Unit - IIThe ARM processor
Beagle Bone :• Beagle Board• Beagle BoardxM• Beagle Bone White• Beagle Bone Black
• Based on ARM cortex A8• 512 DDR3 RAM• 4 GB on board Storage
Introduction to Beagle Boards :• Beagle boards are tiny computers with all the capabilities of
today’s desktop machine.• To teach open source hardware and software capabilities• Produced by Texas Instruments in association with Digi-
Key and Newark element14• Developed as a demonstration of OMAP (Open Multimedia
Application platform) System on Chip (Soc)• CPU: ARM Cortex A8• Supported OS: Linux, Minix, FreeBSD, Android, Symbian, RISC
OS
Beagleboard – Rev. C
Hardware - Beagleboard OMAP3530 (Soc) forms the core of the board. Uses Package on Package stacking of memory on top of OMAP Memory:
256MB NAND, 256MB DDR SDRAM Interfaces:
DVI-D (via HDMI connector), JTAG, RS232, USB2 OTG Stereo In, Stereo Out, S-Video, USB2 Host Expansion Header: I2C, I2S, SPI, MMC/SD
Can be USB bus powered or take DC power
Using the Beagleboard Booting:
NAND -> USB-> UART -> MMC (For Beagle Board) USB -> UART -> MMC -> NAND (For processor) Uses U-Boot (Universal Boot loader)
Provides a simple Command Line Interface to manipulate hardware prior to booting a kernel
MMC/SD is the only way to bring up a new board.
Beagleboard - Software Distributions you can use:
Angstrom Ubuntu Android (Google’s open source software stack for mobile devices) Number of other embedded Linux distros.
Developing for Beagleboard Openembedded (OE):
Provides an easy to use build environment Collection of metadata about software packages support for many hardware architectures runs on any Linux distribution Cross Compilation
Other options: Use the Android SDK Build your own toolchain Start from a ready made image
BeagleBone• Announced in the end of October 2011
• The BeagleBone is a barebone development board with a Sitara ARM Cortex-A8 processor
• 720 MHz, 256 MB of RAM
• Two 46-pin expansion connectors
• On-chip Ethernet
• A microSD slot and a USB host port
• A device port which includes low-level serial control and JTAG hardware debug connections, so no JTAG emulator is required.
BeagleBone Features :• Built-in networking• Remote access• File system• Use many different programming languages• Multitasking• Linux software• Open Source
BeagleBone Black
Component Locations
Connector and switch Locations
4 LEDs
Lets start with basic: LEDS• There are four user LED(s) on the Beaglebone. The user
LED(s) are • Accessible from user space on the file system at this location:
/sys/class/leds/• There is one directory per user LED, named as shown below:
• /sys/class/leds/beaglebone::usr0/ (GPIO1_21)• /sys/class/leds/beaglebone::usr1/ (GPIO2_22)• /sys/class/leds/beaglebone::usr2/ (GPIO2_23)• /sys/class/leds/beaglebone::usr3/ (GPIO2_24)
On-board LED:• Write the following commands in your terminal (First one is
for turning ON and latter for OFF):• USER0 : heartbeat indicator from the Linux kernel.• USER1 : SD card access• USER2 : activity indicator. Turns on when the kernel is not in
the idle loop.• USER3 : Onboard eMMC is access.
Comparison :
U-Boot :• Universal Boot loader for embedded systems• Locating and loading the kernel with the set arguments• Setting up the arguments• Initializing additional hardware• Makes booting from serial and USB port possible
Boot Modes :• eMMC Boot (MMC1)
• Uses onboard memory• Default boot mode• Fastest
• SD Boot (MMC0)• uSD card
• Serial Boot• Boots from serial ports
• USB Boot (USB0)• Boots from USB
Booting Options :• Without holding the boot button :
• eMMC Boot• uSD Boot• Serial Boot• USB Boot
• Holding the boot button :• uSD Boot• USB Boot• Serial Boot
BBB interfacing :• Initialization
• Export• Input
• Direction• Logic
• Changing the values• Output
• Direction
BBB interfacing with Stepper Motor
Connector Number
BBB PINNumber
PIN Description PIN connects to stepper motor connected FRC
Function
P9 1,2 GND GND(25pin) GND
P9 5 VCC(5V) VCC(26pin) VCC
P9 11 GPIO0[30] FRC-21pin Out
P9 12 GPIO1[28] FRC-22pin Out
P9 13 GPIO0[31] FRC-19pin Out
P9 14 GPIO1[18] FRC-20pin Out
Embedded System Processors• A number of choice available for embedded processors• Two categories are:
• Standalone Processors • Requires external chipset to form complete system
• Integrated Processors • SoC: System on Chip
Standalone Processors• Dedicated exclusively to the processor functions
• Needs external controllers to interfacing with surroundings. E.g. DRAM controller, keyboard controller and serial ports
• Highest Overall CPU performance.
Standalone Microprocessor Based System
Standalone Processors: Example• Many standalone processors in 32 bit and 64 bit exist and
widely used in embedded systems:• IBM 970FX :
• A high performing 64 bit capable stand alone processor.• Superscalar architecture: Core can fetch, decode and execute for
more than one instruction at a time (Deeply Pipelined)• Used also in IBM blade server platform
Standalone Processors: Example• Intel Pentium M
• One of the most popular x86 architecture for 32 and 64 bit.• Super scalar architecture like IBM 970 FX.• Used in many earlier laptops and commercial embedded systems
Intel Atom• Widely used in notebooks and embedded system applications.
Known for low power consumption
Integrated Processor :SoC
SoC• A microchip that has all the components to run the system.• Integrates all the components of computer in a single chip• Majority of embedded application uses Integrated processors
(SoC)• Beagleboard
• Processor TI OMAP3530 SoC - 720 MHz ARM Cortex-A8 core
ARM TIMELINE :• 1985: Acorn Computer Group manufactures the first commercial
RISC microprocessor. (ARM – I . . . V)• 1990: Acorn, Apple and VLSI based Technology group = Advanced
RISC Machines (A.R.M.). • 1991: ARM6, First embeddable RISC microprocessor. • 1993 : ARM7, the first multimedia microprocessor is introduced.• Users :
• Samsung• Atmel• Philips• Etc.
ARM :
Advanced RISC Machine :• Instructions are same size : 32 bit• Instructions are executed in 1 cycle• Load/Store access memory
• Advantage:• Number of transistors are less compared to similar CISC
architecture.• Less hardware results in less die size
• Low power consumption
Advanced Features • Thumb:
• A new 16 bit instruction set called thumb is made available.• This is less powerful instruction set but quite useful for
application that do not require full power of 32 bit instructions.• Advantage: High Code Density
• (Higher amount of code in per unit memory area)
• MMU and MPU: • Desktop system requires it.• It depends on application requirement in embedded system• ARM processor can be implemented with MMU and MPU or with
one of them or neither of them.
Advanced Features• Debug Interface:
• There is chip testing unit called JTAG (joint testing action group) interface.
• JTAG standard defines a set of interface for testing hardware and initial code.
• Jazalle DBX: (Direct Byte code Execution)• Some ARM processors have direct execution support for byte
code in hardware.• Useful in devices for execution games and java application that
otherwise require a heavy JVM.
Advanced Features• Vector Floating Point Unit
• Hardware support for floating point computation
• Cache:• The first ARM processor with Cache is ARM3. It had 1 KB chip of 4
KB.• ARM 7 had a cache of 8 KB.
Advanced Features• Fast Multiplier
• Even though ARM is a RISC processor, there are many features that do not conform to RISC philosophy
• ARM processors may have a fast multiplier hardware unit.
• Synthesizable: • Design Code (RTL) is available with License, using which
extensions and modification are possible in basic core
Advanced Features• Embedded ICE (In Circuit Emulator) Macrocell:
• The current hardware trend is to design system as macrocells.• The ARM core could be considered as macrocell and other units
may also be added as (e.g. peripheral units) macrocells.• Some processor has embedded ICE macrocell for testing.• Used for debugging and have registers to set watch points and
breakpoints .
Naming Conventions for ARM
• Example: ARM7TDMI
ARM CORTEX• Latest in ARM is cortex series• Based on architecture V7 version:
• THUMB-2 technology (Both 16 and 32 bit supported)• No need to switch between ARM and THUMB instruction set
• Cortex has well defined profile for different application areas:• A• R• M
Cortex Profiles• A profile:
• For High End applications in Embedded Systems with modern OS. (e.g. Android)
• ARMv7-A architecture• Used in Mobile phones and Video Systems
• R Profile:• For high end application on systems with Real time capabilities• ARMv7-R architecture• Used in safety critical systems
• M profile:• Designed for Core embedded microcontroller type systems• ARMv7-M architecture• Used in control applications
Advanced Features :• Data bus width :
• 32 bit data bus• 32 bit read/write in 1 cycle
• Computational capability:• RISC Approach provides good computations• RISC architecture with few CISC add-ons
• Low Power:• Power saving• Operates at low clock frequencies• 60MHz to 1 GHz
Advanced Features :• Multiple Register Instructions :
• Data processing with registers mostly• Processing instructions do not use addressing modes that uses
one operand in memory.• But, instructions for loading and storing data to registers.
• DSP Enhancement:• Additional DSP features
Pipelining :• Dividing instruction processing in sub-stages• 3 Stage pipeline: (ARM-7)
• Fetch – Decode – Execute• 5 Stage Pipeline: (ARM-9)
• Fetch – Decode – Execute – Buffer - Write
• (ARM-10) – 6 stage pipeline
• Drawback:• Problem with branch instructions• Due to sequence change some instructions are discarded• Loss of data, computation time• Higher penalty with more stages
Instruction Set Architecture• Programmers view of computer architecture• Consists of :
• Instruction Sets• Addressing Modes• Registers etc.
• Basic ISA of all ARM processor are more or less same
CPSR (Current Program Status Register)
Bit Nos. Notion Interpretation
0 to 4 Mode Specifies the current mode of operation
5 T State : ARM = 1 or THUMB = 0
6 F Disables (F=1) FIQ
7 I Disables (I=1) IRQ
8 to 23 Undefined
25 to 26 Undefined
24 J J=1 means in Jazalle state
27 Q Sticky Overflow flag
28 to 31 V C Z N Condition flags
CPSR
N: Negative (N=1 indicates negative results)Z: Zero ( Z=1 indicates result is 0) C: Carry V: Overflow
N Z C V u n u s e d mo d e
31 28 27 8 7 6 5 4 0
I F T
Exception Priorities :• Reset (Highest)• Data abort• FIQ• IRQ• Prefetch abort• SWI, undefined instruction (Lowest)
Data Type• 6 data types in all:
• Signed and unsigned• 32 bit/ 16 bit and 8 bit operations supported
• Processing tool offers the option of storing data in little endian and big endian formats
• Data Alignment:• For word (32-bit) should have least 2 bits of address as 0
• Eg: 0x1200• For unaligned data like 0X1201
• (32 – bit ) will access 2 memory cycles 1 @ 0x12001, 2 @ 0x1204
Assembly Language Rules :• Label• Opcode / Instruction field• Operand field• Comment
• Label ADD R1,R2,R3 ;Add instruction
Shift and Rotate• Two types of shifts are possible• Logical and Arithmetic• LSL (Logical Shift Left):
• For a 32 bit register, shift left (a specified number of times) results in shifting every bit left and vacant bits at right are filled with zeroes
• The last bit shifted out from the left is copied to the carry flag• Left shift by one bit position corresponds to multiplication by 2.• An LSL of 5 implies multiplication by 32
Shift and Rotate• LSR (Logical Shift Right)
• Similar to LSL but shifts bits in right
• Vacant bits at left filled by zeroes.
• The last bit shifted out is retained in carry flag
• Shifting right by 1 bit is equivalent to dividing the number by 2.
• Two right shift cause a division by 4
Shift and Rotate• ASR (Arithmetic Shift Right):
• Vacant bit in the left is filled with MSB of the original number.
• This type of shift has the function of doing ‘sign extension’ of data
• There is not instruction for Arithmetic Shift Left
Shift and Rotate• ROR (Rotate Right)
• Data is shifted right• The bit shifted out from right is inserted back through left.• The last bit rotated out is available in carry flag.• There is no Rotate Left instruction, because left rotate ‘n’ times can be
achieved by rotating right ‘32-n’ times.• For example rotating 4 times to the left is achieved by rotating 32-4 =
28 times to the right
Shift and Rotate• RRX (Rotate Right Extended):
• This corresponds to rotating right though the carry bit.
• Bits dropped off from the right side is moved to CF and the carry bit enters through the left of the data.
Format of Shift and Rotate Instruction
• The number of bit position by which shift or rotate operation need to be done is specified by a constant or another register.
• Example:LSL R2,#4 ; shift left logically the content
of R2 by 4 bit positionASR R5,#8 ; Shift right arithmetically the
content of R5 by 8 bit positionROR R1, R2 ;Rotate the content of R1 by the
number specified by R2
Problem• The content of some of the registers are given as:
R1=0xEF00DE12R2=0x0456123FR5=4R6=28
Find the result in destination register for following:• LSL R1, #8• ASR R1, R5• ROR R2, R6• LSR R2, #5
SolutionR1=0xEF00DE12R2=0x0456123FR5=4R6=28
Find the result in destination register for following:LSL R1, #8 (Ans: 0x00DE1200)ASR R1, R5 (Ans: 0xFEF00DE1)ROR R2, R6 (Ans: 0x456123F0)LSR R2, #5 (Ans: 0x0022B091)
Combining the operation of Move and Shift• MOV R1, R2, LSL #2• MOV R1, R2, LSR R3• In both ,instruction R1 is the destination register.• In first instruction, the source operand i.e. content of R2 is
logically shifted left twice and then moved to R1.• In second instruction, amount of shifting is specified by R3.
Problem
R5= 0x72340200 and R2=4
FindMOV R3, R5, LSL #3MOV R6, R5, ASR R2
Problem
R5= 0x72340200 and R2=4
FindMOV R3, R5, LSL #3 (R3=0x91A01000)MOV R6, R5, ASR R2 (R6=0x07234020)
Conditional Execution• An important and distinguished feature of ARM• Instruction is executed only if specified condition is true.• In general, all data processing instruction are expected to
affect conditional flags.• But in ARM, we must suffix the instruction with ‘S’ for this to
happen. • ‘S’ suffix in data processing instruction causes the flags in
CPSR to be updated.
Example• MOV R3, R5, LSL #3
• No affect on carry flat and N flag in CPSR
• MOVS R3,R5, LSL #3• The MOV instruction is made conditional by suffixing it with S.• C and N flags are now set.
• This flag setting can be used to make an instruction following it to be conditional.
Recap: Carry Flag
• The carry (C) flag is set when an operation results in a carry, or when a subtraction
results in no borrow.
• In ARM, C is set in one of the following ways:
• For an addition, C is set to 1 if the addition produced a carry (that is, an unsigned
overflow), and to 0 otherwise.
• For a subtraction, including the comparison instruction CMP, C is set to 0 if the
subtraction produced a borrow (that is, an unsigned underflow), and to 1
otherwise.
• For non-additions/subtractions that incorporate a shift operation, C is set to the
last bit shifted out of the value by the shifter.
• For other non-additions/subtractions, C is normally left unchanged.
Detailed Format :
Detailed Format :
Question :• What will be the result :
• ADD R1, R2, R2, LSL #3• RSB R3, R3, R3, LSL #3• RSB R3, R2, R2, LSL #4• SUB R0, R0, R0, LSL #2• RSB R2, R1, #0
Solution :• What will be the result :
• ADD R1, R2, R2, LSL #3 R1 = R2 + 8 R2• RSB R3, R3, R3, LSL #3 R3 = 8R3 – R3• RSB R3, R2, R2, LSL #4 R3 = 16R2 – R2• SUB R0, R0, R0, LSL #2 R0 = R0 – 4R0• RSB R2, R1, #0 R2 = 0 – R1
Q. Write a small assembly program for ARM, required that 2 numbers stored in R1 and R2 registers, the bigger num is to be placed in R10, if 2 num are equal Put it in R9.
Q. Write a small assembly program for ARM, required that 2 numbers stored in R1 and R2 registers, the bigger num is to be placed in R10, if 2 num are equal Put it in R9.
SUBS R3, R1, R2 ;R3 = R1 – R2MOVEQ R9, R1 ;IF R1=R2 / Z=1 . . . R1 -> R9 MOVHI R10, R1 ;IF R1 > R2 / C=1 . . . R1 -> R10
;MOV R10, R2
;MOVLS R10,R2 ;if R1<=R2 , C=0|Z=1 ,move R2 to R10
Flag setting after compare Instruction
If C Z
R3>R4 1 0
R3<R4 0 0
R3=R4 1 1
TST Instruction• TST is similar to compare, but it does ANDing and then sets
conditional flags.• If the result of ANDing is zero, then zero flag is set.• It can be used to verify at least one of the bits of a data word
is set or not.• Write instruction to verify the LSB of a word in register R1 is
set or not.
• TST R1, #01
TEQ Instruction• TEQ does exclusive ORing which tests for equality.
• If both operands are equal then only zero flag is set.
• TEQ R1,#45
Data Processing Instructions :
Multiplication :
Example :
• MUL R1,R2,R3
• MULS R1,R2,R3
• MULSEQ R1,R2,R3
• MULEQ R1,R2,R3
• UMULL R1, R2, R3, R4
Branch Instructions :• B Branch• BL Branch and Link• BX Branch and Exchange• BLX Branch and Exchange with Link
• Eg :• <Label> B New• STOP B STOP• <Label> BNE New• <Label> BHI New
Assembly Programming in ARM• Two kind of statements :
• Executable statements• Directives (related to assembler)
• AREA• ENTRY• RN• END• Defining data
Directives :• ENTRY
• Entry point of first executable instruction
• END
• AREA• AREA <NAME_OF_REGEION> , CODE/DATA,
READONLY/READWRITE
• Eg. AREA SORT,CODE,READONLY
Directives :• Defining Data
• NUMS DCB 9, 10, 15• NUM1 DCW 0x6787, 0x4565• NUM2 DCD 0x00000123, 0x67890900
• RN• Giving variable names to registers• X RN 1• Y RN 10
• EQU• Equate• FACT EQU 35• ASD EQU 0x40004000
Question :• Write a program to find 3X + 4Y + 9Z ,
• WHERE X = 2• Y = 3• Z = 4
Program to calculate factorial of 5 numbers• Write down an ARM assembly program to calculate factorial of
5.
• Instructions Involved:• MUL • SUBS• BNE
Solution
AREA FACTO, CODE ;Define the code area
ENTRY ;entry pointMOV R1, #5 ;R1=5MOV R2,#1 ;R2=1
REPT MUL R2, R2, R1 ;R2=R2XR1SUBS R1, R1, #1 ;R1=R1-1BNE REPT ;Branch to REPT if
Z!=0B B STOP ;last line
END ;End
Subroutine/Procedures• Another kind of branch used in Subroutine calls – BL (Branch
and Link)
• When a BL encountered (control transfer to new sequence of instruction OR the new procedure) ARM saves current PC value in Link register.
• PC then starts with new instruction set (Branch Target).
• At the end of procedure , LR is copied to PC
Finding 3X2 + 5Y2 , where X=8 and Y=5
AREA PROCED, CODEENTRYMOV R2, #8BL SQUAREADD R1,R3,R3 , LSL #1MOV R2, #5BL SQUAREADD R0,R3,R3,LSL #2ADD R4, R1, R0
STOP B STOPSQAURE MUL R3, R2, R2
MOV PC,LREND
Example• The constant value being added to Rn is immed_8 rotated right by
2*rotate_imm.
Constants :• Only decimal values within range 0 – 16320 can be created
using this schema.• Instructions MOV, MVN can also be used with ROR
Literal Pools• Literal Pool is a lookup table used to hold literals during assembly
and execution. • Literals : Written exactly as it is meant to be interpreted. Example:
x=125 ; x is variable, 125 is literal• Take an example of immediate operand
• MOV R1, #0x33333333• Assembler will give error that such constants cannot be generated.• To avoid the situation we can write:• LDR R1, = 0x33333333• (This is a pseudo instruction for assembler)
Literal Pools
LDR R1, =0x33333333• The pseudo instruction forces the assembler to check for one
of the following possibilities
1. Can the constant be constructed with MOV or MVN combined with rotation?
2. Assembler places the value in literal pool and generated and LDR with program relative address
• Memory Space after END• LTORG statement
Example• LDR R3,[R2, LSL #2]
• The effective address is the content of R2 left shifted by 2 (multiplied by 4)
• STR R9, [R1,R2, ROR #2]• The effective address is specified by R1 and R2 and a right
rotation• LDR R4,[R3,R2]
• The effective address here is sum of R3 and R2• STR R5,[R4, R3, ASL #4]
• The effective address is the sum of content of R4 and the arithmetically left shifted (by 4) content of R3
Bytes, Half Words and Words• ARM has instruction to transfer specifically a word (32 bits),
half word (16 bits) or a byte 8 bits) between memory and registers.
Load Instruction Description Store Instruction Description
LDR Load Word STR Store Word
LDRH Load Half Word STRH Store Half Word
LDRSH Load Signed Half Word
LDRB Load Byte STRB Store Byte
LDR Load Signed Byte
Problem
• Memory areas are referenced by two registers • R1=0x00001200, R2=0x40001100
1. LDR R3,[R1]2. LDRB R3,[R1]3. LDRH R3, [R1]4. STRB R3,[R2], provided that R3= 0x 00002356
Address Byte Stored
0X 00001200 56
0X 00001201 23
0X 00001202 0D
0X 00001203 AE
Solution:• LDR R3,[R1]
• R3 = 0xAE0D2356• LDRB R3,[R1]
• R3 = 0x00000056• LDRH R3, [R1]
• R3 = 0x00002356• STR R3,[R2], provided that R3= 0x AE0D2356
Address Byte Stored
0X 40001100 56
0X 40001101 23
0X 40001102 0D
0X 40001103 AE
STRHSTRB
Loading Signed Numbers :• R7 = 0xCDEF8204
• LDR R1, [R7] R1 = 0xCDEF8204• LDRSH R1, [R7] R1 = 0xFFFF8204• LDRSB R1, [R7] R1 = 0x00000004
Indexed Addressing Modes• Pre Indexed Addressing Modes
• LDR R0, [R7,#4]• R7 is the base register and effective address is R7+4 . The data at
effective address is copied to R0.• Add ! For write back option• LDR R0, [R7,#4]! R7 = R7 + 4;
• Post Indexed Addressing Mode• LDR R0, [R4],#4• The data pointed by R4 is first copied to R0. Then the content of
R4 is changed to R4+4
Multiple Load and Store (LDM and STM)
• Multiple register load means that multiple memory locations are to be accessed and loaded into multiple registers.
• There is a base register acting as pointer to the first memory location to be accessed.
• The register then incremented or decremented to point the next memory location
• LDM/STM{condition} address-mode Rn {!} , reg-list
LDM and STM• Suffixes used with LDM and STM• IA : Increment After• IB : Increment Before• DA : Decrement After• DF : Decrement BeforeLDMDA R0,{R4-R9}32 bit word pointed by R0 is copied to R432 bit word pointed by R0-4 is copied to R532 bit word pointed by R0-8 is copied to R6and so on ........ till R9.
• LDMIA R10,{R9, R1-R3}32 bit word pointed by R10 is copied to R132 bit word pointed by R10+4 is copied to R232 bit word pointed by R10+8 is copied to R332 bit word pointed by R10+12 is copied to R9
The STM instruction• Same format as LDM• STMIA R1, {R2-R4}
• Equivalent to the following instruction• SRT R2, [R1]• STR R3, [R1,#4]• STR R4, [R1,#8]
ARM9: Major Improvements over ARM7
• Decreased heat production and lower overheating risk.• Shifting from a three-stage pipeline to a five-stage one lets the
clock speed be approximately doubled, on the same silicon fabrication process.
• Cycle count improvements. Many unmodified ARM7 binaries were measured as taking about 30% fewer cycles to execute on ARM9 cores.
• Some ARM9 cores incorporate "Enhanced DSP" instructions, such as a multiply-accumulate, to support more efficient implementations of digital signal processing algorithms.
ARM 9• Implement Harvard Architecture: The Harvard architecture is
a computer architecture with physically separate storage and signal pathways for instructions and data.
ARM9: LPC 29XX ARM MCU• The LPC29xx consists of:
• An ARM968E-S processor with real-time emulation support• An AMBA multi-layer Advanced High-performance Bus (AHB) for
interfacing to the on-chip memory controllers• Two DTL buses for interfacing to the interrupt controller• Three or four ARM Peripheral Buses (APB) for connection to on-chip
peripherals
ARM9 : Advanced Microprocessor Bus Architecture • The ARM’s AMBA protocols are an open standard, on-chip
interconnect specification.
• It specifies the connection and management of functional blocks in a System-on-Chip (SoC).
• It facilitates right-first-time development of multi-processor designs with large numbers of controllers and peripherals.
ARM9 : AHB and APB• AHB stands for Advanced High-performance Bus • APB sands for Advanced (sometimes ARM) Peripheral Bus.• Both are part of the Advanced Microprocessor Bus
Architecture (AMBA).• Dedicated AHB to APB bridges are used to interconnect.
ARM Cortex M3• Cortex-M3 Processor
• The ARM Cortex-M3 processor is the industry-leading 32-bit processor for highly deterministic real-time applications
• Specifically developed to enable partners to develop high-performance low-cost platforms for: • Microcontrollers• automotive body systems• Industrial control systems • wireless networking and sensors
• LPC17XX