Post on 18-Dec-2015
transcript
D =
MV
First, enter the givens into the density table.
48,000 tons
1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL?48,000 tons 0.000600 pL?
0.000600 pL
D =
MV
Next, enter the units from the mass and volume into the left side of the density table.
1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL?
48,000 tons = ? pL = ? tons
0.000600 pL
No conversion is necessary.
D
Use the formula triangle to determine the correct formula.
1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL?
V
M ÷
MV
xD =
D =
MV
Substitute the values into the equation.
1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL?
48,000 tons = ? pL = ? tons
0.000600 pL
D = M/V
D = (48,000 tons) / (0.000600 pL)
D =
MV
Divide and round to the LEAST number of significant digits.
1. Find the density of a substance whose mass is 48,000 tons and volume is 0.000600 pL?
48,000 tons = ? pL = ? tons
0.000600 pL
D = M/V
D = (48,000 tons) / (0.000600 pL)
D = 8.0 x 107 tons/pL
D =
MV
First, enter the givens into the density table.
49.7 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?49.7 lbs/Tm3 204,900 ng ?
204,900 ng
D =
MV
Next, enter the units from the density into the right side of the density table.
49.7 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
204,900 ng = ? Tm3
= ? lbs
D =
MV
If a conversion is necessary, complete it now.
0.006921 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
204,900 ng = ? Tm3
= ? lbs
204,900 ng = ?? lbs
Start with what you are looking for!!
lbs
Since lbs is an English unit and the given, ng, is a metric unit, Ms. Mullins must provide an English
to metric conversion. Always look back at the instructions to find the conversions. Use:
1 lb = 453.59 g
g
1
453.59
204,900 ng = ?? lbs
Since g is further left (so it is larger) than ng, g gets the one and ng gets the ten.
T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p
1 2 3 864 975
1 lb
453.59 g
g
ng
1
10 9
204,900 ng = ?? lbs
Bring the denominator unit up to the next numerator.
1 lb
453.59 g
g
ng
1
109
ng
When you have reached the given unit, ng, then insert the given numerical value.
204,900
D =
MV
Enter the answer from the dimensional analysis into the density table.
49.7 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
204,900 ng = ? Tm3
= 4.517 x 107 lbs
D
Use the formula triangle to determine the correct formula.
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
V
M ÷
MD
xV =
D =
MV
Substitute the values into the equation.
49.7 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
204,900 ngTm3
V = M/DV = (4.517 x 107 lbs) / (49.7 lbs/Tm3)
= 4.517 x 107 lbs
D =
MV
Divide and round to the LEAST number of significant digits.
49.7 lbs1 Tm3
2. Find the volume of a substance whose density is 49.7 lbs/Tm3 and mass is 204,900 ng?
204,900 ngTm3
V = M/DV = (4.517 x 107 lbs) / (49.7 lbs/Tm3)
= 4.517 x 107 lbs
V = 2.24 x 105 Tm3
D =
MV
First, enter the givens into the density table.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/mm3 and volume is 7.0835 x 107 mi3?0.006921 lbs/Tm3 7.0835 x 107 mi3 ?
7.0835 x 107 mi3
D =
MV
Next, enter the units from the density into the right side of the density table.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
7.0835 x 107 mi3 = ? Tm3
= ? lbs
D =
MV
If a conversion is necessary, complete it now.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
7.0835 x 107 mi3 = ? Tm3
= ? lbs
7.0835 x 107 mi3 = ?? Tm3
Start with what you are looking for!!
Tm3
Since Tm3 is a metric unit and the given, mi3, is an English unit, Ms. Mullins must provide an
English to metric conversion. Always look back at the instructions to find the conversions. Use:
1 m = 1.0936 yd
7.0835 x 107 mi3 = ?? Tm3
Tm3
However, the conversion is not a cubic conversion so.... 1 m = 1.0936 yd
(1 m)3 = (1.0936 yd)3
1 m3 = 1.3079 yd3
7.0835 x 107 mi3 = ?? Tm3
Since Tm3 is further left (so it is larger) than m3, Tm3 gets the one and m3 gets the ten.
Tm3
m3
T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p
1
10
7.0835 x 107 mi3 = ?? Tm3
Either count by threes
Tm3
m3
T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _
n _ _ p
1
10
3 6 9 3630241812 33272115
36
7.0835 x 107 mi3 = ?? Tm3
Or count between units and multiply by three.
Tm3
m3
T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _
n _ _ p
1
10
1 2 3 1210864 11975
36
12 x 3 = 36
7.0835 x 107 mi3 = ?? Tm3
Now use the English to metric cubic conversion.
1 Tm3
1 m = 1.0936 yd(1 m)3 = (1.0936 yd)3
1 m3 = 1.3079 yd3
1036 m3
m31
1.3079 yd3
7.0835 x 107 mi3 = ?? Tm3
Bring the denominator unit up to the next numerator.
1 Tm3
1036 m3
m31
1.3079 yd3
yd3
7.0835 x 107 mi3 = ?? Tm3
Remember that you are working towards the given which is mi3.
1 Tm3
1036 m3
m31
1.3079 yd3
yd3
There isn’t a conversion between yards and miles, but there is between feet and miles, so first develop a
conversion between yd3 and ft3.1 yd = 3 ft
(1 yd)3 = (3 ft)3
1 yd3 = 27 ft3
ft327
1
7.0835 x 107 mi3 = ?? Tm3
Bring the denominator unit up to the next numerator.
1 Tm3
1036 m3
m31
1.3079 yd3
1 yd3
27 ft3
ft3
7.0835 x 107 mi3 = ?? Tm3
Remember that you are working towards the given which is mi3.
1 Tm3
1036 m3
m31
1.3079 yd3
yd3
There is a conversion between feet and miles, so first develop a conversion between ft3 and mi3.
5280 ft = 1 mi(5280 ft)3 = (1 mi)3
1.47 x 1011 ft3 = 1 mi3
ft3
27
1
ft3 mi3
1.47 x 1011
1
7.0835 x 107 mi3 = ?? Tm3
Bring the denominator unit up to the next numerator.
1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3
1036 m3 1.3079 yd3 27 ft3 1 mi3
mi3
7.0835 x 107 mi3 = ?? Tm3
1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3
1036 m3 1.3079 yd3 27 ft3 1 mi3
mi37.0835 x 107
When you have reached the given unit, mi3, then insert the given numerical value.
7.0835 x 107 mi3 = ?? Tm3
SOLVE!!
1 Tm3 1 m3 1 yd3 1.47 x 1011 ft3
1036 m3 1.3079 yd3 27 ft3 1 mi3
mi37.0835 x 107
= 2.9487 x 1019 Tm3
D =
MV
Enter the answer from the dimensional analysis into the density table.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
7.0835 x 107 mi3 = 2.9487 x 1019
= ? lbsTm3
D
Use the formula triangle to determine the correct formula.
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
V
M ÷
M = DV x
D =
MV
Substitute the values into the equation.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
7.0835 x 107 mi3 = 2.9487 x 1019
= ? lbsTm3
M = DV M = (0.006921 lbs/Tm3) (2.9487 x 1019 Tm3)
D =
MV
Multiply and round to the LEAST number of significant digits.
0.006921 lbs1 Tm3
3. Find the mass of a substance whose density is 0.006921 lbs/Tm3 and volume is 7.0835 x 107 mi3?
7.0835 x 107 mi3 = 2.9487 x 1019
= ? lbsTm3
M = DV M = (0.006921 lbs/Tm3) (2.9487 x 1019 Tm3)
M = (2.041 x 1021 lbs)
Practice Problems:1. Find the mass of a substance whose density is 3.544 x 106 dg/yd3 and volume is 94,000 Mm3?2. Find the density of a substance whose mass is 1.87 x 106 cg and volume is 234,567 dam3?3. Find the volume of a substance whose density is 0.00807400 Gg/hm3 and mass is 204,900 tons?4. Find the mass of a substance whose density is 0.0007770 lbs/nL and volume is 4.7222 x 104 yd3?5. Find the density of a substance whose mass is 4.8 x 1028 kg and volume is 640,800 TL?6. Find the volume of a substance whose density is 3.04 x 1023 g/m3 and mass is 0.2030405 oz?