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Adc Manual New

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Common Emitter Amplifier circuit diagram

CE Amplifier without Feedback :

CE Amplifier with Feedback:

COMMON EMITTER AMPLIFIER

EXPERIMENT: 01DATE:

1. OBJECTIVE:

To Design and Construct a Common Emitter Amplifier using voltage divider bias and to determine its:

0. DC Characteristics

0. Maximum Signal Handling Capacity

0. Gain of the amplifier

0. Bandwidth of the amplifier

0. Gain -Bandwidth Product

1. REQUIREMENTS: S.noRequirementNameRangeQuantity

1Transistor [Active]BC 1071

2Resistor [Passive]61k, 10k, 1k,1,1,1,2

Components4.7k

3Capacitor [Passive]10f, 100f2,1

4Signal Generator(0-3)MHz1

5CRO30MHz1

EquipmentRegulated power

6(0-30)V1

supply

7Bread Board-1

8AccessoriesConnecting WiresSingle strandas required

DESIGN PROCEDURE:

Given specifications:

VCC= 10V, IC=1.2mA, AV= 30, hFE= 100

(i) To calculate RC:

The voltage gain is given by, AV= -hfe (RC|| RF) / hie h ie = re

re = 26mV / IE = 26mV / 1.2mA = 21.6 hie = 150 x 21.6 =3.2K

Apply KVL to output loop,

VCC= IC RC + VCE+ IE RE ----- (1)

Where VE = IE RE (IC= IE)

VE= VCC / 10= 1V

Therefore RE= 1/1.2x10-3=0.8K= 1K

VCE= VCC/2= 5V

From equation (1), RC= ( Vcc - VCE - IE RE / IC ) = ________

(ii) To calculate R1&R2:

S=1+ (RB/RE)

Where RE = 1 K and S = 9

RB= (S-1) RE= (R1 || R2) =1K

RB=( R 1R2 ) /( R1+ R2) ------- (2)

VB= VBE + VE = 0.7+ 1= 1.7V

VB= VCC (R2 / R1+ R2 )------- (3)

Solving equation (2) & (3),

R1= ____ & R2= ______

(iii) Input coupling capacitor :

Xci= Rif / 10= 2.4 (since XCi


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