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Calculating Degree of UnsaturationCalculating Degree of Unsaturation
• Relates molecular formula to possible structures• Degree of unsaturation: number of multiple bonds or rings• Formula for a saturated acyclic compound is CnH2n+2
• Alkene has fewer hydrogens than an alkane with the same number of carbons —CnH2n because of double bond
• Each ring or multiple bond replaces 2 H's
Example: CExample: C66HH1010
• Saturated is C6H14
– therefore 4 H's are not present• This has two degrees of unsaturation
– Two double bonds?– or triple bond?– or two rings?– or ring and double bond?
Degree of Unsaturation With Other ElementsDegree of Unsaturation With Other Elements
• Organohalogens (X: F, Cl, Br, I)• Halogen replaces hydrogen
• C4H6Br2 and C4H8 have one degree of unsaturation
Degree of Unsaturation (Continued)Degree of Unsaturation (Continued)
• Organoxygen compounds (C,H,O) – Oxygen forms 2 bonds• When 2 bonds are to different things, these don't affect
unsaturation, and can be ignored• When oxygen forms a double bond to the same ion,
assume that 2 H are lost (1 degree of unsaturation)
Organonitrogen CompoundsOrganonitrogen Compounds• Nitrogen is trivalent, acts like ½ of a carbon
To determine degree of unsaturation when N is present, use the following general formula to determine how many H the compound should have:
(2 x number of C) + 2 + (Number of N)
Next, subtract the actual number of H then divide by 2
Cis-Trans Cis-Trans Isomerism in AlkenesIsomerism in Alkenes
• Carbon atoms in a double bond are sp2-hybridized– Three equivalent orbitals at 120º separation in plane– Fourth orbital is atomic p orbital
• Combination of electrons in two sp2 orbitals of two atoms forms bond between them
• Additive interaction of p orbitals creates a bonding orbital– Subtractive interaction creates a anti-bonding orbital
• Occupied orbital prevents rotation about -bond• Rotation prevented by bond - high barrier, about 268
kJ/mole in ethylene
• Rotation of bond is prohibitive• This prevents rotation about a carbon-carbon double bond
(unlike a carbon-carbon single bond).• Creates possible alternative structures
Cis-Trans Cis-Trans Isomerism in Alkenes (Continued)Isomerism in Alkenes (Continued)
• the presence of a carbon-carbon double bond can create two possible structures– cis isomer - two similar groups on same side of the double bond– trans isomer - similar groups on opposite sides
• Each carbon must have two different groups for these isomers to occur
Cis-Trans Cis-Trans Isomerism in Alkenes (Continued)Isomerism in Alkenes (Continued)
Cis-Trans Cis-Trans Isomerism in Alkenes (Continued)Isomerism in Alkenes (Continued)
Cis-Trans Isomerization requires that end groups differ in pairs
Bottom pair cannot be superposed without breaking C=C
Alkene Stereochemistry and the Alkene Stereochemistry and the E,ZE,Z Designation Designation
• Cis-Trans naming system discussed thus far only works with disubstituted alkenes
• Tri- and Tetra substituted double bonds require more general method
• Method referred to as the E,Z system
E,ZE,Z Stereochemical Nomenclature Stereochemical Nomenclature
• Priority rules of Cahn, Ingold, and Prelog
• Compare where higher priority groups are with respect to bond and designate as prefix
• E -entgegen, opposite sides
• Z - zusammen, together on the same side
Cahn-Ingold-Prelog RulesCahn-Ingold-Prelog Rules
RULE 1• Must rank atoms that are connected at comparison point• Higher atomic number gets higher priority
– Br > Cl > S > P > O > N > C > H
RULE 2• If atomic numbers are the same, compare at next connection point
at same distance• Compare until something has higher atomic number• Do not combine – always compare
Cahn-Ingold-Prelog RulesCahn-Ingold-Prelog Rules
RULE 3• Multiple-bonded atoms are equivalent to the same number of
single-bonded atoms• Substituent is drawn with connections shown and no double or
triple bonds• Added atoms are valued with 0 ligands themselves
Cahn-Ingold-Prelog RulesCahn-Ingold-Prelog Rules
Stability of AlkenesStability of Alkenes
• Cis alkenes are more polar, less stable than trans alkenes• Compare heat given off on hydrogenation: Ho
• Less stable isomer is higher in energy– And gives off more heat– hyperconjugation of R groups stabilize the pi bond
Effects of Increasing Alkene SubstitutionEffects of Increasing Alkene Substitution
• Increasing substitution on alkene carbon atoms increases stability (again, hyperconjugation)
• This will become very important when we begin to look at possible products resulting from elimination reactions.
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