Concrete Mix Desig Data:- Specific Characteristics Strerngth: 28 MPa at the age of 28 Exposure Condition: very severe( In Pile) Clear Cover to be used : 30mm Maximum Size of Aggregate: 20mm Specific Gravity of Fine Aggregate: 2.55 Specific Graivity of Coarse Aggregate 2.65 Targeted Slump 180 mm Step 1:- Determination of Targated Mean Strength:- fm= fmin+ks 34.56MPa Here, s= Standard Deviatio = 4 K= 1.64 ( where 5% result are allowed to fall bel Step 2:- Determination of Water Content Ratio:- By Using Table: 11.11 & Figure: 11.3 from concrete technolo Water / Cement Ratio0.65 Step 3:- Determination of Water Content : Considering Slump: 180 mm Maximum Size of Aggregate 20mm (Crushed) ** Reduction of Water: Since portland composite cement will be used and most of t more than 20% Flyash. Assuming Fly ash content 20% . Water to the table 11.13 considering slump = 125mm Mix of Fly Ash in Cement: 2 Reduction per So Final Water Content Target Mean Strenth = Specific Charateristics Strenth + Himsworth Con 28+1.64×4 By Table 11.2 water content is 225 Kg/m 15kg/m^3 225-15 = 210 kg/m^3
Transcript
Concrete Mix Design
Data:-Specific Characteristics Strerngth: 28 MPa at the age of 28 days
Exposure Condition: very severe( In Pile)Clear Cover to be used : 30mmMaximum Size of Aggregate: 20mmSpecific Gravity of Fine Aggregate: 2.55Specific Graivity of Coarse Aggregate 2.65Targeted Slump 180 mm
Step 1:-Determination of Targated Mean Strength:-
fm= fmin+ks = 34.56MPa
Here,
s= Standard Deviation = 4K= 1.64 ( where 5% result are allowed to fall below specific design strength)
Step 2:-Determination of Water Content Ratio:-
By Using Table: 11.11 & Figure: 11.3 from concrete technology by M.S. ShettyWater / Cement Ratio = 0.65
Step 3:-Determination of Water Content :
Considering Slump: 180 mm Maximum Size of Aggregate : 20mm (Crushed)
** Reduction of Water:Since portland composite cement will be used and most of the cement brands usesmore than 20% Flyash. Assuming Fly ash content 20% . Water to be reduced according
to the table 11.13 considering slump = 125mm
Mix of Fly Ash in Cement: 20% Reduction per CBM:So Final Water Content :
Target Mean Strenth = Specific Charateristics Strenth + Himsworth Constant × Standard deviation
28+1.64×4
By Table 11.2 water content is 225 Kg/m^3
15kg/m^3 225-15 = 210 kg/m^3
Step 4 :-Determination of Cement Content:
Cement Content = ( 100 - p)*w Here,
( 100 -0.7P)* W/C p = percent of flyash
= ( 100 - 20)*210 W = water content (100 -0.7*20)* 0.65
= 301 Kg
the fly ash content = pC 100 - p
= 20*337 100 - 20
= 75.25 kg
Hence the total cementitious material content is 301 + 75.25 = 376.25 kg/m^3
Refferring to table 9.20, for very severe exposure condition concrete cover 25mm the maximum free water/cemetitious material ratio is 0.50 and minimum cement content is 350 kg/m^3
*** Water also can be reduced by use wate reducing Admixture or high range water reducer
Rheobuild 623 is Prescibe to be used and water reducer considered 10%
So Water = 188 - 18.8Step 5:-Determination of Total Aggregate:
Bulk Specific gravity of 20mm Crushed Aggregate = 2.65
Step 6:-Determination of Fine Aggregate:-
Water/ Cement Ratio = 0.50
Maximum size of Aggregate = 20mmRatio of Fine Aggregate = 40%
So Final Estimated Quantities: Cement = 376 kg FA = 742 kg CA = 1114 Kg Water = 169 kgAdmixure @ 1% of Count weight
= 3.762404.76kg
Say, Cement Content = 376 kg/m^3
Thus water content = 376*0.50 = 188 kg/m^3
= 169.2 kg/m^3≈ 169 kg/m^3
Free Water Content = 188 kg/m^3By using figure 11.4 , Density of wet Concrete is 2401 kg/m^3
So weight of total Aggrgate = 2401 - ( 376+ 169) = 1856kg/m^3
Quantity of Fine Aggregate = 742 kg/ m^3Amount of Coarse Aggregate = 1837 - 735 = 1114 kg/ m^3
Step 4 :-Determination of Cement Content:
Total Water = Water /Cement Ratio= 0.55
Cement Content =
According to the durabelity and exposure condition table 9.20, Minimum cement content is
Maximum Content is Accepted
189 kg/m^3
189/0.55 = 358kg/m^3
So, 344 Kg/m^3
= 325 kg/m^3
Refferring to table 9.20, for very severe exposure condition concrete cover 25mm the maximum
Concrete Mix Design
Data:-Specific Characteristics Strerngth: 30 MPa at the age of 28 days
Exposure Condition: Severe( In Pier)Clear Cover to be used : 30mmMaximum Size of Aggregate: 20mmSpecific Gravity of Fine Aggregate: 2.55Specific Graivity of Coarse Aggregate 2.65Targeted Slump 150 mm
Step 1:-Determination of Targated Mean Strength:-
fm= fmin+ks = 36.56MPa
Here,
s= Standard Deviation = 4K= 1.64 ( where 5% result are allowed to fall below specific design strength)
Step 2:-Determination of Water Content Ratio:-
By Using Table: 11.11 & Figure: 11.3Water / Cement Ratio = 0.62
Step 3:-Determination of Water Content :
Considering Slump: 125mm Maximum Size of Aggregate : 20mm (Crushed)
** Reduction of Water:Since portland composite cement will be used and most of the cement brands usesmore than 20% Flyash. Assuming Fly ash content 20% . Water to be reduced according
to the table 11.13 considering slump = 125mm
Mix of Fly Ash in Cement: 20% Reduction per CBM:So Final Water Content :
Target Mean Strenth = Specific Charateristics Strenth + Himsworth Constant × Standard deviation
30+1.64×4
By Table 11.2 water content is 225 Kg/m^3
15kg/m^3 225-15 = 210 kg/m^3
Step 4 :-Determination of Cement Content:
Cement Content = ( 100 - p)*w Here,
( 100 -0.7P)* W/C p = percent of flyash
= ( 100 - 20)*210 W = water content (100 -0.7*20)* 0.62
= 315 Kg
the fly ash content = pC 100 - p
= 20*315 100 - 20
= 78.75 kg
Hence the total cementitious material content is 315 + 78.75 = 395.75 kg/m^3
Refferring to table 9.20, for Severe exposure condition concrete cover 30mm the maximum free water/cemetitious material ratio is 0.50 and minimum cement content is 350 kg/m^3
*** Water also can be reduced by use wate reducing Admixture or high range water reducer
Rheobuild 623 is Prescibe to be used and water reducer considered 10%
So Water = 197 - 19.7Step 5:-Determination of Total Aggregate:
Bulk Specific gravity of 20mm Crushed Aggregate = 2.65
Step 6:-Determination of Fine Aggregate:-
Water/ Cement Ratio = 0.50
Maximum size of Aggregate = 20mmRatio of Fine Aggregate = 40%
So Final Estimated Quantities: Cement = 394 kg FA = 731 kg CA = 1096 Kg Water = 177 kgAdmixure @ 1% of Count weight
= 3.942401.94 kg
Say, Cement Content = 394 kg/m^3
Thus water content = 394*0.50 = 197 kg/m^3
= 177.3 kg/m^3≈ 177 kg/m^3
Free Water Content = 177 kg/m^3By using figure 11.4 , Density of wet Concrete is 2398 kg/m^3
So weight of total Aggrgate = 2398- ( 394+ 177) = 1827 kg/m^3
Quantity of Fine Aggregate = 731 kg/ m^3Amount of Coarse Aggregate = 1827 - 731 = 1096 kg/ m^3
Concrete Mix Design
Data:-Specific Characteristics Strerngth: 32 MPa at the age of 28 days
Exposure Condition: Severe( In Pier)Clear Cover to be used : 30mmMaximum Size of Aggregate: 20mmSpecific Gravity of Fine Aggregate: 2.55Specific Graivity of Coarse Aggregate 2.65Targeted Slump 125 mm
Step 1:-Determination of Targated Mean Strength:-
fm= fmin+ks = 38.56MPa
Here,
s= Standard Deviation = 4K= 1.64 ( where 5% result are allowed to fall below specific design strength)
Step 2:-Determination of Water Content Ratio:-
By Using Table: 11.11 & Figure: 11.3Water / Cement Ratio = 0.61
Step 3:-Determination of Water Content :
Considering Slump: 125mm Maximum Size of Aggregate : 20mm (Crushed)
** Reduction of Water:Since portland composite cement will be used and most of the cement brands usesmore than 20% Flyash. Assuming Fly ash content 20% . Water to be reduced according
to the table 11.13 considering slump = 125mm
Mix of Fly Ash in Cement: 20% Reduction per CBM:So Final Water Content :
Target Mean Strenth = Specific Charateristics Strenth + Himsworth Constant × Standard deviation
32+1.64×4
By Table 11.2 water content is 225 Kg/m^3
15kg/m^3 225-15 = 210 kg/m^3
Step 4 :-Determination of Cement Content:
Cement Content = ( 100 - p)*w Here,
( 100 -0.7P)* W/C p = percent of flyash
= ( 100 - 20)*210 W = water content (100 -0.7*20)* 0.61
= 320 Kg
the fly ash ontent = pC 100 - p
= 20*320 100 - 20
= 80 kg
Hence the total cementitious material content is 320 + 80 = 400 kg/m^3
Refferring to table 9.20, for Severe exposure condition concrete cover 30mm the maximum free water/cemetitious material ratio is 0.50 and minimum cement content is 350 kg/m^3
*** Water also can be reduced by use wate reducing Admixture or high range water reducer
Rheobuild 623 is Prescibe to be used and water reducer considered 15%
So Water = 200 - 30Step 5:-Determination of Total Aggregate:
Bulk Specific gravity of 20mm Crushed Aggregate = 2.65
Step 6:-Determination of Fine Aggregate:-
Water/ Cement Ratio = 0.50
Maximum size of Aggregate = 20mmRatio of Fine Aggregate = 40%
So Final Estimated Quantities: Cement = 400 kg FA = 728 kg CA = 1092 Kg Water = 170 kgAdmixure @ 1% of Count weight
= 4.002394 kg
So, Cement Content = 400 kg/m^3
Thus water content = 400*0.50 = 200 kg/m^3
= 170 kg/m^3
Free Water Content = 200 kg/m^3By using figure 11.4 , Density of wet Concrete is 2390 kg/m^3
So weight of total Aggrgate = 2390- ( 400+ 170) = 1820 kg/m^3
Quantity of Fine Aggregate = 728 kg/ m^3Amount of Coarse Aggregate = 1820 - 728 = 1092 kg/ m^3
Concrete Mix Design
Data:-Specific Characteristics Strerngth: 35 MPa at the age of 28 days
Exposure Condition: Moderate( In Deck)Clear Cover to be used : 30mmMaximum Size of Aggregate: 20mmSpecific Gravity of Fine Aggregate: 2.55Specific Graivity of Coarse Aggregate 2.65Targeted Slump 125 mm
Step 1:-Determination of Targated Mean Strength:-
fm= fmin+ks = 41.56MPa
Here,
s= Standard Deviation = 4K= 1.64 ( where 5% result are allowed to fall below specific design strength)
Step 2:-Determination of Water Content Ratio:-
By Using Table: 11.11 & Figure: 11.3 from concrete technology by M.S. ShettyWater / Cement Ratio = 0.58
Step 3:-Determination of Water Content :
Considering Slump: 125mm Maximum Size of Aggregate : 20mm (Crushed)
** Reduction of Water:Since portland composite cement will be used and most of the cement brands usesmore than 20% Flyash. Assuming Fly ash content 20% . Water to be reduced according
to the table 11.13 considering slump = 125mm
Mix of Fly Ash in Cement: 20% Reduction per CBM:So Final Water Content :
Target Mean Strenth = Specific Charateristics Strenth + Himsworth Constant × Standard deviation
35+1.64×4
By Table 11.2 water content is 225 Kg/m^3
15kg/m^3 225-15 = 210 kg/m^3
Step 4 :-Determination of Cement Content:
Cement Content = ( 100 - p)*w Here,
( 100 -0.7P)* W/C p = percent of flyash
= ( 100 - 20)*210 W = water content (100 -0.7*20)* 0.58
= 337 Kg
the fly ash content = pC 100 - p
= 20*337 100 - 20
= 84.25 kg
Hence the total cementitious material content is 337 + 84.25 = 421.35 kg/m^3
Refferring to table 9.20, for moderate exposure condition concrete cover 25mm the maximum free water/cemetitious material ratio is 0.50 and minimum cement content is 350 kg/m^3
*** Water also can be reduced by use wate reducing Admixture or high range water reducer
Rheobuild 623 is Prescibe to be used and water reducer considered 15%
So Water = 211 - 31.5Step 5:-Determination of Total Aggregate:
Bulk Specific gravity of 20mm Crushed Aggregate = 2.65
Step 6:-Determination of Fine Aggregate:-
Water/ Cement Ratio = 0.50
Maximum size of Aggregate = 20mmRatio of Fine Aggregate = 40%
So Final Estimated Quantities: Cement = 421 kg FA = 720 kg CA = 1080 Kg Water = 179 kgAdmixure @ 1% of Count weight
= 4.212404.21 kg
Say, Cement Content = 421 kg/m^3
Thus water content = 421*0.50 = 210.5≈ 211 kg/m^3
= 179.35 kg/m^3≈ 179 kg/m^3
Free Water Content = 211 kg/m^3By using figure 11.4 , Density of wet Concrete is 2400 kg/m^3
So weight of total Aggrgate = 2400 - ( 421+ 179) = 1800 kg/m^3
Quantity of Fine Aggregate = 720 kg/ m^3Amount of Coarse Aggregate = 1800 - 720 = 1080 kg/ m^3
Step 4 :-Determination of Cement Content:
Total Water = Water /Cement Ratio= 0.55
Cement Content =
According to the durabelity and exposure condition table 9.20, Minimum cement content is
Maximum Content is Accepted
189 kg/m^3
189/0.55 = 358kg/m^3
So, 344 Kg/m^3
= 325 kg/m^3
Concrete Mix Design
Data:-Specific Characteristics Strerngth: 35 MPa at the age of 28 days
Exposure Condition: Moderate( In Girder)Clear Cover to be used : 30mmMaximum Size of Aggregate: 20mmSpecific Gravity of Fine Aggregate: 2.55Specific Graivity of Coarse Aggregate 2.65Targeted Slump 150 mm
Step 1:-Determination of Targated Mean Strength:-
fm= fmin+ks = 41.56MPa
Here,
s= Standard Deviation = 4K= 1.64 ( where 5% result are allowed to fall below specific design strength)
Step 2:-Determination of Water Content Ratio:-
By Using Table: 11.11 & Figure: 11.3Water / Cement Ratio = 0.58
Step 3:-Determination of Water Content :
Considering Slump: 150mm Maximum Size of Aggregate : 20mm (Crushed)
** Reduction of Water:Since portland composite cement will be used and most of the cement brands usesmore than 20% Flyash. Assuming Fly ash content 20% . Water to be reduced according
to the table 11.13 considering slump = 125mm
Mix of Fly Ash in Cement: 20% Reduction per CBM:So Final Water Content :
Target Mean Strenth = Specific Charateristics Strenth + Himsworth Constant × Standard deviation
35+1.64×4
By Table 11.2 water content is 225 Kg/m^3
15kg/m^3 225-15 = 210 kg/m^3
Step 4 :-Determination of Cement Content:
Cement Content = ( 100 - p)*w Here,
( 100 -0.7P)* W/C p = percent of flyash
= ( 100 - 20)*210 W = water content (100 -0.7*20)* 0.58
= 337 Kg
the fly ash content = pC 100 - p
= 20*337 100 - 20
= 84.25 kg
Hence the total cementitious material content is 337 + 84.25 = 421.35 kg/m^3
Refferring to table 9.20, for moderate exposure condition concrete cover 25mm the maximum free water/cemetitious material ratio is 0.50 and minimum cement content is 350 kg/m^3
*** Water also can be reduced by use wate reducing Admixture or high range water reducer
Rheobuild 623 is Prescibe to be used and water reducer considered 10%
So Water = 211 - 21.1Step 5:-Determination of Total Aggregate:
Bulk Specific gravity of 20mm Crushed Aggregate = 2.65
Step 6:-Determination of Fine Aggregate:-
Water/ Cement Ratio = 0.50
Maximum size of Aggregate = 20mmRatio of Fine Aggregate = 40%
So Final Estimated Quantities: Cement = 421 kg FA = 716 kg CA = 1073 Kg Water = 190 kgAdmixure @ 1% of Count weight
= 4.212404.21 kg
Say, Cement Content = 421 kg/m^3
Thus water content = 421*0.50 = 210.5≈ 211 kg/m^3
= 189.9 kg/m^3≈ 190 kg/m^3
Free Water Content = 211 kg/m^3By using figure 11.4 , Density of wet Concrete is 2400 kg/m^3
So weight of total Aggrgate = 2400 - ( 421+ 190) = 1789 kg/m^3
Quantity of Fine Aggregate = 716 kg/ m^3Amount of Coarse Aggregate = 1789 - 716 = 1073 kg/ m^3
