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Brdy 6Ed Ch23 OrganicPolymersAndBiochemicals

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    Chapter 23:

    Organic Chemistry,Polymers, and Biochemicals

    Chemistry: The Molecular Natureof Matter, 6E

    Jespersen/Brady/Hyslop1

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Carbon ChemistryBonding

    Strong covalent bonding to itself and to other non-metal elementsCapable of forming extremely long carbon-carbonchains

    Multiple arrangements ofidentical molecular formulaslead to numerous isomers.

    2

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Structural Formula RepresentationsLewis Structure of Pentane

    Condensed Structural FormulaCH3CH2CH2CH2CH3 pentane

    3

    C

    C

    C C

    C

    HH

    H

    H

    H

    H

    H

    H

    H

    H

    H H

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Structural Formula Representations

    Lewis Structure of Pentan-1-ol

    Condensed Structural FormulaCH3CH2CH2CH2CH2OH 1-pentan ol

    4

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E 5

    Chiral Isomers of CarbonChirality exists when carbon has fourunique constituents bond to itself

    |||||

    Non-superimposable mirror images

    3

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Chiral Isomers of Butan-2-ol

    6

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Abbreviated or Bond-Line Structure

    Carbon atoms occur at intersection butno symbol used

    CH3-CH2-CH3 would appear as:

    Non-carbon atoms would appear assymbols

    CH3-CH2-CH2-OH would appear as:

    7

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Abbreviated or Bond-Line Structure

    Open-Chain CompoundsExamples

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E 9

    Abbreviated or Bond-Line Structure ofRing Compounds

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Abbreviated or Bond-Line Structure

    Heterocyclic Compounds

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Learning Check 1. Draw at least two geometric isomers of C 4H10

    using abbreviated structures.

    -Draw the four carbon chain first-Now rearrange CH 3 groups

    11

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!When a chemical formula is written in the followingform, CH 3CH2CH2COOH, the representation isknown as:

    A. an abbreviated structure

    B. a Lewis dot structure

    C. a condensed formula

    D. an optical isomer

    12

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Functional Groups in OrganicOrganic families can be defined by functionalgroups.

    Frequently use R as a place holder foralkane-like hydrocarbon groups

    R-OH alcohol

    R-COOH organic acidR-O-R ether

    13

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Functional Groups in Organic

    14

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Learning Check

    1.Write the abbreviated structure for benzoicacid.

    2. What family does C 6H5NH 2 belong to?

    1.2. amine family

    15

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    HydrocarbonsHydrocarbon compounds only contain C and H

    Alkanes C nH2n+2 CH3CH2CH3 propane

    Alkenes C nH2n CH3CHCH2 propene

    Alkynes C nH2n-2 CH3CCH propyne

    Aromatic C 6H6 benzeneCharacterized by cyclic delocalized bonding

    17

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Hydrocarbons Alkanes are defined as saturated compounds.

    All singles bond to carbonCannot add more hydrogen atoms

    Alkenes and alkynes are unsaturatedcompounds.

    Alkenes have double bonds and H atoms can beadded to the double bond to create a saturatedcompound.

    Alkynes have triple bonds and H atoms can beadded to create a saturated compound.CH2=CHCH3 + H 2 CH3CH2CH3

    18

    Pt uuuur

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Aromaticity- Characterized by conjugated bonds in a ring such

    as benzene.- electrons are delocalized over the ring- Leads to greater stability than expected- Properties are different than those of other

    hydrocarbon families- Polycyclic examples:

    19

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Hydrocarbon NomenclatureRules for naming alkanes

    Established by IUPAC

    1. Name ends in -ane 2. Complete name uses that of parent

    compound with constituent groups added.

    3. Parent is longest continuous carbon chain.4. Name of longest chain based on the number

    of carbons.5. Carbon atoms are numbered starting at theend that gives the lowest number for the

    first branch.20

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Straight Chained Alkanes

    21

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alkyl Groups Alkane type groups added to parent chain areknown as alkyl groups. Consist of alkane,minus one H atom. Name always ends in - ylExampleCH4 : now remove one H which yields CH 3

    Naming of CH 3Start with parent name, which is methane

    Drop ane and add ylSo methane becomes methyl group

    22

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Nomenclature6. Aryl groups names are prefixed to parent

    name.7. Multiple aryl groups on a parent are

    numbered and named alphabetically.8. When there are multiple identical groups add

    di, tri, tetra to the aryl name.9. If multiple, identical aryl groups are attached

    to the same carbon repeat the carbon

    number.

    24

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Examples

    What is the name of the compound shown?

    1. The longest carbon chain (parent) isfour. Parent name is butane.

    2. Start numbering from the left to get thesmallest number for the attached group.

    25

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Examples3. The attached alkyl group is a methyl

    group.Thus, the correct name is:

    2-methylbutane

    What is the name of the following compound?

    26

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    ExamplesThe parent chain contains five carbons.Thus, the parent name is pentane.Number from the left to obtain the smallest numberfor the first alkyl group.

    The alkyl groups are at the 2 and 3 positions.The 2 and 3 positions each contain a methyl group.

    27

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    ExamplesThe parent chain is six carbons long.The lowest correct numbering of positions isshown below.

    There are methyl and ethyl groups attached tocarbon 3.

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!What is the correct name for the molecule shownbelow?

    A. 3-butylpentaneB. 1,1-diethylpentane

    C. 3-ethylheptaneD. 5-ethylheptane

    31

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!What is the name of the compound shown below?

    A. 3-methyl-3-methyloctaneB. 3,3-dimethyloctaneC. 2-ethyl-2-methylheptane

    D. 6,6-dimethyloctane

    32

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alkenes and Alkynes Alkenes contain one or more double bonds

    General form: C nH2n Alkynes contain one or more triple bonds

    General form: C nH2n-2

    Non-polar compounds are not water solubleExamples:

    34

    2 2

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alkenes and AlkynesNomenclature

    The parent chain must contain the multiple bondeven if it is a smaller chain length than one without

    a multiple bondNumber from end that gives the lowest number tothe first carbon of the multiple bondThe number is given as -x- and placed just beforethe ene or yne of the parent name. For example,but-2-ene. The double bond starts on carbon 2 ofthe chain.

    35

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alkene Examples

    Start numbering from the left to get the lowestnumber for the first carbon with the double bond

    The parent is heptene and the correct namingincluding the double bond location would behep-2-ene

    36

    lk l

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alkene Example

    The parent chain is four carbons2,3-dimethylbut-2-ene

    We would not name this 2-methyl-3-methylbut-

    2-ene

    37

    N i P l

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Naming PolyenesHow do we name compounds such as the following?

    This compound contains two double bonds and isknown as a diene

    We want the lowest number for the first carbon ofeach of the double bondsStart numbering from the right

    38

    N i P l

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Naming PolyenesThe correct name would be hex-1,3-diene

    Three double bonds would be a triene

    hex-1,3,5-triene

    39

    C li Alk

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Cyclic Alkenes

    Number ring to obtain lowest number for firstcarbon of the double bond

    40

    C li Alk

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Cyclic AlkenesCorrect name is 1,6-dimethylcyclohex-1-ene

    Other ring examples

    41

    Y T !

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!What is the correct name for the compound shownbelow?

    A. 1,4-dimethylcyclopent-1-eneB. 1,3-dimethylcyclopent-1-ene

    C. 1-methyl-4-methylcyclopent-1-eneD. 1,3-dimethylcyclo-1-pentene

    42

    Your Turn!

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!What is the correct structure for 3,3-dimethylpro-1-ene?

    A.

    B.

    C.

    D.

    43

    Geometric Isomers

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Geometric IsomersGroups cannot freely rotate about a double bondTherefore, it is possible to have geometricisomers

    Examples:

    44

    Reactions of Alkene

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Reactions of Alkene Alkenes readily add across the double bondExamples of an addition reaction:

    CH2CH2 + H 2 CH3CH3 hydrogenation

    CH2CH2 + HCl CH3CH2Cl

    CH2CH2 + H 2O CH3CH2OH

    CH2CH2 + Cl 2 CH2ClCH2Cl

    45

    Pt

    Aromatic Hydrocarbons

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Aromatic HydrocarbonsThe most common aromatic compound isbenzene and its derivativesRepresentation of bonding

    Delocalized bonds create unique stability,called resonance stabilization. The circle in thering represents delocalization.

    46

    Reactions

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    ReactionsSubstitution reactions maintain benzenesresonance structure.

    Addition reactions, like those of alkenes, destroyresonance structure

    Substitution reaction:

    47

    Addition Reaction

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Addition Reaction

    Notice that you have reduced the doublebonding in the ring and altered the resonancestabilization of the ring

    48

    L i Ch k

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Learning Check:What product would form if benzene reacted withnitric acid using an appropriate catalyst?

    Sulfuric acid is the catalyst

    A substitution reaction occurs

    49

    Your Turn!

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Your Turn!

    Which product is most likely formed when sulfuricacid reacts with benzene?

    A.

    B.

    C.

    D.50

    Organic Compounds Containing Oxygen

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    g p g yg

    Important functional groups:

    51

    R

    R'

    O

    R

    O

    O

    R

    OH

    O

    R'

    Alcohols and Ethers

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alcohols and Ethers

    Common alcohols: names end in -olCH3OH methanolCH3CH2OH ethanolCH3CH2CH2OH propan-1-ol

    If the OH group was attached to the central carbonthen the alcohol would be propan-2-ol

    Alcohols form hydrogen bonds, causing their boiling

    points to be higher than predicted.

    52

    Alcohols and Ethers

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alcohols and Ethers

    Primary alcohols:

    Secondary alcohols:

    Tertiary alcohols:

    53

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    Reactions of Alcohols

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Alcohols can undergo oxidation to form a varietyof products. Oxidation removes an H atom fromthe alcoholic carbon as well as the H on the O H

    group.

    Primary alcohols can be oxidized to aldehydesand carboxylic acids

    55

    Reactions of Alcohols

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Aldehydes are more readily oxidized thanalcohols

    Secondary alcohols can be oxidized to ketones

    56

    Reactions of Alcohols

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Ketones are not further oxidizedTertiary alcohols have no H atom on thealcoholic carbon and thus, do not undergooxidation

    Alcohols undergo elimination reactions in thepresence of concentrated H 2SO4 forming waterand alkenes

    -OH group readily accepts a proton fromsulfuric acid

    57

    Elimination Reaction

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Dehydration of an alcohol

    During the reaction a very unstable carbocationis formed. This ion eliminates a proton to formthe alkene.

    58

    H 3 C

    H 2 C C

    H 2 C OH

    2 4

    H 3 C

    H 2C

    CH

    CH 22

    H

    H

    Substitution Reactions of Alcohols

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Using heat and concentrated HBr, HI, or HCl, ahalogen will replace the OH group

    A proton adds to the OH forming OH 2+

    Water leaves and the halogen ion attaches to thecarbon site where the OH was attached

    59

    Aldehydes and Ketones

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Naming AldehydesParent name ends in al , replacing e in the alkanenameThe aldehyde group is always at the end of a chainand numbering starts with that end of the chain

    60

    Naming Aldehydes

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Number from the Aldehyde end

    Do not use -1- for Aldehyde:3-methylpropan-1-al, or 3-methyl-1-propanalwould be wrong

    61

    Learning Check

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    What is the name of the following aldehyde?

    4-ethylhexanal

    62

    Naming Ketones

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Parent name ends in one Parent chain must contain carbonyl groupNumbering so carbonyl carbon has lowestpossible number

    4-ethylheptan-3-oneNOT: 4-ethylheptan-5-one

    63

    Your Turn!

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    What is the correct name for the aldehyde shownbelow?

    A. 2,4-dimethylpentanal

    B. 2,4-dimethyl-1-pentanalC. 2-methyl-4-methylpropanalD. 2,4-dimethyl-5-pentanal

    64

    Your Turn! - Solution

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Aldehydes are numbered from the aldehyde endof the molecule

    There are two identical groups, (methyl) so weuse di in the naming

    65

    Your Turn!

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    What is the correct name for the ketone shownbelow?

    A. 4-methyl-3-ethylhexan-2-one

    B. 4-ethyl-3-methylhexan-5-oneC. 3-ethyl-4-methylhexan-2-oneD. 3,4-diethylpentan-2-one

    66

    Your Turn! - Solution

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Number to give lowest number to keto group soyou start from the right

    Alkyl groups are ordered alphabetically so ethylcomes before methyl

    67

    Reactions of Aldehydes and Ketones

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Aldehydes and ketones add hydrogen across theC=O bondProcess is hydrogenation or reduction

    68

    2

    O OH

    2

    Carboxylic Acids and Esters

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E 69

    Naming Carboxlic Acids

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Name ends in oic, replacing e in the parentnameNumbering begins with carboxyl group

    -COOH or -CO 2H is the condensed formCH3COOH is ethanoic acid (acetic acid)

    70

    Naming Carboxylic Acids

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Benzoic acid

    Propanoic acid

    71

    O

    OH

    Naming Esters

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Name begins with alkyl group attached to the OName of parent acid is separate from the alkylgroup name and oic is replaced with ate

    Ethyl propanate

    72

    Learning Check

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    What is the name of the following ester?

    Alkyl group is propylNumber, starting withthe ester carbonPropyl 4-methylpentanate

    73

    3

    2

    1

    O

    O

    4

    5

    propyl group

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    Reactions of Carboxylic Acids

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    The COOH is weakly acidic and therefore reactswith base

    RCOOH + OH - RCOO- + H 2O

    75

    Formation of Esters

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Esters give fruits their characteristic odor

    ethyl pentanoate76

    O

    O H + H 3 C C

    OH

    H

    H

    O

    O

    + H 2O

    Saponification

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Strong base reacts with an ester to form alcoholand the esters anion formspentanoate ion

    77

    Your Turn!

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Name the ester formed when methanol reacts withhexanoic acid.

    A. 1-methyl hexanoateB. methylhexanoate

    C. methyl hexanoateD. methyl hexan-1-oate

    78

    Organic Derivatives of Ammonia

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Amines are derived from ammonia with one ormore H atoms replaced with organic groupsLike ammonia, amines are weakly basic

    Amines react with acids

    79

    Acid Property of Protonated Amines

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    Ethylmethylammonium ion is the conjugate acidof ethylmethylamine

    pK a = 10.76 pK b= 3.24

    80

    CH 2

    N

    H

    CH 3

    H 3 C+ H+CH 2

    N

    H

    CH 3H 3 C

    H

    ethylmethylamineethylmethylammoniun ion

    +H2O

    Amides

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    General form

    Where (H)R indicates either an H atom or an R

    group attachedNaming

    The name of the parent acid is amended droppingthe oic ending and replacing it with - amide

    81

    2

    Example Names of Amides

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    Propanamide

    4-ethylhexamide

    These are examplesof simple amides

    82

    Synthesis of Simple Amides

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    An organic acid reacts with aqueous NH 3 to forman amide

    2-methylpropanoic acid yields 2-methylpropanamide

    83

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    Amide Reactions

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    Urea, an amide, ultimately hydrolyzes to NH 3,CO2 and waterCarbonic acid is formed, which then decomposes

    to carbon dioxide and waterThe overall reaction is:

    85

    Basicity of Amides

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    Amides are not basic like aminesThe lone pair on the N atom is delocalized andthus not readily available for donation to a

    proton

    Amides are neutral in an acid-base sense

    86

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    Organic PolymersMacromolecule made up of small, repeating units

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Example, polypropylene

    Starting material

    88

    PolymersRepeating unit is called a monomer

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    The reaction to create a polymer is known aspolymerization

    Chain Growth Polymers

    Polymers created by the addition of one monomerto another monomerPolypropylene is an example of a chain growth

    polymer

    89

    Common Polymers

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    Dacron-A Polyester Another example of a condensation copolymer

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    Physical PropertiesHDPE is lightweight, water repellent, resists tears

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    Common usesStrong mailing envelopes

    Tyvek

    Ultrahigh molecular weight polyethlene3 to 6 million molar massUHMWPE

    Used to make very strong polymersSails, bullet proof vests, bike helmets

    96

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    Disaccharide

    Sucrose

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    Sucrose

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    Disaccharide ReactionsDisaccharide molecules split intomonosaccharides

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    monosaccharidesGal-O-Glu + H 2O galactose + glucose

    Polysaccharides

    Starch is a large polymeric sugar moleculeCan be broken down into glucose, which is used forenergy in biochemical reactions

    Amylose is the structurally simpler glucose polymerportion of starch

    99

    Disaccharide Reactions Amylose

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    Amylose + n H2O n glucose

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    PolysaccharidesThe majority of starch is made up of a morecomplex polysaccharide known as amylopectin

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    complex polysaccharide known as amylopectin

    101

    Cellulose A polymer of glucose with different oxygenbridge orientations

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    bridge orientationsWe lack an enzyme to digest cellulose

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    LipidsWater insoluble natural productsDi l i l l t

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    Dissolve in non-polar solventsRelatively non-polar with large segments that are

    hydrocarbon-likeCholesterol

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    LipidsFats and oils

    Triacylglycerols esters of glycerol and long chain

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    Triacylglycerols-esters of glycerol and long chaincarboxylic acids (fatty acids)

    104

    Fatty Acids

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    TriacylglycerolsTriacylglycerol example

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E 106

    H 2C

    HC

    C

    H 2

    O

    O

    O

    C

    C

    C

    O

    O

    O

    CH 2

    HC

    CH 2

    CH 3

    CH 2

    H 3 C

    CH 2

    CH 2

    CH 3

    Reactions of TriacylclycerolsDigestion

    Breaks down the triacylclycerol into its three

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    Breaks down the triacylclycerol into its threecomponent fatty acids and glycerol. Takes place inbase so in fact the fatty acids are in their anion form

    Hydrogenation

    The addition of hydrogen to the double bondsTurns oils into solids

    107

    SoapCastile soap is made from olive oilOlive oil has many different fatty acids

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    Olive oil has many different fatty acidsTwo major fatty acid constituents are oleic acid, 50-

    85%, and linoleic acid, 4-20%

    Saponification of triacylglcerols using NaOH or otherbase, and heat, results in salts of the fatty acidcomponents plus glycerol

    Sodium oleate and sodium linoleate, for example

    This product mixture, soap, is thus the result ofsaponification of triacylglcerols

    108

    Cell MembranesGlycerophospholipids

    Diacylclcerols with phosphate unit which is attached

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    Diacylclcerols with phosphate unit which is attachedto a amino alcohol unit

    Contain a hydrophobic, water avoiding, unit and ahydrophilic, water loving, unit

    Aggregate together to form lipid bilayers withhydrophilic layers oriented to the outside and insidelayers of the membrane

    109

    Cell Membranes

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    Cell MembranesMembrane also contains protein units, somewhich act as ion channels to move select ions in

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    and out of cells

    Other proteins act as molecular recognition sitesfor hormones and neurotransmitters

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    ProteinsPolypeptides made up of -amino acidsServe as hormones, neurotransmitters, and

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    Serve as hormones, neurotransmitters, andenzymes

    Essential amino acids are those the body doesnot synthesizeBasic amino acidstructure:

    112

    Amino AcidsLysine

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    Cysteine

    Amino AcidsIsoleucine

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    Alanine

    114

    PolypeptidesFormation of peptide bond

    OOH

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    H 3 N

    O

    R

    N

    O

    R'

    H

    H

    H 3 N

    O

    R

    N

    O

    O

    R'

    H

    2

    PolypeptidesCombining two amino acids forms a dipeptideOften the amino acids are abbreviated

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    Jespersen/Brady/Hyslop Chemistry: The Molecular Nature of Matter, 6E

    Glycine - Gly

    Alanine Ala A dipeptide of these would then be shown as:

    Gly- Ala

    A few amino acids can be arranged in a verylarge number of orders leading to many different

    proteinsGly-Ala-Arg Gly-Arg-Ala Ala-Gly-ArgPlus three more

    116

    Polypeptides and ProteinsHow many ways can you arrange n differentobjects?

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    n ! Therefore 3 amino acids have 6 arrangements

    You can also use the same amino acid more thanonce in a polypeptideProteins

    Consist of polypeptides and usually small organicmoleculesThey may also incorporate metal ions into theirstructure

    117

    Structure of Hemoglobin

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    Nucleic AcidsRNA ribonucleic acidDNA deoxyribonucleic acid

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    The chemical of a gene

    Chemical basis of inherited characteristics

    119

    Nucleic Acid Sugars

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    Basic Nucleic Acid Structure

    phosphate Sugar phosphate sugar phosphate Sugar phosphate

    G G' G"

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    Where G is a placeholder for a unique nucleicacid side chainThe sugars are ribose for RNA and deoxyribosefor DNA The groups, G, are:

    adenine (A), thymine(T), uracil(U), guanine(G), andcytosine(C)

    121

    phosphate g p p g phosphate Sugar phosphate

    DNA - Double Helix Structure A unique arrangement of amino acids maximizedhydrogen bonding resulting in a pairing ofstrands to form a do ble heli

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    strands to form a double helixBase Pairing A only with T

    C only with G

    122

    DNA ReplicationEnzyme catalyzed process unzips the two strands

    Arrangement of base pairs dictates replication

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    pattern

    123

    Polypetide SynthesisControlled formation of peptide bonds to make apolypeptideRepeated man times to form pol peptides and

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    Repeated many times to form polypeptides andproteinsGenetic information is transcribed from DNA in thenucleus onto RNA ( m RNA)

    This messenger RNA moves outside the nucleus andthrough a complex process, using other RNA types,synthesizes a specific protein

    The order of amino acid synthesis is coded so thatthe correct amino acids are made available in theproper sequence

    124


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