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CS352 - Introduction to Queuing Theory
Rutgers University
CS352 Fall,2005 2
Queuing theory definitions (Bose) “the basic phenomenon of queueing arises
whenever a shared facility needs to be accessed for service by a large number of jobs or customers.”
(Wolff) “The primary tool for studying these problems [of congestions] is known as queueing theory.”
(Kleinrock) “We study the phenomena of standing, waiting, and serving, and we call this study Queueing Theory." "Any system in which arrivals place demands upon a finite capacity resource may be termed a queueing system.”
(Mathworld) “The study of the waiting times, lengths, and other properties of queues.”
http://www2.uwindsor.ca/~hlynka/queue.html
CS352 Fall,2005 3
Applications of Queuing Theory Telecommunications Traffic control Determining the sequence of computer
operations Predicting computer performance Health services (eg. control of hospital bed
assignments) Airport traffic, airline ticket sales Layout of manufacturing systems.
http://www2.uwindsor.ca/~hlynka/queue.html
CS352 Fall,2005 4
Example application of queuing theory
In many retail stores and banks multiple line/multiple checkout system a
queuing system where customers wait for the next available cashier
We can prove using queuing theory that : throughput improves increases when queues are used instead of separate lines
http://www.andrews.edu/~calkins/math/webtexts/prod10.htm#QT
CS352 Fall,2005 5
Example application of queuing theory
http://www.bsbpa.umkc.edu/classes/ashley/Chaptr14/sld006.htm
CS352 Fall,2005 6
Queuing theory for studying networks
View network as collections of queues FIFO data-structures
Queuing theory provides probabilistic analysis of these queues
Examples: Average length Average waiting time Probability queue is at a certain length Probability a packet will be lost
CS352 Fall,2005 7
Little’s Law
Little’s Law: Mean number tasks in system = mean arrival rate x mean response time Observed before, Little was first to prove
Applies to any system in equilibrium, as long as nothing in black box is creating or destroying tasks
Arrivals Departures
System
CS352 Fall,2005 8
Proving Little’s Law
J = Shaded area = 9
Same in all cases!
1 2 3 4 5 6 7 8
Packet #
Time
123
1 2 3 4 5 6 7 8
# in System
123
Time
1 2 3
Time inSystem
Packet #
123
Arrivals
Departures
CS352 Fall,2005 9
Definitions J: “Area” from previous slide N: Number of jobs (packets) T: Total time l: Average arrival rate
N/T W: Average time job is in the system
= J/N L: Average number of jobs in the system
= J/T
CS352 Fall,2005 10
1 2 3 4 5 6 7 8
# in System(L) 1
23
Proof: Method 1: Definition
Time (T) 1 2 3
Time inSystem(W)
Packet # (N)
123
=
WL TN )(
NWTLJ
WL )(
CS352 Fall,2005 11
Proof: Method 2: Substitution
WL TN )(
WL )(
))(( NJ
TN
TJ
TJ
TJ Tautology
CS352 Fall,2005 12
Model Queuing System
Server System Queuing System
Queue Server
Queuing System
Use Queuing models to Describe the behavior of queuing systems Evaluate system performance
CS352 Fall,2005 13
Characteristics of queuing systems
Arrival Process The distribution that determines how the tasks
arrives in the system. Service Process
The distribution that determines the task processing time
Number of Servers Total number of servers available to process the
tasks
CS352 Fall,2005 14
Kendall Notation 1/2/3(/4/5/6)
Six parameters in shorthand First three typically used, unless specified
1. Arrival Distribution
2. Service Distribution
3. Number of servers
4. Total Capacity (infinite if not specified)
5. Population Size (infinite)
6. Service Discipline (FCFS/FIFO)
CS352 Fall,2005 15
Distributions
M: stands for "Markovian", implying exponential distribution for service times or inter-arrival times.
D: Deterministic (e.g. fixed constant) Ek: Erlang with parameter k
Hk: Hyperexponential with param. k G: General (anything)
CS352 Fall,2005 16
Kendall Notation Examples
M/M/1: Poisson arrivals and exponential service, 1 server, infinite
capacity and population, FCFS (FIFO) the simplest ‘realistic’ queue
M/M/m Same, but M servers
G/G/3/20/1500/SPF General arrival and service distributions, 3 servers, 17
queue slots (20-3), 1500 total jobs, Shortest Packet First
CS352 Fall,2005 17
Poisson Process
For a poisson process with average arrival rate , the probability of seeing n arrivals in time interval delta t
0...)2Pr(
)1Pr()(...]!2
)(1[)1Pr(
1)0Pr()(1...!2
)(1)0Pr(
)(!
)()Pr(
2
2
ttott
ttte
ttott
te
tnEn
ten
t
t
nt
CS352 Fall,2005 18
Poisson process & exponential distribution
Inter-arrival time t (time between arrivals) in a Poisson process follows exponential distribution with parameter
1)(
)Pr(
tE
et t
CS352 Fall,2005 19
Analysis of M/M/1 queue
Given: • l: Arrival rate of jobs (packets on input link) • m: Service rate of the server (output link)
Solve: L: average number in queuing system Lq average number in the queue W: average waiting time in whole system Wq average waiting time in the queue
CS352 Fall,2005 20
M/M/1 queue model
l m
1
Wq
W
L
Lq
CS352 Fall,2005 21
Solving queuing systems
4 unknowns: L, Lq W, Wq
Relationships: L=lW Lq=lWq (steady-state argument) W = Wq + (1/m)
If we know any 1, can find the others Finding L is hard or easy depending on the type of
system. In general:
0
n
nnPL
CS352 Fall,2005 22
Analysis of M/M/1 queue
Goal: A closed form expression of the probability of the number of jobs in the queue (Pi) given only l and m
CS352 Fall,2005 23
Equilibrium conditions
n+1nn-1
l l ll
m mm m
)(tPnDefine to be the probability of having n tasks in the system at time t
0)()(
lim,)(lim, when Stablize
)()()()()()(
)()()()(
)]1)()[(()]1)()[((])1)(1)[(()(
)]1)()[((])1)(1)[(()(
11
1000
11
100
t
tPttPPtP
tPtPtPt
tPttP
tPtPt
tPttP
tttPtttPtttttPttP
tttPtttttPttP
nn
tnn
t
nnnnn
nnnn
CS352 Fall,2005 24
Equilibrium conditions
11
10
)(
nnn PPP
PP
n+1nn-1
l l ll
m mm m
CS352 Fall,2005 25
Solving for P0 and Pn
Step 1
Step 2
0,0
2
201 , PPPPPPn
n
0
0
000
1,1,1
n
n
n
n
nn PPthenP
CS352 Fall,2005 26
Solving for P0 and Pn
Step 3
Step 4
1ρρ1
1
ρ1
ρ1ρ,ρ
00
n
n
n
n
then
ρ1ρandρ1ρ
1
0
0
nn
n
n
PP
CS352 Fall,2005 27
Solving for L
0
n
nnPL )1(0
n
nn )1(1
1
n
nn
11)1( d
d
0
)1(n
ndd
2)1(1)1(
)1(
CS352 Fall,2005 28
Solving W, Wq and Lq
11LW
)(11
WWq
)()(
2
qq WL
CS352 Fall,2005 29
Online M/M/1 animation
http://www.dcs.ed.ac.uk/home/jeh/Simjava/queueing/mm1_q/mm1_q.html
CS352 Fall,2005 30
Response Time vs. Arrivals
1W
Waiting vs. Utilization
0
0.05
0.1
0.15
0.2
0.25
0 0.2 0.4 0.6 0.8 1 1.2
W(s
ec)
CS352 Fall,2005 31
Stable Region
Waiting vs. Utilization
0
0.005
0.01
0.015
0.02
0.025
0 0.2 0.4 0.6 0.8 1
W(s
ec)
linear region
CS352 Fall,2005 32
Example
On a network gateway, measurements show that the packets arrive at a mean rate of 125 packets per second (pps) and the gateway takes about 2 millisecs to forward them. Assuming an M/M/1 model, what is the probability of buffer overflow if the gateway had only 13 buffers. How many buffers are needed to keep packet loss below one packet per million?
CS352 Fall,2005 33
Example
Measurement of a network gateway: mean arrival rate (l): 125 Packets/s mean response time (m): 2 ms
Assuming exponential arrivals: What is the gateway’s utilization? What is the probability of n packets in the gateway? mean number of packets in the gateway? The number of buffers so P(overflow) is <10-6?
CS352 Fall,2005 34
Example
Arrival rate λ = Service rate μ = Gateway utilization ρ = λ/μ = Prob. of n packets in gateway =
Mean number of packets in gateway =
CS352 Fall,2005 35
Example Arrival rate λ = 125 pps Service rate μ = 1/0.002 = 500 pps Gateway utilization ρ = λ/μ = 0.25 Prob. of n packets in gateway =
Mean number of packets in gateway =
nn )25.0(75.0ρ)ρ1(
33.057.0
25.0
ρ1
ρ
CS352 Fall,2005 36
Example
Probability of buffer overflow:
To limit the probability of loss to less than 10-
6:
CS352 Fall,2005 37
Example Probability of buffer overflow:
= P(more than 13 packets in gateway)
To limit the probability of loss to less than 10-6:
CS352 Fall,2005 38
Example Probability of buffer overflow:
= P(more than 13 packets in gateway) = ρ13 = 0.2513 = 1.49x10-8
= 15 packets per billion packets To limit the probability of loss to
less than 10-6:
CS352 Fall,2005 39
Example Probability of buffer overflow:
= P(more than 13 packets in gateway) = ρ13 = 0.2513 = 1.49x10-8
= 15 packets per billion packets To limit the probability of loss to
less than 10-6:
610ρ n
CS352 Fall,2005 40
Example To limit the probability of loss to
less than 10-6:
or
25.0log/10log 6n
610ρ n
CS352 Fall,2005 41
Example To limit the probability of loss to
less than 10-6:
or
= 9.96
25.0log/10log 6n
610ρ n
CS352 Fall,2005 42
Empirical Example
M/M/msystem