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Chapter 18

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Chapter 18. The Combined Gas Law & Graham’s Law. Combined Gas Law. 10.0 cm 3 volume of a gas is collected at 75.6 kPa and 60.0  C. What would its volume be at STP? 6.12 cm 3. Combined Gas Law Problem. - PowerPoint PPT Presentation
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Chapter 18 The Combined Gas Law & Graham’s Law
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Page 1: Chapter 18

Chapter 18

The Combined Gas Law

&

Graham’s Law

Page 2: Chapter 18

Combined Gas Law

• 10.0 cm3 volume of a gas is collected at 75.6 kPa and 60.0C. What would its volume be at STP?

6.12 cm3

Page 3: Chapter 18

Combined Gas Law Problem

A sample of helium gas has a volume of 0.180 L, a pressure of 0.800 atm and a temperature of 29°C. What is the new temperature(°C) of the gas at a volume of 90.0 mL and a pressure of 3.20 atm?

Page 4: Chapter 18

Combined Gas Law Problem

A sample of helium gas has a volume of 0.180 L, a pressure of 0.800 atm and a temperature of 29°C. What is the new temperature(°C) of the gas at a volume of 90.0 mL and a pressure of 3.20 atm?

x 3.20 atm x 90.0 mL 0.800 atm 180.0 mL

604 K - 273 = 331 °C

302 K = 604 K

Page 5: Chapter 18

Weather Balloons

Page 6: Chapter 18

Weather Balloons• A weather balloon is an instrument which measures

temperature, humidity, and atmospheric pressure. The weather balloon is generally a balloon mounted with weather measuring equipment and a radio transmitter. Some weather balloons are equipped with GPS or global positioning systems for the weather station to track it more accurately.

• In North America prior to release the balloon is usually filled with hydrogen gas due to lower cost, though helium can be used as a substitute. Weather balloons may reach altitudes of 40 km (25 miles) or more where the diminishing pressure eventually causes the balloon to expand to such a degree that it pops.

• Weather balloons are sometimes cited as the cause for unidentified flying object sightings.

Page 7: Chapter 18

A weather balloon with a volume of 305L at STP is released and rises until it expands and explodes at a pressure of

7.00 torr and a temperature of –21°C. What was the volume of the balloon when it burst?

≈ 30,600 L

Page 8: Chapter 18

A weather balloon with a volume of 305L at STP is released and rises until it expands and

explodes at a pressure of 7.00 torr and a temperature of –21°C. How many times larger

is the balloon than when it was released?

About 100 times larger

Page 9: Chapter 18

Diffusion

• The spreading of a gas from an area of higher concentration to an area of lower concentration.

Page 10: Chapter 18

Which gas would diffuse throughout a room faster?

NH3(g) or HCl(g)

Page 11: Chapter 18
Page 12: Chapter 18

Gas Diffusion and Effusion

• Graham's Law:

• Allows for the calculation of the rate of diffusion of gas molecules.

Page 13: Chapter 18

Gas Diffusion and Effusion

Graham's Law: governs the rate of diffusion of gas molecules.

A of massmolar B of massmolar

B of RateA of Rate

Page 14: Chapter 18

Calculate the rate of diffusion of NH3(g) compared to HCl(g)

A of massmolar B of massmolar

B of RateA of Rate

NH3 diffuses 1.47 times faster than HCl

Page 15: Chapter 18

Use measurement to confirm the rate of diffusion of NH3(g) compared to HCl(g)

HCl NH3

Page 16: Chapter 18

Calculate the rate of diffusion of helium compared to argon.

A of massmolar B of massmolar

B of RateA of Rate

Helium diffuses 3.2 times faster than argon

Page 17: Chapter 18

Calculate the rate of diffusion of hydrogen compared to neon.

A of massmolar B of massmolar

B of RateA of Rate

hydrogen diffuses 3.2 times faster than neon

Page 18: Chapter 18

Homework

• Worksheet: Combined Gas Law & Graham’s Law

• Summarize the (I) Purpose and (II) Procedure of the “Gas Laws” Lab.


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