PHP with MYSQL
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<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "password") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_close($link);?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");
$result = @mysql_query("SELECT idno from donor") or die("Invalid query: " . mysql_error());
while ( $row = mysql_fetch_row($result)){ echo ("<p>" . $row[0] . "</p>");}?>
My database as assigned by Nevidia.
My table.
I am now looping through the table showing one row at a time starting the index at 0.
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", ”password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");
$result = @mysql_query("SELECT idno from donor") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){ echo ("<p>ID= ". $row["idno"] ." </p>");}?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");
$result = @mysql_query("SELECT idno, name from donor") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_array($result)){ echo ("<br> ID = ". $row["idno"] . "<br> NAME = " . $row["name"] . "<br>");}?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", ”password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");
$result = @mysql_query("SELECT * from donor") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_array($result)){ echo ("<br> ID = ". $row["idno"] . "<br> NAME = " . $row["name"] . "<br>"); echo("CITY = " . $row["city"] . "<br> STATE = " . $row["state"] . "<br>");}?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", ”password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$state="RI";$result = @mysql_query("SELECT * from donor where state = '$state'") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_array($result)){ echo ("<br> ID = ". $row["idno"] . "<br> NAME = " . $row["name"] . "<br>"); echo("CITY = " . $row["city"] . "<br> STATE = " . $row["state"] . "<br>");}?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", ”password", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$idno='11111';$result = @mysql_query("SELECT * from donor where idno = '$idno'") or die("Invalid query: " . mysql_error());$row = mysql_fetch_array($result); echo ("<br> ID = ". $row[0] . "<br> NAME = " . $row["name"] . "<br>"); echo("CITY = " . $row["city"] . "<br> STATE = " . $row["state"] . "<br>");
?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$sql = "INSERT INTO donor values ('33333', 'Al Richards', '111 South St', 'Braintree', 'MA', '02184','2002-10-10',300, 'John Smith')";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?> Note that I did the insert as one long
string that I had to wrap to show on the slide.
I then ran connect7.php to show that the record got added.
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$sql = "INSERT INTO donor values ('44444', 'Sarah Grove', '123 Elm St', 'Seekonk', 'MA', '02345','2001-10-12',300, 'John Smith')";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?>
Again I wrapped for the slide, the insert is one line in my code.
Indicates successful execution.
When I executed insert1a.php a second time this error message was returned.
See insert on previous slide
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$sql = "INSERT INTO donor values ('45654', 'John Doe', '123 Elm St', 'Swansea', 'MA', '02345', '2001-10-12',300, 'John Smith')";if (mysql_query($sql,$link)) { echo "record added"; }else { echo "must have been a duplicate"; }?>
Again note the wrap that is not in the code.
When I ran insert1b.php a second time I got my duplicate message.
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully "); mysql_select_db("pgrocer_biz_data");$getidno='45654';$sql = "DELETE FROM donor WHERE idno = '$getidno'";if (mysql_query($sql,$link)) { echo "record deleted"; }?>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$getidno = '33333';$sql = "UPDATE donor SET stadr = '111 North St' WHERE idno = '$getidno'";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?>
The update changes the street name from South to North.
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");
$result = @mysql_query("SELECT * from donor") or die("Invalid query: " . mysql_error());
while ($row = mysql_fetch_array($result)){ echo ("<br> ID = ". $row["idno"] . "<br> NAME = " . $row["name"] . "<br>"); echo ("STREET ADDRESS = " . $row["stadr"] . "<br>"); echo("CITY = " . $row["city"] . "<br> STATE = " . $row["state"] . "<br>");}?>
<html><head><title>Insert</title></head><body><form action="insert2.php" method="POST">IDNO:<input type="text" name="inidno"><br>NAME:<input type="text" name="inname"><br>STREET ADDRESS:<input type="text" name="instadr"><br>CITY:<input type="text" name="incity"><br>STATE:<input type="text" name="instate"><br>ZIP:<input type="text" name="inzip"><br>DATE FIRST CONTRIBUTED:<input type="text" name="indatefst"><br>YEAR GOAL:<input type="text" name="inyrgoal"><br>CONTACT:<input type="text" name="incontact"><br><input type="submit" value="Click"></form></body></html>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$idno=$_POST[inidno];$name=$_POST[inname];$stadr=$_POST[instadr];$city=$_POST[incity];$state=$_POST[instate];$zip=$_POST[inzip];$datefst=$_POST[indatefst];$yrgoal=$_POST[inyrgoal];$contact=$_POST[incontact];$sql = "INSERT INTO donor values ('$idno', '$name', '$stadr', '$city', '$state', '$zip', '$datefst', '$yrgoal', '$contact')";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?>
The code has the insert on one line. I wrapped to fit on the slide.
<html><head><title>Insert</title></head><body><form action="delete2.php" method="POST">Enter the identification number for the record you want to delete.<br><br>IDNO:<input type="text" name="inidno"><input type="submit" value="Click"></form></body></html>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$idno=$_POST[inidno];$sql = "DELETE FROM donor WHERE idno = '$idno'";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?>
<html><head><title>Insert</title></head><body><form action="update2.php" method="POST">Change the name for the following id.<br><br>IDNO:<input type="text" name="inidno"><br>NAME:<input type="text" name="inname"><br><input type="submit" value="Click"></form></body></html>
<?php $link = mysql_connect("mysql2.nevidia.com", "pgrocer.biz", "whatever", "pgrocer_biz_data") or die("Could not connect: " . mysql_error()); print ("Connected successfully"); mysql_select_db("pgrocer_biz_data");$idno=$_POST[inidno];$name=$_POST[inname];$sql = "UPDATE donor SET name = '$name' WHERE idno = '$idno'";$result= mysql_query($sql,$link) or die(mysql_error());echo $result;?>
