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AP Calculus BCTuesday, 08 September 2015
• OBJECTIVE TSW (1) study and use a formal definition of a limit.
• WS Practice with Limits is due Friday, 09/11/15.
• T-shirt money due today!!!
• Test on Chapter 2 is Friday.
Formal Limits and Limits at Infinity
A Formal Definition of Limit- Definition
Let f be a function defined on an open interval containing c (except possibly at c) and let L be a . The statement
means that for each > 0, a > 0 if
lim
x cf x L
0 , then .x c f x L
A real numberEpsilon
“There exists”Delta
“Such That”
Formal Limits and Limits at Infinity
A Formal Definition of Limit
Ex: Given that
Find such that
whenever
2
lim 5 4 6.x
x
5 4 6 0.01x
0 2 .x
5 4 6 0.01x
5 10 0.01x
5 2 0.01x
2 0.002x 0.002
Formal Limits and Limits at Infinity
A Formal Definition of Limit
Ex: Given that
Find such that
whenever
3
lim 3 2 11.x
x
3 2 11 0.01x
0 3 .x
3 2 11 0.01x
3 9 0.01x
3 3 0.01x
3 0.003x 0.003
Formal Limits and Limits at Infinity
Limits at infinity have many of the same properties of limits at specific values.
For example, if
lim and lim both exist, thenx x
f x g x
a lim lim lim)x x x
f x g x f x g x
b lim lim l) imx x x
f x g x f x g x
Similar properties hold for .
Formal Limits and Limits at Infinity
Ex: Find each limit:
2
3 5lim
5a)
2x
x
x
0
2 2
2
2 2
3 5
lim5 2x
xx xxx x
2
2
3 5
lim2
5x
x x
x
0 0
5 0
Divide numerator and denominator by the highest power of the variable.
2
2
1
1x
x
Apply “Limits at Infinity” theorem.
2
2
3 5lb i) m
5 2x
x
x
Formal Limits and Limits at Infinity
Ex: Find each limit:
3
5
2
2 2
2
2 2
3 5
lim5 2x
xx xxx x
2
2
53
lim2
5x
x
x
3 0
5 0
Ex: Find each limit:
Formal Limits and Limits at Infinity
3
2
3 5lc i) m
5 2x
x
x
DNE
3
3 3
2
3 3
3 5
lim5 2x
xx xxx x
3
3
53
lim5 2x
x
x x
3 0
0 0
Formal Limits and Limits at Infinity
How to find horizontal asymptotes:
1) Degree of Num. < Degree of Denom.HA: y = 0
2) Degree of Num. = Degree of Denom.HA:
3) Degree of Num. > Degree of Denom.HA: none
leading coefficient num.
leading coefficient denom.y
Formal Limits and Limits at Infinity
Ex: Find each limit:
2
5 3lim
7 2a)
x
x
x
2
5 3
lim7 2x
xx x
xx
2
2
35
lim7 2x
x
x
x
2
2 2
35
lim7 2x
x
x
x x
2
35
lim2
7x
x
x
5 0
7 0
5
7