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116/11/50
ENE 490Applied Communication
Systems
ENE 490Applied Communication
Systems
Lecture 2 circuit matching on Smith chart
216/11/50
Review (1)Review (1)
High frequency operation and its applications Transmission line analysis (distributed elements)
– Use Kirchholff’s law to obtain general equations for transmission lines
– Voltage and current equations are the combination of incident and reflected waves.
0 0
0 0
0 0
( )
( )
j z j z
j z j z
V z V e V e
V VI z e e
Z Z
where Z0 is a characteristic impedance of a transmission line.
Assume the line is lossless.
316/11/50
Review (2)Review (2)
Terminated lossless line– voltage reflection coefficient
– impedance along a transmission line
or
20
0
( )
j dV
d eV
00
0
tan( )
tan
L
L
Z jZ dZ d Z
Z jZ d
1 ( )( )
1 ( )
d
Z dd
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Review (3)Review (3)
- voltage standing wave ratio
source and loaded transmission line
max max
min min
( ) ( ) 1
( ) ( ) 1
L
L
V d I dVSWR
V d I d
200
0
( )
j lin
inin
Z Zd l e
Z Z
0
0
S
SS
Z Z
Z Z
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Review (4)Review (4)
power transmission of a transmission line
for lossless and a matched condition
power in decibels
*1Re2avP VI
218
Sin avs
S
VP P
Z
10log
1P W
P dBmmW
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Impedance matching network (1) Impedance matching network (1)
The need for matching network arises because amplifiers, in order to deliver maximum power to a load or to perform in a certain desired way, must be properly terminated at both the input and the output ports.
+
-VS
ZL
Inputmatching network
TransistorOutput
matching network
ZS
WZ1=50
WZ2=50
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Impedance matching network (2) Impedance matching network (2)
Effect of adding a series reactance element to an impedance or a parallel susceptance are demonstrated in the following examples.
Adding a series reactance produces a motion along a constant-resistance circle in the ZY Smith chart.
Adding a shunt susceptance produces a motion along a constant-conductance circle in the ZY Smith chart.
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Ex1 Adding a series inductor L (zL = j0.8) to an impedance z = 0.3-j0.3.
Ex1 Adding a series inductor L (zL = j0.8) to an impedance z = 0.3-j0.3.
= 0.3-j0.3
zL= j0.8
z
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Ex2 Adding a series capacitor C (zC = -j0.8) to an impedance z = 0.3-j0.3.
Ex2 Adding a series capacitor C (zC = -j0.8) to an impedance z = 0.3-j0.3.
= 0.3-j0.3
zC =-j0.8
z
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Ex3 Adding a shunt inductor L (yL = -j2.4) to an admittance y = 1.6+j1.6.
Ex3 Adding a shunt inductor L (yL = -j2.4) to an admittance y = 1.6+j1.6.
= 1.6+j1.6yyL=-j2.4
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Ex4 Adding a shunt capacitor C (yC = j3.4) to an admittance y = 1.6+j1.6.
Ex4 Adding a shunt capacitor C (yC = j3.4) to an admittance y = 1.6+j1.6.
C = 1.6+j1.6yyC=j3.4
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Examples of matching network designExamples of matching network design
Ex5 Design a matching network to transform the load Zload = 100+j100 W to
an input impedance of Zin = 50+j20 W.
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Ex6 Design the matching network that provides YL = (4-j4)x10-3 S to the transistor. Find the element values at 700 MHz.
Ex6 Design the matching network that provides YL = (4-j4)x10-3 S to the transistor. Find the element values at 700 MHz.
C
L 50W
yL=(4-j4)x10 S-3
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L matching networksL matching networks
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Forbidden regionsForbidden regions
Sometimes a specific matching network cannot be used to accomplish a given match.
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Load quality factor The developed matching networks can also be viewed as resonance circuits with f0 being a resonance frequency. These networks may be described by a loaded quality factor, QL.
The estimation of QL is simply accomplished through the use
of a so-called nodal quality factor Qn. At each node of the
L-matching networks, there is an equivalent series input impedance, denoted by RS +jXS. Hence a circuit node Qn can
be defined at each node as
0L
fQ
BW
S Pn
S P
X BQ
R G
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Circuit node Qn and loaded QL
Circuit node Qn and loaded QL
L-matching network is not a good choice for a design of high QL circuit since it is fixed by Qn.
For more complicated configurations (T-network, Pi-network), the loaded quality factor of the match network is usually estimated as simply the maximum circuit node quality factor Qn.
2n
LQ
Q
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The example of Q calculationThe example of Q calculation
At 500 MHz Qn = 2
then QL = 1.
and = 500 MHz0
L
fBW
Q
C=12.7 pF 10W
L=3.18 nH L=3.18 nH
VS
50W
Z IN = 50W
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Ex7 The low pass L network shown below wa s designed to transform a 200 W load to an in
put resistance of 200 W . Determine the loade d Q of the circuit at f = 500 MHz .
Ex7 The low pass L network shown below wa s designed to transform a 200 W load to an in
put resistance of 200 W . Determine the loade d Q of the circuit at f = 500 MHz .
ACC
=4
.77
5 p
F
R =
20
020 W
W
L = 19.09 nH
2016/11/50
Constant Qn contoursConstant Qn contours
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The upper and lower part of Q contours satisfy a circle equation.
The upper and lower part of Q contours satisfy a circle equation.
Since
then
which can be written as
2 2
2 2 2 2
1 1 21 (1 ) (1 )
U V
z r jx jU V U V
2 2
2
1
n
x UQ
r U V
2 22
1 1( ) 1
n n
U VQ Q
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Contour equationsContour equations
The equations for these contours can be derived from the general derivation of the Smith chart. By following the derivation, Qn contours follow this circle equation,
22 2
2
1 11i r
n nQ Q
where the plus sign is taken for positive reactance x and the minus sign for negative x.
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Qn circle parametersQn circle parameters
For x > 0, the center in the plane is at (0, -1/Qn).
For x < 0, the center in the plane is at (0, +1/Qn).
the radius of the circle can be written as
2
11 .
n
rQ
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Ex8 Design two T networks to transform the load impedance ZL = 50 W to the input impedance Zin = 10-j15 W with a Qn of 5.
2516/11/50
Ex9 Design a Pi network to transform the load impedance Zload = 50 W to the input impedance Zin = 150 W with a Qn of 5.
Ex9 Design a Pi network to transform the load impedance Zload = 50 W to the input impedance Zin = 150 W with a Qn of 5.