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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
MECHANICAL ENGINEERING
Engineering Economics
Based on
White, J.A (1990) Engineering Economics,
Chapter 15 in Eshbach's andboo! o"
Engineering #$ndamenta%s (&th Edition), John
Wi%e ons(a*ai%ab%e on+%ine thro$gh the W -ibraries)
Joyce Cooper
esign "or En*ironment -ab
ni*ersit o" Washington
cooper/s$.ashington.ed$
UWME DFE Lab:
http233"ac$%t.ashington.ed$3cooper/s3
4%an,
decompose, benchmar!
#orm$%ate ana%e
Comm$nicate /$sti"
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
Engineering economics
6n essence, design decisions are economic decisions.
7er "e sit$ations e8ist in hich there are not a%ternati*e materia%s,processes, and phsica% designs a*ai%ab%e to the engineer and each
a%ternati*e has di""erent costs associated ith it.
:he economics o" engineering decisions m$st be *ieed "rom
a broad perspecti*e. :he %i"e+cc%e cost o" a prod$ct is the tota% cost o" design, prod$ction,
maintenance, s$bse;$ent rep%acements o*er the %i"e o" the prod$ct
and retirement of the product.
esign choices dictate a broad set o" costs (e.g., scres *s. snap "itsimpact assemb%, maintenance, and recc%ing costs).
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
Engineering economics
:pica% economic decisions con"ronting engineers are ne
prod$ct or process introd$ction, %ease *ers$s b$, ma!e
*ers$s b$, rep%acement o" machiner and e;$ipment,
process modi"ication, and capacit e8pansion.
6n per"orming economic comparisons o" engineeringa%ternati*es, it is recommended that a cash "%o approach be
ta!en.
ere, an end+o"+period cash "%o con*ention is $sed. peci"ica%%,
hen the period is e;$a% to a ear, an receipts or disb$rsementsocc$rring d$ring a ear i%% be shon as occ$rring at the end o" the
ear and the present is considered to be the end o" ear zero.
We $se this con*ention in ma!ing cash "%o diagrams.
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
Cash "%o diagrams Cash "%o diagrams are $sed to depict the timing and
magnit$des o" the cash "%o amo$nts in the present "$t$re.
4$rchase costs ann$a% e8pendit$res "or maintenance, energ, and%abor charges and sa%*age *a%$es occ$r in a cash "%o series.
Cash "%o diagrams Begin at ear 0 (no) and end at the end o" the pro/ect (ear n++ represents pro/ect horion)
Cash "%os each ear can be a combination o" receipts and paments & 5 ?
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:pes o" cash "%os
Single payment cash flow+ can occ$r at the beginning o" a time %ine
(t@0), at the end o" the time %ine (t@n), or an time in beteen.
Uniform series cash flow+ consists o" a series o" e;$a% transactions
starting at t@1 and ending at t@n. A is tpica%% $sed to represent
the magnit$de o" each "%o.
Uniform gradient cash flow+ starts ith a cash "%o (denoted as ) at t@=
and increases b each ear thro$gh t@n, at hich time the cash "%o is(n+1)
t=2
G
t=n
2G
3G
(n-1)G
t=1
A each
t=n
e.g., 6ncreasing
maintenance costs ith
aging e;$ipment
e.g., re*en$e (an $p arro) or
materia% costs (a don
arro)
e.g., e;$ipment costs
P
t=0
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
Cash "%o diagrams
#or e8amp%e, a mechanica% de*ice i%% cost =0,000 hen p$rchased.
aintenance i%% cost 1,000 per ear. :he de*ice i%% generate re*en$eso" 5,000 each ear "or 5 ears, a"ter hich the sa%*age *a%$e is e8pected
to be D,000.
#rom #E
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:he time *a%$e o" mone
6n genera%,
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:he time *a%$e o" mone
Simple nterest 6" 6 borro a present s$m o" mone or a principal P at a simple
interest rate i, the ann$a% cost o" interest is 6@4i. 6" 6 repa the %oan in a lump sum at the end o" n ears, the amo$nt oed
is2
Amo$nt oed @ 4 H n6 @ 4(1Hni)
#or e8amp%e, 6" 6 borro 1,000 "or ? ears at a simp%e interest rate o" 10I, at the end
o" the ? ears 6 oe2Amo$nt oed @4(1Hni)@1,0001H?(0.1)K@1,?00
here2
4@ princip%e or present orth
6@ ann$a% cost o" interest
i@ ann$a% interest rate
n@ n$mber o" ears
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:he time *a%$e o" mone
Compo!nd nterest 6n compo$nd interest, the interest d$e at the end o" a period is not
paid o$t b$t is instead added to the principa%. :h$s, d$ring the ne8t
period, interest is paid on the tota% s$m.#irst period2 amo$nt oed1@4(1Hi)
econd period2 amo$nt oed=@ 4(1Hi)Hi4(1Hi)@ 4(1Hi)=
nth period2 amo$nt oedn@ 4(1Hi)n
imp%e *s. compo$nd interest #or 1,000 %oaned "or ? periods at 10I simp%e or compo$nd interest
Simple vs. Compound Interest
$0
$500
$1,000
$1,500
$2,000
0 1 2 3 4 5 6
End of Interest Period
Am
ountOwed
Simple Interest
Compound Interest
Simple Interest
period
(1) amount
ow ed at the
beginning of the
period
(2)=1,000 x 10%
interest amount
for period
(3)=(1)+(2)
amount
ow ed at the
end of the
period
1 $1,000 $100 $1,100 =1,000(1+.1)
2 $1,100 $100 $1,200 =1,000(1+.2)
3 $1,200 $100 $1,300 =1,000(1+.3)
4 $1,300 $100 $1,400 =1,000(1+.4)
5 $1,400 $100 $1,500 =1,000(1+.5)
6 $1,500 $100 $1,600 =1,000(1+.6)
Compound Interest
period
(4) amount
ow ed at the
beginning of
the period
(5)=(4)x10
% interest
amount for
period
(6)=(4)+(5)
amount ow ed
at the end of
the period
1 $1,000 $100 $1,100 =1,000(1.1)
2 $1,100 $110 $1,210 =1,000(1.1)^2
3 $1,210 $121 $1,331 =1,000(1.1)^3
4 $1,331 $133 $1,464 =1,000(1.1)^4
5 $1,464 $146 $1,611 =1,000(1.1)^5
6 $1,611 $161 $1,772 =1,000(1.1)^6
6n the reading, a%%
interest ca%c$%ationsare based on
compo$nd interest
rather than simp%e
interest.
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:ime *a%$e o" mone
:he interest rate $sed in ca%c$%ations is !non
as the e""ecti*e interest rate.
#or compo$nd interest2
6" compo$nding is once a ear, the interest rate isca%%ed an e""ecti*e ann$a% interest rate.
E""ecti*e ;$arter%, month%, or dai% interest rates are
a%so $sed.
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:he time *a%$e o" mone nemonic con*ention
:he amo$nt oed in the nth period is ca%%ed the "$t$re orth or "$t$re
*a%$e (#) ith "o%%oing mnemonic con*ention $sed2
# @ 4(1Hi)n
denoted as # @ 4(#L4 iI,n)
here (#L4 iI, n) can be stated as
#ind #, gi*en 4, $sing an interest rate o" iI o*er n ears.F
:he ;$antit (1 H i)n is re"erred to as the sing%e s$m, "$t$re orth
"actor and is genera%% ca%%ed a discounting factor DSC"U#$#% F&C$"'S ("or "$t$re and other timed "%os) are tab$%ated
in the appendi8 o" the reading.
WhMN beca$se sometimes e8ams do not a%%o o$ to bring a ca%c$%ator or $se E8ce%O.
here2
F ( the f!t!re )al!e or f!t!re worth
4@ princip%e or present orth
i@ ann$a% interest rate
n@ n$mber o" ears
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:ime *a%$e o" mone
6 p$t 1,000 in a ban! acco$nt that earns &I per ear. o m$ch
i%% 6 ha*e in 10 earsM :he 1,000 is re"erred to as the present *a%$e o" the in*estment. 6 am tring to
ca%c$%ate the "$t$re *a%$e o" the in*estment a"ter 10 ears.
# @ 4(#L4 iI,n) @ 4(1Hi)n
# @ 1000(1H0.0&)10 @ 1,&P0
We%% that is /$st not eno$gh, 6 ant G
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
isco$nt "actors "or discrete compo$nding
#rom Engineering Economic Ana%sis, EIT Reference Manual,
4ro"essiona% 4$b%ications 6nc.
Factor Name Converts Symbol FormulaSingle payment compoundamount
P to F (F/P, i%, n) niPF )1( +=
Single payment present worth F to P (P/F, i%, n)n
iFP
+= )1( Uniform series sinking fund F to A (A/F, i%, n)
1)1( +=
ni
iFA
Capital recovery P to A (A/P, i%, n)
11
1
+
+=
n
n
)i(
)i(iPA
Uniform series compoundamount
A to F (F/A, i%, n)
iiAF
n
1)1( +
=
Uniform series present worth A to P (P/A, i%, n)n
n
)i(i
)i(AP
+
+=
1
11
Uniform gradient present worth G to P (P/G, i%, n)
+
+
+=
nn
n
)i(i
n
)i(i
)i(GP
11
112
Uniform gradient future worth G to F (F/G, i%, n)
+=
i
n
i
iGF
n
2
1)1(
Uniform gradient uniformseries
G to A (A/G, i%, n)
+
=
11
1n)i(
n
iGA
e.g., 4eriodic contrib$tion to 6
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
sing disco$nt "actors2 consider the nationa% debt
#rom http233.bri%%ig.com3debtQc%oc!3 at ?21D this morning
#rom http233.treas$rdirect.go*3R43debt3c$rrent
And according to the :reas$rO
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
sing disco$nt "actors
Concerning the nationa% debtO :he nationa% debt is S1D.9 tri%%ion. What is the re;$ired
pament per ear to comp%ete% pa o"" the debt in =0 ears,
ass$ming an interest rate o" ?IM
time0 1 = OO. =0
1D.9 tri%%ion
A A A
sing the capita% reco*erdisco$nt "actor ("or %oan repament)
A @ 4(AL4,?I,=0)
@ (1D.9 tri%%ion)T0.0PD=@ 1.5? tri%%ion per ear (hmm)
1)06.01(
)06.01(06.09.17$
20
20
+
+= trillionA
#rom http233.treas$rdirect.go*3R43debt3c$rrent
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
sing disco$nt "actors ith cash "%o diagrams
4resent orth e;$i*a%ent #or an interest rate o" iI, the present worth e*!i)alent o" the cash "%o series is2
4 @ +=0,000(4L# iI,0) H &000(4L# iI,1) H &000(4L# iI,=) H &000(4L# iI,>) H &000(4L# iI,&)
H 11,000(4L# iI,5)
G
methods2 :he present orth (4W) or the ann$a% orth (AW)
Estimate the present orth "or a%% a%ternati*es G< estimate the ann$a%orth "or a%% a%ternati*es, and compare them.
6nterna% rate o" ret$rn (6
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
endof
year(n cashflow
present
worthfactor
-134+2. 56
present
worth
e*!i)alent(@cash"%o
8
present
orth
"actor)
0 0 1 01 =,000 0.P>>> 1,??D
= =,000 0.?9&& 1,>P9
> =,000 0.5DPD 1,15D
& =,000 0.&P=> 9?5
5 =,000 0.&019 P0&
S!m(thepresentworthe*!i)alent 76,>
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Comparing a%ternati*es2
compare the incrementa% 6
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:he impact o" ta8es and depreciation
6n considering the impact o" ta8es on the economic per"ormance o"
a%ternati*es, it is necessar to consider depreciation. epreciation charges are considered beca$se
nder ta8 %a, depreciation charges are an a%%oab%e corporate ded$ction indetermining the income ta8 %iabi%it "or a "irm.
income ta8es are cash "%os and depreciation charges a""ect the sie o"the income ta8 paid
epreciation is an arti"icia% e8pense that spreads the p$rchase price
o" an asset or other propert o*er time.
:he inc%$sion o" depreciation increases the a"ter+ta8 present orth(pro"itabi%it) o" an asset.
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
epreciation methods
4rior to the ear% 19P0s, a n$mber o" di""erent depreciationmethods ere $sed in the to determine ta8ab%e income.
Common% $se methods ere2
straight+%ine depreciation ass$mes a constant depreciation value
dec%ining ba%ance ass$mes a constant depreciation rate per ear.
acce%erated depreciation methods do$b%e dec%ining ba%ance
the dec%ining ba%ance depends on acc$m$%ated depreciation
s$m+o"+the+earXs+digits
depreciation is determined b m$%tip%ing the depreciab%e cost b a scheduleof fractions
n
SCD n
=
here
@ depreciation charge "or ear
C @ the p$rchase price and
n @ the e8pected sa%*age *a%$e
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
epreciation methods
A"ter 19P1, the acce%erated cost reco*er sstem (AC
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:he depreciation o" st$""2AC+ear c%ass (A< midpoint o" U@& ears) s$ch as specia% too%s and de*ices $sed in theman$"act$re o" r$bber prod$cts, specia% hand%ing de*ices s$ch as ret$rnab%e pa%%ets, and
o*er+the+road tractors. :he 5+ear c%ass (A< midpoint o" &+10 ears) s$ch as comp$ters and periphera%s,
a$tomobi%es, b$sses, genera% carpets, and e%ectronic components.
:he D+ear c%ass (A< midpoint o" 10+1? ears) s$ch as o""ice "$rnit$re, rai%road cars and%ocomoti*es, and most prod$ction e;$ipment $sed to man$"act$re ood prod$cts, sporting
goods, /ee%r, m$sica% instr$ments, "i%ms, and tapes, among others. :he 10+ear c%ass (A< midpoint o" 1?+=0 ears) s$ch as assets $sed to man$"act$re tobacco
and certain "ood prod$cts, as e%% as that $sed in petro%e$m re"ining.
:he 15+ear c%ass (A< midpoint o" =0+=5 ears) s$ch as te%ephone distrib$tion e;$ipment,seage treatment p%ants, and assets $sed to prod$ce e%ectricit "or sa%e.
:he =0+ear c%ass (A< midpoint o" =5H ears rea% propert) s$ch as seer pipe, "armb$i%dings, rai%road steam or e%ectric generating e;$ipment, and te%ephone distrib$tion p%ants.
:he rea% propert c%ass is di*ided into residentia% and nonresidentia% residentia% propert isreco*ered o*er =D.5 ears and nonresidentia% propert is reco*ered o*er >1.5 ears.
A< @ assets depreciation range
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AC
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
AC
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
AC+ear reco*er propert. :he AC>>)@ ?,??? B1@=0,000+?,???@ 1>,>>&
=
@
=0,000(0.&&&&)
@
P,PPP B=
@
1>,>>&
+
P,PPP
@
&,&&?
>
@
=0,000(0.1&P=)
@
=,9?& B>
@
&,&&?
+
=,9?&
@
1,&P=
&@=0,000(0.0D&1)@ 1,&P= B&@1,&P=+1,&P=@ 0
For /(724,444Dt = dtP
So in 85years the boo? )al!e is @ero+ f yo!r
cash flow diagram had a hori@on of less than8 years, yo! wo!ld ha)e a sal)age )al!e+
MECHANICAL ENGINEERING
MECHANICAL ENGINEERING
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
:a8es
:pes
4ropert ta8es+ based on the *a%$e o" the propert oned and do not*ar ith pro"its,
a%es ta8es+ imposed on the sa%e o" prod$cts, $s$a%% paid b thep$rchaser
E8cise ta8es+ imposed on the man$"act$re o" certain prod$cts %i!etobacco and a%coho%, these are $s$a%% passed on to the cons$mer
6ncome ta8es+ imposed on corporate pro"its or persona% income, gainsres$%ting "rom the sa%e o" capita% propert are s$b/ect
Beca$se state ta8es are ded$ctib%e "rom "edera% ta8es, thee""ecti*e ta8 rate is2
e""ecti*e ta8 rate@state rate H(1+state rate)("edera% rate)
MECHANICAL ENGINEERING
MECHANICAL ENGINEERING
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ME395: Introduction to Mechanical Design
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Solid Fuels Processing Technologies
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:a8 E8amp%e
A corporation that pas 5>I o" its pro"its in income ta8es. 6t in*ests
10,000 in an asset that i%% prod$ce >,000 ann$a% re*en$e "or eightears. 6" the ann$a% e8penses are D00, the sa%*age *a%$e at the end
o" P ears is 500, and an 9I interest is $sed, hat is the a"ter+ta8
present orth disregarding depreciationM
4 @ +10,000 H (>000)(4LA,9I,P)(1+.05>) N (D00)(4LA,9I,P)(1+.05>) H (500)(4L#,9I,P)
@ +10,000 H (>000)(5.5>5P)(1+.05>) N (D00)(5.5>5P)(1+.05>) H (500)(0.5019)
@ +>,D??
#rom #E
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ME395: Introduction to Mechanical Design
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Solid Fuels Processing Technologies
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6ncome ta8es
What does depreciation do to income ta8esM
6t red$ces the a"ter ta8 cash "%os2
A:C#t @ B:C#t(1+rt)+rtt
here t @ depreciation charge "or ear t
A:C#t @ a"ter+ta8 cash "%o "or ear t
B:C#t @ be"ore+ta8 cash "%o "or ear t
rt @ income ta8 rate "or ear to depreciation itse%" is not a
cash "%oN b$t it has a ro%e in the
"ina% estimation o" cash "%os.
MECHANICAL ENGINEERING
MECHANICAL ENGINEERING
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
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6n"%ation
6n"%ation is a meas$re o" the b$ing poer o"
mone. When sharp increases occ$r in the amo$nt o"
c$rrenc in circ$%ation, s$dden decreases can
occ$r in the p$rchasing poer o" mone d$e to
rising prices.
enera%%, the in"%ation rate "or a co$ntr is
determined $sing a mar!et bas!etF
approach2
6n"%ation is represented as the a*erage rate o"
increase in prices "or a ide range o" goods and
ser*ices. :he Cons$mer 4rice 6nde8 (C46) is one
common% $sed meas$re o" in"%ation in the .
MECHANICAL ENGINEERING
MECHANICAL ENGINEERING
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ME395: Introduction to Mechanical Design
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Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
6n"%ation
Economic st$dies m$st be per"ormed in terms o" constant+
*a%$e do%%ars. :here are se*era% methods to accomp%ish this hen in"%ation is
present. Gne is to rep%ace the e""ecti*e ann$a% interest rate i
ith a *a%$e ad/$sted "or in"%ation. :he ad/$sted *a%$e is
ca%%ed the combined disco!nt rate2
icombined @ i H / H i/
here / is the in"%ation rate per ear and is $sed to comp$te the
present orth *a%$es.
#rom #E
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ME395: Introduction to Mechanical Design
MECHANICAL ENGINEERING
Solid Fuels Processing Technologies
MECHANICAL ENGINEERING
Engineering economics
Concepts
:he time *a%$e o" mone
Cash "%os
isco$nt "actors
Comparing a%ternati*es
epreciation, ta8es, and in"%ation
MECHANICAL ENGINEERING
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Z$estionsM