5 Elevators

7/30/2019 5 Elevators

1/10

1

Viet nam August 2005

ALTIVAR71Lift Training

Lift Training Vietnam Augu

Load detai ls Vector drive required

Constant torque (torque load dependant)

Lift regenerative on raising empty car

Dynamic brake or Network Braking required

Calculations Gearbox & Pulley system efficiencies

Maximum mass of car & counter weight mass

Lifting and lowering speed

Acceleration & Deceleration rate

Lif t Char act er ist ics


2/10

2


Car

Counterweight

Supply

Dyna

micBrake

Gener al Ar r angement

Encoder


ua r an on r o -Mot or ing

Car

with

full

load

+

Torqu

e

-

Torqu

e

+

Speed

-

Speed

C

ar

Coun

ter

weig

ht

Motoring

Motoring

Car

with

no

load

Count

er

weight

Ca

r


3/10

3


ua r an on r o -Regenerat ing

+

Torqu

e

-

Torqu

e

+

Speed

-

Speed

Count

er

weight

Ca

r

Car

with

no

load

Car

with

full

load

Regenerating

Regenerating

Car

Co

unt

er

wei

ght

Brake

Brake


4 Quadr ant Cont r ol

Car

with

full

load

+

Torqu

e

-

Torqu

e

+

Speed

-

Speed

C

ar

Coun

ter

weig

ht

Motoring

Motoring

Car

with

no

load

Count

er

weight

Ca

r

Count

er

weight

Ca

r

Car

with

no

load

Car

with

full

load

Regenerating

Regenerating

Car

Co

unt

er

wei

ght

Brake

Brake


4/10

4


Motor and gear box

efficiency 90%

Example Calculat ion

Empty CarMass 1270kg

Counter weightmass (car + maximum load)1560kg

Maximum loadMass 580kg

Vertical

Speed1.6m/s

Cable

mass100kg

Motor & gear box Inertia

0.034kg/m2

Idler pulley Inertia

0.006kg/m2

Acceleration0.8 m/s2

System efficiencyincludes friction of carand counterweightagainst guides, cableand pulleys etc. 95%


m.

))((

.

(ravelocityAngular

(m/velocityLinearradiusEquivalent

01020

2601500

61

2

2

36520

010010015601850

m/kg.

.)(radiequivalentMassInertia

qu va en a us oGyr at ion

Car

Counterweight

1) Calculate the equivalent rotating

inertia of the car, counterweight& rope

Car full load1850 kg

Counter weight1560 kg

Vertical speed 1.6m/sAcceleration 0.8

m/s2

Motor 1500 RPM

11kW

Motor & G/Box Inertia0.034kg/m2

Motor gearbox efficiency90%

System efficiency

95%

Use equivalent radius to simplify calculations.

Do not need to know gearbox ratios, pulley orrope sizes. Uses inertia of a cylinder whereall weight is effectively distributed around anarc scribed by the equivalent radius.


5/10

5


watts

Efficiency

oAcceleVelocityInertiaP MotorACC

465

9.0

2

157157034.0

AngularAngular

2) Calculate the power to accelerate t he motor

and gearbox

Acceler at ing Power

Car

Counter

weight

3) Calculate the power to accelerate the car,

counterweight, cables and load

watts

Efficiency

oAcceleVelocityInertiaP

systemACC

737,4

95.0

2

1571573652.0

AngularAngular

4) Total Accelerating power required

wa

,PTotalACC

5202

47374



Vertical speed 1.6

m/sAcceleration 0.8

m/s2

Motor 1500 RPM

11kW



System efficiency

95%


5) Calculate t he worst case lifting or loweringpower requirement.

watts

..

..

Efficiency

GraVelocity)W/CloadCar(PLift

5416

90950

8196115601850

Tot al Power Requir ement

Car

Counterweight

6) Calculate the total power

required.

kWatts

k

PPP LiftonAcceleratiTotal

618.10

)416.5202.5(

The 11kW motor is just adequate but it does notallow a safety factor for possible overloadsituations




m/s2

Motor 1500 RPM

11kW



System efficiency

95%

This power isrequired from

the motor


6/10

6


watts

EfficiGravityVelocityEmptyCarghtCounterWeiPgen

3891

9.095.081.96.112701560

)(Re

8) Calculate the decelerating regenerative power for

system and motor gearbox.

097,8

3891206,4

Regen

LowerDEC PPP

Regener at ive Power

Car

Counter

weight

7) Calculate the worst case lowering or

lifting regenerative power.


Counter weight

1560 kg

Vertical speed 1.6

m/sAcceleration 0.8m/s2

Motor 1500 RPM

11kWMotor & G/Box Inertia

0.034kg/m2

Motor gearbox efficiency

90%

System efficiency95%

watts

Efficiency

oAcceleVelocityInertiaP

MotorsystemDEC

206,4

95.09.02

1571573652.0034.0

AngularAngular&

9) Calculate the total regenerative power.

This energy

must bedissipated


10) Calculate maximum Brake Reis tance

Po

VsistorRe

2

76

8097

785Re

2

sistor

ynam c ra e es s orSizing

Car

Counterweight




m/s2

Motor 1500 RPM

11kW



System efficiency

95%

Points:

1) This is a maximum resistor resistance. Anyincrease in resistor resistance means that thepeak power of 8.097kW can not be dissipatedcausing the Drive to fault on over voltage etc.

2) Peak regeneration occurs at maximum speedwhen accelerating or decelerating when underregeneration. At half speed under the sameoperating conditions power dissipation by theresistor will only be 4kW.

3) No allowance has been made for a car that couldbe overloaded!!


7/10

7


-

SchindlerElevators in New Zealand and Australia

Project : Elevator c ontrol

-

retrofit applications.

ec r on csExper iance


Linear speed display in m/s.

4 adjustable S curves

Smooth transitions

Adaptive speed gains

Speed dependant response

Pre-torque star ting

No roll back

Schindler Requier ment s


8/10

8


a n equ r emenCurves


7 63 8 92 2/ 8 98 7 2 2/ 09 / 93 S C H IN DL ER L I FT S V AR IO US / W AI KA TO P OL Y TE CH U D3 C US TO M SO FT WA RE D E VE LO PM EN T

7 64 9 04 2 2 2/ 08 /95 S C HI ND LE R L IF TS D IG IT AL H OU SE BU IL DI NG M V3 CU ST OM S OF TW AR E D EV EL OP ME NT

7 66 9 04 5 0 4/ 07 /95 S C HI ND LE R L IF TS M OU NT S MA RT S TA DI UM 1 *U D3 -6 0/ 1 *D B- 30 0/ 1 * SO FT WA RE / 1* CU ST OM R ESI ST

7 67 9 08 6 2 0/ 04 /95 S C HI ND LE R L IF TS W AI KA TO P O LY TE CH NI C 1 *U D3 -4 6/ 1 *D B- 30 0/ 1 *S OF TW AR E/ 1* CU ST OM R ESI ST

683 9009 5131150 29/04 /94SCHINDLER LIFTSLTD ENDEANSBUILDINGAUCKLAND DYNAMICBRAKE RESISTOR

6 84 9 01 3 5 22 74 0 1 7/ 09 / 94 S C H IN DL ER L I FT S LT D G RE E NL AN E HO SP I TA L D YN AM IC B RA KE R ES I ST OR S

768 9060 18/01 /95SCHINDLER L IFTSLTD TARANAKI SAVINGS BANKCENTR2*UD3-31 /2*SOFTWARE/ 2*DB300/ 2*CUSTOMRESIST

765 9104 07/06 /95SCHINDLER L IFTSNF LTD LEARNIING RESOURCE CENTRE 1*UD3-46/1*DB-300/ 1*SOFTWARE/ 1*CUSTOMRESIST

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ome o s omp e e yNapier


9/10

9


Control System

OEM PCB Based Logic Standard Start Forward Start Reverse and Jog

Control of the VSD

Output Contactor

Used Schneider PLC or Use Controller Inside

Implement S Curve Functionality within the Drive

Use Drive Position on Limit Switch Functionality

Use ATV71 Power Removal Function (No MoreOutput Contactor?)

Output Contactor Control for Safety Requirements

Performance Requirements

Needs to be Smooth

Needs to be Fast

Use Pretorque Functionality within Drive

Speed PID Loop

High Speed Hoisting

External Poition Sensors

OEM Visit s


Elecrical Equipment

Do not used 1 supplier

Use Schneider.

Single Point of Contact.

Schneider can Supply VSD, Contactors,Overloads, Brake Reistors, Network Brakingand Full Expertise with ConsiderableExperience.

OEM Visit s


10/10

10


Thank You

Date post:	04-Apr-2018
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