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Module 4Module 4
Operational AmplifierOperational Amplifier
ByBy
H V Balachandra AcharH V Balachandra Achar
ContentsContents IntroductionIntroduction OPAMP SymbolOPAMP Symbol Internal block diagramInternal block diagram Open-loop configurationOpen-loop configuration Common mode rejection ratioCommon mode rejection ratio OPAMP equivalent circuitOPAMP equivalent circuit OPAMP characteristicsOPAMP characteristics Closed-loop configurationClosed-loop configuration
ContentsContents Inverting AmplifierInverting Amplifier Non-inverting AmplifierNon-inverting Amplifier Summing Amplifier Difference AmplifierSumming Amplifier Difference Amplifier DifferentiatorDifferentiator IntegratorIntegrator TutorialsTutorials
Reference bookReference bookOPAMPS and Linear Integrated OPAMPS and Linear Integrated
CircuitsCircuitsby Ramakanth Gayakwadby Ramakanth Gayakwad
IntroductionIntroduction Operational Amplifier (OPAMP) is a very Operational Amplifier (OPAMP) is a very
high gain amplifier fabricated on high gain amplifier fabricated on Integrated Circuit (IC)Integrated Circuit (IC)
Finds application in Finds application in Audio amplifierAudio amplifierSignal generatorSignal generatorSignal filtersSignal filtersBiomedical InstrumentationBiomedical Instrumentation
And numerous other applicationsAnd numerous other applications
IntroductionIntroduction Advantages of OPAMP over transistor Advantages of OPAMP over transistor
amplifieramplifierLess power consumptionLess power consumptionCosts lessCosts lessMore compactMore compactMore reliableMore reliableHigher gain can be obtainedHigher gain can be obtainedEasy designEasy design
OPAMP terminalsOPAMP terminals
+VC
C
+
–
Non inverting input
Inverting inputOutput
–VEE
OPAMP terminalsOPAMP terminals
OPAMP terminalsOPAMP terminals If input is applied to non inverting input If input is applied to non inverting input
terminal, then output will be in-phase with terminal, then output will be in-phase with inputinput
If input is applied to inverting input If input is applied to inverting input terminal, then output will be 180 degrees terminal, then output will be 180 degrees out of phase with inputout of phase with input
If inputs are applied to both terminals, If inputs are applied to both terminals, then output will be proportional to then output will be proportional to difference between the two inputsdifference between the two inputs
OPAMP terminalsOPAMP terminals Two DC power supplies (dual) are required Two DC power supplies (dual) are required Magnitudes of both may be sameMagnitudes of both may be same The other terminal of both power supplies The other terminal of both power supplies
are connected to common groundare connected to common ground All input and output voltages are All input and output voltages are
measured with reference to the common measured with reference to the common groundground
OPAMP terminalsOPAMP terminals
Integrated Circuit
Internal Block DiagramInternal Block Diagram
Four stages can be identified – Four stages can be identified – Input stage or differential amplifier stage Input stage or differential amplifier stage
can amplify difference between two input can amplify difference between two input signals; Input resistance is very high; signals; Input resistance is very high; Draws zero current from the input sourcesDraws zero current from the input sources
IntermediateStage
LevelShifterStage
OutputStage
Differential Amplifier
Stage
Internal Block DiagramInternal Block Diagram Intermediate stage (or stages) use direct Intermediate stage (or stages) use direct
coupling; provide very high gaincoupling; provide very high gain Level shifter stage shifts the dc level of Level shifter stage shifts the dc level of
output voltage to zero (can be adjusted output voltage to zero (can be adjusted manually using two additional terminals)manually using two additional terminals)
Output stage is a power amplifier stage; Output stage is a power amplifier stage; has very small output resistance; so has very small output resistance; so output voltage is the same, no matter output voltage is the same, no matter what is the value of load resistance what is the value of load resistance connected to the output terminalconnected to the output terminal
Open-loop configurationOpen-loop configuration
If v1 = 0, then vo = –AOLv2 Inverting amplifierIf v2 = 0, then vo = AOLv1 Non inverting amp
Open-loop configurationOpen-loop configuration AAOLOL is the open-loop voltage gain of OPAMP is the open-loop voltage gain of OPAMP
Its value is very highIts value is very highTypical value is 0.5 millionTypical value is 0.5 million
So, even if input is in micro volts, output So, even if input is in micro volts, output will be in voltswill be in volts
But output voltage cannot cross the value But output voltage cannot cross the value of power supply of power supply VVCCCC
So, if input is in milli volts, output reaches So, if input is in milli volts, output reaches saturation value saturation value VVsatsat = = VVCCCC (or (or VVEEEE))
Open-loop configurationOpen-loop configuration If vIf v11 = v = v22, then ideally output should be , then ideally output should be
zerozero But in practical Op-Amp, output is But in practical Op-Amp, output is
Where, Where, AACMCM is the common-mode gain of is the common-mode gain of Op-AmpOp-Amp
So, final gain equation is:So, final gain equation is:
2
vvAv 21cmo
2
vvAvvAv 21cm21do
icmcmiddo vAvAv
Open-loop configurationOpen-loop configuration Common-mode rejection ratioCommon-mode rejection ratio
It is a measure of the ability of Op-Amp It is a measure of the ability of Op-Amp to reject the signals common to both to reject the signals common to both input terminals (noise)input terminals (noise)
Defined asDefined as
cm
d
AACMRR
cm
d10dB A
Alog 20CMRR
ProblemsProblems An OPAMP has differential voltage gain of 100,000 An OPAMP has differential voltage gain of 100,000
and CMRR of 60 dB. If non inverting input voltage and CMRR of 60 dB. If non inverting input voltage is 150 is 150 μμV and inverting input voltage is 140 V and inverting input voltage is 140 μμV, V, calculate the output voltage of OPAMPcalculate the output voltage of OPAMP Ans: 1.01 VAns: 1.01 V
For an OPAMP, when v1 is 0.5 mV and v2 is –0.5 For an OPAMP, when v1 is 0.5 mV and v2 is –0.5 mV, output voltage is 8 V. For the same OPAMP, mV, output voltage is 8 V. For the same OPAMP, when v1 = v2 = 1 mV, output voltage is 12 mV. when v1 = v2 = 1 mV, output voltage is 12 mV. Calculate the CMRR of the OPAMPCalculate the CMRR of the OPAMP Ans: 56.48 dBAns: 56.48 dB
OPAMP equivalent circuitOPAMP equivalent circuit
+–
vovi2vi1
Ri
AOLvidRo
Practical OPAMP
OPAMP equivalent circuitOPAMP equivalent circuitIdeal OPAMP
+–
vovi2vi1
AOLvid
OPAMP CharacteristicsOPAMP Characteristics Ideal OPAMPIdeal OPAMP
Infinite differential mode gainInfinite differential mode gain Zero common mode gainZero common mode gain Infinite CMRRInfinite CMRR Infinite input resistanceInfinite input resistance Zero output resistanceZero output resistance Infinite bandwidthInfinite bandwidth Infinite slew rate Infinite slew rate Zero input offset voltageZero input offset voltage Zero input offset currentZero input offset current Zero output offset voltageZero output offset voltage
OPAMP CharacteristicsOPAMP Characteristics Differential mode gain Differential mode gain AAdd
It is the factor by which the difference between It is the factor by which the difference between the two input signals is amplified by the OPAMPthe two input signals is amplified by the OPAMP
Common mode gain Common mode gain AAcmcm It is the factor by which the common mode input It is the factor by which the common mode input
voltage is amplified by the OPAMPvoltage is amplified by the OPAMP
Common mode rejection ratio Common mode rejection ratio CMRRCMRR Is the ratio of Is the ratio of AAdd to to AAcmcm expressed in decibels expressed in decibels
OPAMP CharacteristicsOPAMP Characteristics Input resistance Input resistance RRii
It is the equivalent resistance measured It is the equivalent resistance measured between the two input terminals of OPAMPbetween the two input terminals of OPAMP
Output resistance Output resistance RRoo It is equivalent resistance measured between It is equivalent resistance measured between
output terminal and groundoutput terminal and ground
BandwidthBandwidth It is the range of frequency over which the gain It is the range of frequency over which the gain
of OPAMP is almost constantof OPAMP is almost constant
OPAMP CharacteristicsOPAMP Characteristics Output offset voltage Output offset voltage VVoooo
It is the output voltage when both input It is the output voltage when both input voltages are zerovoltages are zero
Denoted as Denoted as VVoooo
Input offset voltage Input offset voltage VVioio It is the differential input voltage that must be It is the differential input voltage that must be
applied at the input terminals in order to make applied at the input terminals in order to make output voltage equal to zerooutput voltage equal to zero
VVioio = | = |vv1 1 – v– v22| for | for vvoo = 0 = 0
OPAMP CharacteristicsOPAMP Characteristics Input offset current Input offset current IIioio
It is the difference between the currents in the It is the difference between the currents in the input terminals when both input voltages are input terminals when both input voltages are zerozero
IIioio = | I = | I11 – I – I22 | when | when vv11 = v = v2 2 = 0= 0
Input bias current Input bias current IIibib It is the average of the currents in the input It is the average of the currents in the input
terminals when both input voltages are zeroterminals when both input voltages are zero IIibib = (I = (I11 + I + I22) / 2) / 2 when when vv11 = v = v22 = 0 = 0
OPAMP CharacteristicsOPAMP Characteristics Slew rate Slew rate SRSR
It is the maximum rate of change of output It is the maximum rate of change of output voltage with respect to timevoltage with respect to time
Slew rate has to be very high if OPAMP has to Slew rate has to be very high if OPAMP has to operate efficiently at high frequenciesoperate efficiently at high frequencies
Supply voltage rejection ratio Supply voltage rejection ratio SVRRSVRR It is the maximum rate at which input offset It is the maximum rate at which input offset
voltage of OPAMP changes with change in voltage of OPAMP changes with change in supply voltagesupply voltage
OPAMP CharacteristicsOPAMP Characteristics Practical characteristics of 741C OPAMPPractical characteristics of 741C OPAMP
Differential mode gain is 200,000Differential mode gain is 200,000 CMRR is 90 dBCMRR is 90 dB Input resistance is 2 MInput resistance is 2 MΩΩ Output resistance is 75 Output resistance is 75 ΩΩ Unity-gain Bandwidth is 1 MHzUnity-gain Bandwidth is 1 MHz Slew rate is 0.5 V / Slew rate is 0.5 V / μμss Output offset voltage is 1 mVOutput offset voltage is 1 mV Input offset current is 20 nAInput offset current is 20 nA Input bias current is 80 nAInput bias current is 80 nA
Closed-loop configurationsClosed-loop configurations Open-loop voltage gain of OPAMP is very Open-loop voltage gain of OPAMP is very
high; such high gain is not required in high; such high gain is not required in most applicationsmost applications
In order to reduce gain, a part of output In order to reduce gain, a part of output signal is fed back to the inverting input signal is fed back to the inverting input terminal (called negative feedback)terminal (called negative feedback)
Many other OPAMP characteristics are Many other OPAMP characteristics are improvised with thisimprovised with this
Inverting AmplifierInverting AmplifierRF
Inverting AmplifierInverting Amplifier Input is applied to inverting terminalInput is applied to inverting terminal Non inverting is groundedNon inverting is grounded Feedback is given to inverting terminal Feedback is given to inverting terminal
through resistor through resistor RRFF
Assuming Assuming vvoo is less than is less than VVCCCC
since since AAdd is very high, is very high, vvidid should be very should be very small; small; vvidid taken as almost zero taken as almost zero
Current entering OPAMP input terminal is Current entering OPAMP input terminal is almost zeroalmost zero
Inverting AmplifierInverting AmplifierRF
Virtual groun
d
+0 V–
0i1
i2
Inverting AmplifierInverting Amplifier
111
0Rv
Rvi inin
F
o
F
o
Rv
Rvi
0
2
21 ii
F
oin
Rv
Rv
1
1RRvv F
ino 1RR
vvA F
in
oV
Non Inverting AmplifierNon Inverting Amplifier
RF
Non Inverting AmplifierNon Inverting Amplifier Input is applied to non inverting terminalInput is applied to non inverting terminal Feedback is given to inverting terminalFeedback is given to inverting terminal Output voltage will be in-phase with input Output voltage will be in-phase with input
voltagevoltage Here again, the following assumptions are Here again, the following assumptions are
mademade Since Since AAdd is very high, is very high, vvidid should be very small; should be very small; vvidid
taken as almost zerotaken as almost zero Current entering OPAMP input terminal is almost Current entering OPAMP input terminal is almost
zerozero
Non Inverting AmplifierNon Inverting Amplifier
RF
v1
v2
i2i1
Non Inverting AmplifierNon Inverting Amplifier0idv invvv 21
11
21 R
vRvi in
F
ino
F
o
Rvv
Rvvi
22
21 ii
F
inoin
Rvv
Rv
1
1
1RRvv F
ino
ProblemsProblems For an inverting amplifier using OPAMP, RFor an inverting amplifier using OPAMP, R11=1K, =1K,
RRFF=100K, v=100K, vinin=0.1sin(=0.1sin(ωωt). Find vt). Find voo..Ans: –10sin(Ans: –10sin(ωωt)t)
For a non inverting amplifier, RFor a non inverting amplifier, R11=10K, R=10K, RFF=100K. =100K. Calculate vCalculate voo if v if vii = 25 mV dc. = 25 mV dc.
Ans: 275 mV dcAns: 275 mV dc An ac signal of rms value 2 mV needs to be An ac signal of rms value 2 mV needs to be
amplified to 1.024 V rms, 180 degree phase shifted. amplified to 1.024 V rms, 180 degree phase shifted. Design a suitable amplifier choosing RDesign a suitable amplifier choosing R11=1.2K=1.2K
Ans: Inv amplifier with RAns: Inv amplifier with RFF=614.4K=614.4K
Voltage FollowerVoltage Follower
Special case of non inverting amplifier where RSpecial case of non inverting amplifier where RFF=0=0 Voltage gain is unity.Voltage gain is unity. vvoo = v = vinin Has very high input resistance and very low output Has very high input resistance and very low output
resistance; Used as buffer for impedance matchingresistance; Used as buffer for impedance matching
Summing Amplifier (Adder)Summing Amplifier (Adder)
iA
iB
iF
Summing Amplifier (Adder)Summing Amplifier (Adder)
If If RRAA=R=RBB=R=RFF, then, then
A
AA R
vi B
BB R
vi
FBA iii
F
oF R
vi
F
o
B
B
A
A
Rv
Rv
Rv
B
FB
A
FAo R
RvRRvv
BAo vvv
Difference Amplifier Difference Amplifier (Subtractor)(Subtractor)
Difference Amplifier Difference Amplifier (Subtractor)(Subtractor)
The circuit is analyzed using superposition The circuit is analyzed using superposition theoremtheorem
Consider only vConsider only v11 to be present; v to be present; v22=0=0Now derive expression for output voltage Now derive expression for output voltage vvo1o1
Next consider only vNext consider only v22 to be present; v to be present; v11=0=0Derive expression for output voltage vDerive expression for output voltage v0202
Actual output voltage vActual output voltage voo = v = vo1o1+v+vo2o2
Difference Amplifier Difference Amplifier (Subtractor)(Subtractor)
vx
21 1
RRvv F
xo
231
311 1
RR
RRRvv F
o
Difference Amplifier Difference Amplifier (Subtractor)(Subtractor)
222 RRvv F
o
22
231
3121 1
RRv
RR
RRRvvvv FF
ooo
FR3R2R1R if21 vv
ProblemsProblems Design an OPAMP circuit such that output Design an OPAMP circuit such that output
is given by is given by vvoo=–(0.5=–(0.5vv11+0.75+0.75vv22) where ) where vv11 and and vv22 are input voltages. Choose are input voltages. Choose RRFF=10K=10K
Design an OPAMP subtractor to have Design an OPAMP subtractor to have output given by output given by Choose RChoose RFF=R=R22=1K=1K
Design an OPAMP adder/subtractor to get Design an OPAMP adder/subtractor to get output voltage output voltage
2132
o vvv
3232
121
o vvvv
IntegratorIntegrator
IntegratorIntegrator Integrator is a circuit whose output is Integrator is a circuit whose output is
proportional to (negative) integral of the proportional to (negative) integral of the input signal with respect to timeinput signal with respect to time
Feedback is given through capacitor to Feedback is given through capacitor to inverting terminalinverting terminal
Since same current flows through R and C,Since same current flows through R and C,
dtdvC
Rv oin
t
0ino dtvv
RC1
IntegratorIntegrator
DifferentiatorDifferentiator
DifferentiatorDifferentiator Differentiator is circuit whose output is Differentiator is circuit whose output is
proportional to (negative) differential of proportional to (negative) differential of input voltage with respect to timeinput voltage with respect to time
Input is given through capacitor, feedback Input is given through capacitor, feedback given through resistor to inv terminalgiven through resistor to inv terminal
Since current through R and C are same,Since current through R and C are same,
Rv
dtdvC oin
dtdvv in
o RC
End of Module 4