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CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the...

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1 CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020) SINGLE CORRECT 1 2 3 4 Two mutually perpendicular tangents of the parabola y 2 = 4ax (a > 0) meet the axis in P 1 and P 2 . If S is the focus of the parabola then 1 2 1 1 l( ) l( ) SP SP is equal to 1) 4 a 2) 2 a 3) 1 a 4) 1 4a 5 The straight line joining any point P on the parabola y 2 = 4ax to the vertex and perpendicular from the focus to the tangent at P, intersect at R, then the equation of the locus of R is 1) x 2 + 2y 2 – ax = 0 2) 2x 2 + y 2 – 2ax = 0 3) 2x 2 + 2y 2 – ay = 0 4) 2x 2 + y 2 – 2ay = 0
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Page 1: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

1

CONIC SECTION

ASSIGNMENT -6 (DATE:- 20.04.2020)

SINGLE CORRECT

1

2

3

4 Two mutually perpendicular tangents of the parabola y2 = 4ax (a > 0) meet the axis in

P1 and P2. If S is the focus of the parabola then 1 2

1 1

l( ) l( )SP SP is equal to

1)4

a 2)

2

a 3)

1

a 4)

1

4a

5 The straight line joining any point P on the parabola y2 = 4ax to the vertex and

perpendicular from the focus to the tangent at P, intersect at R, then the equation of

the locus of R is

1) x2 + 2y2 – ax = 0 2) 2x2 + y2 – 2ax = 0

3) 2x2 + 2y2 – ay = 0 4) 2x2 + y2 – 2ay = 0

Page 2: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

2

MULTY CORRECT TYPE

6. If a circle touches the parabola 2 4y x= at A(9,6) and is tangent to x-axis then which is/are correct

A) The minimum possible radius of circle is 60 18 10-

B) The maximum possible radius of circle is 60 18 10+

C) The y-intercept of common normal through A is 3 times x-intercept of common normal through A

D) The area of triangle formed by tangent, normal at A to parabola and x-axis is 60 square units

7. Let ‘O’ be origin and the curve y x 9 meets the x-axis and y-axis respectively at A and B. Which of

the following is/ are correct

A) The abscissa of the point where the tangent at B intersect the curve again is 36 18 2

B) Normal at A to the curve is x + 9 = 0

C) Tangent at B meets the tangent at A at , such that =15

2

D) The area of quadrilateral formed by the tangents at A and B and the co-ordinate axes is 33

4 square units

8. Let lines 1 1L : y 6 m x 4 and 2 2L : y 6 m x 4 touching parabola 2y 4ax a 0 at points

A and B respectively where A lies in I quadrant and 1 2

1 1 3,

m m 2 then

A) Length of latus rectum of parabola is 12

B) 1L and 2L are perpendicular

C) 1 2m m

D) Slope of normal at point B on parabola is 2

9. If a tangent of slope 1

3of the ellipse

2 2

2 21

x y

a b+ = ( )a b> is normal to the circle

2 2 2 2 1 0x y x y+ + + + = then which is/are correct

A) maximum value of ab is 2

3 B)

2,2

5a

æ ö÷ç ÷Î ç ÷ç ÷çè ø

C) 2

,23

aæ ö

÷çÎ ÷ç ÷çè ø D) Maximum value of ab is 1

10. If a tangent of slope 1

3 of the ellipse

2 2

2 21

x y

a b (a > b) is normal to the circle 2 2 2 2 1 0x y x y ,

then

Page 3: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

3

A) Maximum value of ab is 2

3 B) 2

,25

a

C) 2,2

3a

D) maximum value of ab is 1

COMPREHENSION TYPE QUESTIONS

Paragraph for Question Nos. 11 to 12

y f x is parabola of the form 2 1f x x bx , b is a constant. The tangent line is drawn at the

point where f x cuts y – axis, also touches2 2x y r . It is also given that at least one tangent can be

drawn from point P to y f x , where D is a point at which y x is non – differentiable .R

11. For maximum value of b, the area of circle is

A) 10

B)

5

C) D) 5

12. The value of L is,.

A) 21 1,1 , 1,0y x x y

B) 21 2,2 , 0,1y x x y

C) 21 2,2 , 3,1y x x y

D) 21 1,1 , 0,1y x x y

Page 4: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

4

INTEGER TYPE QUESITNS 15. An isosceles triangle has its vertex at origin and its base, parallel to the x-axis with the vertices above

the x-axis on the curve 227y x . Then maximum area of the triangle is K square units, where9

k

( [.]

G.I.F )

16. Radius of the circle which touches the tangents drawn from ( -2, 0) to the parabola 2y 4x & the parabola

2y 4x is , then 2

2 1 ______

17. The shortest distance between the parabola 22 2 1y x= - and

22 2 1x y= - is 1

d then

2d ___

18. Area of the figure (polygon) formed by the points on the ellipse

2 2

150 20

x y+ = , such that the pair of

tangents drawn from each of such points to the ellipse

2 2

116 9

x y+ = are perpendicular is K then sum of

digits of K equals

19. Let L be locus of midpoint of focal chords of the ellipse2 2x y

19 25 . The integer nearest to the area

enclosed by curve L is ................

20. The three ellipses

2 2

2 2

i i

x y1

a b , i = 1, 2, 3, have a common tangent, then the value of

2 2

1 1

2 2

2 2

2 2

3 3

a b 1

a b 1

a b 1

Page 5: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

5

MATRIX MATCHING TYPE QUESTIONS

21. A line L: 3y mx meets the y-axis at E(0,3) and the arc of the parabola

2 16 , 0 6y x y , at the point 0 0,F x y . The tangent to the parabola at 0 0,F x y

intersects the y-axis at 10,G y . The slope m of the line L is chosen such that the area

of triangle EFG has a local maximum.

Column-I Column-II

A) m= P) ½

B) Maximum area of EFG is Q) 4

C) 0y = R) 2

D) 1y = S) 1

22. If AB is a chord subtending right angle at the vertex of 2 4y x , P is the centroid of

OAB and S be the focus of parabola (where O is origin)

Column-I Column-II

A) The min area of PAB is P) 4

3

B) The locus of centroid of SAB is a

parabola whose length of

latusrectum is 4

then is

Q) 10

3

C) If the focus of the locus of centroid of

SAB is , then is

R) 16

3

D) The distance of P from the directrix of

2 4y x when area of PAB is

S) 11

3

Page 6: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

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minimum is

KEY AND SOLUTIONS

1 2 3 4 5 6 7 8 9

A B D 3 2 ABCD AC BCD AB

10 11 12 13 14 15 16 17 18

AB B D BCD AD 6 6 8 5

19 20 21 22

8 0 A-S

B-P

C-Q D-R

A-R

B-R

C-Q D-S

SINGLE CORRECT

1

2

Page 7: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

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3

4

Key: 3

SP1 = a(1 + 2

1t ) ;SP2 = a(1 + 2

2t )

t1t2 = – 1

1

1

SP =

2

1

(1 )a t ;

2

1

SP =

2

2(1 )

t

a t

1

1

SP +

2

1

SP=

1

a

5 Key: 2

T :ty = x + at2 ....(1)

Page 8: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

8

line perpendicular to (1) through (a,0)

tx + y = ta .... (2)

equation of OP : y –2

t x = 0....(3)

from (2) & (3) eleminating t we get locus ]

MULTY CORRECT TYPE 6. KEY: ABCD

SOL: Minimum 3

610

r ræ ö

÷ç- =÷ç ÷÷çè ø

60 18 10rÞ = -

Maximum 3

610

r ræ ö

÷ç+ =÷ç ÷÷çè ø

60 18 10rÞ = +

Tgt: 3 9 0x y- + =

Normal 3 33 0x y+ - =

111 33

x yÞ + =

Area 26 1 10

3 18 602 3 3

= + = ´ = sq. units

7. Key: AC

SOL:

Tgt at B

x-6y+18=0

Solving with 2y x 9

2y 6y 18 9

2y 6y 9 0 y 3 3 2 x 36 18 2

Solving x - 6y + 18 = 0 and x + 9 = 0 3 15

92 2

,

Area

391 1 27 81

27292 2 2 4

3

8. KEY: BCD

9. If a tangent of slope 1

3of the ellipse

2 2

2 21

x y

a b+ = ( )a b> is normal to the circle

2 2 2 2 1 0x y x y+ + + + = then which is/are correct

Page 9: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

9

A) maximum value of ab is 2

3 B)

2,2

5a

æ ö÷ç ÷Î ç ÷ç ÷çè ø

C) 2

,23

aæ ö

÷çÎ ÷ç ÷çè ø D) Maximum value of ab is 1

KEY: AB

SOL: Conceptual

10. KEY: AB

SOL: 2 2 2y mx a m b 2

21 ay x b

3 9

2 23y x a 9b passes through (-1, -1)

2 23 1 a 9b

2 22 a 9b 2 29 4a b 2 2

2 2a 9b9a b

2

COMPREHENSION TYPE QUESTIONS 11. KEY: B

12. KEY: D

13. KEY: BCD

14. KEY: AD

SOL: 57 & 58

Page 10: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

10

INTEGER TYPE QUESITNS 15. KEY: 6

SOL: K = 54

16. KEY: 6

SOL:

12 2 2

2r 3 1S 2 6

2

r 1 3

17. KEY: 8

SOL:

P

Qy x

3 1

,4 2

Pæ ö

÷ç= ÷ç ÷çè ø

Page 11: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

11

1 3

,2 4

Qæ ö

÷ç= ÷ç ÷çè ø

1

2 2PQ =

18. KEY: 5

SOL: circle 2 2 25x y+ =

There are 4 points of intersect with given ellipse

These points form square Þ diamond= 2 5 10´ =

\ area( )

210

502

= = Þ sum of digits = 5

19. KEY: 8

SOL: 2e

Area ab4

16

.3.525.4

12

. 7.565

nearest integer is 8

20. KEY: 0

SOL: . Let the common tangent be y = mx + c

Point of tangencies to the given ellipses are

2 22 2 2 2

3 31 1 2 2a m ba m b a m b

, , , , ,c c c c c c

Which are collinear

2 2

1 1

2 2

2 2

2 2

3 3

a m b1

c c

a m b1 0

c c

a m b1

c c

MATRIX MATCHING TYPE QUESTIONS

21. Key:-A-S B-P C-Q D-R

Sol:-Let point F on the parabola be 24 ,8t t

Tangent at this point is 24ty x t .

It meets the y-axis at (0, 4t).

Then the area of triangle EFG is

Page 12: CONIC SECTION ASSIGNMENT -6 (DATE:- 20.04.2020)...x 3 meets the y-axis at E(0,3) and the arc of the parabola y2 d6, at the point y 00,. The tangent to the parabola at y 00, intersects

12

2 2 32 3 4 6 8A t t t t t .

Differentiating w.r.t. t, we get 2' 12 24A t t t

For 1

' 0,2

A t t , which is point of maxima, So,

Point F is (1, 4). Slope of EF=1

m=1 or max

1| .

2A t sq units

0 4y and 1 2y 22. Key:-A-R B-R C-Q D-S

Sol:-Min area of 1

3PAB min area of OAB =

1

1

4 4

3t

t =

16

3

S=(1,0) A= 2

1 1, 2A t t , 2

2 2, 2B t t

Let centroid of ,SAB x y

2 2

1 2 1 23 1 ; 3 2x t t y t t

2

2

1 2 1 2

93 1 2 8

4

yx t t t t

2 43

3y x


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