BUILDING STRUCTURE [ARC 2522]PROJECT 2: EXTENSION OF A R.C. BUNGALOW
CHOOSEN BUILDING: KAJANG BUNGALOW, JADE HILLS
LECTURER: MS. NORITA JOHAR
GROUP MEMBERS:
BENNY TAN SHIOWEE 0315447LEE YAUE SHEN 0315381NICOLAS WONG XIAO EN 0314377PRESTON LIEW RU PING 0313822TAN SHING YEOU 0314850WOO WEN JIAN 0315123YUAN KHAI SHIEN 0314818
TABLE OF CONTENT
1.0 Introduction to case study
2.0 Architectural Drawings
3.0 Structural Drawings
4.0 Load Distribution Table
5.0 Dead & Live Load Acting Table
6.0 Calculation
7.0 Conclusion
1.0 Introduction to case study
The case study we chose is a two and half storey bungalow. It is located in Jade Hill, Kajang. It is designed by Arkitek Juruperunding Suria Rahim Sdn. Bhd.
The built up area of a single unit of the bungalow is approximately 4400 sq. ft. Col-umns and beams are assembled in moment resisting frames which is a common prac-tice in residential design, in order to define the location of each columns in the build-ing, we have studied and analyzed the spaces through plans.
WET KITCHEN
CORR
IDO
R
TOIL
ET
MAID’SROOM
DRYKITCHEN
DINING AREA
CORRIDORCORRIDOR
TOILET
GUESTROOM
LIVINGAREA PRAYING
AREA
CAR PORCHCAR PORCH
WET KITCHEN A-C/7-8= 6000 / 4800 = 1.25 < 2 ( Two way slab)
TOILET D-E/8b-8= 3000 / 1500 = 2 = 2 ( Two way slab)
MAID’S ROOM E-G/7-8= 4800 / 3000 = 1.6 < 2 ( Two way slab)
DRY KITCHEN A-D/6-7= 6000 / 3900 = 1.54 < 2 ( Two way slab)
DINING AREA D-G/6-7= 4500 / 3900 = 1.15 < 2 ( Two way slab)
TOILET F-G/5a-5= 2400 / 1800 = 1.33 < 2 ( Two way slab)
GUEST ROOM E-G/3-4= 3000 / 1900 = 1.58 < 2 ( Two way slab)
LIVING AREA A-D/2-4= 6400 / 6000 = 1.07 < 2 ( Two way slab)
PRAYING AREA D-G/2-3= 4500 / 4500 = 1 < 2 ( Two way slab)
CAR PORCH A0-D/1-2= 9150 / 4200 = 2.18 > 2 ( One way slab)
4.0 LOAD DISTRIBUTION TABLE
BEDROOM B-C/7-8= 4800 / 2712 = 1.77 < 2 (Two way slab)
TOILET C-D/8a-8= 2700 / 1800 = 1.5 < 2 ( Two way slab)
CORRIDOR C-D/7-8a= 2100 / 1800 = 1.17 < 2 ( Two way slab)
BEDROOM D-G/7-8= 4800 / 4500 = 1.07 < 2 ( Two way slab)
STUDIO A-C/6-7= 4200 / 3900 = 1.08 < 2 ( Two way slab)
CORRIDOR C-D/6-7= 3900 / 1800 = 2.17 > 2 ( One way slab)
TOILET E1-G/6a-7= 2700 / 1800 = 1.5 < 2 ( Two way slab)
FAMILY AREA D-G/6-6a= 4500 / 2100 = 2.14 > 2 ( One way slab)
CORRIDOR B-D/5-6= 4512 / 1800 = 2.51 > 2 ( One way slab)
CORRIDOR D-G/5-6= 450 / 1800 = 2.5 > 2 ( One way slab)
CORRIDOR C-G/4-5= 6300 / 3500= 1.8 < 2 ( Two way slab)
5.0 QUANTITY DEAD LOADS ACTING ON STRUCTURE
GROUND FLOOR PLANSlab Thickness = 150 mmSlab self-weight = 0.15m x 24kN/m
= 3.6kN/m
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2
FIRST FLOOR PLANSlab Thickness = 150 mmSlab self-weight = 0.15m x 24kN/m
= 3.6kN/m
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2
SECOND FLOOR PLANSlab Thickness = 150 mmSlab self-weight = 0.15m x 24kN/m
= 3.6kN/m
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2
ROOF PLANSlab Thickness = 150 mmSlab self-weight = 0.15m x 24kN/m
= 3.6kN/m
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BRICK WALL= wall height x thickness x density= 3.1m x 0.15m x 19kN/m= 8.84kN/m
BEAM SELF WEIGHT(Beam Size 125mm x 450mm)= Beam size x Concrete density= 0.125m x 0.45m x 24kN/m= 1.35kN/m
COLUMN SELF WEIGHT(Column Size 125mm x 300mm)= Beam size x Height x Concrete density= 0.125m x 0.3m x 3.1m x 24kN/m= 2.79kN
3
(Column Size 450mm x 450mm)= Beam size x Height x Concrete density= 0.45m x 0.45m x 3.1m x 24kN/m= 15.066kN
QUANTITY LIVE LOADS ACTING ON STRUCTURE
GROUND FLOOR PLANKITCHEN BATHROOM BEDROOM CORRIDOR DINING AREA STORE LIVING AREA PRAYING AREACAR POACHSTAIRWELL
= 3.0 kN/m= 2.0 kN/m= 1.5 kN/m= 2.0 kN/m= 2.0 kN/m= 3.0 kN/m= 4.0 kN/m= 2.0 kN/m= 2.5 kN/m= 2.0 kN/m
SECOND FLOOR PLANBATHROOM BEDROOM CORRIDOR DRESSING AREA STUDIO FAMILY AREASTUDY AREAROOFSTAIRWELL
= 2.0 kN/m= 1.5 kN/m= 2.0 kN/m= 2.0 kN/m= 2.0 kN/m= 4.0 kN/m= 2.0 kN/m= 0.5 kN/m= 2.0 kN/m
THIRD FLOOR PLANBATHROOM CORRIDOR STAIRWELL ENTERTAINMENT AREA LOUNGE
(According to 4 schedule of UBBL for live load according to the function of the space)
= 2.0 kN/m= 2.0 kN/m= 2.0 kN/m= 4.0 kN/m= 2.0 kN/m
th
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7.0 Conclusion
Throughout this project, we learnt about structural theory and basic structural pro-posal. We learnt about the load path in slab ( one way and two way slabs). We are now understand the concept of structural analysis which needed to identify the structural components.
We learnt how load is sitting on beams on columns. By calculating load transferred to beams and loads, we clearly understand the basic requirement such as thickness needed for a column or beam while designing a building. This is helpful as it is important for us in our future study.