An Enthalpy Model for Dendrite Growth Vaughan Voller
University of Minnesota
Growing Numerical CrystalsObjective: Simulate the growth (solidification) of crystals from asolid seed placed in an under-cooled liquid melt
Some Physical Examplessnow-flakes-ice crystals
Germs
Dendrite grains in material systems
(IACS), EPFL science.nasa.gov Voorhees,Northwestern
l
TLe
~0.5 m ~5 mmComputational grid size
Process REV
~ 1 m
In terms of the process
Sub grid scale
Simulation can be achieved using modest models and computer power
Growth of solid seed in a liquid melt Initial dimensionless undercooling T = -0.8 Resulting crystal has an 8 fold symmetry
Solved in ¼Domain withA 200x200 grid
Box boundariesare insulated
Since thethermal boundarylayer is thin Boundariesdo not affect growth until seed approaches edges
By changing conditionscan generate any number of realistic shapes in modest times
PC CPU ~5mins
BUT—WHY do we get these shapes ?—WHAT is Physical Bases for Model ?Solution is with a FIXED grid -HOW does the Numerical solution work ?
IS the solution “correct” ?
Complete
garbage
First recognize that there are two under-coolings
The bulk liquid is under-cooled, i.e., in a liquid statebelow the equilibrium liquidus temperature TM
The temperature of the solid-liquid interface is undercooled
nM
L0Merfaceinterfaceint v
LT)CC(mTTT
Conc. of Solute, m < 0 slopeof liquidus Gibbs Thomson
curvature, surface tension
Kinetic vn normal interfacevelocity
MinitialBulk TTT
Can describe process with the Sharp Interface Model—for pure materialWith dimensionless numbers
c/LTTT m
* 2
** tt,xx
Assumed constant properties
Insulated domain Initiated with small solid seeds
2s TtT
l2l Tt
T
nvn
Capillary length~10-9 for metal
On interface
nls vTT nn
)4cos151(dT o
Angle between normal and x-axis
The heat flows from warm solid intothe undercooeld liquid drives solidification
Preferred growth direction and interplay betweencurvature and liquid temperature gradient determine Growth rate and shape.
)2
ntanh(121)t,y,x(f
Smear out interface
n
1f
0f
Use smooth interpolation forLiquid fraction f across interface
f=1f=0
A Diffusive interface model: Usually implies Phase Field—Here we mean ENTHALPY (see Tacke 1988, Dutta 2006)
,TtH 2
fTH
1f,1H1f0),f(T0f,H
TThe Enthalpy -sum of sensible and latent heats-change continuously and smoothly throughout domain—Hence can write Single Field Eq. For Heat transport
undercooling
Can be solved on a Fixed grid
Growth of Equiaxed CrystalIn under-cooled melt
A microstructure model
Phase change temperaturedepends on interfacecurvature, speed and concentration
Sub-grid modelsAccount for Crystal anisotropyand “smoothing” of interface jumps
)4cos151()( Four fold symmetry
Sub grid constitutive
TtH 2
fTH fHT If f= 0 or f = 1 If 0 < f < 1
2/32y
2x
yy2xxyyxxx
2y
)ff(fffff2ff
)ff(tany
x1curvature
Local direction
)(dT o
Capillary length 10-9 m in Al alloys
ENTHALPY
Numerical Solution Very Simple—Calculations can be done on regular PC
seed
Typical gridSize 200x200¼ geometry
At end of time step if solidificationCompletes in cell iForce solidification in ALL fullyliquid neighboring cells.
Physical domain ~ 2-10 microns
Initially insulated cavity contains liquid metal with bulk undercoolingT0 < 0. Solidification induced by placing solid seed at center.
Some Results
Problem: range of cells with 0 < f < 1 restricted to width of one cell Accuracy in curvature calc?
Remedial scheme: smear out f value, e.g.,
NEPmod
P f)1(ff
Remedial Scheme: Use nine volume stencil to calculate derivatives
2SWSSEEPWNWNNE
2
2
x)21()ff2f()ff2f()ff2f(
xf
Tricks and Devices
Produces nice answers BUT are they correct
4do (blue)3.25do (black)
2.5do (red)
Dendrite shape with 3 grid sizes shows reasonable independence
= 0.05, T0 = -0.65
Dimensionless time = 6000
= 0.25, = 0.75
0
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.09
0.1
0 1000 2000 3000 4000 5000 6000
Dim. Time
Dim
. Tip
Vel
.
Solvabillity (kim et al)
Long term tip dynamics approaches theory
BUT results begin to deteriorate if grid is made smaller !!
0
2
4
6
8
10
12
14
16
0 50 100 150 200 250
,t2s
0T)(erfce 02
Verify solution coupling by Comparing with one-d solidification of an under-cooled melt
T0 = -.5
Compare with Analytical Similarity Solution Carslaw and Jaeger
Temperatureat dimensionless time t =250
Front Movement
-0.6
-0.5
-0.4
-0.3
-0.2
-0.1
0
0.1
0 20 40 60 80 100 120 140 160
)),t(sx(,)(erfct2
xerfcTTT 00
Verification 1 Looks Right!!
k = 0 (pure), = 0.05, T0 = -0.65, x = 3.333d0
Enthalpy Calculation
Dimensionless time = 0 (1000) 60002
odtk
k = 0 (pure), = 0.05, T0 = -0.55, x = d0
Level Set Kim, Goldenfeld and Dantzig
Dimensionless time = 37,600
75.0,do5.2x Red my calculation for these parameters With grid size
The Solid color is solved with a 45 deg twist on the anisotropy and then twisted back—the white line is with the normal anisotropy
,75.0)0(,95.0)45(
,25.0
0
0
Note: Different “smear” parameters are usedin 00 and 450 case
0
50
100
150
200
250
300
350
0 2000 4000 6000
Dim. Time
Tip
Pos.
45 deg. twist in anisotropy
Tip position with time
Dimensionless time = 6000
= 0.05, T0 = -0.65
Not perfect: In 450 case the tip velocity at time 6000 (slope of line) is below the theoretical limit.
Low Grid Anisotropy
m
For binary system need to consider – solute transport, discontinuous diffusivities and solutes
k)k1(fCV
fDkD)f1(DfCC)f1(C
ls
ls
Use smoothly interpolatedVariables across the interface
isC
ilC
)CD(tC
sss
)CD(tC
lli
nlllss v)k1(CCDCD nn
Sharp Interface Model
il
is kCC
LT)CC(mTT M
L0Merfaceint
Single Domain Eq.
)VD(tC
)V1(MC)4cos151(dT
0
o
Comparison with one-d Analytical Solution
Constant Ti, Ci
k = 0.1, Mc = 0.1, T0 = -.5, Le = 1.0
0
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
1.8
0 10 20 30 40x
C
T/T0k = 0.1MC0 = 0.1T0 = -0.5
Le = 1.0
Concentration and Temperatureat dimensionless time t =100
0
2
4
6
8
10
12
0 100 200 300
timeps
oitio
n
Front Movement
Effect of Lewis Number: small Le interface concentration close to C0
0Le
10Le
1Le
2.Le
k = 0.15, Mc = 0.1, T0 = -.65= 0.05, x =3.333d0
l
le DL
All predictions attime =6000
0
0.5
1
1.5
2
2.5
3
3.5
4
0 50 100 150 200 250 300 350 400 450 500
distance
Conc
entra
tion
k = 0.15, Mc = 0.1, T0 = -.55, Le = 20.0
= 0.02, x = 2.5d0
Concentration field at time = 30,000
,1,25.0
Profile along dashed line
Concentration
= 0.05, T0 = -0.65 time = 6000
= 0.25, = 0.75, x =4d0
FAST-CPUThis
On This
In 60 seconds !
Conclusion –Score card for Dendritic Growth Enthalpy Method (extension of original work by Tacke)
Ease of Coding ExcellentCPU Excellent (runs
shown here took between 1 and 2 hours on a regular PC)
Convergence to known analytical sol.
Excellent
Convergence to known operating state
Very Good (if grid is not too fine and remedial parameters well chozen
Grid Anisotropy Good (see comment above)
Alloy Promising
0
2
4
6
8
10
12
14
16
0 50 100 150 200 250
0
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.090.1
0 1000 2000 3000 4000 5000 6000
Dim. Time
Dim
. Tip
Vel
.
Playing Around
A Problem with Noise Multiple Grains-multiple orientations
Grains in A Flow Field
Thses calculations were performed by Andrew Kao, University of Greenwich, LondonUnder supervision of Prof Koulis Pericleous and Dr. Georgi Djambazov.
Can this work be related to other physical cases ?
Extensions:Grain Growth
Couple with porosity formation ?
100 mseconds
100 km
1000’s of years
e.g., shoreline in sedimentary basin
NCED’s purpose:to catalyze development of an integrated, predictive science of the processes shaping the surface of the Earth, in order to transform management of ecosystems, resources, and land use
The surface is the environment!
Research fields• Geomorphology• Hydrology• Sedimentary geology• Ecology• Civil engineering• Environmental economics• Biogeochemistry
Who we are: 19 Principal Investigators at 9 institutions across
the U.S.
Lead institution: University of Minnesota
Fans Toes Shoreline
Two Sedimentary Moving Boundary Problems of Interest
Moving Boundaries in Sediment Transport
1km
Examples of Sediment FansMoving Boundary
How does sediment-basement interfaceevolve
Badwater Deathvalley
sediment
h(x,t)
x = u(t)
0q
bed-rock
ocean
x
shoreline
x = s(t)
land surface
A Sedimentary Ocean Basin
An Ocean Basin
Melting vs. Shoreline movement
pressurizedwater reservoir
to water supply
solenoidvalve
stainless steelcone
to gravel recycling
transport surface
gravel basement
rubber membrane
experimental deposit
Experimental validation of shoreline boundary model
~3m
Base level
Measured and Numerical results ( calculated from 1st principles)
1-D finite difference deforming grid vs. experiment
xxt+Shoreline balance
Is there a connection
Grain Growth in Metal SolidificationFrom W.J. Boettinger
m
10km
“growth” of sediment delta into oceanGanges-Brahmaputra Delta