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Bab 4 Goodtest

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    4Pengumpulandan pengolahan data

    4.1 Pengumpulan data

    4.1.1 Data poisson dan eksponensial

    Tabel 4.1.1Data poisson dan eksponensial

    N

    o

    Data Haidar Data Kahfi

    Poisson Eksponensial Poisson Eksponensial

    1 0.00 0.88 0.00 1.43

    2 0.00 0.92 0.00 2.12

    3 0.00 0.93 0.00 2.52

    4 0.00 0.98 0.00 2.855 0.00 1.00 0.00 3.12

    6 0.00 1.02 0.00 3.63

    7 0.00 1.02 0.00 3.97

    8 0.00 1.02 0.00 4.08

    9 0.00 1.05 0.00 4.13

    10 0.00 1.08 0.00 4.25

    11 0.00 1.10 0.00 4.47

    12 0.00 1.13 0.00 4.75

    13 0.00 1.18 0.00 5.02

    14 1.00 1.18 0.00 5.03

    15 1.00 1.22 0.00 5.03

    16 1.00 1.22 0.00 5.05

    17 1.00 1.33 0.00 5.08

    18 1.00 1.53 0.00 5.18

    19 1.00 1.58 1.00 5.20

    20 1.00 1.62 1.00 5.52

    21 1.00 1.63 1.00 5.82

    22 1.00 1.63 1.00 6.28

    23 1.00 1.70 1.00 6.5024 1.00 1.73 1.00 6.80

    25 1.00 1.78 1.00 6.92

    26 1.00 1.80 1.00 6.97

    27 2.00 1.85 1.00 7.05

    28 2.00 1.87 1.00 7.10

    29 2.00 1.97 1.00 7.17

    30 2.00 1.98 1.00 7.25

    Tabel 4.1.1Data poisson dan eksponensial (lanjutan)

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    N

    o

    Data Haidar Data Kahfi

    Poisson Eksponensial Poisson Eksponensial

    31 2.00 2.38 2.00 7.47

    32 2.00 2.57 2.00 7.82

    33 2.00 2.62 2.00 7.85

    34 2.00 3.08 2.00 8.02

    35 2.00 3.25 2.00 10.83

    4.2 Pengolahan data

    4.2.1 Uji chi-square

    4.2.1.1Ujichi-square satu sampel diskit (poisson !aida) n"#$

    a) Uji hipotesis

    H0= sampel mengikuti disti!usi poisson

    H1= sampel tidak mengikuti disti!usi poisson

    b) "iteia penolakan

    H0ditolak jika #2hit$ #

    2% & '( dimana v=kp1=311=1 )4.1*

    % = 1+ = #2% & ' = #20.01 & 1 = 6.635

    % = 5+ = #2% & '= #20.05 & 1 = 3.841

    % = 10+ = #2% & ' = #20.1 & 1 = 2.710

    c) Uji statistik

    Tabel 4.1.2Distibusi %ekuensi satu sampel diskit

    xi Oi = Fi Fi.xi

    0 13 0

    1 13 13

    2 9 18

    3 3!

    1* ,ata-ata

    =Fi.x i

    Fi )4.2*

    =31

    35=0.89

    imana& / adalah ata-ata pesentase sukses

    adalah jumlah pesentase sukses

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    # adalah pengamatan

    2* o!a!ilitas poisson

    P ( , x )=e

    x

    X !

    )4.3*

    P (0.89,0 )=2.718280.86

    0.890

    0 ! = 0.411

    P (0.89 ,1 )=2.71828

    0.860.89

    0

    1! = 0.365

    P (0.89 ,2 )= 2.718280.86

    0.892

    2!

    = 0.163

    imana& adalah po!a!litas

    / adalah ata-ata pesentase sukses

    e adalah epsilon, nilaina adalah 2.71828

    adalah !anakna sukses dalam sampel ukuan n

    3* ekuensi haapan

    Ei=n P )4.4*

    Ei(0)=350.411=14.385

    Ei(1)=350.365=12.775

    Ei(2)=350.163=5.705

    imana& i adalah ekuensi haapan

    adalah po!a!litas

    n adalah !anakna sampel

    4* hi-square hitung

    OiEi2

    X(xi )2 =

    )4.5*

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    1314.3852

    X(0)2 =

    1312.7752

    X(1)2 =

    95.7052

    X(2)2 =

    imana& #2adalah hi-square hitungi adalah ekuensi haapan

    i adalah ekuensi

    Tabel 4.4.#Distibusi %ekuensi chi-square satu sampel diskit

    K xi Oi = Fi Pi Ei "#

    1 0 13 0.411 14.385 0.133

    2 1 13 0.365 12.775 0.004

    3 2 9 0.163 5.705 1.903

    #2hit 2.04

    d) :nalisis pe!andingan

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    &amba 4.4.1'ua pebandingan uji chi-square satu sampel diskit

    e) "esimpulan

    % = 1+ H0diteima( sampel mengikuti disti!usi poisson.

    % = 5+ H0diteima( sampel mengikuti disti!usi poisson.

    % = 10+ H0diteima( sampel mengikuti disti!usi poisson.

    4.2.1.2 Ujichi-square dua sampel diskit (poisson !aida dan poisson 'ah%i) n"*

    a) Uji hipotesis

    H0= sampel mengikuti disti!usi poisson

    H1= sampel tidak mengikuti disti!usi poisson

    b) "iteia penolakan

    H0ditolak jika #2hit$ #

    2% & '

    dimana v=(R1)(kp1)=(21)(311)=1 )4.6*

    % = 1+ = #2% & ' = #20.01 & 2 = 6.635

    % = 5+ = #2% & '= #20.05 & 2 = 3.841

    % = 10+ = #2% & ' = #20.1 & 2 = 2.710

    c) Uji statistik

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    Tabel 4.1.4Distibusi %ekuensi satu sampel diskit

    Data Haidar Data Kahfi

    xi Oi = Fi "i Oi = Fi

    0 13 0 18

    1 13 1 12

    2 9 2 5

    3 3

    1* ekuensi haapan

    Ei=(Oi1+Oi2 ) n1

    n1+n2

    )4.7*

    Ei(0)=(13+18 )3535+35

    =15.5

    Ei(1)=(13+12 )3535+35

    =12.5

    Ei(2)=(9+5 )3535+35

    =7

    imana& i adalah ekuensi haapani1 adalah ekuensi sampel ep ;aepul ,

    i2 adalah ekuensi sampel :

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    1312.52

    X(2)2 =

    972

    X(3)2 =

    imana& #2adalah hi-square hitung

    i adalah ekuensi haapan

    i adalah ekuensi

    3* hi-square hitung "ahi

    OiEi2

    X(xi )2 =

    )4.9*

    1815.52

    X(1)2 =

    1212.52

    X(2)2

    =

    572

    X(3)2 =

    imana& #2adalah hi-square hitung

    i adalah ekuensi haapan

    i adalah ekuensi

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    min adalah nilai paling endah atau minimum

    2* ?umlah kelas

    Jk=1+3.3 logn )4.11*

    Jk=1+3.3 log35 = 6.10

    imana& ?k adalah jumlah atau jangkauan kelas

    n adalah jumlah data

    3* Interval

    I=R

    Jk)4.12*

    I=R

    Jk=

    2.37

    6 =0.40

    imana&Iadalah interval

    Tabel 2.4.1#Distibusi %ekuensi eksponensial

    Interval Fi $%& '%& %( fi.%(

    0.88 > 1.22 16 0.875 1.275 1.075 17.200

    1.28 > 1.67 6 1.275 1.675 1.475 8.850

    1.68 > 2.07 8 1.675 2.075 1.875 15.000

    2.08 > 2.47 1 2.075 2.475 2.275 2.275

    2.48 > 2.87 2 2.475 2.875 2.675 5.350

    2.88 > 3.27 2 2.875 3.275 3.075 6.150

    3 .*#

    4* @enentukan ata-ata

    =X=fi.cm

    fi )4.13*

    =X=54.825

    35 = 1.566

    imana& adalah ata-ata

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    5* @enentukan po!a!ilitas AB

    P1= P(LCB) =1e

    (LCB ) )4.14*

    P1(1) =12.71828

    (0.8751.566)= 0.428

    P1(2) =12.71828

    (1.2751.566)= 0.557

    P1(3) =12.71828

    (1.6751.566)= 0.657

    P1(4) =12.71828

    (2.0751.566)= 0.734

    P1(5) =12.71828

    (2.4751.566)= 0.794

    P1(6) =12.71828

    (2.8751.566)= 0.840

    6* @enentukan po!a!ilitas UB

    P2= P(UCB) =1e

    (UCB ) )4.15*

    P1(2) = 12.71828(1.2751.566)= 0.557

    P1(3) =12.71828

    (1.6751.566)= 0.657

    P1(4) =12.71828

    (2.0751.566)= 0.734

    P1(5) =12.71828

    (2.4751.566)= 0.794

    P1(5) = 12.71828(2.875

    1.566

    )= 0.840P1(6) =

    12.71828(3.2751.566)= 0.876

    7) Menentukan Probabiita!

    P = P2" P1 )4.16*

    P(1)= 0.557 " 0.428 = 0.129

    P(2)= 0.657 " 0.557 = 0.100

    P(3)= 0.734 " 0.657 = 0.077

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    P(4) = 0.794 " 0.734 = 0.060

    P(5)= 0.840 " 0.794 = 0.046

    P(6)= 0.876 " 0.840 = 0.036

    imana& adalah adalah po!a!litas

    ABadalah po!a!ilitas pada tiap kelas AB

    UBadalah po!a!ilitas pada tiap kelas UBe adalah epsilon( nilaina adalah 2.17828

    C adalah ata-ata

    8* @enentukan ekuensi haapan

    Eixi=n p )4.17*

    Ei1=350.129=4.515

    Ei2=350.100=3.500

    Ei3=350.077=2.695

    Ei4=350.060=2.100

    Ei5=350.046=1.610

    Ei6=350.036=1.260

    imana& i adalah ekuensi haapan

    n adalah !anakna sampel

    p adalah po!a!ilitas

    9* @enentukan hi-squarehitung

    OiEi2

    X(xi )2 =

    )4.18*

    164.5152

    X(1 )

    2 =

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    63.5002

    X(2)2 =

    82.6952

    X(3)2 =

    12.1002

    X(4)2 =

    21.6102

    X(5)2 =

    21.2602

    X(6)2 =

    imana& #2adalah hi-square hitung

    i adalah ekuensi haapan

    i adalah ekuensi

    Table 4.4.Distibusi %ekuensi chi-squaresatu sampel kontin+u

    K $%& '%& Oi = Fi P! P# Pi Ei "#

    10.875 1.275 16 0.428 0.557 0.129 4.515 29.215

    1.275 1.675 6 0.557 0.657 0.100 3.500 1.786

    2

    1.675 2.075 8 0.657 0.734 0.077 2.695 10.443

    2.075 2.475 1 0.734 0.794 0.060 2.100 0.576

    2.475 2.875 2 0.794 0.840 0.046 1.610 0.094

    3 2.875 3.275 2 0.840 0.876 0.036 1.260 0.435

    "#hit #.

    * "iteia penolakan

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    H0ditolak jika #2hit$ #

    2% & '( dimana v=kp1=311=1 )4.19*

    % = 1+ = #2% & ' = #20.01 & 1 = 6.635

    % = 5+ = #2% & '= #20.05 & 1 = 3.841

    % = 10+ = #2% & ' = #20.1 & 1= 2.710

    d* :nalisis pe!andingan

    &amba 4.4.#'ua pebandingan uji chi-square satu sampel kontin+ue* "esimpulan

    % = 1+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.

    % = 5+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.

    % = 10+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.

    4.2.1.4 Uji chi-square dua sampel kontin+u (eksponensial !aida daneksponensial 'ah%i) n"*

    a) Uji hipotesis

    H0= kedua sampel mengikuti disti!usi eksponensial

    H1= kedua sampel tidak mengikuti disti!usi eksponensial

    !* Uji ;tatistik

    1) Range

    Range= max min )4.20*

    Range= 10.83 > 0.88 = 9.95

    imana& Range),* adalah jaak

    maxadalah nilai paling tinggi atau maksimum

    min adalah nilai paling endah atau minimum

    2* ?umlah kelas

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    Jk=1+3.3 logn )4.21*

    Jk=1+3.3 log70 = 7.09 D 6

    imana& ?k adalah jumlah atau jangkauan kelas

    n adalah jumlah data

    3* Interval

    I=R

    Jk)4.22*

    I=R

    Jk=

    9.95

    6 =1.66

    imana&Iadalah interval

    Tabel 4.4.,Distibusi %ekuensi dua sampel kontin+u

    +nter,al Fi sa-pel Haidar Fi sa-pel Kahfi 0.88 > 2.53 31 3

    2.54 > 4.19 4 6

    4.20 > 5.85 0 12

    5.86 > 7.51 0 10

    7.52 > 9.17 0 3

    9.18 > 10.83 0 1

    3 3

    4* @enentukan ekuensi haapan

    Ei=(Oi1+Oi2)n1

    n1+n2

    )4.23*

    Ei1=(31+3 )3535+35

    =17

    Ei2=(4+6 )3535+35

    =5

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    Ei3=(0+12 )3535+35

    =6

    Ei4

    =(0+10)35

    35+35 =5

    Ei5=(0+3 )3535+35

    =1.5

    Ei6=(0+1)3535+35

    =0.5

    imana& i adalah ekuensi haapani1 adalah ekuensi sampel Haida

    i2 adalah ekuensi sampel "ahi

    5* @enentukan hi-square hitung Haida

    OiEi2

    X(xi )2 =

    )4.24*

    3117

    2

    X1 (1)2 =

    452

    X1 (2)2 =

    062

    X1 (3 )2 =

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    052

    X1 (4)2 =

    01.52

    X1 (5 )2 =

    00.52

    X1 (6 )2 =

    imana& #2adalah hi-square hitung

    i adalah ekuensi haapan

    i adalah ekuensi

    6* @enentukan hi-square hitung "ahi

    OiEi

    2

    X(xi )2 =

    )4.25*

    3172

    X1 (1)2 =

    652

    X1 (2)2 =

    1262

    X1 (3 )2

    =

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    1052

    X1 (4)

    2 =

    31.52

    X1 (5 )2 =

    10.52

    X1 (6 )2 =

    imana& #2adalah hi-square hitung

    i adalah ekuensi haapan

    i adalah ekuensi

    Tabel 4.4.Distibusi %ekuensi chi-squaredua sampel kontin+u

    "! "# "3 " " " "#hit

    N

    !

    31

    17

    4 5 0 6 0 5 0 1.5 00.50

    24.73

    11.53 0.20 6.00 5.00 1.50 0.30

    N

    #

    31

    76 5

    1

    26

    1

    05 3 1.5 1

    0.5

    0

    24.73

    11.53 0.20 6.00 5.00 1.50 0.30

    /.

    * "iteia penolakan

    H0ditolak jika #2hit$ #2% & '

    dimana v=(R1)(kp1)=(21)(611)=4 )4.26*

    % = 1+ = #2% & ' = #20.01 & 4 = 13.28

    % = 5+ = #2% & '= #20.05 & 4 = 9.49

    % = 10+ = #2% & ' = #20.1 & 4 = 7.28

    d* :nalisis pe!andingan

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    &amba 4.4.4'ua pebandingan chi-squaredua sampel kontin+u

    e* "esimpulan

    % = 1+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.

    % = 5+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.

    % = 10+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.

    4.2.2 Uji kolmogorov-smirnov

    4.2.2.1 Uji kolmogorov-smirnov satu sampel diskit (poisson !aida) n"#$

    a) Uji hipotesis

    H0= sampel mengikuti disti!usi poisson

    H1= sampel tidak mengikuti disti!usi poisson

    b) "iteia penolakan

    H0ditolak jika nhit$ n % & n

    % = 1+ = n % & n = n 0.01 & 35 = 0.27

    % = 5+ = n % & n= n 0.05 & 35 = 0.23

    % = 10+ = n % & n = n 0.1 & 35 = 0.21

    c) Uji statistik

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    1* ,ata-ata

    =Fi.x i

    Fi )4.27*

    =31

    35=0.89

    imana& / adalah ata-ata pesentase sukses

    adalah jumlah pesentase sukses

    # adalah pengamatan

    2* o!a!ilitas poisson

    Fe=P ( , x )= e x

    X !)4.28*

    P (0.89,0 )=2.71828

    0.860.89

    0

    0 ! = 0.411

    P (0.89 ,1 )=2.71828

    0.860.89

    0

    1! = 0.365

    P (0.89 ,2 )=2.71828

    0.860.89

    2

    2! = 0.163

    imana& adalah po!a!litas

    / adalah ata-ata pesentase sukses

    e adalah epsilon, nilaina adalah 2.71828

    adalah !anakna sukses dalam sampel ukuan n

    3* ekuensi kumulati elati

    Fo=Fkr= Fk Fi

    )4.29*

    Fkr(0)=13

    35=0.37 1

    Fkr(1)=26

    35=0.743

    Fkr(3)=35

    35

    =1 .000

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    imana& k adalah ekuensi kumulati elati

    k adalah ekuensi kumulati

    i adalah ekuensi

    4* n mahitung

    n=|FeFo| )4.30*

    n0=|0.4110.371|=0.040

    n1=|0.3650.743|=0.378

    n2=|0.1631.000|=0.837

    imana& n adalahKolmogorov smirnov hitunge adalah po!a!ilitas

    o adalah ekuensi kumulati elati'e

    Tabel 4.4.1*Distibusi %ekeunsi Kolmogorov-smirnov satu sampel diskit

    xi Fi Fk Fi.xi Fo = Fkr Fe = P Dn

    0 13 13 0 0.371 0.411 0.040

    1 13 26 13 0.743 0.365 0.378

    2 9 35 18 1.000 0.163 0.837 35 31

    n ma = 0.837

    d* :nalisis pe!andingan

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    &amba 4.4.$'ua pebandingan uji Kolmogorov-smirnov satu sampeldiskit

    e* "esimpulan

    % = 1+ H0ditolak( sampel tidak mengikuti disti!usi poisson.

    % = 5+ H0ditolak( sampel tidak mengikuti disti!usi poisson.

    % = 10+ H0ditolak( sampel tidak mengikuti disti!usi poisson.

    4.2.2.2 Uji kolmogorov-smirnov dua sampel diskit (poisson !aida danPoisson 'ah%i) n"*

    a) Uji hipotesis

    H0= sampel mengikuti disti!usi poisson

    H1= sampel tidak mengikuti disti!usi poisson

    !* "iteia penolakan

    H0ditolak jika nhit$ n % & n

    % = 1+ = n % & n = n 0.01 & 70 = 0.19

    % = 5+ = n % & n= n 0.05 & 70 = 0.16

    % = 10+ = n % & n = n 0.1 & 70 = 0.15

    * Uji ;tatistik

    1* ekuensi kumulati elati'e Haida

    Fo=Fkr= Fk

    Fi

    )4.31*

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    Fkr(0)=13

    35=0.371

    Fkr(1)=2635=0.743

    Fkr(2)=35

    35=1

    imana& k adalah ekuensi kumulati elati

    k adalah ekuensi kumulati

    i adalah ekuensi

    2* ekuensi kumulati elati'e "ahi

    Fo=Fkr= Fk

    Fi

    )4.32*

    Fkr(0)=18

    35=0.514

    Fkr(1)=30

    35=0.857

    Fkr(2)=3535=1 .000

    imana& k adalah ekuensi kumulati elati

    k adalah ekuensi kumulati

    i adalah ekuensi

    3* n hitung

    n=|Fo1Fo2| )4.33*

    n0=|0.3710.514|=0.143

    n1=|0.7430.857|=0.20

    n2=|11|=0

    Tabel 4.4.11Distibusi %ekuensi uji Kolmogorov-smirnov dua sampeldiskit

    xiFi Fk Fkr = Fo Dn

    n! n# n! n# n! n#

    0 13 18 13 18 0.371 0.514 0.143

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    1 13 12 26 30 0.743 0.857 0.114

    2 9 5 35 35 1.000 1.000 0.000

    3 3

    n ma = 0.143

    d* :nalisis pe!andingan

    &amba 4.4.'ua pebandingan uji Kolmogorov-smirnov dua sampel diskit

    e* "esimpulan

    % = 1+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.

    % = 5+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.

    % = 10+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.

    4.2.2.# Uji kolmogorov-smirnov satu sampel kontin+u

    a) Uji hipotesis

    H0= sampel mengikuti disti!usi eksponensial

    H1= sampel tidak mengikuti disti!usi eksponensialb) "iteia penolakan

    H0ditolak jika nhit$ n % & n

    % = 1+ = n % & n = n 0.01 & 35 = 0.27

    % = 5+ = n % & n= n 0.05 & 35 = 0.23

    % = 10+ = n % & n = n 0.1 & 35 = 0.21

    c) Uji statistik

    Tabel 4.4.12Distibusi %ekuensi Kolmogorov-smirnov satu sampel kontin+u

    xi Fi Fk fi.xi fkr p Dn -ax

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    0.88 1 1 0.88 0.03 0.43 0.40

    0.92 1 2 0.92 0.06 0.44 0.38

    0.93 1 3 0.93 0.09 0.45 0.36

    0.98 1 4 0.98 0.11 0.46 0.35

    1.00 1 5 1.00 0.14 0.47 0.331.02 3 8 3.06 0.23 0.86 0.63

    1.05 1 9 1.05 0.26 0.49 0.23

    1.08 1 10 1.08 0.29 0.50 0.21

    1.10 1 11 1.10 0.31 0.50 0.19

    1.13 1 12 1.13 0.34 0.51 0.17

    1.18 2 14 2.36 0.40 0.78 0.38

    1.22 2 16 2.44 0.46 0.79 0.33

    1.33 1 17 1.33 0.49 0.57 0.08

    1.53 1 18 1.53 0.51 0.62 0.11

    1.58 1 19 1.58 0.54 0.63 0.09

    1.62 1 20 1.62 0.57 0.63 0.07

    1.63 2 22 3.26 0.63 0.87 0.241.70 1 23 1.70 0.66 0.66 0.00

    1.73 1 24 1.73 0.69 0.67 0.02

    1.78 1 25 1.78 0.71 0.68 0.03

    1.80 1 26 1.80 0.74 0.68 0.06

    1.85 1 27 1.85 0.77 0.69 0.08

    1.87 1 28 1.87 0.80 0.70 0.10

    1.97 1 29 1.97 0.83 0.71 0.12

    1.98 1 30 1.98 0.86 0.72 0.14

    2.38 1 31 2.38 0.89 0.78 0.11

    2.57 1 32 2.57 0.91 0.80 0.11

    2.62 1 33 2.62 0.94 0.81 0.13

    3.08 1 34 3.08 0.97 0.86 0.11

    3.25 1 35 3.25 1.00 0.87 0.13

    n ma = 0.495

    !) @enentukan ata-ata

    =X= f i . x i

    fi

    )4.34*

    =X=54.8335

    = 1.57

    imana& adalah ata-ata

    #) @enentukan ekuensi elati'e

    Fo=Fkr= Fk

    Fi

    )4.35*

    Fkr (0.88 )=1

    35=0.03

    Fkr (1.53 )=19

    35=0.54

    Fkr (1.58 )=20

    35=0.57

    Fkr (1.62 )=22

    35=0.63

    Fkr (1.63 )=22

    35=0.63

    Fkr (1.70 )=23

    35=0.66

    Fkr (1.73 )=24

    35=0.69

    Fkr (1.78)=2535

    =0.71

    Fkr (1.80 )=26

    35

    =0.74

    Fkr (1.85 )=27

    35=0.77

    Fkr (1.87 )=28

    35=0.80

    Fkr (1.97 )=29

    35=0.83

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    Fkr (0.92 )=2

    35=0.06

    Fkr (0.93 )=3

    35=0.09

    Fkr (0.98 )= 435

    =0.11

    Fkr (1.00 )=5

    35=0.14

    Fkr (1.02 )= 8

    35=0.23

    Fkr (1.02 )= 9

    35=0.26

    Fkr (1.05 )=10

    35=0.29

    Fkr (1.08 )=11

    35=0.31

    Fkr (1.10 )=12

    35=0.34

    Fkr (1.13 )=14

    35=0.40

    Fkr (1.18 )=16

    35=0.46

    Fkr (1.22 )=17

    35=0.49

    Fkr (1.33 )=17

    35=0.49

    Fkr (1.43 )=18

    35=0.51

    imana& k adalah ekuensi kumulati elati

    k adalah ekuensi kumulati

    i adalah ekuensi

    3) @enentukan po!a!ilitas

    P(#i) = 1e(xi) )4.36*

    P(0.88)=12.71828

    (0.881.57) = 0.03 P(1.62)=12.71828

    ( 1.621.57 ) =0.57

    P(0.92)=12.71828

    (0.921.57) = 0.06 P(1.63)=12.71828

    ( 1.631.57 ) =0.63

    P(0.93)=12.71828

    (0.931.57) = 0.09 P(1.70)=12.71828

    ( 1.701.57 ) =0.66

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    P(0.98)=12.71828

    (0.981.57) = 0.11 P(1.73)=12.71828

    ( 1.731.57 ) =0.69

    P(1.00)=12.71828(

    1.001.57 ) = 0.14 P(1.78)=

    12.71828(1.781.57 ) = 0.71

    P(1.02)=12.71828

    ( 1.021.57 ) = 0.23 P(1.80)=

    12.71828(1.801.57 ) = 0.74

    P(1.05)=12.71828

    ( 1.051.57 ) = 0.26 P(1.85)=

    12.71828(1.851.57 ) = 0.77

    P(1.08)=12.71828

    ( 1.081.57 ) = 0.29 P(1.87)=

    12.71828(1.871.57 ) = 0.80

    P(1.10)=12.71828

    ( 1.101.57 ) = 0.31 P(1.97)=

    12.71828(1.971.57 ) = 0.83

    P(1.13)=12.71828

    ( 1.131.57 ) = 0.34 P(1.98)=

    12.71828(1.981.57 ) = 0.86

    P(1.18)=12.71828

    ( 1.181.57 ) = 0.40 P(2.38)=

    12.71828(2.381.57 ) = 0.89

    P(1.22)=

    12.71828( 1.221.57 ) = 0.46 P(2.57)=

    12.71828(2.571.57 ) = 0.91

    P(1.33)=12.71828

    ( 1.331.57 ) = 0.49 P(2.62)=

    12.71828(2.621.57 ) = 0.94

    P(1.53)=12.71828

    ( 1.531.57 ) = 0.51 P(3.08)=

    12.71828(3.081.57 ) = 0.97

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    P(1.58)=12.71828

    ( 1.581.57 ) = 0.54 P(3.25)=

    12.71828(3.251.57 ) = 1.00

    ) n hitung

    n=|FeFo| )4.37*

    Dn (0.88 )=|0.43-0.03|=0.40Dn (0.92 )=|0.44-0.06|=0.38Dn (0.93 )=|0.45-0.09|=0.36

    Dn (0.98)=|0.46-0.11|=0.35Dn (1.00 )=|0.47-0.14|=0.33Dn (3.06)=|0.86-0.23|=0.63Dn (1.05 )=|0.49-0.26|=0.23Dn (1.08)=|0.50-0.29|=0.21Dn (1.10 )=|0.50-0.31|=0.19Dn (1.13 )=|0.50-0.34|=0.17Dn (2.36 )=|0.51-0.40|=0.38Dn (2.44 )=|0.78-0.46|=0.33Dn (1.33 )=|0.79-0.49|=0.08

    Dn (1.53 )=|0.57-0.51|=0.11Dn (1.58 )=|0.62-0.54|=0.09Dn (1.62 )=|0.63-0.57|=0.07Dn (3.26 )=|0.64-0.63|=0.24

    imana& n adalahKolmogorov smirnov hitunge adalah po!a!ilitas

    o adalah ekuensi kumulati elati'e

    d) :nalisis pe!andingan

    n (1.70 )=|0.870.66|=0.00n (1.73)=|0.660.69|=0.02n (1.78 )=|0.670.71|=0.03

    n (1.80 )=|0.680.74|=0.06n (1.85 )=|0.680.77|=0.08n (1.87 )=|0.690.80|=0.10n (1.97 )=|0.700.83|=0.12n (1.98 )=|0.710.86|=0.14n (2.38 )=|0.720.89|=011n (2.57 )=|0.780.91|=0.11n (2.62 )=|0.800.94|=0.13n (3.08 )=|0.810.97|=0.11n (3.25 )=|0.861.00|=0.13

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    x ifi Fk Fkr=Fo

    Dnn1 n2 n1 n2 n1 n2

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    0.88 0 1 0 1 0 0.03 0.03

    0.92 0 1 0 2 0 0.06 0.06

    0.93 0 1 0 3 0 0.09 0.09

    0.98 0 1 0 4 0 0.11 0.11

    1 0 1 0 5 0 0.14 0.14

    1.02 0 3 0 8 0 0.23 0.23

    1.05 0 1 0 9 0 0.26 0.26

    1.08 0 1 0 10 0 0.29 0.29

    1.1 0 1 0 11 0 0.31 0.31

    1.13 0 1 0 12 0 0.34 0.34

    1.18 0 2 0 14 0 0.40 0.40

    1.22 0 2 0 16 0 0.46 0.46

    1.33 0 1 0 17 0 0.49 0.49

    1.43 1 0 1 17 0.03 0.49 0.46

    1.53 0 1 1 18 0.03 0.51 0.49

    1.58 0 1 1 19 0.03 0.54 0.51

    1.62 0 1 1 20 0.03 0.57 0.54

    1.63 0 2 1 22 0.03 0.63 0.60

    1.7 0 1 1 23 0.03 0.66 0.63

    1.73 0 1 1 24 0.03 0.69 0.66

    1.78 0 1 1 25 0.03 0.71 0.69

    1.8 0 1 1 26 0.03 0.74 0.71

    1.85 0 1 1 27 0.03 0.77 0.74

    1.87 0 1 1 28 0.03 0.80 0.77

    1.97 0 1 1 29 0.03 0.83 0.80

    1.98 0 1 1 30 0.03 0.86 0.83

    2.12 1 0 2 30 0.06 0.86 0.80

    2.38 0 1 2 31 0.06 0.89 0.83

    2.52 1 0 3 31 0.09 0.89 0.80

    2.57 0 1 3 32 0.09 0.91 0.83

    2.62 0 1 3 33 0.09 0.94 0.86

    2.85 1 0 4 33 0.11 0.94 0.83

    3.08 0 1 4 34 0.11 0.97 0.86

    3.12 1 0 5 34 0.14 0.97 0.83

    3.25 0 1 5 35 0.14 1.00 0.86

    3.63 1 0 6 35 0.17 1.00 0.83

    3.97 1 0 7 35 0.20 1.00 0.80

    4.08 1 0 8 35 0.23 1.00 0.77

    4.13 1 0 9 35 0.26 1.00 0.74

    4.25 1 0 10 35 0.29 1.00 0.71

    4.47 1 0 11 35 0.31 1.00 0.69

    4.75 1 0 12 35 0.34 1.00 0.66

    5.02 1 0 13 35 0.37 1.00 0.63

    5.03 2 0 15 35 0.43 1.00 0.57

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    5.05 1 0 16 35 0.46 1.00 0.54

    5.08 1 0 17 35 0.49 1.00 0.51

    5.18 1 0 18 35 0.51 1.00 0.49

    5.20 1 0 19 35 0.54 1.00 0.46

    5.52 1 0 20 35 0.57 1.00 0.43

    5.82 1 0 21 35 0.60 1.00 0.40

    6.28 1 0 22 35 0.63 1.00 0.37

    6.50 1 0 23 35 0.66 1.00 0.34

    6.80 1 0 24 35 0.69 1.00 0.31

    6.92 1 0 25 35 0.71 1.00 0.29

    6.97 1 0 26 35 0.74 1.00 0.26

    7.05 1 0 27 35 0.77 1.00 0.23

    7.10 1 0 28 35 0.80 1.00 0.20

    7.17 1 0 29 35 0.83 1.00 0.17

    7.25 1 0 30 35 0.86 1.00 0.14

    7.47 1 0 31 35 0.89 1.00 0.11

    7.82 1 0 32 35 0.91 1.00 0.09

    7.85 1 0 33 35 0.94 1.00 0.06

    8.02 1 0 34 35 0.97 1.00 0.03

    10.83 1 0 35 35 1.00 1.00 0.00

    1) Men$ari niai %kr&iai ini 'itentukan 'enan er!a*aan 4.4.12 berikut+

    Fo=Fkr (x i)= Fk

    fi

    n1!Fkr (0.88 )= 0

    35=0

    Fkr (0.92 )=0

    35=0

    Fkr (0.93 )=0

    35=0

    Fkr (0.98 )=0

    35=0

    Fkr (1.00 )=0

    35=0

    Fkr (1.02 )= 0

    35=0

    Fkr (1.02 )= 0

    35=0

    Fkr (1.05 )=0

    35=0

    Fkr (1.08 )=0

    35=0

    n2 Fkr (0.88 )= 1

    35=0.03

    Fkr (0.92 )=2

    35=0.06

    Fkr (0.93 )=3

    35=0.09

    Fkr (0.98 )=4

    35=0.11

    Fkr (1.00 )=5

    35=0.14

    Fkr (1.02 )= 8

    35=0.23

    Fkr (1.02 )= 9

    35=0.26

    Fkr (1.05 )=10

    35=0.29

    Fkr (1.08 )=11

    35=0.31

    )4.4.1

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    Fkr (1.10 )=0

    35=0

    Fkr (1.13 )=0

    35=0

    Fkr (1.18 )= 035

    =0

    Fkr (1.22 )= 0

    35=0

    Fkr (1.33 )=0

    35=0

    Fkr (1.43 )=1

    35=0.03

    Fkr (1.53 )=1

    35=0.03

    Fkr (1.58 )=1

    35=0.03

    Fkr (1.62 )= 1

    35=0.03

    Fkr (1.63 )=1

    35=0.03

    Fkr (1.70 )=1

    35=0.03

    Fkr (1.73 )=1

    35=0.03

    n1 Fkr (1.78 )=1

    35=0.03

    Fkr (1.80 )=1

    35=0.03

    Fkr (1.85 )=1

    35=0.03

    Fkr (1.87 )=1

    35=0.03

    Fkr (1.97 )=1

    35=0.03

    Fkr (1.98 )=1

    35=0.03

    Fkr (2.12 )= 2

    35=0.06

    Fkr (2.38 )=2

    35=0.06

    Fkr (2.52 )= 3

    35=0.09

    Fkr (2.57 )=3

    35=0.09

    Fkr (2.62 )= 3

    35=0.09

    Fkr (1.10 )=12

    35=0.34

    Fkr (1.13 )=14

    35=0.40

    Fkr (1.18 )=1635

    =0.46

    Fkr (1.22 )=17

    35=0.49

    Fkr (1.33 )=17

    35=0.49

    Fkr (1.43 )=18

    35=0.51

    Fkr (1.53 )=19

    35=0.54

    Fkr (1.58 )=20

    35=0.57

    Fkr (1.62 )=22

    35=0.63

    Fkr (1.63 )=22

    35=0.63

    Fkr (1.70 )=23

    35=0.66

    Fkr (1.73 )=24

    35=0.69

    n2 Fkr (1.78 )=25

    35=0.71

    Fkr (1.80 )=26

    35=0.74

    Fkr (1.85 )=27

    35=0.77

    Fkr (1.87 )=28

    35=0.80

    Fkr (1.97 )=29

    35=0.83

    Fkr (1.98 )=30

    35=0.86

    Fkr (2.12 )=30

    35=0.86

    Fkr (2.38 )=31

    35=0.89

    Fkr (2.52 )=31

    35=0.89

    Fkr (2.57 )=32

    35=0.91

    Fkr (2.62 )=33

    35=0.94

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    Fkr (2.85 )=4

    35=0.11

    Fkr (3.08 )=4

    35=0.11

    Fkr (3.12 )= 535

    =0.14

    Fkr (3.25 )=5

    35=0.14

    Fkr (3.63 )=6

    35=0.17

    Fkr (3.97 )=7

    35=0.20

    Fkr (4.08 )= 8

    35=0.23

    Fkr (4.13 )= 9

    35=0.26

    Fkr (4.25 )=10

    35=0.29

    Fkr (4.47 )=11

    35=0.31

    Fkr (4.75 )=12

    35=0.34

    Fkr (5.02 )=13

    35=0.37

    Fkr (5.03 )=15

    35=0.43

    Fkr (5.05 )=16

    35=0.46

    Fkr (5.08 )=17

    35=0.49

    Fkr (5.18 )=18

    35=0.51

    Fkr (5.20 )=19

    35=0.54

    Fkr (5.52 )=20

    35=0.57

    n1 Fkr (5.82 )=21

    35=0.60

    Fkr (6.28 )=22

    35=0.63

    Fkr (6.50 )=23

    35=0.66

    Fkr (6.80 )=24

    35=0.69

    Fkr (6.92 )=25

    35=0.71

    Fkr (2.85 )=33

    35=0.94

    Fkr (3.08 )=34

    35=0.97

    Fkr (3.12 )=3435

    =0.97

    Fkr (3.25 )=35

    35=1.00

    Fkr (3.63 )=35

    35=1.00

    Fkr (3.97 )=35

    35=1.00

    Fkr (4.08 )=35

    35=1.00

    Fkr (4.13 )=35

    35=1.00

    Fkr (4.25 )=35

    35=1.00

    Fkr (4.47 )=35

    35=1.00

    Fkr (4.75 )=35

    35=1.00

    Fkr (5.02 )=35

    35=1.00

    Fkr (5.03 )=35

    35=1.00

    Fkr (5.05 )=35

    35=1.00

    Fkr (5.08 )=35

    35=1.00

    Fkr (5.18 )=35

    35=1.00

    Fkr (5.20 )=35

    35=1.00

    Fkr (5.52 )=35

    35=1.00

    n2 Fkr (5.82 )=35

    35=1.00

    Fkr (6.28 )=35

    35=1.00

    Fkr (6.50 )=35

    35=1.00

    Fkr (6.80 )=35

    35=1.00

    Fkr (6.92 )=35

    35=1.00

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    Fkr (6.97 )=26

    35=0.74

    Fkr (7.05 )=27

    35=0.77

    Fkr (7.10 )=2835

    =0.80

    Fkr (7.17 )=29

    35=0.83

    Fkr (7.25 )=30

    35=0.86

    Fkr (7.47 )=31

    35=0.89

    Fkr (7.82 )=32

    35=0.91

    Fkr (7.85 )=33

    35=0.94

    Fkr (8.02 )=34

    35=0.97

    Fkr (10.83 )=35

    35=1.00

    Fkr (6.97 )=35

    35=1.00

    Fkr (7.05 )=35

    35=1.00

    Fkr (7.10 )=3535

    =1.00

    Fkr (7.17 )=35

    35=1.00

    Fkr (7.25 )=35

    35=1.00

    Fkr (7.47 )=35

    35=1.00

    Fkr (7.82 )=35

    35=1.00

    Fkr (7.85 )=35

    35=1.00

    Fkr (8.02 )=35

    35=1.00

    Fkr (10.83 )=35

    35=1.00

    2) Men$ari niai ,n

    &iai ini 'i$ari 'enan er!a*aan 4.4.14 berikut+

    n=|Fkr (1)Fkr (2)|

    Dn (0.88 )=|0-0.03|=0.03Dn (0.92 )=|0-0.06|=0.06Dn (0.93 )=|0-0.09|=0.09Dn (0.98 )=|0-0.11|=0.11Dn (1.00 )=|0-0.14|=0.14Dn (1.02 )=|0-0.23|=0.23Dn (1.05 )=|0-0.26|=0.26Dn (1.08 )=|0-0.29|=0.29

    Dn (1.10 )=|0-0.31|=0.31Dn (1.13 )=|0-0.34|=0.34Dn (1.18 )=|0-0.40|=0.40Dn (1.22 )=|0-0.46|=0.46Dn (1.33 )=|0-0.49|=0.49Dn (1.43 )=|0.03-0.49|=0.46Dn (1.53 )=|0.03-0.51|=0.49Dn (1.58 )=|0.03-0.54|=0.51Dn (1.62 )=|0.03-0.57|=0.54Dn (1.63 )=|0.03-0.63|=0.60

    Dn (1.70 )=|0.03-0.66|=0.63

    Dn (1.80 )=|0.03-0.74|=0.71Dn (1.85 )=|0.03-0.77|=0.74Dn (1.87 )=|0.03-0.80|=0.77Dn (1.97 )=|0.03-0.83|=0.80Dn (1.98 )=|0.03-0.86|=0.83Dn (2.12 )=|0.06-0.86|=0.80Dn (2.38 )=|0.06-0.89|=0.83Dn (2.52 )=|0.09-0.89|=0.80

    Dn (2.57 )=|0.09-0.91|=0.83Dn (2.62 )=|0.09-0.94|=0.86Dn (2.85 )=|0.11-0.94|=0.83Dn (3.08 )=|0.11-0.97|=0.86Dn (3.12 )=|0.14-0.97|=0.83Dn (3,25 )=|0.14-1.00|=0.86Dn (3.63 )=|0.17-1.00|=0.83Dn (3.97 )=|0.20-1.00|=0.80Dn (4.08 )=|0.23-1.00|=0.77Dn (4.13 )=|0.26-1.00|=0.74

    Dn (4.25 )=|0.29-1.00|=0.71

    )4.4.1

    ,n *a#

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    35/35

    Dn (1.73 )=|0.03-0.69|=0.66Dn (1.78 )=|0.03-0.71|=0.69Dn (5.02 )=|0.37-1.00|=0.69Dn (5.03 )=|0.43-1.00|=0.57Dn (5.05 )=|0.46-1.00|=0.54Dn (5.08 )=|0.49-1.00|=0.51Dn (5.18 )=|0.51-1.00|=0.49Dn (5.20 )=|0.54-1.00|=0.46Dn (5.52 )=|0.57-1.00|=0.43Dn (5.82 )=|0.60-1.00|=0.40Dn (6.28 )=|0.63-1.00|=0.37Dn (6.50 )=|0.66-1.00|=0.34Dn (6.80 )=|0.69-1.00|=0.31

    Dn (4.47 )=|0.31-1.00|=0.69Dn (4.75 )=|0.34-1.00|=0.66Dn (6.92 )=|0.71-1.00|=0.29Dn (6.97 )=|0.74-1.00|=0.26Dn (7.05 )=|0.77-1.00|=0.23Dn (7.10 )=|0.80-1.00|=0.20Dn (7.17 )=|0.83-1.00|=0.17Dn (7.25 )=|0.86-1.00|=0.14Dn (7.47 )=|0.89-1.00|=0.11Dn (7.82 )=|0.91-1.00|=0.09Dn (7.85 )=|0.94-1.00|=0.06Dn (8.02 )=|0.97-1.00|=0.03Dn (10.83)=|1.00-1.003|=0

    b) -nai!a erban'inan

    &amba 4.4.,'ua uji 'olmogoo-smino dua sampel kontin+u$) e!i*uan

    "=1, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential"=5, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential"=10, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential


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