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Career: Aeronautical Engineering
Cuatrimestre: 8A
Teacher: Dr. Pablo Alejandro Arizpe Carren
Student: Erick Alberto Trejo Ziga
Subject: Fundamentals of rotary engine.Homework: Real Simple Joule Brayton Cycle
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0
100
200
300
400
500
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
Wc
Wc
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
As can be seen, the compression work increases relative to the pressure ratio, this is due to having more pressure ratio
(compression), we are saying that the air entering at a constant ambient pressure passing through the compressor, compressed
more times in relation to the inlet pressure to produce a greater compression work.
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Real form, the compression work is increased in relation to the compression ratio but is higher than the ideal work because air to
pass right through the compressor, friction occurs, which increases the temperature at the output thereof causing the energy
produced by friction increases the compression work.
0
100
200
300
400
500
600
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
Wc'
Wc'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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As can be seen, the work turbine is affected by the temperature change of design, as it is the temperature at the turbine inlet, the
pressure ratio also increases and the work of turbine does likewise due that ideally the compression ratio is equal to the ratio
expansion, so having more expansion turbine work increases, because the combustion gases to exit with greater pressure increase
turbine work
0
200
400
600
800
1000
1200
0 5 10 15 20 25 30 35
Wt
Wt
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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.
As can be seen, the work of actual turbine is greater than the ideal job, this is because the friction, additional energy is produced,
there will be more heat which results in more work, the actual work increase for the same reasons that the ideal job, since increasing
the expansion ratio of the turbine moves with greater magnitude turbine producing more work.
0
200
400
600
800
1000
1200
0 5 10 15 20 25 30 35
Wt'
Wt'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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The heat supplied to each T3 increases with increasing temperature but the pressure ratio decreases the heat this is because the
expansion ratio is inversely proportional to T3.
0
200
400
600
800
1000
1200
1400
0 5 10 15 20 25 30 35
qs
qs
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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Real form, qs is higher than ideal due to the friction of mechanical parts and production of friction, creating more heat because the
energy that is sent to the combustion chamber is larger and increases the heat supplied.
0
200
400
600
800
1000
1200
1400
1600
1800
0 5 10 15 20 25 30 35
qs'
qs'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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As shown in the graph as the heat supplied increases as the design temperature grows, as this is said to be a higher inlet temperature
(the temperature of the turbine exhaust gases), having a higher temperature in the turbine the more heat will be rejected, decreases
with respect to the pressure ratio.
0
200
400
600
800
1000
1200
0 5 10 15 20 25 30 35
qr
qr
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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As you can observe the actual heat rejected is much higher than ideal, this because in the real rejected heat is taken into account fuel
and energy produced by friction, this means that in reality the turbine exit the heat rejection is greater, also as can be seen as the
pressure ratio (expansion) increases this decreases this is because the temperature of the turbine outlet is inversely proportional to
the expansion ratio so that exceed this the temperature 4 decreases.
0
200
400
600
800
1000
1200
1400
1600
0 5 10 15 20 25 30 35
qr'
qr'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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The useful work is increased depending on the temperature of the turbine inlet (T3) that due to the temperature increase that inject
more energy to the turbine to produce more work, to produce greater turbine work and constant compression work, work be much
more useful, as can be seen with increasing T3 ideally more useful work starts to become constant, but at lower temperatures reach
a peak and then begins to lower himself there because this passes the opt peaking useful work that can be produced with this
design temperature after their began to decrease.
0
100
200
300
400
500
600
0 5 10 15 20 25 30 35
Wutil
Wutil
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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Para el trabajo til real, esto disminuye porque en realidad no todo el trabajo producido puede ser explotado porque hay prdidas por
friccin, ya que en realidad se puede observar a pesar del aumento de la temperatura de diseo esta alcanza un mximo y luego
empieza a disminuir, lo mismo que sucede como con el ideal llega a su relacin de presin ptima que experiment el mximo
trabajo til y luego comenz a disminuir.
0
100
200
300
400
500
600
0 5 10 15 20 25 30 35
Wutil'
Wutil
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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As shown, the specific fuel consumption is maintained almost constant for each T3 but by increasing the pressure ratio begins to
decrease this due to having more compression and expansion respectively greater energy and labor in the compressor occurs and
the turbine, doing this is that as the energy increased fuel consumption is increasingly smaller to meet the required power.
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
0 5 10 15 20 25 30 35
SFC
SFC
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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In the specific case of actual fuel consumption is the same, but here depend on the increase in T3 and friction, as can be seen as
having a lower temperature and with increasing pressure ratio declining but this anger reached a point where consumption begins to
increase, and if we increase the temperature at the turbine inlet and increase the pressure ratio that will produce more work so less
fuel is needed to meet the required power.
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
0 5 10 15 20 25 30 35
SFC'
SFC'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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As can be seen, the f of fuel will be increased for each increase in T3 but decrease with increased pressure ratio, this is due to having higher
pressure ratio greater work in the turbine and the compressor occurs, the increase work due to this condition the fuel to meet growing power
will be lower but for maximum temperature increasing f will be greater.
0
0.005
0.01
0.015
0.02
0.025
0.03
0.035
0.04
0.045
0 5 10 15 20 25 30 35
f
f
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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0
50
100
150
200
250
300
0 10 20 30 40
a
a
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C0
50
100
150
200
250
300
350
0 10 20 30 40
a'
a'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
As can be seen, the mass flow is inversely proportional to the useful work, this means that a constant power to meet and have a
useful work increasing the mass flow will decrease, this encompasses that when you reach the maximum useful work also reaches
the minimum mass flow as the useful work begins to decrease the mass flow increase to meet a fixed power can be increased in area
and increase the mass flow which we create the need for a less useful work in a real way the mass flow is needed is greater as the
frictional losses have useful W decreases.
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0
1
2
3
4
5
6
0 10 20 30 40
f
f
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C0
1
2
3
4
5
6
0 10 20 30 40
f'
f'T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
As seen in the graphs, as the specific fuel consumption by increasing the pressure ratio as already mentioned turbine work therefore
increases the need for more fuel to meet the power requirement decreases, have less fuel mass flow thereof also decrease real way,
he knows there are friction losses which makes the actual work is less than ideal so really the fuel mass flow increase, unlike the
perfect flow actual fuel mass for smaller design temperature will be greater at lower temperatures because the turbine will p roduce
less work.
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0
0.1
0.2
0.3
0.4
0.5
0.6
0 10 20 30 40
t
t
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C 0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
0.45
0 10 20 30 40
t'
t'T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300CT=1400C
As shown in the graphs, the efficiency increases as the pressure ratio and ideally for each design temperature is nearly equal, this
increases efficiency and lower design temperature remains almost constant, but the actual efficiency shows that design temperature
low and increased the pressure ratio, this reached a maximum and then there will decrease, this is because in reality not all work
produced can be tapped, there lost with those produced by the friction causing the efficiency real turbine is less than ideal.
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0
500
1000
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
T2
T2
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
0
500
1000
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
T2'
T2'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
The T2 increases due to increased pressure ratio that is because air enters the compressor and to deflect this higher temperature
occurs, actually the temperature at the compressor outlet is higher because when air enters and pink party mechanical friction
occurs by increasing the temperature.
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0
2000
4000
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
P2=P3
P2=P3
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
As shown, the pressure 2 and 3 of the pressure are equal ideally even compression and expansion ratios are also, to increase the
pressure ratio of the pressure increase linear 3 in any real pressure relationships are not are equal pressure losses due to friction so
that the actual manner p3 is less than ideal p3.
0
1000
2000
3000
2 5 8 11 14 17 20 23 26 29
P3'
P3'
T=800C
T=900C
T=1000C
T=1100C
T=1200C
T=1300C
T=1400C
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CONCLUSIONS:
With the completion of work, it was observed that the ideal conditions vary too much from the real, this due to an effect called friction, the
friction present in the component produces heat which causes variations in parameters such as turbine and compression works by altering cycle,
that is why the actual temperatures are higher but that does not mean it's good because the energy is lost in heat which makes the real
efficiencies decrease and vary from ideal.