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6 Permutations&C

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    6 Permutations& Combinations

    F5

    TEO POH

    GURU CEMERLANG MATEMATIK

    SMK ALOR AKAR, KUANTAN,

    PAHANG

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    6 Permutations & Combinations

    PAST YEAR QUESTIONS ......

    (2003) Permutations : Form Code of 3 letters

    +2 digits

    (2004) Permutations : arrange HEBAT

    (2005) Combinations : Form debating teams of5 students

    (2006) Permutations : Form 4-letter code from

    UNIFORM

    (2007) Combinations : Form Badminton team of 5

    players : 2 boys and 3 girls

    F5

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    Question students always ask .....

    When do we use nPr ??

    ... and WHEN do we use nCr ???

    F5 6 Permutations & Combinations

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    Ask yourself .....

    Does the problem involve arrangement ?

    If the order is important, then use nPr.

    F5 Permutations

    eg. 1. Arrange numbers 1, 2, 3, 4 to form 4-digit words

    2. Arrange letters D, N, A to form 3-letter code words

    3. Arrange books on a shelf

    4. Arrange students (in a row) to take photos

    Key word : ARRANGE

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    Ask yourself ..... IsORDERimportant ???

    Since order is NOT important, use nCr.

    F5 Combinations

    eg. 1. Choose 3 students from a class

    2. Choose 5 members to form a PTA committee

    3. Choose a debating team of 4 students from [2005]

    4. Choose players to form badminton teams [2007]

    Key word : CHOOSE

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    (a) Find the number of possible arrangements, in arow, of all the cards.

    (b) Find the number of these arrangements in

    wh

    ich

    th

    e letters E and A are side by side.

    (a) No. of ways = 5 != 120

    (b) No. of ways = 4 ! 2 != 48

    F5 PERMUTATIONS AND COMBINATIONS

    EA orAE

    H E B A T

    SPM 04

    P1,Q23Q1

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    Find the number offour digitnumbers which

    can be formed from the numbers 1, 3, 8, 9 ifeach number is allowed to be used once only.

    How many of this numbers are even ?

    (a) No. of 4-digit numbers = 4 != 24

    (b) No. of 4-digit even numbers

    = 3 . 2 . 1 . 1= 6

    F5 PERMUTATIONS AND COMBINATIONS

    8 only !

    Q2

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    Find the number offour digit numbers exceeding3000 which can be formed from the numbers

    2, 3, 6, 8, 9 if each number is allowed to be usedonce only.

    No. of ways = 4 . 4. 3. 2

    = 96

    3, 6, 8, 9

    F5 PERMUTATIONS AND COMBINATIONSQ3(a)

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    Find the number ofthree-digit numbers exceeding

    600 which can be formed from the numbers

    3, 0, 6, 8 if each number is allowed to be usedmore thanonce.

    No. of 3-Dnumbers = 2 . 4. 4= 326, 8

    F5 PERMUTATIONS AND COMBINATIONS Q3(b)

    (> 600) : = 32 1= 31

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    Vowels : E, A, IConsonants : B, S, T, RArrangements : C V C V C V C

    No. of ways = 4! 3 !

    = 144

    Find the number of ways the word BESTARI can bearranged so that the vowels and consonants alternate

    with each other. [ 3 marks ]

    F5Q4

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    Given : 4 M, 2AM, 6 P (12 students)To form 5-member debating team.

    (a) No. of ways = 12C5= 792(b) No. of ways = 4C1 .

    6C3 .2C1

    = 160

    A debating team consists of 5 students. These 5 studentsare chosen from 4 monitors, 2 assistant monitors and 6

    prefects.Calculate the number of ways the teams can be formed if

    (a) there is no restriction,

    (b) the team contains only 1 monitor and exactly 3prefects.

    [ 4 marks ]

    F5 SPM 05, P1,Q22

    Q5

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    Answers :

    Given : 3 M, 2AM, 5 P (10 students)TASK : To form 4-member debating team

    A debating team consists of 4 students. These

    4students are chosen from

    3monitors,

    2assistant monitors and 5 prefects.

    Calculate the number of ways the teams canbe formed if there are

    (a) at least three prefects ,

    (b) not more than 2 monitors. [ 4 marks ]

    TryThis .!!!

    Q6

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    Answers :

    Given : 3 M, 2AM, 5 P (10 students)TASK : To form 4-member debating team

    (a) at least three prefects :

    (i) 3 prefects : 5C3.5C1 = 50

    (ii) 4 prefects : 5C4. 5C0 = 5

    Total : 55 ways

    Q6

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    Answers :

    Given : 3 M, 2AM, 5P (10 students)TASK : To form 4-member debating team

    (b) Not more than two monitors :

    (i) 0 monitor : 3C0.7C4 = 35

    (ii) 1 monitor : 3C1. 7C3 = 105(iii) 2monitors : 3C2.

    7C2 = 63

    Total : 203 ways

    Q6


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