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Common pitfalls while using FEM

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Common pitfalls while using FEM Chair for Computational Engineering Faculty of Civil Engineering, Cracow University of Technology e-mail: [email protected] With thanks to: R. de Borst (Delft University of Technology) R.L. Taylor (University of California at Berkeley) M. Radwa´ nska, Z. Waszczyszyn, A. Winnicki, A. Wosatko (Cracow Univ. of Technol.) SOKI, BIM, 2020 Contents Power of FE technology What is locking? In-plane shear locking Volumetric locking What is localization? Sources: Books of Hughes, Cook, Zienkiewicz & Taylor, Belytschko et al Figures taken from: R.D. Cook, Finite Element Method for Stress Analysis, J. Wiley & Sons 1995. C.A. Felippa, Introduction to Finite Element Methods, University of Colorado, 2001. http://caswww.colorado.edu/Felippa.d/FelippaHome.d/Home.html R. Lackner, H.A. Mang. Adaptive FEM for the analysis of concrete structures. Proc. of EURO-C 1998 Conference, Balkema, Rotterdam, 1998. SOKI, BIM, 2020
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Common pitfalls while using FEM

Chair for Computational Engineering

Faculty of Civil Engineering, Cracow University of Technology

e-mail: [email protected]

With thanks to:R. de Borst (Delft University of Technology)R.L. Taylor (University of California at Berkeley)M. Radwanska, Z. Waszczyszyn, A. Winnicki, A. Wosatko (Cracow Univ. of Technol.)

SOKI, BIM, 2020

Contents

Power of FE technology

What is locking?

In-plane shear locking

Volumetric locking

What is localization?

Sources:Books of Hughes, Cook, Zienkiewicz & Taylor, Belytschko et al

Figures taken from:R.D. Cook, Finite Element Method for Stress Analysis,J. Wiley & Sons 1995.C.A. Felippa, Introduction to Finite Element Methods,University of Colorado, 2001.http://caswww.colorado.edu/Felippa.d/FelippaHome.d/Home.html

R. Lackner, H.A. Mang. Adaptive FEM for the analysis of concrete structures.

Proc. of EURO-C 1998 Conference, Balkema, Rotterdam, 1998.

SOKI, BIM, 2020

Modelling process

From: T. Kolendowicz Mechanika budowli dla architektw

Set of assumptions: model of structure, material and loadingPhysical model: representation of essential featuresMathematical model: set of equations (algebraic, differential, integral) +limiting (boundary, initial) conditionsProblems can be stationary (static) or nonstationary (dynamic)Mathematical models can be linear or nonlinear

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Understanding a structure

tension

compression

Stress flow in panels

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Numerical model

Discretization (e.g. FEM)

Simplest case: set of linear equations

Ku = f

K - stiffness matrix

u - vector of degrees of freedom

f - loading vector

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Discontinuity of derivatives

Contour plots of σxx

Without smoothing With smoothing

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Smoothing of selected component

σh – function obtained from FE solutionσ∗ – function after smoothing

Difference between these two fields is a discretization error indicator ofZienkiewicz and Zhu

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Where FE mesh should be finer (Felippa)

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Variants of mesh refinement (Cook)

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Adaptive mesh refinement

Example from Altair Engineering http://www.comco.com

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Mesh generation

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Discretization error monitored

Adaptive mesh refinement

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Advanced problems solved using FEMMechanics:

I Extreme load cases, e.g. impactI Physical nonlinearities, e.g. damage, cracking, plasticityI Geometrical nonlinearities, i.e. large displacements and/or strains,

e.g. spongeI Contact problems (unilateral constraints)

Multiphysics:I ANSYS simulations 1 2 3 4I ADINA simulations 1 2 3 4

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Let’s solve a simple problem

Brazilian test, plane strain, one quarter, elasticity

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Brazilian test, elasticity

Deformation, vertical stress σyy and stress invariant Jσ2

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Brazilian split test

Elasticity, mesh sensitivity of stresses

Stress σyy for coarse and fine meshes

Stress under the force goes to infinity (results depend on mesh density) -solution at odds with physics

SOKI, BIM, 2020

Brazilian split test

Ideal Huber-Mises-Hencky plasticity

Final deformation and stress σyy

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Brazilian split test

Ideal Huber-Mises-Hencky plasticity

Final strain εyy and strain invariant Jε2

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Brazilian split test

Ideal Huber-Mises-Hencky plasticity

0 0.2 0.4 0.6 0.8 1

Displacement

0

200

400

600

800

Forc

e

0 0.2 0.4 0.6 0.8 1

Displacement

0

200

400

600

800

Forc

e

This is correct!

For four-noded element load-displacement diagram exhibits artificialhardening due to so-called volumetric locking, since HMH flow theorycontains kinematic constraint - isochoric plastic behaviour which cannotbe reproduced by FEM model.

Eight-noded element does not involve locking.

SOKI, BIM, 2020

Limitations of finite elements

I Various kinds of locking(overstiff response)

I Zero-energy deformation modes

I Kinematic constraints (e.g.incompressibility)

I Ill-posed problems (e.g. due to softening)

Locking is a result of two many constraints in comparison with thenumber of degrees of freedom.

Q4-FI Q4-RI(NDOF=4×2=8, NCON=4×3=12) (NDOF=4×2=8, NCON=1×3=3)

Locking (overstiff response) Singularity (hourglass modes)

SOKI, BIM, 2020

Remedies to locking

I Higher-order interpolation

I Special arrangement of elements (e.g. crossed-diagonal)

I Selective integration or B approach of Hughes

I Mixed formulations (e.g. pressure discretization)

I Enhanced Assumed Strain (EAS) apprach of Simo

Sometimes locking does not prevent convergence, but affects accuracyfor coarse meshes.

Be careful with CST, Q4, T4 i H8

SOKI, BIM, 2020

In-plane shear locking (Cook)

SOKI, BIM, 2020

In-plane shear locking

Only at the element centre γxy = 0

Incompatible quadrilateral Q6

u =∑4

i=1 Niui + (1− ξ2)g1 + (1− η2)g2

v =∑4

i=1 Nivi + (1− ξ2)g3 + (1− η2)g4

γxy =∑4

i=1∂Ni

∂y ui +∑4

i=1∂Ni

∂x vi−

− 2yb2 g2 − 2x

a2 g3

SOKI, BIM, 2020

In-plane shear locking

SOKI, BIM, 2020

Incompressibility locking

For plane strain or 3D when ν → 0.5Pressure related to volumetric strain grows to infinity (isochoricdeformation is impossible).

SOKI, BIM, 2020

Deviatoric-volumetric split

G =E

2(1 + ν), K =

E

3(1− 2ν)

(GKdev + KKvol)u = f

When ν → 0.5, KKvol acts as a penalty constraint and locks thesolution, unless Kvol is singular.

SOKI, BIM, 2020

Mixed formulation

Linear elasticity

σij = 2Gui,j + λuk,kδij , λ =2νG

1− 2ν

Incompressibilityuk,k = 0

Modification of theory

σij = 2Gui,j − pδij , p =1

3σii − extra unknown

Incompressibility or compressibility

uk,k +p

λ= 0

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Mixed formulation

Strong formLTσ + b = 0

∇Tu +p

λ= 0

Weak form∫V

(Lδu)TσdV =

∫V

(δu)TbdV +

∫S

(δu)TtdS ∀δu

∫V

δp(∇Tu +

p

λ

)dV = 0 ∀δp

Discretization of displacements and pressure

u = Nu u, p = Np p

SOKI, BIM, 2020

Mixed formulationTwo-field elements [

K GGT M

] [up

]=

[ffp

]If M = 0 (incompressibility) then eliminate u:(1) → u → (2) discrete Poisson equation → pIf M 6= 0 (compressibility) then eliminate p:(2) → p → (1) standard → u

Constraint ratior =

nequncon

Optimal r = 2, e.g. Q4p1 - constant pressure element (B, SI)

SOKI, BIM, 2020

Localization of deformation

Active process takes place in a narrow band

From: D.A. Hordijk Local approach to fatigue of concrete, Delft University of Technology, 1991

SOKI, BIM, 2020

Definition of localization

I Strain localization is a constitutive effect.

I It is a precursor to failure in majority of materials.

SOKI, BIM, 2020

Forms of localization

From: M.S.A. Siddiquee,FEM simulations of deformation and failureof stiff geomaterials based on elementtest results, University of Tokyo, 1994

From: P.B. Lourenco,Computational strategies for masonrystructures,Delft University of Technology, 1996

SOKI, BIM, 2020

Cause of localization

From: D.A. Hordijk Local approach to fatigue of concrete,

Delft University of Technology, 1991

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Pathological mesh sensitivity of numerical solution

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Enhanced continuum description - no pathology

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Continuum vs discontinuumDisplacement and strain distribution in one dimension

displacement

strain∞

displacement

strain

displacement

strain

Strong discontinuity Weak discontinuity Regularized discontinuity

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