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ReviewProblemsfortheFinalimathesis.com/media/calculus1-finalreview.pdf · x→1 2−2ex−1 sin(x−1). (b) lim x→3 x3 − 2x2 −2x−3 2x3 −6x2 +x−3. (c) lim x→0+ √ xlnx.
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