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Chapter 5 Amplitude Modulation

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    Chapter 5

    Amplitude Modulation

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    InformationSource

    SignalModulator

    PropagationChannel

    SignalDemodulator

    InformationDestination

    Analog Communication System

    Analog signals may be transmitted directly via carrier modulation overthe propagation channel and to be carrier-demodulated at the receiver.

    TransmitterModulator

    Receiver Demodulator

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    Modulation: The process by which some characteristics of a carrier

    signal (i.e. modulated signal) is varied in accordance with message

    signal (i.e. modulating signal)

    f(t): message signal

    A bandlimited signal whose frequency content is in the neighbourhoodoff=0 (DC) ? baseband signal

    c(t): the carrier signal, independent off(t)

    c(t)=Ac cos(2pfct+? c)Ac : Carrier amplitude

    fc : Carrier frequency wc=2pfc (radian frequency)

    ? c : Carrier phase

    f(t) modulates c(t) in either amplitude, frequency or phase. In effect,

    modulation convertsf(t) to a bandpass form, in the neighborhood of the

    center frequencyfc.

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    Why is Modulation Required?

    To achieve easy radiation: If the communication channel consists of

    free space, antennas are required to radiate and receive the signal.

    Dimension of the antennas is limited by the corresponding wavelength.

    Example: Voice signal bandwidthf=3kHz

    ? /4=25000m!!

    If we modulate a carrier wave @ fc = 100MHz with the voice signal

    ? /4=75cm

    m10103

    103 53

    8

    =

    ==f

    c

    m310100

    1036

    8

    =

    == fc

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    5

    Why is Modulation Required? (Contd)

    s1

    f

    f

    fC1

    fC2

    To accommodate for simultaneous transmission of several signals

    f

    fC3

    Example: Radio/TV broadcasting

    s2

    s3

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    Why is Modulation Required? (Contd)

    To expand the bandwidth of the transmitted signal for better

    transmission quality (to reduce noise and interference)

    ( )SNRBC += 1log 2

    Channel capacity Bandwidth Signal-to-noise ratio

    Channel capacity: Maximum achievable information rate that can be

    transmitted over the channel

    12 = BC

    SNR

    B The required SNR (for fixed noise level, corresponding signal

    power) decreases

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    Amplitude Modulation (AM)

    (Ch. 5 in Textbook)

    Objectives:

    To study different amplitude modulation scheme

    To study generation and detection of AM signals To study application of AM

    Double Sideband Large Carrier (DSB-LC) Modulation: Commercialbroadcast stations use this type and it is commonly known as just

    amplitude modulation (AM).

    Double Sideband Suppressed Carrier (DSB-SC) Modulation

    Single Sideband (SSB) Modulation Vestigial Sideband (VSB) Modulation

    We will study

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    Double Side Band Large Carrier (DSB-LC)(5.2 in Textbook)

    ( )tcjtcjc eet +=

    2

    1cos

    ( ) ( ){ }tfF F= ( ) ( ){ }t F=

    ( ) ( ) ( ) ( )[ ]ttftA ccc coscos += F

    ( ) ( )

    +++= tjtjtjctjc cccc etfetfeAeA

    2222F

    ( ) ( ) ( ) ( )cccccc FFAA +++++=2

    1

    2

    1

    Modulator ( ) ( )( ) tAtft cc cos+=

    ( ) tAtc cc cos=

    ( )tf

    ( ) tAttf ccc coscos +=

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    t

    f(t)

    c+2B

    passband

    baseband

    t

    t

    F [f(t) cosct]

    cc-2B

    F(0)/2

    F()= F [f(t)]

    F(0)

    2B-2B

    F [Ac cosct]pA

    -c

    c-c

    Ac cosct

    F [Ac cosct+ f(t)cosct]

    c-c

    pA

    Ac cosct+ f(t)cosct envelope

    t

    f(t) cosct

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    F()= F [f(t)]

    F(0)

    2B-2B

    ()=

    F [Ac cosct+ f(t)cosct]

    c-cc-2B c+2B

    Bandwidth=B [Hz] Bandwidth=2B

    F(0)/2 pA pA

    Observations:

    Modulation shifts the content ofF() to the neighbourhood ofc .

    F() for[-2B, 0] is shifted to () for[c-2B, c] and called aslower sideband.

    F() for[0, 2B] is shifted to () for[c, c+2B] and called asupper sideband.

    Let B denote the highest frequency component off(t).

    Assume fc >> B ? (t) is defined as a narrowbandsignal (i.e. its spectralcontent is located in the immediate vicinity of some high center frequency)

    Upper

    sideband

    Lower

    sideband

    baseband passband

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    Observations (contd)

    The bandwidth of message signal isB. The transmission bandwidth

    T=2B (i.e. DSB-LC is wasteful of bandwidth)

    The carrier term does not carry any information and hence the carrier

    power is wasted.

    F(

    )= F [f(t)]

    F(0)

    2B-2B

    ()= F [A

    ccos

    ct+ f(t)cos

    ct]

    c-cc-2B c+2B

    Bandwidth=B [Hz] Bandwidth=2B

    F(0)/2 pA pAUpper

    sideband

    Lower

    sideband

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    Zero crossings

    Envelope has the

    same shape of f(t)

    Envelope distortion

    Observations (contd)

    If Ac+f(t)>0 for all t, the envelope of(t) of has essentially the same shapeas thef(t).

    If Ac+f(t)

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    14Effects of varying modulation indexes

    overmodulated

    ? envelope dist.

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    Carrier and Sideband Power in DSB-LC

    ( ) ( ) ( ) ( )ttftAt ccc coscos +=

    ( ) ( ) ( ) ( ) ( ) ( )ttfAttftAt ccccc 222222 cos2coscos ++=

    ( ) ( ) ( ) ( )ttftAt ccc 22222 coscos +=

    ( ) ( ) 22 222 tfAt c +=

    ( ) dttT

    tT

    Tc

    Tc =

    +

    2/

    2/

    22 cos1limcos ( )dttT

    T

    Tc

    T +=+

    2/

    2/

    2cos1211lim

    ( )2

    12cos1

    1lim

    2

    1lim

    2

    1 2/

    2/

    2/

    2/

    = ++=+

    dttTT

    t T

    Tc

    T

    T

    TT

    = 0

    Assume and f(t) varies slowly with respect to ( )tccos( ) 0=tf

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    ( ) ( ) 22 222 tfAt c +=

    Carrier Power Sideband Power (carries information)

    Modulation (Power)Efficiency

    useful powertotal power

    =

    ( )

    ( ) 22

    222

    2

    tfA

    tf

    c +=

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    ( )[ ]8

    cos2

    222

    2

    cmc

    c AmtmA =+

    ( )[ ]

    8

    cos

    2

    222

    2

    cmc

    c AmtmA

    =

    ( ) ( ) ( )[ ] ( )[ ]tmA

    tmA

    tAt mcc

    mcc

    cc +++= cos2

    cos2

    cos

    Example (Contd)

    Upper sidebandpower

    Lower sideband

    power

    total useful power

    total power=

    2

    2

    222

    22

    242

    4

    m

    m

    AmA

    Am

    cc

    c

    +

    =

    +

    =

    Form= 1 ? = 33%. Under the best condition, i.e. m=1, 67% of

    the total power is used in the carrier and represents wasted power.


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