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TODAY’S LEARNING TARGETS• LT 6.16 – I can hypothesize about the moleculariry of a elementary
reaction.
• LT 6.17 – I can determine the rate law for a multistep reaction and discuss the relationship between the fast and slow steps for the reaction.
• LT 6.18 – I can compare and contrast homogeneous and heterogeneous catalysts. Furthermore, I can identify a catalyst for a multi-step reaction.
REACTION MECHANISMS• The steps that a reaction takes in order to occur is the reaction
mechanism
• These are the steps of bonds breaking, atoms rearranging, and new bonds forming
ELEMENTARY REACTIONS• Reactions that occur in a single step are elementary reactions
• The number of molecules that participate in elementary reactions is known as the molecularity of the reaction.
• Unimolecular – Single molecule involved• Bimolecular – Collision of two molecules required• Termolecular – Collision of three molecules required
• Molecularity is never higher than 3 because the odds of 4 molecules colliding all at the same time and in the correct orientation is highly unlikely.
MULTISTEP MECHANISMS• Most chemical reactions require multiple steps in order to occur
• For example the reaction:
NO2 + CO NO + CO2
• Requires 2 steps in order to occur:
NO2 + NO2 NO3 + NO
NO3 + CO NO2 + CO2
• They must create an intermediate, those molecules that are produces and then consumed before reaction completion, before producing the final product
• Insert Figure 14.20
RATE LAWS AND ELEMENTARY REACTIONS• Every reaction is made up of one or more elementary reaction
• If the reaction is elementary, then its rate law is based on molecularity
• For example, if the reaction is elementary and it is of the form:
A Products
• Then the rate law is simply:
Rate = k [A]
RATE LIMITING STEPS• The majority of reactions require 2 or more elementary reactions.
• Each step has its own rate constant and activation energy
• The overall rate of the reaction can not exceed the rate of the slowest elementary reaction.
• The slow step is the rate – determining step
• The rate – limiting step greatly inhibits mechanism and rate law.
MECHANISMS WITH SLOW INITIAL STEP• For the multistep reaction previously discussed:
• The first step is the rate limiting step, so k2 >> k1
• Therefore, we can only use the rate constant and reaction from the slow first step. Therefore, the rete law is:
TABLE TALK• The decomposition of nitrous oxide, N2O, is believed to occur by a two
step mechanism. What is the rate law using the mechanism below?
MECHANISMS WITH FAST INITIAL STEP• Sometimes the first step is not the slow step.
• Consider the following reaction:
NO + NO + Br2 2 NOBr
• This occurs through two steps where the second step is the slow step
k-1
TABLE TALK• You run the following reaction:
NO + O2 NO2
• Based on the data the following mechanism is proposed. Determine the rate law using the mechanism below.
k-1
CATALYSTS• A catalyst is a substance that speeds up a
chemical reaction by lowering the activation energy
• It provides an alterative pathway by which the reaction can occur
• ΔG is not impacted
• A homogeneous catalyst is a catalyst whose phase is the same as the reactants
• A heterogeneous catalyst is a catalyst whose phase is different from that of the reactants.
WHITE BOARD PROBLEMS1. Complete the following table:
2. Determine the rate law for the following mechanism:
WHITE BOARD PROBLEMS3. What is the intermediate for this mechanism?
4. For the Diet Coke and Mentos experiment, are the Mentos a heterogeneous or homogeneous catalyst?
5. Based on the following diagram, how many intermediates are formed when a catalyst is used? Is it exothermic or endothermic?
STATIONS REVIEW• Station 1 –
• Station 2 –
• Station 3 –
• Station 4 –
• Station 6 –
• Station 7 –
• Station 8 –
• Station 9 –
• Station 10 –