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2-D Motion

Date post: 23-Feb-2016
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2-D Motion. Because life is not in 1-D. General. Solving 2-D Problems. Resolve all vectors into components x-component Y-component Work the problem as two one-dimensional problems. Each dimension can obey different equations of motion. - PowerPoint PPT Presentation
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2-D Motion Because life is not in 1-D
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Page 1: 2-D Motion

2-D MotionBecause life is not in 1-D

Page 2: 2-D Motion

General

Page 3: 2-D Motion

Solving 2-D Problems Resolve all vectors into components

x-component Y-component

Work the problem as two one-dimensional problems. Each dimension can obey different

equations of motion. Re-combine the results for the two

components at the end of the problem.

Page 4: 2-D Motion

A roller coaster rolls down a 20o incline with an acceleration of 5.0 m/s2.

How far horizontally has the coaster traveled in 10 seconds?

How far vertically has the coaster traveled in 10 seconds?

Page 5: 2-D Motion

A particle passes through the origin with a speed of 6.2 m/s traveling along the y axis. If the particle accelerates in the negative x direction at 4.4 m/s2

.

a. What are the x and y positions at 5.0 s?

Page 6: 2-D Motion

A particle passes through the origin with a speed of 6.2 m/s traveling along the y axis. If the particle accelerates in the negative x direction at 4.4 m/s2

.

b. What are the x and y components of velocity at this time?

Page 7: 2-D Motion

Projectile MotionMoves both horizontally and vertically, subject to acceleration by gravity in vertical direction.

Page 8: 2-D Motion

Projectile MotionFired, thrown, shot, or hurled near the earth’s surface. Horizontal velocity is constant. Vertical velocity is accelerated. Air resistance is ignored.

Page 9: 2-D Motion

Horizontal Component of Velocity

Page 10: 2-D Motion

Vertical Component of Velocity Undergoes accelerated motion Accelerated by gravity (9.8 m/s2 down)

Vy = Vo,y - gty = yo + Vo,yt - 1/2gt2

vy2 = Vo,y

2 - 2g(y – yo)

Page 11: 2-D Motion

Horizontal and Vertical

Page 12: 2-D Motion

Horizontal and Vertical

Page 13: 2-D Motion

Zero Launch angle

A zero launch angle implies a perfectly horizontal launch.

vo

Page 14: 2-D Motion

The Zambezi River flows over Victoria Falls in Africa. The falls are approximately 108 m high. If the river is flowing horizontally at 3.6 m/s just before going over the falls, what is the speed of the water when it hits the bottom? Assume the water is in freefall as it drops.

Page 15: 2-D Motion

An astronaut on the planet Zircon tosses a rock horizontally with a speed of 6.75 m/s. The rock falls a distance of 1.20 m and lands a horizontal distance of 8.95 m from the astronaut. What is the acceleration due to gravity on Zircon?

Page 16: 2-D Motion

General launch angle

vo

Projectile motion is more complicated when the launch angle is not straight up or down (90o or –90o), or perfectly horizontal (0o).

Page 17: 2-D Motion

General launch angle

vo

You must begin problems like this by resolving the velocity vector into its components.

Page 18: 2-D Motion

Resolving the velocityUse speed and the launch angle to find horizontal and vertical velocity components

VoVo,y = Vo sin

Vo,x = Vo cos

Page 19: 2-D Motion

Resolving the velocityThen proceed to work problems just like you did with the zero launch angle problems.

VoVo,y = Vo sin

Vo,x = Vo cos

Page 20: 2-D Motion

A soccer ball is kicked with a speed of 9.50 m/s at an angle of 25o above the horizontal. If the ball lands at the same level from which is was kicked, how far from the kicker does it land?

Page 21: 2-D Motion

Trajectory of a 2-D Projectile

x

y

Mathematically, the path is defined by a parabola.

Page 22: 2-D Motion

Trajectory of a 2-D Projectile

x

y

For a projectile launched over level ground, the symmetry is apparent.

Page 23: 2-D Motion

Range of a 2-D Projectile

x

y

Range

Definition: The RANGE of the projectile is how far it travels horizontally.

Page 24: 2-D Motion

Maximum height of a projectile

x

y

Range

MaximumHeight

The MAXIMUM HEIGHT of the projectile occurs when it stops moving upward.

Page 25: 2-D Motion

Maximum height of a projectile

x

y

Range

MaximumHeight

The vertical velocity component is zero at maximum height.

Page 26: 2-D Motion

Maximum height of a projectile

x

y

Range

MaximumHeight

For a projectile launched over level ground, the maximum height occurs halfway through the flight of the projectile.

Page 27: 2-D Motion

Acceleration of a projectile

g

g

g

g

g

x

y

Acceleration points down at 9.8 m/s2 for the entire trajectory of all projectiles.

Page 28: 2-D Motion

Velocity of a projectile

vo

vf

v

v

v

x

y

Velocity is tangent to the path for the entire trajectory.

Page 29: 2-D Motion

Velocity of a projectile

vy

vx

vx

vy

vx

vy

vx

x

y

vx

vy

The velocity can be resolved into components all along its path.

Page 30: 2-D Motion

Velocity of a projectile

vy

vx

vx

vy

vx

vy

vx

x

y

vx

vy

Notice how the vertical velocity changes while the horizontal velocity remains constant.

Page 31: 2-D Motion

Velocity of a projectile

vy

vx

vx

vy

vx

vy

vx

x

y

vx

vy

Maximum speed is attained at the beginning, and again at the end, of the trajectory if the projectile is launched over level ground.

Page 32: 2-D Motion

vo -

vo

Velocity of a projectile

Launch angle is symmetric with landing angle for a projectile launched over level ground.

Page 33: 2-D Motion

to = 0

tTime of flight for a projectile

The projectile spends half its time traveling upward…

Page 34: 2-D Motion

Time of flight for a projectile

to = 0

t

2t … and the other half traveling down.

Page 35: 2-D Motion

Snowballs are thrown with a speed of 13m/s from a roof 7.0 m above the ground. Snowball A is thrown straight downward; snowball B is thrown in a direction 25o above the horizontal. When the snowballs land, is the speed of A greater than, less than, or the same speed of B? Verify your answer by calculation of the landing speed of both snowballs.


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