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Chapter 6 Problems

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Chapter 6 Problems. 6-29, 6-31, 6-39, 6.41, 6-42, 6-48,. 6-29. Distinguish between Lewis Acids/Bases & Bronsted-Lowry acids and bases. Give an example. 6-31. Why is the pH of water usually < 7? How can you prevent this from happening?. 6-39. - PowerPoint PPT Presentation
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Chapter 6 Problems 6-29, 6-31, 6-39, 6.41, 6-42, 6-48,
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Page 1: Chapter 6 Problems

Chapter 6 Problems

6-29, 6-31, 6-39, 6.41, 6-42, 6-48,

Page 2: Chapter 6 Problems

6-29

Distinguish between Lewis Acids/Bases & Bronsted-Lowry acids and bases. Give an example.

Page 3: Chapter 6 Problems

6-31.

Why is the pH of water usually < 7? How can you prevent this from happening?

Page 4: Chapter 6 Problems

6-39.

The equilibrium constant for autoprotolysis of water is 1.0 x 10-14 at 25oC. What is the value of K for 4 H2O 4H+ + 4OH-

K = [H+]4 [OH]4

K = (1x10-7)4(1x10-7)4

K = 1 x 10-56

Page 5: Chapter 6 Problems

6-41

Use Le Chatelier’s principle and Kw in Table 6-1 to decide whether the autoprotolysis of water is exothermic or endothermic at 25oC 100oC 300oC

0

1E-12

2E-12

3E-12

4E-12

5E-12

6E-12

7E-12

0 100 200 300 400

Temp

K

Page 6: Chapter 6 Problems

6-42

Make a list of strong acid and strong bases. Memorize this list.

Page 7: Chapter 6 Problems

6-48 Which is the stronger acid?

Dichloracetic acid Chloroacetic acidKa = 8 x 10-2 Ka = 1.36 x 10-3

Stronger Base?

Hydrazine UreaKb = 1.1 x 10-6 Kb = 1.5 x 10-14

Page 8: Chapter 6 Problems

Chapter 8

ActivityActivity

Page 9: Chapter 6 Problems

HomeworkHomeworkChapter 8 - Chapter 8 - ActivityActivity

8.2, 8.3, 8.6, 8.9, 8.10, 8.12

Page 10: Chapter 6 Problems

8-1 Effect of Ionic Strength 8-1 Effect of Ionic Strength on Solubility of Saltson Solubility of Salts

Consider a saturated solution of Hg2(IO3)2 in ‘pure water’. Calculate the concentration of mercurous ions.

Hg2(IO3)2(s) Hg22+ + 2IO3

- Ksp=1.3x10-18

A seemingly strange effectseemingly strange effect is observed when a salt such as KNO3 is added. As more KNO3 is added to the solution, more

solid dissolves until [Hg22+] increases to 1.0 x 10-6 M. Why?

1823

22 103.1]][[ IOHgK sp

IICCEE

somesome -- - --x-x +x+x +2x+2xsome-xsome-x +x+x +2x+2x

182 103.1]2][[ xxK sp7109.6][ x

Page 11: Chapter 6 Problems

Increased solubility

Why? LeChatelier’s Principle?

NO – not a product nor reactant Complex Ion?

No Hg2

2+ and IO3- do not form complexes

with K+ or NO3-.

How else?

Page 12: Chapter 6 Problems

The Explanation

Consider Hg22+ and the IO3

-

-2+

Electrostatic attraction

Page 13: Chapter 6 Problems

The Explanation

Consider Hg22+ and the IO3

-

2+

Electrostatic attraction

-

Hg2(IO3)2(s) The Precipitate!!The Precipitate!!

Page 14: Chapter 6 Problems

The Explanation

Consider Hg22+ and the IO3

-

-2+

Electrostatic attraction

Add KNO3

NO3-K+

Page 15: Chapter 6 Problems

The Explanation

Consider Hg22+ and the IO3

-

-2+

Add KNO3

K+K+

K+K+

K+K+

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

K+K+

K+K+

K+ K+

Page 16: Chapter 6 Problems

The Explanation

Consider Hg22+ and the IO3

-

2+

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

Hg22+ and IO3

- can’t getCLOSE ENOUGH to form Crystal latticeOr at least it is a lot “Harder” to form crystal lattice

-

K+ K+

K+K+

K+K+

K+K+

K+K+

K+ K+

Page 17: Chapter 6 Problems
Page 18: Chapter 6 Problems

The potassium hydrogen tartrate example

K+-O

O

OH

OH

O

OH

potassium hydrogen tartrate

Page 19: Chapter 6 Problems

Alright, what do we mean by Ionic strength?

Consider Hg22+ and the IO3

-

-2+

Add KNO3

K+K+

K+K+

K+K+

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

NO3-

K+K+

K+K+

K+ K+

Low Ionic StrengthHigher Ionic StrengthHigh Ionic Strength

Page 20: Chapter 6 Problems

Alright, what do we mean by Ionic strength?

Ionic strength is a measure of the total measure of the total concentration of ions in solutionconcentration of ions in solution.

Ionic strength is dependent on the number of ions in solution and their charge. Not dependent on the chemical nature of the

ions

Ionic strength () = ½ (c1z12+ c2z2

2 + …)Or Ionic strength (m) = ½ cizi

2

Page 21: Chapter 6 Problems

Examples Calculate the ionic strength of (a) 0.1 M

solution of KNO3 and (b) a 0.1 M solution of

Na2SO4 (c) a mixture containing 0.1 M KNO3

and 0.1 M Na2SO4.() = ½ (c1z1

2+ c2z22 + …)

Page 22: Chapter 6 Problems

Alright, that’s great but how does it affect the equilibrium constant?

A + B C + D

Activity = Ac = [C]c

AND

bB

baA

a

dD

dcC

c

bB

aA

dD

cC

BA

DC

AA

AAK

][][

][][

Page 23: Chapter 6 Problems

Relationship between activity coefficient and ionic strength

x

x

xz

3.31

51.0log

2

Debye-Huckel Equation

2 comments

= ionic strength of solution = activity coefficientZ = Charge on the species x = effective diameter of ion (nm)

(1)What happens to when approaches zero?(2)Most singly charged ions have an effective radius of about 0.3 nm

We generally don’t need to calculate – values are tabulated

Page 24: Chapter 6 Problems

Concept Test

List at least three properties of activity coefficients

• Dimensionless• Depends on size of the ions (ex. Hg2

2+ and IO3-)

• Depends on the Ionic Strength of the Solution (K+ & NO3

-)• Depends on the charge of the ions (ex. Hg2

2+ and IO3

-)• In dilute solutions, where ionic strength is minimal,

the activity coefficient -> 1, and has little effect on equilibrium constant

Page 25: Chapter 6 Problems

Activity coefficients are Activity coefficients are related to the hydrated related to the hydrated radius of atoms in radius of atoms in moleculesmolecules

Page 26: Chapter 6 Problems

Relationship between and

Page 27: Chapter 6 Problems
Page 28: Chapter 6 Problems
Page 29: Chapter 6 Problems

Back to our original problem

223

22

2

3223

22

][][ IOHgIOHgsp IOHgAAK

Consider a saturated solution of Hg2(IO3)2 in ‘pure water’. Calculate the concentration of mercurous ions.

Hg2(IO3)2(s) Hg22+ + 2IO3

- Ksp=1.3x10-18

At low ionic strengths -> 1

11 11

Page 30: Chapter 6 Problems

Back to our original problem

223

22

2

3223

22

][][ IOHgIOHgsp IOHgAAK

Consider a saturated solution of Hg2(IO3)2 in ‘pure water’. Calculate the concentration of mercurous ions.

Hg2(IO3)2(s) Hg22+ + 2IO3

- Ksp=1.3x10-18

In 0.1 M KNO3 - how much Hg22+ will be dissolved?

Page 31: Chapter 6 Problems
Page 32: Chapter 6 Problems
Page 33: Chapter 6 Problems

Back to our original problem

223

22

2

3223

22

][][ IOHgIOHgsp IOHgAAK

Consider a saturated solution of Hg2(IO3)2 in 0.1 M KNO0.1 M KNO33.. Calculate the concentration of mercurous ions.

Hg2(IO3)2(s) Hg22+ + 2IO3

- Ksp=1.3x10-18 22

322

2

3322

775.0][355.0][ IOIOHgsp IOHgAAK

222 775.0]2[355.0][3

22

xxAAK IOHgsp

)4(213122.0103.1 318 xx x 65 101.1

Page 34: Chapter 6 Problems

Consider a saturated solution of Hg2(IO3)2 Calculate the concentration of mercurous ions in: In Pure water = 6.9 x 106.9 x 10-7-7

in 0.1 M KNO0.1 M KNO33 = 1.1 = 1.155 x 10 x 10-6-6

Page 35: Chapter 6 Problems

pH revisited

Page 36: Chapter 6 Problems

Definition of pH

pH = -log AH

or pH = - log [H+] H

Page 37: Chapter 6 Problems

pH of pure water

H2O (l) H+ (aq) + OH-

(aq)Kw =1.0 x 10-14

Kw = AH AOH

Kw = [H+] H [OH-] OH

Page 38: Chapter 6 Problems
Page 39: Chapter 6 Problems

pH of pure water

H2O (l) H+ (aq) + OH-

(aq)Kw =1.0 x 10-14

Kw = AH AOH

Kw = [H+] H [OH-] OH

Kw = x2 x = 1.0 x 10-7 M

11

- -ICE

+x +x+x +x

Page 40: Chapter 6 Problems

pH of pure water

x = 1.0 x 10-7 M

Therefore [H+] = 1.0 x 10-7 M

pH = -log AH

= -log [H+] H

= - log [1.0 x 10-7]

= 7.00

1

Page 41: Chapter 6 Problems

pH of pure water containing salt

Calculate the pH of pure water containing 0.10 M KCl at 25oC.

Page 42: Chapter 6 Problems

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