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Arenes
Introduction
1. Hydrocarbon that contain rings which stabilised by electron delocalisation are called aromatic hydrocarbon or arenes
2. The simplest yet most important member of the aromatic hydrocarbons is benzene
Naming Aromatic Hydrocarbon
• Monosubstituted alkylbenzene is named as derivatives of benzene. For example:
CH3
methylbenzene(Toluene)
CH2CH3
ethylbenzene
OH
Phenol
COOH
Benzeoic acid
CHO
Benzaldehyde
NH2
Aniline(Phenylamine)
CH=CH2
Phenylethene(Styrene)
• The IUPAC system retains certain common names for some simpler alkylbenzenes. For example: Aniline, styrene, toluene.
• When two or more substituents on a benzene ring, three structural isomers are possible.a) Location of two substituents may be indicated by the
prefixs ortho, meta or para– 1,2 is equivalent to ortho, o-– 1,3 is equivalent to meta, m-– 1,4 is equivalent to para, p-
b) The order of decreasing priorities of common substituents is:COOH > SO3H> CHO> CN > C=O> OH> NH2> R> NO2> XWhere R= alkyl group ;
X= halogen
CH3
1,2-dimethylbenzeneo-xylene
CH3 OH
Phenol
COOH
Benzeoic acid
CH312
3
4
5
6
CH3
1,4-dimethylbenzenep-xylene
CH3
Br
CH3
Br
CH3
Br
1
2
34
5
6
2-bromomethylbenzeneo-bromotoluene
3-bromomethylbenzenem-bromotoluene
4-bromomethylbenzenep-bromotoluene
OH
NO2
OH
NO2
1
2
34
5
6
2-nitrophenolo-nitrophenol
4-nitrophenolp-nitrophenol
• When three or more groups are on the benzene ring, a numbering system must be used to locate them. For example,
CH3
NO2
NO2
1
2
3
45
6
CH3
Br
NO2
1
2
3
4
5
6
2,4-dinitromethylbenzene 2-bromo-4-nitrophenol
• In more complex molecules, the benzene ring is named as a substituent on a parent chain. In this case, the C6H5- group is called a phenyl group. For example
CH2CH CHCH3
1 2 3 4
1-phenylbut-2-ene
CHCH2CH2CH3
CH31
2 3 4 5
2-phenylpentane
Exercise
• Name the following aromatic compoundsCH2CH3 NO2 Cl CH3
Cl
CH3
NO2
CH3
O2N
NO2
COOH
H3C
COOH
HO
Reaction of benzene
1. Nitration• Nitration is the substitution of a nitro group, -
NO2, for one of the hydrogen atoms on the benzene ring
• Benzene reacts with a mixture of concentrated nitric acid and concentrated sulphuric acid
• The product is nitrobenzene, a pale yellow liquid
+ HNO3
NO2
concentrated H2SO4
<55oCrefulx
+ H2O
2. Halogenation– This reaction involves substitution of a halogen
atom for a hydrogen atom on the aromatic ring– In the presence of a catalyst or halogen carrier
such as aluminium chloride, AlCl3, benzene is substituted by chlorine or bromine at room temperature.
+ Cl2
AlCl3
room temp
Cl
+ HCl
• The catalyst aluminium chloride, AlCl3, an electron-deficient compound which has only six electrons in its outer shell, accepts a lone pair of electrons from one of the chlorine atoms, which induces polarisation in the chlorine molecule.
• The positively charged end of the chlorine molecule is now an electrophile and attacks the benzene ring.
Cl Cl -
AlCl3
3. Alkylation: Friedel-Crafts reaction• This reaction substitutes an alkyl group for a
hydrogen atom on an aromatic ring• When benzene is warmed with
chloromethane, CH3Cl and aluminium chloride (catalyst) under anhydrous conditions, a substitution reaction occurs and methylbenzene is formed
+ CH3Clanhydrous AlCl3
warm
CH3
+ HCl
– AlCl3 polarise the CH3 Cl molecule
– The positively charged methyl group attacks the benzene ring and electrophilic substitution occurs
AlCl3H3C Cl
AlCl3H3C Cl
CH3
+ + AlCl4-
CH3
CH3HCH3
+ H+
4. Acylation• Involves substitution of an acyl group, RCO,
for a hydrogen atom on the aromatic ring.• When benzene is added to ethanoyl chloride
and AlCl3, under anhydrous conditions, a substitution reaction occurs and phenylethanone is formed.
+ H3C C
O
Cl
AlCl3
heat
C
O
CH3
+ HCl
Exercise
• Write the structural formula for the producta formed from Friedal Crafts alkylation or acylation of benzene with
(a) CH3CH2CH2Cl
(b) CH3CH2CH2COCl
5. Sulphonation• Involves substitution of an –SO3H group for a
hydrogen atom on the aromatic ring.• If benzene and [H2SO4] are reflux together for
several hours, benzenesulphonic acid is formed:
+ concentrated H2SO4reflux SO3H
+ H2O
Benzenesulphonicacid
Reaction of methylbenzene
1. Reaction with chlorine• When chlorine, Cl2, is bubbled through
boiling methylbenzene in strong sunlight or uv light, substitution takes place on the methyl group:CH3 CH2Cl CHCl2 CCl3
Cl2, boil
uv light
• If Cl2 is bubbled through methylbenzene in the absence of uv light but in the presence of AlCl3, the ring is substitutes. A mixture of two isomers is obtained.
• White fumes of HCl are given off• Electron density of the benzene ring more strongly at the 2-
and 4- positionsCH3
+ Cl2AlCl3
room temperature
CH3
Cl
+ HCl
AlCl3
room temperature
CH3
Cl
+ HCl
2. Reaction with HNO3
• When methyl benzene is added to HNO3 and concentrated H2SO4, at room temperature, a mixture of 2- and 4-nitromethylbenzeneCH3
+ HNO3
H2 SO
4
room temperature
CH3
NO2
+ H2O
room temperature
CH3
NO2
+ H2O
H2SO4
• If the temperature is raised, two or three nitro groups, NO2 are introduced
CH3
NO2
NO2
CH3
NO2
NO2
O2N
2,4-diphenylmethylbenzene 2,4,6-triphenylmethylbenzene
3. Reaction with CH3I (Friedal craft alkylation)
• When methlbenzene is added to CH3I in AlCl3 at 20 oC, a mixture of 1,2-dimethylbenzene and 1,4-dimethylbenzene is formed
CH3
room temperature
CH3
CH3
CH3
CH3
AlCl3+ CH3I + HI
+ HI
4. Reaction with CH3COCl (FriedalCraft Acylation)
• The reaction of an acyl chloride with an aromatic hydrocarbon is known as FriedalCraft acylation.
• Involves substitution of an acyl group, RCO-, for a hydrogen atom on the aromatic ring in the presence of AlCl3.
CH3
AlCl3
80oC
CH3
C
CH3
AlCl3
80 oC
+ H3C C Cl
O
ethanoylchloride
O
CH3+ HCl
C
OCH3
+ HCl
Exercise
• Write the structural formula for the products formed by Friedal Crafts acylation or alkylation of methylbenzene with
(a)C6H5COCl
(b) CH3CH2Br
5. Reaction with SO3
• When methylbenzene is added to fuming H2SO4 containing SO3 at 0oC, a mixture of 2- and 4-methylbenzenesulphonic is obtained.CH3
+ SO3
H2SO4
0 oC
CH3
SO3H
CH3
SO3H
1
4
1
2
+ H+
+ H+
H2 SO
40 oC
2-methylbenzenesulphonic acid
4-methylbenzenesulphonic acid
6. Oxidation of alkylbenzene• Alkylbenzenes are oxidised to benzoic acid on
prolonged reflux with KMnO4 or K2Cr2O7
RKMnO4 / K2Cr2O7
COOH + H2O + CO2
• Example
CH3KMnO4 / K2Cr2O7
COOH + H2O+ 3 [O]
reflux
CH2CH3KMnO4 / K2Cr2O7
COOH + 2H2O + CO2+ 6 [O]reflux
Exercise
• Predict the products from treatment of each of the following compounds with KMnO4 / H2SO4 under reflux.CH3
CH3
CH3
CH3
CH2CH2CH3
CH3
(a) (b) (c)
Exercise
• Name compound P, Q, R and S belowCH3
NO2
CH3 CH3
Br
4-methylbenzenesulphonic acid
fumingH2SO4
P + Q
R
AlCl3
(S)
Exercise
• Draw the structural formulae of the organic products formed when methylbenzene reacts with
(a)Concentrated nitric acid and concentrated sulphuric acid at room temp
(b)Chlorine in the presence of anhydrous aluminium chloride
(c)Chloromethane in the presence of aluminium chloride