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CDA 3100 Spring 2013
Special Thanks
• Thanks to Dr. Xiuwen Liu for letting me use his class slides and other materials as a base for this course
Course Information
04/21/23 CDA3100 4
About Me
• My name is Zhenghao Zhang– Why I am teaching this course: I worked for two
years as an embedded system engineer, writing codes for embedded controllers.
04/21/23 CDA3100 5
Class Communication
• This class will use class web site to post news, changes, and updates. So please check the class website regularly
• Please also make sure that you check your emails on the account on your University record
• Blackboard will be used for posting the grades
04/21/23 CDA3100 6
Required Textbook
• The required textbook for this class is – “Computer Organization and Design”
• The hardware/software interface
– By David A. Patterson and John L. Hennessy– Fourth Edition
04/21/23 CDA3100 7
Lecture Notes and Textbook• All the materials that you will be tested on will be
covered in the lectures – Even though you may need to read the textbook for
review and further detail explanations– The lectures will be based on the textbook and handouts
distributed in class
Motivations
What you will learn to answer (among other things)
• How does the software instruct the hardware to perform the needed functions
• What is going on in the processor • How a simple processor is designed
04/21/23 CDA3100 10
Why This Class Important?• If you want to create better computers
– It introduces necessary concepts, components, and principles for a computer scientist
– By understanding the existing systems, you may create better ones
• If you want to build software with better performance
• If you want to have a good choice of jobs• If you want to be a real computer scientist
04/21/23 CDA3100 11
Career Potential for a Computer Science Graduate
http://www.jobweb.com/studentarticles.aspx?id=904&terms=starting+salary
04/21/23 CDA3100 12
Career Potential for a Computer Science Graduate
Source: NACE Fall 2005 Report (http://www.jobweb.com/resources/library/Careers_In/Starting_Salary_51_01.htm)
Required Background
Required Background
• Based on years of teaching this course, I find that you will suffer if you do not have the required C/C++ programming background.
• We will need assembly coding, which is more advanced than C/C++.
• If you do not have a clear understanding at this moment of array and loop , it is recommended that you take this course at a later time, after getting more experience with C/C++ programming.
Array – What Happens? #include <stdio.h>
int main (void)
{
int A[5] = {16, 2, 77, 40, 12071};
A[A[1]] += 1;
return 0;
}
Loop – What Happens?#include <stdio.h>
int main ()
{
int A[5] = {16, 20, 77, 40, 12071};
int result = 0;
int i = 0;
while (result < A[i]) {
result += A[i];
i++;
}
return 0;
}
Getting Started!
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Decimal Numbering System• We humans naturally use a particular numbering system
04/21/23 CDA3100 19
Decimal Numbering System• For any nonnegative integer , its
value is given by
– Here d0 is the least significant digit and dn is the most significant digit
011 dddd nn
011
00
11
11
0
10)10)10)100((((
1010101010
dddd
ddddd
nn
nn
nn
n
i
ii
04/21/23 CDA3100 20
General Numbering System – Base X
• Besides 10, we can use other bases as well– In base X,
– Then, the base X representation of this number is defined as dndn-1…d2d1d0.
– The same number can have many representations on many bases. For 23 based 10, it is• 23ten
• 10111two
• 17sixteen, often written as 0x17.
–
011
00
11
11
0
)))0(((( dXdXdXdX
XdXdXdXdXd
nn
nn
nn
n
i
ii
04/21/23 CDA3100 21
Commonly Used Bases
– Note that other bases are used as well including 12 and 60
• Which one is natural to computers?– Why?
Base Common Name Representation Digits
10 Decimal 5023ten or 5023 0-9
2 Binary 1001110011111two 0-1
8 Octal 11637eight 0-7
16 Hexadecimal 139Fhex or 0x139F 0-9, A-F
04/21/23 CDA3100 22
Meaning of a Number Representation
• When we specify a number, we need also to specify the base– For example, 10 presents a different quantity in a
different base
• – There are 10 kinds of mathematicians. Those who
can think binarily and those who can't... http://www.math.ualberta.ca/~runde/jokes.html
Question
• How many different numbers that can be represented by 4 bits?
Question
• How many different numbers that can be represented by 4 bits?
• Always 16 (24), because there are this number of different combinations with 4 bits, regardless of the type of the number these 4 bits are representing.
• Obviously, this also applies to other number of bits. With n bits, we can represent 2n different numbers. If the number is unsigned integer, it is from 0 to 2n-1.
04/21/23 CDA3100 26
Conversion between Representations
• Now we can represent a quantity in different number representations– How can we convert a decimal number to binary?– How can we then convert a binary number to a
decimal one?
04/21/23 CDA3100 27
Conversion Between Bases
• From binary to decimal example15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0
215 214 213 212 211 210 29 28 27 26 25 24 23 22 21 20
0 0 0 1 0 0 1 1 1 0 0 1 1 1 1 1
5023
1248161282565124096
222222222 0123478912
Converting from binary to decimal
• Converting from binary to decimal. This conversion is also based on the formula:d = dn-12n-1 + dn-22n-2 +…+ d222 + d121 + d020
while remembering that the digits in the binary representation are the coefficients.
• For example, given 101011two, in decimal, it is
25 + 23 + 21 + 20 = 43.
Conversion Between Bases
• Converting from decimal to binary: – Repeatedly divide it by 2, until the quotient is 0.– Write down the remainder from right to the left.
• Example: 11.
Quotient Remainder
5 1
2 1
1 0
0 1
Digging a little deeper
• Why can a binary number be obtained by keeping on dividing by 2, and why should the last remainder be the first bit?
• Note that– Any integer can be represented by the summation of the
powers of 2: d = dn-12n-1 + dn-22n-2 +…+ d222 + d121 + d020
– For example, 19 = 16 + 2 + 1 = 1 * 24 + 0 * 23 + 0 * 22 + 1 * 21 + 1 * 20.
– The binary representation is the binary coefficients. So 19ten in binary is 10011two.
Digging a little deeper
• In fact, any integer can be represented by the summation of the powers of some base, where the base is either 10, 2 or 16 in this course. For example, 19 = 1 * 101 + 9 * 100. How do you get the 1 and 9? You divide 19 by 10 repeatedly until the quotient is 0, same as binary!
• In fact, the dividing process is just an efficient way to get the coefficients.
• How do you determine whether the last bit is 0 or 1? You can do it by checking whether the number is even or odd. Once this is determined, you go ahead to determine the next bit, by checking (d - d020)/2 is even or odd, and so on, until you don’t have to check any more (when the number is 0).
Conversion between Base 16 and Base 2
• Extremely easy. – From base 2 to base 16: divide the digits in to
groups of 4, then apply the table.– From base 16 to base 2: replace every digit by a 4-
bit string according to the table.
• Because 16 is 2 to the power of 4.
Addition in binary
• 39ten + 57ten = ?
• How to do it in binary?
Addition in Binary
• First, convert the numbers to binary forms. We are using 8 bits. – 39ten -> 001001112
– 57ten -> 001110012
• Second, add them.001001110011100101100000
Addition in binary
• The addition is bit by bit. • We will encounter at most 4 cases, where the
leading bit of the result is the carry: 1. 0+0+0=00 2. 1+0+0=013. 1+1+0=104. 1+1+1=11
Subtraction in Binary
• 57ten – 39ten = ?
Subtraction in Binary
001110010010011100010010
Subtraction in binary• Do this digit by digit. • No problem if
– 0 - 0 = 0, – 1 - 0 = 1– 1 – 1 = 0.
• When encounter 0 - 1, set the result to be 1 first, then borrow 1 from the next more significant bit, just as in decimal. – Borrow means setting the borrowed bit to be 0 and the bits from the bit following the
borrowed bit to the bit before the current bit to be 1. – Think about, for example, subtracting 349 from 5003 (both based 10). The last digit is
first set to be 4, and you will be basically subtracting 34 from 499 from now on.