence(f(X∗V X + Y ∗WY ) 0

0 f(0)

)

= f

((X 0

Y 0

)∗(V 0

0 W

)(X 0

Y 0

))= f (S∗TS)

≤ 2S∗f

(T

2

)S + 2S ′∗f

2

)S ′ (by inequality (3.3))

= 2

(X 0

Y 0

)∗f

((V2

0

0 W2

))(X 0

Y 0

)+

(0 0

0 2f(λ2

) )

=

(2X∗f

(V2

)X + 2Y ∗f

(W2

)Y 0

0 2f(λ2

) ) ,whence

f(X∗V X + Y ∗WY ) ≤ 2X∗f

(V

2

)X + 2Y ∗f

(W

2

)Y. (3.4)

Moreover

2

((Aσ

C

2) + (Bσ

D

2)

)= 2

(A

12

(Iσ

(A−

12C

2A−

12

))A

12 +B

12

(Iσ

(B−

12D

2B−

12

))B

12

)(by the property (iii) of σ)

= 2

((A+B)

12 X∗

(IσV

2

)X(A+B)

12 + (A+B)

12Y ∗

(IσW

2

)Y (A+B)

12

)= 2

((A+B)

12

(X∗f

(V

2

)X

)(A+B)

12 + (A+B)

12

(Y ∗f

(W

2

)Y

)(A+B)

12

)= (A+B)

12

(2X∗f

(V

2

)X + 2Y ∗f

(W

2

)Y

)(A+B)

12

≥ (A+B)12f(X∗V X + Y ∗WY )(A+B)

12 (by 3.4)

= (A+B)12 (Iσ(X∗V X + Y ∗WY )) (A+B)

12

= (A+B)σ(A

12V A

12 +B

12WB

12

)(by the property (iii) of σ)

= (A+B)σ(C +D) . (3.5)

12 M.S. MOSLEHIAN, M. BAKHERAD

Since σ is upper continuous, we get the desired inequality.

(ii) For all α ∈ [0, 1] we have

2α(AσC) + 2(1− α)(BσD) = 2(αAσαC) + 2((1− α)Bσ(1− α)D)

≥ (αA+ (1− α)B)σ(αC + (1− α)D) .

Corollary 3.2. Let A,B,C,D ∈ B(H ) be positive operators such that A ≤ C ≤(1 + 2

√2)A and B ≤ D ≤ (1 + 2

√2)B. Then

2 (A]νC +B]νD) ≥ (A+B)]ν(C +D)

for all ν ∈ [0, 1].

Corollary 3.3. Let {Ai}ni=1 and {Bi}ni=1 be positive operators in B(H ) such that

λAj ≤ Bj ≤ (1 + 2√

2)λAj (j = 1, · · · , n) for some λ ∈ R+ and let σ be an operator

mean. Then

2n∑j=1

(AjσBj) ≥ (n∑j=1

Aj)σ(n∑j=1

Bj).

Example 3.4. (i) A reverse of Holder’s inequality: If 0 ≤ Bqj ≤ Apj ≤ (1+2

√2)Bq

j (j =

1, · · · , n) and p, q > 0 with p−1 + q−1 = 1, then

2n∑j=1

(Apj] 1pBqj ) ≥

( n∑j=1

Apj)] 1p

( n∑j=1

Bqj

).

(ii) A reverse of Minkowski’s inequality: If 0 < Bj ≤ Aj ≤ (1 + 2√

2)Bj (j = 1, · · · , n),

then by utilizing A!B = 2(A−1 +B−1)−1 we get

2n∑j=1

(A−1j +B−1

j )−1 ≥[( n∑

j=1

A−1j

)−1+( n∑j=1

B−1j

)−1]−1

.

4. Chebyshev inequality for synchronous functions involving states

In this section, we apply the continuous functional calculus to synchronous functions

and present some Chebyshev type inequalities involving states on C∗-algebras. Our

main result of this section reads as follows.

Theorem 4.1. Let A be a unital C∗-algebra, τ1, τ2 be states on A and f, g : J → Rbe synchronous functions. Then

τ1

(f(A)g(A)

)+ τ2

(f(B)g(B)

)≥ τ1

(f(A)

)τ2

(g(B)

)+ τ2

(f(B)

)τ1

(g(A)

)(4.1)

for all A,B ∈ BJh(H ).

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 13

Proof. For the synchronous functions f, g and for each s, t ∈ J

f(t)g(t) + f(s)g(s)− f(t)g(s)− f(s)g(t) ≥ 0.

Fix s ∈ J . By the functional calculus for the operator A we have

f(A)g(A) + f(s)g(s)− f(A)g(s)− f(s)g(A) ≥ 0,

whence

τ1

(f(A)g(A)

)+ f(s)g(s)− τ1

(f(A)

)g(s)− f(s)τ1

(g(A)

)≥ 0.

Now for the operator B

τ1

(f(A)g(A)

)+ f(B)g(B)− τ1

(f(A)

)g(B)− f(B)τ1

(g(A)

)≥ 0.

For the state τ2 we have

τ1

(f(A)g(A)

)+ τ2

(f(B)g(B)

)≥ τ1

(f(A)

)τ2

(g(B)

)+ τ2

(f(B)

)τ1

(g(A)

).

Using Theorem 4.1 we obtain two next corollaries.

Corollary 4.2. Let A be a unital C∗-algebra, τ be a state on A and f, g : J → R be

synchronous functions. Then

τ(f(A)g(A)

)≥ τ

(f(A)

)τ(g(A)

)for all operator A ∈ BJh(H ). In particular

τ(f(A)2

)≥ τ

(f(A)

)2.

Proof. Put B = A in inequality (4.1) to get the result. �

Corollary 4.3. [5, Theorem 1] Let f, g : J → R be synchronous functions. Then

〈f(A)g(A)x, x〉+ 〈f(B)f(B)y, y〉 ≥ 〈f(A)x, x〉〈g(B)y, y〉+ 〈f(B)y, y〉〈g(A)x, x〉

for all operators A,B ∈ BJh(H ) and all unit vectors x, y ∈H .

Proof. Apply Theorem 4.1 to the states τ1, τ2 defined by τ1(A) = 〈Ax, x〉, τ2(A) =

〈Ay, y〉 (A ∈ B(H )) for fixed unit vectors x, y ∈H . �

14 M.S. MOSLEHIAN, M. BAKHERAD

Example 4.4. (i) Let τ be a state on B(H ) and p, q > 0. Since f(t) = tp and g(t) = tq

are synchronous

τ(Ap+q) + τ(Bp+q) ≥ τ(Ap)τ(Bq) + τ(Bp)τ(Aq) (A,B ≥ 0).

In a similar fashion, for self-adjoint operators A,B ∈ B(H )

τ(eαA+βA) + τ(eαB+βB) ≥ τ(eαA)τ(eβB) + τ(eβB)τ(eαA) (α, β ≥ 0).

(ii) Let f, g : J → R be synchronous functions. Then for n × n matrices A,B with

spectra in J

tr(f(A)g(A) + f(B)g(B)

)≥ 1

n

(tr(f(A)

)tr(g(B)

)+ tr

(g(A)

)tr(f(B)

)).

(iii) Let A,B be positive matrices, C be a positive definite matrix with tr(C) = α and

p, q ≥ 0. Utilizing τ(A) = tr(A ◦ C) we have

tr(Ap+q ◦ C +Bp+q ◦ C) ≥ 1

α

(tr(Ap ◦ C)tr(Bq ◦ C) + tr(Aq ◦ C)tr(Bp ◦ C)

).

Using the same strategy as in the proof of [15, Lemma 2.1] we get the next theorem.

Theorem 4.5. Let A be a unital C∗-algebra, τ be a state on A and f : J → [0,+∞),

g : J → R be continuous functions such that f is decreasing and g is operator decreasing

on a compact interval J . Then

τ(f(A)g(A)

)≥ τ

(f(B)

)τ(g(A)

)for all A,B ∈ BJh(H ) such that A ≤ B.

Proof. Put α = infx∈J g(x) and β = supx∈J g(x). Then α ≤ g(x) ≤ β (x ∈ J). So

αI ≥ g(B) ≥ βI, whence α ≥ τ(g(B)

)≥ β. Therefore, there exists a number t0 ∈ J

satisfying either

g(x) ≤ τ(g(B)

)if x ∈ J, x ≥ t0

and

g(x) ≥ τ(g(B)

)if x ∈ J, x < t0

or satisfying

g(x) ≤ τ(g(B)

)if x ∈ J, x > t0

and

g(x) ≥ τ(g(B)

)if x ∈ J, x ≤ t0.

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 15

Hence (f(x)− f(t0)

)(g(x)− τ

(g(B)

))≥ 0

for all x ∈ J . Thus

f(x)(g(x)− τ

(g(B)

))≥ f(t0)

(g(x)− τ

(g(B)

))for all x ∈ J . Hence

f(A)(g(A)− τ

(g(B)

))≥ f(t0)

(g(A)− τ

(g(B)

)).

Now

τ(f(A)g(A)

)− τ(g(B)

)τ(f(A)

)= τ(f(A)

(g(A)− τ(g(B))

))≥ τ

(f(t0)

(g(A)− τ(g(B))

))= f(t0)

(τ(g(A)

)− τ(g(B)

))≥ 0. (since g is operator decreasing)

Remark 4.6. Assumption A ≤ B is necessary in Theorem 4.5, since if τ(A) = 12tr(A),

f(t) = g(t) = 1t, A =

(2 0

0 3

)and B =

(1 0

0 1

), then we observe that A � B and

τ(A−2) = 1372< 5

12= τ(A−1)τ(B−1).

Corollary 4.7. Suppose that f : J → [0,+∞) and g : J → R are continuous functions

such that f is decreasing and g is operator decreasing. Then

〈f(A)g(A)x, x〉 − 〈f(B)x, x〉〈g(A)x, x〉 ≥ 0

for all operators A,B ∈ BJh(H ) such that A ≤ B and all unit vector x ∈H .

Proof. Apply Theorem 4.5 to the state τ defined by τ(A) = 〈Ax, x〉 (A ∈ B(H )) for a

fixed unit vector x ∈ H. �

Using the same strategy as in the proof of Theorem 4.1 we get the next result.

Theorem 4.8. Let A be a unital C∗-algebra, τ1, τ2 be states on A and f, g : R → Rbe synchronous functions. Then

τ2

(f(A)g(A)

)+ f(τ1(B)

)g(τ1(B)

)≥ f

(τ1(A)

)τ2

(g(B)

)+ τ1

(f(B)

)g(τ2(A)

)(4.2)

for all self-adjoint operators A,B.

16 M.S. MOSLEHIAN, M. BAKHERAD

Corollary 4.9. Let f, g : J → R be synchronous functions. Then

〈f(A)g(A)x, x〉+ f(〈By, y〉)g(〈By, y〉) ≥ f(〈Ax, x〉)〈g(B)y, y〉+ 〈f(B)y, y〉g(〈Ax, x〉)

for all operators A,B ∈ BJh(H ) and all unit vectors x, y ∈H .

Proof. Apply Theorem 4.8 to the states τ1, τ2 defined by τ1(A) = 〈Ax, x〉, τ2(A) =

〈Ay, y〉 (A ∈ B(H )) for fixed unit vectors x, y ∈H . �

Corollary 4.10. [5, Theorem 2] Let f, g : J → R are synchronous functions. Then

〈f(A)g(A)x, x〉 − f(〈Ax, x〉)g(〈Ax, x〉) ≥ [〈f(A)x, x〉 − f(〈Ax, x〉)][g(〈Ax, x〉)− 〈g(A)x, x〉]

for all operator A ∈ BJh(H ) and any unit vector x ∈H .

Corollary 4.11. Let A be a unital C∗-algebra, τ be a state on A and f, g : R → Rbe synchronous functions. Then

τ(f(B)g(B)

)− τ(f(B)

)τ(g(B)

)≥(τ(f(B)

)− f

(τ(A)

))(g(τ(A)

)− τ(g(B)

))for all self-adjoint operators A,B.

Proof. By using inequality (4.2) we have

τ(f(B)g(B)

)− τ(f(B)

)τ(g(B)

)≥ f

(τ(A)

)τ(g(B)

)+ τ(f(B)

)g(τ(A)

)− f

(τ(A)

)g(τ(A)

)− τ(f(B)

)τ(g(B)

)=(τ(f(B)

)− f

(τ(A)

))(g(τ(A)

)− τ(g(B)

)).

By using Corollary 4.11 and the Davis–Choi–Jensen inequality [12] to get the next

result.

Corollary 4.12. Let A be a unital C∗-algebra, τ be a state on A and f, g : R → Rbe synchronous and one is convex while the other is concave on R. Then

τ(f(A)g(A)

)− τ(f(A)

)τ(g(A)

)≥(τ(f(A)

)− f

(τ(A)

))(g(τ(A)

)− τ(g(A)

))≥ 0

for all self-adjoint operator A.

In the next proposition we establish a version of Aczel–Chebyshev type inequality.

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 17

Proposition 4.13. Let A be a unital C∗-algebra, τ be a state on A and f, g be

continuous functions such that 0 ≤ f(x) ≤ α and 0 ≤ g(x) ≤ β for some non-negative

real numbers α, β. Then(αβ − τ

(f(B)g(B)

))≥(α− τ

(f(B)

))(β − τ

(g(A)

))(4.3)

for all positive operators A,B ∈ A .

Proof. If α = 0 or β = 0, inequality (4.3) is travail. Now assume that α > 0 and β > 0.

Then (4.3) is equivalent to the inequality(1− τ

(f(B)g(B)

))≥(1− τ

(f(B)

))(1− τ

(g(A)

)),

with 0 ≤ f(x) ≤ 1 and 0 ≤ g(x) ≤ 1. Then we have(1− τ

(f(B)g(B)

))≥(1− τ

(f(B)

))≥(1− τ

(f(B)

))(1− τ

(g(A)

))≥ 0.

5. Chebyshev type inequalities involving singular values

In this section we deal with some singular value versions of the Chebyshev inequality

for positive n× n matrices. We need the following known result.

Lemma 5.1. [2, Corollary III.2.2] Let A,B be n× n Hermitian matrices. Then

λ↓j(A+B) ≥ λ↓n(A) + λ↓j(B) (1 ≤ j ≤ n).

Theorem 5.2. Let f, g : [0,+∞)→ [0,+∞) be synchronous functions. Then

sj(f(A)g(A)

)+ sj

(f(B)g(B)

)≥ sn

(f(A)

)sn(g(B)

)+

1

2

(sj(g(A)

)sj(f(B)

)+ sj

(g(B)

)sj(f(A)

))for all positive matrices A,B ∈Mn and all j = 1, 2, · · · , n.

Proof. For synchronous functions f, g we have

f(t)g(t) + f(s)g(s) ≥ f(t)g(s) + f(s)g(t) (s, t ≥ 0).

If we fix s ∈ [0,+∞), then

f(A)g(A) + f(s)g(s)I ≥ f(A)g(s) + f(s)g(A).

18 M.S. MOSLEHIAN, M. BAKHERAD

Hence

sj(f(A)g(A)

)+ f(s)g(s) = sj

(f(A)g(A) + f(s)g(s)

)≥ sj

(f(A)g(s) + f(s)g(A)

)≥ sn

(f(A)g(s)

)+ sj

(f(s)g(A)

)(by inequality (5.1) )

= sn(f(A)

)g(s) + f(s)sj

(g(A)

)(1 ≤ j ≤ n).

Using functional calculus for B we get

sj(f(A)g(A)

)+ f(B)g(B) ≥ sn

(f(A)

)g(B) + sj

(g(A)

)f(B) (1 ≤ j ≤ n).

Thus

sj(f(A)g(A)

)+ sj

(f(B)g(B)

)≥ sj

(sn(f(A)

)g(B) + sj

(g(A)

)f(B)

)≥ sn

(sn(f(A)g(B)

))+ sj

(sj(g(A)

)f(B)

)(by inequality (5.1) )

= sn(f(A)

)sn(g(B)

)+ sj

(g(A)

)sj(f(B)

)(1 ≤ j ≤ n).

(5.1)

In inequality (5.1), if we interchange the roles of A and B, then we get

sj(f(B)g(B)

)+ sj

(f(A)g(A)

)≥ sn

(f(B)

)sn(g(A)

)+ sj

(g(B)

)sj(f(A)

)(1 ≤ j ≤ n).

(5.2)

By (5.1) and (5.2)

sj(f(A)g(A)

)+ sj

(f(B)g(B)

)≥ sn

(f(A)

)sn(g(B)

)+

1

2

(sj(g(A)

)sj(f(B)

)+ sj

(g(B)

)sj(f(A)

))(1 ≤ j ≤ n).

In the following example we show that the constant 12

is the best possible one.

Example 5.3. For arbitrary synchronous functions f, g : [0,+∞) → [0,+∞), let us

putA = B = In×n. Then sj(f(A)g(B)

)= sj

(f(B)g(B)

)= f(1)g(1) and sj

(f(B)g(A)

)=

sj(g(B)f((A)

)= f(1)g(1), (1 ≤ j ≤ n). Thus

sj(f(A)g(A)

)+ sj

(f(B)g(B)

)= sn

(f(A)

)sn(g(B)

)+

1

2

(sj(g(A)

)sj(f(B)

)+ sj

(g(B)

)sj(f(A)

))for all j = 1, 2, · · · , n.

Using the same strategy as in the proof of Theorem 5.2 we get the next result.

CHEBYSHEV TYPE INEQUALITIES FOR HILBERT SPACE OPERATORS 19

Theorem 5.4. Let f, g : [0,+∞)→ [0,+∞) be synchronous functions. Then

f(sj(A)

)g(sj(A)

)+ sj

(f(B)g(B)

)≥ f

(sj(A)

)sn(g(B)

)+ sj

(f(B)

)g(sj(A)

)for all positive matrices A,B ∈Mn and for all j = 1, 2, · · · , n.

Example 5.5. Let A,B be positive n× n matrices and p, q > 0. Then

sj(Ap+q) + sj(B)psj(B)q ≥ sn(Bq)sj(A)p + sj(A)qsj(B

p) (1 ≤ j ≤ n).

If A be a positive definite n× n matrix, then

sj((logA)2

)+(

log sj(A))2 ≥ sn(logA) log sj(A) + log sj(A)sj(logA) (1 ≤ j ≤ n).

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1 Department of Pure Mathematics, Center of Excellence in Analysis on Alge-

braic Structures (CEAAS), Ferdowsi University of Mashhad, P. O. Box 1159, Mashhad

91775, Iran

E-mail address: [email protected], [email protected]

2 Department of Pure Mathematics, Ferdowsi University of Mashhad, P. O. Box

1159, Mashhad 91775, Iran.

E-mail address: [email protected]; [email protected]


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